For some reason I'm unable to use comparisons on GUID columns, it does not return any results.
See below, with the WHERE clause set to the exact value of the 'secguid' column, it does not return any results. What's going on?
SELECT * FROM dbMobileFile
SELECT * FROM dbMobileFile WHERE secguid = '3137459D-EFDE-449E-94A3-89345A8580FA'
SELECT * FROM dbMobileFile WHERE secguid LIKE '3137459D-EFDE-449E-94A3-89345A8580FA'
Using LIKE does not work either.
Try this
SELECT [fileID],
[fileCOde],
[filePassword],
[fileDescription],
[rowguid],
[secguid]
FROM [dbo].[dbMobileFile]
WHERE CAST(secguid as uniqueidentifier) = CAST('3137459D-EFDE-449E-94A3-89345A8580FA' as uniqueidentifier)
Since you mention that the column is stored as NVARCHAR, its possible that the string has leading or trailing whitespaces, which is why it might not be popping up in the query with the WHERE clause.
You can try this :
SELECT [fileID],
[fileCOde],
[filePassword],
[fileDescription],
[rowguid],
[secguid]
FROM [dbo].[dbMobileFile]
WHERE LTRIM(RTRIM(secguid)) = '3137459D-EFDE-449E-94A3-89345A8580FA'
which should show you the result as leading and trailing whitespaces are eliminated in the WHERE clause.
Also, in case you want to make use of the LIKE operator, you can write your query as :
SELECT [fileID],
[fileCOde],
[filePassword],
[fileDescription],
[rowguid],
[secguid]
FROM [dbo].[dbMobileFile]
WHERE secguid LIKE '%3137459D-EFDE-449E-94A3-89345A8580FA%'
Hope this helps!!!
I've had this problem with a corrupt database. Some GUIDs be contained in the WHERE clause, with other GUIDS on the same table would not return results.
Turns out that database had Index issues. Run DBCC to make sure your database isn't corrupt.
The accepted answer works, but it is a bit verbose and probably not the intended way to do this. UniqueIdentifier is qualified by {}, so the following is the easiest;
SELECT * FROM dbMobileFile WHERE secguid = '{3137459D-EFDE-449E-94A3-89345A8580FA}'
See inside the database that guid value stored as 32 hex digits:00000000000000000000000000000000 so if we search by 32 hex digits separated by hyphens: 00000000-0000-0000-0000-000000000000, it's not get any output
Try this:
SELECT * FROM dbMobileFile WHERE secguid = ('3137459D-EFDE-449E-94A3-89345A8580FA')
Use parentheses to enclose GUID string LIKE ('GUID')
Related
I have a table with about 200 million records. One of the columns is defined as varchar(100) and it's included in a full text index. Most of the values are numeric. Only few are not numeric.
The problem is that it's not working well. For example if a row contains the value '123456789' and i look for '567', it's not returning this row. It will only return rows where the value is exactly '567'.
What am I doing wrong?
sql server 2012.
Thanks.
Full text search doesn't support leading wildcards
In my setup, these return the same
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'28400')
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"2840*"')
This gives zero rows
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"*840*"')
You'll have to use LIKE or some fancy trigram approach
The problem is probably that you are using a wrong tool since Full-text queries perform linguistic searches and it seems like you want to use simple "like" condition.
If you want to get a solution to your needs then you can post DDL+DML+'desired result'
You can do this:
....your_query.... LIKE '567%' ;
This will return all the rows that have a number 567 in the beginning, end or in between somewhere.
99% You're missing % after and before the string you search in the LIKE clause.
es:
SELECT * FROM t WHERE att LIKE '66'
is the same as as using WHERE att = '66'
if you write:
SELECT * FROM t WHERE att LIKE '%66%'
will return you all the lines containing 2 'sixes' one after other
I have the following extract of a code used in SAS and wanted to write it in SQL Server to extract data.
substr(zipname,1,4) in("2000","9000","3000","1000");run;
How do I write this in SQL Server ?
I tried and got this error:
An expression of non-boolean type specified in a context where a
condition is expected
In sql server, there's no substr function (it's substring)
by the way, you need a complete query...
select blabla
from blibli
where substring(zipname, 1, 4) in ('2000', '9000', 3000', '1000')
assuming zipname is a varchar or something like that...
You need a table that you are getting the records from, and zipname would be a column in the table. The statement would be something like this:
select * from tablename where substring(zipname,1,4) in ('2000','9000','3000','1000')
Since you want the first x characters, you can also use the left() function.
where left(zipname, 4) in (values go here)
Bear in mind that your values have to be single quoted. Your question has double quotes.
Suppose I have a table named 'Customer' with many columns and I want to display all customers who's name ends with 'Thomas'(Lastname = 'Thomas'). The following query shows an empty result(no rows). Also it didn't show any error.
SELECT * FROM Customer WHERE Lastname = 'Thomas';
While executing the following query give me correct result.
SELECT * FROM Customer WHERE Lastname LIKE '%Thomas%';
I would like to know what is the problem with my first query. I am using sqlite3 with Npm. Below is the result of '.show' command(Just in case of the problem is with config).
sqlite> .show
echo: off
explain: off
headers: on
mode: column
nullvalue: ""
output: stdout
separator: "|"
stats: off
width:
Use Like instead of =
Trim to ensure that there arent spaces messing around
so the query will be
SELECT * FROM Customer WHERE trim(Lastname) LIKE 'Thomas';
depending on your types, probably you dont need point 2, since as can be read in mysql manual
All MySQL collations are of type PADSPACE. This means that all CHAR
and VARCHAR values in MySQL are compared without regard to any
trailing spaces
But the point 1 could be the solution. Actually if you want to avoid problems, you should compare strings with LIKE, instead of =.
If You still have problems, probably you will have to use collates.
SELECT *
FROM t1
WHERE k LIKE _latin1 'Müller' COLLATE latin1_german2_ci; #using your real table collation
more information here But specifically with 'Thomas' you shouldn't need it, since it hasn't got any special characters.
I'm trying to retrieve all columns that start with any non alpha characters in SQlite but can't seem to get it working. I've currently got this code, but it returns every row:
SELECT * FROM TestTable WHERE TestNames NOT LIKE '[A-z]%'
Is there a way to retrieve all rows where the first character of TestNames are not part of the alphabet?
Are you going first character only?
select * from TestTable WHERE substr(TestNames,1) NOT LIKE '%[^a-zA-Z]%'
The substr function (can also be called as left() in some SQL languages) will help isolate the first char in the string for you.
edit:
Maybe substr(TestNames,1,1) in sqllite, I don't have a ready instance to test the syntax there on.
Added:
select * from TestTable WHERE Upper(substr(TestNames,1,1)) NOT in ('A','B','C','D','E',....)
Doesn't seem optimal, but functionally will work. Unsure what char commands there are to do a range of letters in SQLlite.
I used 'upper' to make it so you don't need to do lower case letters in the not in statement...kinda hope SQLlite knows what that is.
try
SELECT * FROM TestTable WHERE TestNames NOT LIKE '[^a-zA-Z]%'
SELECT * FROM NC_CRIT_ATTACH WHERE substring(FILENAME,1,1) NOT LIKE '[A-z]%';
SHOULD be a little faster as it is
A) First getting all of the data from the first column only, then scanning it.
B) Still a full-table scan unless you index this column.
I have stored values in my database that look like 5XXXXXX, where X can be any digit. In other words, I need to match incoming SQL query strings like 5349878.
Does anyone have an idea how to do it?
I have different cases like XXXX7XX for example, so it has to be generic. I don't care about representing the pattern in a different way inside the SQL Server.
I'm working with c# in .NET.
You can write queries like this in SQL Server:
--each [0-9] matches a single digit, this would match 5xx
SELECT * FROM YourTable WHERE SomeField LIKE '5[0-9][0-9]'
stored value in DB is: 5XXXXXX [where x can be any digit]
You don't mention data types - if numeric, you'll likely have to use CAST/CONVERT to change the data type to [n]varchar.
Use:
WHERE CHARINDEX(column, '5') = 1
AND CHARINDEX(column, '.') = 0 --to stop decimals if needed
AND ISNUMERIC(column) = 1
References:
CHARINDEX
ISNUMERIC
i have also different cases like XXXX7XX for example, so it has to be generic.
Use:
WHERE PATINDEX('%7%', column) = 5
AND CHARINDEX(column, '.') = 0 --to stop decimals if needed
AND ISNUMERIC(column) = 1
References:
PATINDEX
Regex Support
SQL Server 2000+ supports regex, but the catch is you have to create the UDF function in CLR before you have the ability. There are numerous articles providing example code if you google them. Once you have that in place, you can use:
5\d{6} for your first example
\d{4}7\d{2} for your second example
For more info on regular expressions, I highly recommend this website.
Try this
select * from mytable
where p1 not like '%[^0-9]%' and substring(p1,1,1)='5'
Of course, you'll need to adjust the substring value, but the rest should work...
In order to match a digit, you can use [0-9].
So you could use 5[0-9][0-9][0-9][0-9][0-9][0-9] and [0-9][0-9][0-9][0-9]7[0-9][0-9][0-9]. I do this a lot for zip codes.
SQL Wildcards are enough for this purpose. Follow this link: http://www.w3schools.com/SQL/sql_wildcards.asp
you need to use a query like this:
select * from mytable where msisdn like '%7%'
or
select * from mytable where msisdn like '56655%'