I have a table and i want output as given below
want only distinct values.
I used cross apply but doesn't work.
Customer Book
C1 B1
C2 B1
C3 B1
I need output: All combination of all customers. Only distinct values
Example:
Customers
C1,C2
C1,C3
C2,C3
You can do this with Primary key column
CREATE TABLE #TAB( ID INT IDENTITY,Customer VARCHAR(10), Book VARCHAR(10))
INSERT INTO #TAB
SELECT 'C1','B1'
UNION ALL
SELECT 'C2','B1'
UNION ALL
SELECT 'C3','B1'
SELECT T2.Customer ,T.Customer
FROM #TAB T
INNER JOIN #TAB T2 ON T.ID >T2.ID
Result :
+----------+----------+
| Customer | Customer |
+----------+----------+
| C1 | C2 |
| C1 | C3 |
| C2 | C3 |
+----------+----------+
This should work, at least for your sample data and the narrative:
select distinct case when t1.customer > t2.customer then t2.customer + ',' + t1.customer else t1.customer + ',' + t2.customer end
from tbl t1
join tbl t2
on t1.book = t2.book
and t1.customer <> t2.customer
If you want customers with the same book, query should be something similar. Note the < operator, since we want (C1, C2), not (C2, C1):
select distinct a.customer_col , b.customer_col
from customer_table a join customer_table b
on a.book_col = b.book_col and a.customer_col < b.customer_col
Hoping i understood question correctly,
Please check below query. Please replace table and columns with your original one.
Rextester link - http://rextester.com/RPPXQO21553
select
a.customer_col , b.customer_col , a.rn , b.rn
from
(select customer_col , row_number() over (order by customer_col) rn from customer_table) a join
(select customer_col , row_number() over (order by customer_col) rn from customer_table) b
on a.customer_col <> b.customer_col
and a.rn < b.rn
order by 1
;
You can achieve this using self join (hope you want customers with the same book), Sample script below
select t1.customer,t2.customer
from #tble t1
inner join #tble t2 on t1.book = t2.book
and t1.customer < t2.customer
I got my answer as
select B,A from(select a.customer A,b.customer B, ROW_NUMBER() over(order by a.customer)rn from CustomerData a
JOIN CustomerData b ON a.customer>b.customer )x
Related
I have a table that contains the following data:
ADD_Col Data OrderId Output NEW_ADD Col1 Col2
----- ------ ------- -----> ------- -------- -------
AD*A*1 A 96 A 1 2
AD*A*1 B 95 B 1 1
AD*A*1 C 94 C 0.8 1
AD*A*1 D 93 D 5 2
AD*A*2 1 92
AD*A*2 1 91
AD*A*2 0.8 90
AD*A*2 5 89
AD*A*3 2 88
AD*A*3 1 87
AD*A*3 1 86
AD*A*3 2 85
This data is all in the same table and I need to link each letter to each factor. I was thinking of doing a ROW_NUMBER() and joining based on the respective row number and assign my letter the same number either that or DENSERANK. What would be the best way to achieve this? If you can please provide query examples that would be great thanks.
Seems like what you need to do is normalise your data here. Here I use PARSENAME to get the "column Number", and then ROW_NUMBER to number the relevant rows in the groups. Finally I use a Cross tab to Pivot to data:
WITH CTE AS(
SELECT V.[Key],
V.data,
V.[Order],
PARSENAME(REPLACE(V.[Key],'*','.'),1) AS ColNo,
ROW_NUMBER() OVER (PARTITION BY V.[Key] ORDER BY V.[Order] DESC) AS RN
FROM (VALUES('AD*A*1','A',96),
('AD*A*1','B',95),
('AD*A*1','C',94),
('AD*A*1','D',93),
('AD*A*2','1',92),
('AD*A*2','1',91),
('AD*A*2','0.8',90),
('AD*A*2','5',89),
('AD*A*3','2',88),
('AD*A*3','1',87),
('AD*A*3','1',86),
('AD*A*3','2',85))V([Key],[data],[Order]))
SELECT MAX(CASE C.ColNo WHEN '1' THEN C.[data] END) AS New_ADD,
MAX(CASE C.ColNo WHEN '2' THEN C.[data] END) AS Col1,
MAX(CASE C.ColNo WHEN '3' THEN C.[data] END) AS Col2
FROM CTE C
GROUP BY C.RN;
For your sample data this will work:
with cte as (
select *,
row_number() over (partition by [key] order by [OrderId desc]) rn,
dense_rank() over (order by [key]) rk
from tablename
)
select t1.data,
max(case when t2.rk = 2 then t2.data end) col1,
max(case when t2.rk = 3 then t2.data end) col2
from (select * from cte where rk = 1) t1
inner join (select * from cte where rk in (2, 3)) t2
on t2.rn = t1.rn
group by t1.data
See the demo.
Results:
> data | col1 | col2
> :--- | :--- | :---
> A | 1 | 2
> B | 1 | 1
> C | 0.8 | 1
> D | 5 | 2
select t1.Data "Key"
, t2.Data "Col1"
, t3.Data "Col2"
from ((SELECT Data,
row_number() over (order by Key_C) rn
from my_table
where Key_C = 'AD*A*1') t1
left join
(SELECT Data,
row_number() over (order by Key_C) rn
from my_table
where Key_C = 'AD*A*2') t2
on t1.rn = t2.rn
left join
(SELECT Data,
row_number() over (order by Key_C) rn
from my_table
where Key_C = 'AD*A*3') t3
on t2.rn = t3.rn);
Here is the DEMO
DROP TABLE IF EXISTS #RawData
SELECT
[ADD_Col]
,[Data]
,[OrderId]
,REPLACE([ADD_Col], 'AD*A*', '') AS [Level]
,DENSE_RANK() OVER (PARTITION BY [ADD_Col] ORDER BY [OrderId] DESC) AS [Grouping]
INTO
#RawData
FROM
[SourceTable]
SELECT
rd.[Data]
,rdc1.[Data] AS [Col1]
,rdc2.[Data] AS [Col2]
FROM
#RawData AS rd
LEFT OUTER JOIN #RawData AS rdc1
ON rdc1.[Level] = 2
AND rd.[Grouping] = rdc1.[Grouping]
LEFT OUTER JOIN #RawData AS rdc2
ON rdc2.[Level] = 3
AND rd.[Grouping] = rdc2.[Grouping]
WHERE
rd.[Level] = 1
I have following Data in myRecords Table
Id Date Name Cash
1 11/25/2016 4:23.123 Ramesh 10000
2 11/25/2016 4:23.173 Suresh 15000
1 11/27/2016 5:23.320 Ramesh 30000
2 11/27/2016 5:23.670 Suresh 40000
and I want to create view So I can get data in following Format
Id1 Date1 Name1 Cash1 Id2 Date2 Name2 Cash2
1 11/25/2016 4:23.123 Ramesh 10000 2 11/25/2016 4:23.173 Suresh 15000
1 11/27/2016 5:23.320 Ramesh 30000 2 11/27/2016 5:23.670 Suresh 40000
How can I do it.
If you are doing date and there will always only be 2 records per day you could convert to drop off the time and do a self join:
DECLARE #myRecords AS TABLE (Id INT, DATE DATETIME, Name VARCHAR(20), CASH INT)
INSERT INTO #myRecords VALUES (1,'11/25/2016 4:23','Ramesh',10000),(2,'11/25/2016 4:23','Suresh',15000)
,(1,'11/27/2016 5:23','Ramesh',30000),(2,'11/27/2016 4:23','Suresh',40000)
SELECT
m1.Id as Id1
,m1.Date as Date1
,m1.Name as Name1
,m1.Cash as Cash1
,m2.Id as Id2
,m2.Date as Date2
,m2.Name as Name2
,m2.Cash as Cash2
FROM
#myRecords m1
LEFT JOIN #myRecords m2
ON CAST(m1.DATE AS DATE) = CAST(m2.DATE AS DATE)
AND m1.Id <> m2.Id
WHERE
m1.Id = 1
Then you can also introduce ROW_NUMBER() to figure out whatever order you want then take all of the ODD RowNumbers and SELF JOIN to the Even RowNumbers:
;WITH cte AS (
SELECT
*
,RowNum = ROW_NUMBER() OVER (ORDER BY Date)
FROM
#myRecords
)
SELECT *
FROM
cte c1
LEFT JOIN cte c2
ON c1.RowNum + 1 = c2.RowNum
WHERE
c1.RowNum % 2 <> 0
As long as your Id joining logic is unclear, this will help In this case but you will need to add Id Filter or additional Identity column and row_number() in future I guess.
SELECT
T.*, TT.*
FROM
[Table] AS T
INNER JOIN
[Table] AS TT
ON T.Date = TT.Date
You can use Cross Apply for the required result set.
SELECT [ID],
[DATE],
[NAME],
[CASH],
B.*
FROM #TABLE1 A
CROSS APPLY (SELECT ID AS ID2,
[DATE] AS DATE2,
[NAME] AS NAME2,
[CASH] AS CASH2
FROM #TABLE1 B
WHERE A.ID < B.ID
AND CONVERT(DATE, A.DATE) = CONVERT(DATE, B.DATE))B
This will also return the same result:
select a.id, a.date, a.name, a.cash, b.id as id2, b.date as date2,
b.name as name2, b.cash as cash2
from myTable a
inner join myTable b on a.id+1 = b.id
and cast(a.date as date) <> cast(b.date as date)
I have 3 SQL tables as below:
Table 1
ItemId Name
----------
A aa
B bb
Table 2
ItemId Category
----------
A 1
A 2
A 3
B 1
Table 3
ItemId Dep
----------
A D1
B D2
B D3
I need result as this
ItemId Name Category Dep
------------------------
A aa 1 D1
2
3
B bb 1 D2
D3
Is there any way to get this result without looping tables?
You can first JOIN the tables on ItemId and then use ROW_NUMBER and RANK for formatting.
I suggest you do the display format in the client side
SQL Fiddle
WITH CTE AS(
SELECT
t1.ItemId, t1.Name, t2.Category, t3.Dep,
Rn_Cat = ROW_NUMBER() OVER(PARTITION BY t1.ItemId, t1.Name ORDER BY t2.Category),
Rn_Dep = ROW_NUMBER() OVER(PARTITION BY t1.ItemId, t1.Name ORDER BY t3.Dep),
Rnk_Cat = RANK() OVER(PARTITION BY t1.ItemId, t1.Name ORDER BY t2.Category),
Rnk_Dep = RANK() OVER(PARTITION BY t1.ItemId, t1.Name ORDER BY t3.Dep)
FROM Table1 t1
LEFT JOIN Table2 t2
ON t2.ItemId = t1.ItemId
LEFT JOIN Table3 t3
ON t3.ItemId = t1.ItemId
)
SELECT
ItemId = CASE WHEN Rn_Cat = 1 THEN ItemId ELSE '' END,
Name = CASE WHEN Rn_Cat = 1 THEN Name ELSE '' END,
Category = CASE WHEN Rn_Cat = Rnk_Cat THEN CONVERT(VARCHAR(10), Category) ELSE '' END,
Dep = CASE WHEN Rn_Dep = Rnk_Dep THEN CONVERT(VARCHAR(10), Dep) ELSE '' END
FROM CTE
May be Using UNION
Fiddle Here
WITH CTE AS(
SELECT
t2.ItemId,t1.Name,t2.Category,t3.Dep,
Rank() over(Partition by t1.ItemId,t1.Name order by t2.Category,t3.Dep) as rn
from
Table1 t1 join Table2 t2 on t1.ItemId=t2.ItemId
join Table3 t3 on t1.ItemId=t3.ItemId
)
SELECT
ItemId,Name,Category,Dep,Rn
FROM CTE where rn=1
union
SELECT
'','',Category,Dep,Rn
FROM CTE where rn>1
this will probably work:
;with cte_t1 as
(
select 'A' as ItemId, 'aa' as Name
union
select 'B' as ItemId, 'bb' as Name
),
cte_t2 as
(
select 'A' AS ItemId, 1 as Category
union
select 'A' AS ItemId, 2 as Category
union
select 'A' AS ItemId, 3 as Category
union
select 'B' AS ItemId, 1 as Category
),
cte_t3 as
(
select 'A' AS ItemId, 'D1' as Dep
union
select 'B' AS ItemId, 'D2' as Dep
union
select 'B' AS ItemId, 'D3' as Dep
),
cte_t4 as
(
SELECT T1.ItemId, t1.Name, T2.Category, T3.Dep, ROW_NUMBER() over(order by T1.ItemId, T2.Category) RowNumber
FROM cte_t1 t1 inner join cte_t2 t2
on t1.ItemId = t2.ItemId
inner join cte_t3 t3
on t1.ItemId = t3.ItemId
and t2.ItemId = t3.ItemId
)
select
case when a.ItemId = b.ItemId then '' else a.ItemId end as ItemId,
case when a.Name = b.Name then '' else a.Name end as Name,
case when a.Category = b.Category then '' else cast(a.Category as varchar(100)) end as Category,
case when a.Dep = b.Dep then '' else a.Dep end as Dep
from cte_t4 a
left join cte_t4 b
on a.RowNumber-1= b.RowNumber
Using this code -
SELECT table1.ItemID,
table1.Name,
table2.Category,
table3.Dep
FROM table1, table2, table3
WHERE table1.ItemID = table2.ItemID AND table1.ItemID = table3.ItemID;
produces this output -
+--------+------+----------+-----+
| ItemID | Name | Category | Dep |
+--------+------+----------+-----+
| A | aa | 1 | D1 |
| A | aa | 2 | D1 |
| A | aa | 3 | D1 |
| B | bb | 1 | D2 |
| B | bb | 1 | D3 |
+--------+------+----------+-----+
Is this what you are after, or do you wish to display a blank space for every repeat of a value?
I have this table:
supplier | product | qty
--------------------------
s1 | p1 | 300
s1 | p2 | 90
s2 | p3 | 89
I want to find suppliers with more than 2 products.
But only with select and where, no group by. Any suggestion?
Why would you want not to use group by is beyond me, but this might work:
SELECT Supplier FROM table outer WHERE
(
select count(Products) from table inner
where inner.Supplier = outer.Supplier
) > 2
Please bear in mind, that group by is made for stuff like that and should be used.
;WITH
sequenced_data AS
(
SELECT
supplier,
ROW_NUMBER() OVER (PARTITION BY supplier ORDER BY product) AS supplier_product_ordinal
FROM
YourTable
)
SELECT
supplier
FROM
sequenced_data
WHERE
supplier_product_ordinal = 3
But I'd expect it to be slower than using GROUP BY.
SELECT DISTINCT
supplier
FROM
yourTable
WHERE
EXISTS (SELECT * FROM yourTable AS lookup WHERE supplier = yourTable.supplier AND product < yourTable.product)
AND EXISTS (SELECT * FROM yourTable AS lookup WHERE supplier = yourTable.supplier AND product > yourTable.product);
In the usual parts and suppliers database, this relvar is named SP:
SELECT DISTINCT T1.SNO
FROM SP AS T1
JOIN SP AS T2
ON T1.SNO = T2.SNO
AND T2.PNO <> T1.PNO
JOIN SP AS T3
ON T1.SNO = T3.SNO
AND T3.PNO <> T1.PNO
AND T3.PNO <> T2.PNO;
Noting that you can use HAVING without GROUP BY:
SELECT DISTINCT T1.SNO
FROM SP AS T1
WHERE EXISTS (
SELECT 1
FROM SP AS T2
WHERE T2.SNO = T1.SNO
HAVING COUNT(*) > 2
);
;WITH T AS
(
SELECT *,
COUNT(*) OVER (PARTITION BY S) AS Cnt
FROM YourTable
)
SELECT DISTINCT S
FROM T
WHERE Cnt > 2
with subquery:
select distinct supplier
from table a
where (select count(*)
from table b
where b.supplier = a.supplier and b.product <> a.product
) > 1
I have TableA in a many-to-many relationship with TableC via TableB. That is,
TableA TableB TableC
id | val fkeyA | fkeyC id | data
I wish the do select sum(val) on TableA, grouping by the relationship(s) to TableC. Every entry in TableA has at least one relationship with TableC. For example,
TableA
1 | 25
2 | 30
3 | 50
TableB
1 | 1
1 | 2
2 | 1
2 | 2
2 | 3
3 | 1
3 | 2
should output
75
30
since rows 1 and 3 in Table have the same relationships to TableC, but row 2 in TableA has a different relationship to TableC.
How can I write a SQL query for this?
SELECT
sum(tableA.val) as sumVal,
tableC.data
FROM
tableA
inner join tableB ON tableA.id = tableB.fkeyA
INNER JOIN tableC ON tableB.fkeyC = tableC.id
GROUP by tableC.data
edit
Ah ha - I now see what you're getting at. Let me try again:
SELECT
sum(val) as sumVal,
tableCGroup
FROM
(
SELECT
tableA.val,
(
SELECT cast(tableB.fkeyC as varchar) + ','
FROM tableB WHERE tableB.fKeyA = tableA.id
ORDER BY tableB.fkeyC
FOR XML PATH('')
) as tableCGroup
FROM
tableA
) tmp
GROUP BY
tableCGroup
Hm, in MySQL it could be written like this:
SELECT
SUM(val) AS sumVal
FROM
( SELECT
fkeyA
, GROUP_CONCAT(fkeyC ORDER BY fkeyC) AS grpC
FROM
TableB
GROUP BY
fkeyA
) AS g
JOIN
TableA a
ON a.id = g.fkeyA
GROUP BY
grpC
SELECT sum(a.val)
FROM tablea a
INNER JOIN tableb b ON (b.fKeyA = a.id)
GROUP BY b.fKeyC
It seems that is it needed to create a key_list in orther to allow group by:
75 -> key list = "1 2"
30 -> key list = "1 2 3"
Because GROUP_CONCAT don't exists in T-SQL:
WITH CTE ( Id, key_list )
AS ( SELECT TableA.id, CAST( '' AS VARCHAR(8000) )
FROM TableA
GROUP BY TableA.id
UNION ALL
SELECT TableA.id, CAST( key_list + ' ' + str(TableB.id) AS VARCHAR(8000) )
FROM CTE c
INNER JOIN TableA A
ON c.Id = A.id
INNER join TableB B
ON B.Id = A.id
WHERE A.id > c.id --avoid infinite loop
)
Select
sum( val )
from
TableA inner join
CTE on (tableA.id = CTE.id)
group by
CTE.key_list