Select sum with other table in SQL - sql

Question

How do I select sum with other table if I have data like below:
Table Member
MemberID Name DateJoin
M0001 John 01/01/2015
M0002 Willy 03/20/2016
M0003 Teddy 02/01/2017
etc....
Table Transaction
MemberID TransDate Total
M0002 02/01/2015 100000
M0002 02/28/2015 222000
M0001 01/01/2016 150000
M0001 01/26/2017 160000
M0002 01/25/2017 160000
M0003 02/01/2017 9000
I want the result as a sum of how many times the member transaction in shop in years 2015-2017
The result I want it's:
MemberID 2015 2016 2017
M0001 0 1 1
M0002 2 0 1
M0003 0 0 1
How many members will appear in Result although don't have transaction too.

Answer 1

try dynamic sql .
--load in #temp table
select MemberID , datepart (yyyy ,TransDate ) as TransDate ,COUNT(*)as cnt into #temp from [Transaction]
group by MemberID , datepart (yyyy ,TransDate )
DECLARE #cols AS NVARCHAR(MAX),
#query AS NVARCHAR(MAX);
SET #cols = STUFF((SELECT distinct ',' + QUOTENAME(c.TransDate)
FROM #temp c
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set #query = 'SELECT MemberID, ' + #cols + ' from
(
select MemberID
, cnt
, TransDate
from #temp
) x
pivot
(
max(cnt)
for TransDate in (' + #cols + ')
) p '
execute(#query)
drop #temp -- cleanup of #temp table

Answer 2

CREATE TABLE #Table1
([MemberID] varchar(5), [Name] varchar(5), [DateJoin] datetime)
;
INSERT INTO #Table1
([MemberID], [Name], [DateJoin])
VALUES
('M0001', 'John', '2015-01-01 00:00:00'),
('M0002', 'Willy', '2016-03-20 00:00:00'),
('M0003', 'Teddy', '2017-02-01 00:00:00')
;
CREATE TABLE #Table2
([MemberID] varchar(5), [TransDate] datetime, [Total] int)
;
INSERT INTO #Table2
([MemberID], [TransDate], [Total])
VALUES
('M0002', '2015-02-01 00:00:00', 100000),
('M0002', '2015-02-28 00:00:00', 222000),
('M0001', '2016-01-01 00:00:00', 150000),
('M0001', '2017-01-26 00:00:00', 160000),
('M0002', '2017-01-25 00:00:00', 160000),
('M0003', '2017-02-01 00:00:00', 9000)
;
select MemberID,[2015], [2016], [2017]
from
(
select a.MemberID,a.name,a.DateJoin,year(b.TransDate)[year],b.Total from #Table1 A join
#Table2 B on a.MemberID=b.MemberID
) src
pivot
(
count(total)
for year in ([2015], [2016], [2017])
) piv;
output
MemberID 2015 2016 2017
M0001 0 1 1
M0002 2 0 1
M0003 0 0 1
IN 2000
SELECT MEMBERID, COUNT(CASE WHEN YEAR=2015 THEN YEAR END ) AS [2015],
COUNT(CASE WHEN YEAR=2016 THEN YEAR END ) AS [2016],
COUNT(CASE WHEN YEAR=2017 THEN YEAR END ) AS [2017]
FROM (
SELECT A.MEMBERID,A.NAME,A.DATEJOIN,YEAR(B.TRANSDATE)[YEAR],B.TOTAL FROM #TABLE1 A JOIN
#TABLE2 B ON A.MEMBERID=B.MEMBERID)A
GROUP BY MEMBERID

Answer 3

It seems there is no information you need from table member. So select from table transaction alone and count conditionally.
select
memberid,
count(case when year(transdate) = 2015 then 1 end) as [2015],
count(case when year(transdate) = 2016 then 1 end) as [2016],
count(case when year(transdate) = 2017 then 1 end) as [2017]
from transaction
group by memberid
order by memberid;
If you want to include members that don't have any transaction, then you do need a join (an outer join that is):
select
m.memberid,
count(case when year(t.transdate) = 2015 then 1 end) as [2015],
count(case when year(t.transdate) = 2016 then 1 end) as [2016],
count(case when year(t.transdate) = 2017 then 1 end) as [2017]
from member m
left join transaction t on t.memberid = m.memberid
group by m.memberid
order by m.memberid;