Display values for specific time-frame - sql

when I run below select:
select name, time, value from table1 where name like '%Z' or '%V'
I got result:
I need to do two things:
1) query will be run every hour, so if we have 12.00.00PM range should be between (11 and 12> PM, if it's 02.00.00AM range will be (01 and 02> AM
2) second thing is to display avg(value) for name ending by '%Z' or '%V' into one row, but into two columns
Below is example of desirable result, when query was run at 12.00.00 PM:

You are asking for three things, which can be thought of as three steps. Getting the time window is fairly straightforward, and only slightly complicated by your column being a timestamp rather than a date. You implied this will run on the hour, but it's possible it will be slightly afterwards - maybe a second or two? - so it's probably safer to take that into account. You can use the trunc() function to modify a date value to the required precision, so to only look at the current hour you would truncate to HH[24]. You can then cast that back to a timestamp. And you can use interval arithmetic to find the hour before that:
alter session set nls_date_format = 'YYYY-MM-DD HH24:MI:SS';
alter session set nls_timestamp_format = 'YYYY-MM-DD HH24:MI:SS.FF3';
alter session set nls_timestamp_tz_format = 'YYYY-MM-DD HH24:MI:SS.FF3 TZR';
select systimestamp,
trunc(systimestamp, 'HH24') as a,
cast(trunc(systimestamp, 'HH24') as timestamp) as b,
cast(trunc(systimestamp, 'HH24') as timestamp) - interval '1' hour as c
from dual;
SYSTIMESTAMP A B C
------------------------------ ------------------- ----------------------- -----------------------
2017-03-01 09:25:39.342 +00:00 2017-03-01 09:00:00 2017-03-01 09:00:00.000 2017-03-01 08:00:00.000
The alter session commands are just to control how the different data types are displayed, for comparison. (Don't rely on NLS settings in your real code; use to_char() for final formatting of datetime values as strings).
Notice that the result of the truncation is now a date (A in that output), so I've cast it back to a timestamp (B). The range you want is essentially time >= A and time < B. And you could use sysdate instead of systimestamp as the input to trunc().
For your sample data using systimestamp or sysdate isn't going to find anything, so I'll use a fake fixed time for the rest, generated in a CTE for separation. Where I've used now from the CTE, you would use systimestamp or sysdate.
The second part is to get the average for each name within that time period. That's simple aggregation:
with fake_time(now) as (
select timestamp '2017-02-10 13:01:07' from dual
)
select name,
avg(value) as avg_value,
cast(trunc(now, 'HH24') as timestamp) as time
from fake_time
join table1 on time >= cast(trunc(now, 'HH24') as timestamp) - interval '1' hour
and time < cast(trunc(now, 'HH24') as timestamp)
group by name, now;
NAME AVG_VALUE TIME
------- ---------- -----------------------
QWER1_Z 20 2017-02-10 13:00:00.000
QWER1_V 35 2017-02-10 13:00:00.000
TEST1_Z 15 2017-02-10 13:00:00.000
TEST1_V 10 2017-02-10 13:00:00.000
To pick up the rows you want I've made the fake time 13:00 instead of 12:00. The average you showed for TEST1_V was also wrong.
The next stage it pivoting those into the format you wanted, as a single row. For that you can add the root (i.e. TEST1 or QWER1) and the letter (Z or V) as extra columns in the result set, and then use that as the subquery for the pivot operation - this requires 11g or higher:
with fake_time(now) as (
select timestamp '2017-02-10 13:01:07' from dual
)
select z_name, z_value, v_name, v_value, time
from (
select substr(name, 1, length(name) - 2) as root,
substr(name, -1) as zv,
name,
avg(value) as avg_value,
cast(trunc(now, 'HH24') as timestamp) as time
from fake_time
join table1 on time >= cast(trunc(now, 'HH24') as timestamp) - interval '1' hour
and time < cast(trunc(now, 'HH24') as timestamp)
group by substr(name, 1, length(name) - 2), name, now
)
pivot (max(name) as name, max(avg_value) as value for (zv) in ('Z' as z, 'V' as v));
Z_NAME Z_VALUE V_NAME V_VALUE TIME
------- ---------- ------- ---------- -----------------------
TEST1_Z 15 TEST1_V 10 2017-02-10 13:00:00.000
QWER1_Z 20 QWER1_V 35 2017-02-10 13:00:00.000
There may be another step required; in your sample output you included a list of the original values that were averaged, but didn't confirm if you actually wanted those or if they were just to show how the average was caculated to help us understand what you needed to do. If you really do want to include that you can use listagg() and concatenation to build up the 'average' string before pivoting:
'avg(' || listagg(value, ',') within group (order by value) || ') = ' || avg(value)
as avg_value,
to get
Z_NAME Z_VALUE V_NAME V_VALUE TIME
------- -------------------- ------- -------------------- -----------------------
TEST1_Z avg(10,20) = 15 TEST1_V avg(10) = 10 2017-02-10 13:00:00.000
QWER1_Z avg(20) = 20 QWER1_V avg(30,40) = 35 2017-02-10 13:00:00.000
As I said earlier, I've only used the fake_date CTE to get a date that matches your sample data. Your real query will be more like:
select z_name, z_value, v_name, v_value, time
from (
select substr(name, 1, length(name) - 2) as root,
substr(name, -1) as zv,
name,
avg(value) as avg_value,
cast(trunc(sysdate, 'HH24') as timestamp) as time
from table1
where time >= cast(trunc(sysdate, 'HH24') as timestamp) - interval '1' hour
and time < cast(trunc(sysdate, 'HH24') as timestamp)
group by substr(name, 1, length(name) - 2), name
)
pivot (max(name) as name, max(avg_value) as value for (zv) in ('Z' as z, 'V' as v));

select T1.Z, T1.V from (
(select avg(values) from table1 where name like '%Z' and time between sysdate and sysdate - interval '1' group by INSTR(name,'Z')) Z,
(select avg(values) from table1 where name like '%V' and time between sysdate and sysdate - interval '1' group by INSTR(name,'V')) V ) T1

Related

How can I extract just the time component from an Oracle timestamp value?

I'm attempting to create a breakdown of requests per hour. As such the date part of the TimeStamp object needs to be ignored. This is what I've tried to far:
select
trunc(request_time, 'HH'),
count(*)
from
service_request
group by
trunc(request_time, 'HH');
This seems to group all data into one hour sections but also groups by the day. How do I go about removing the date part so I end up with results like:
Time Count
--------------
00:00 1
01:00 4
02:00 2
You should be able to do
select to_number( to_char( request_time, 'HH24' ) ),
count(*)
from service_request
group by to_number( to_char( request_time, 'HH24' ) );
The to_number is probably not strictly necessary but it makes more sense to return a numeric hour than a string hour for things like sorting.
If the data type is actually a timestamp, then you could improve this
select extract( hour from request_time ),
count(*)
from service_request
group by extract( hour from request_time );

Need to split datetime ranges by each day

I have a table that needs to be split on the basis of datetime
Input Table
ID| Start | End
--------------------------------------------
A | 2019-03-04 23:18:04| 2019-03-04 23:21:25
--------------------------------------------
A | 2019-03-04 23:45:05| 2019-03-05 00:15:14
--------------------------------------------
Required Output
ID| Start | End
--------------------------------------------
A | 2019-03-04 23:18:04| 2019-03-04 23:21:25
--------------------------------------------
A | 2019-03-04 23:45:05| 2019-03-04 23:59:59
--------------------------------------------
A | 2019-03-05 00:00:00| 2019-03-05 00:15:14
--------------------------------------------
Thanks!!
Try this below code. This will only work if the start and end date fall in two consecutive day. Not if the start and end date difference is more than 1 day.
MSSQL:
SELECT ID,[Start],[End]
FROM Input_Table A
WHERE DATEDIFF(DD,[Start],[End]) = 0
UNION ALL
SELECT ID,[Start], CAST(CAST(CAST([Start] AS DATE) AS VARCHAR(MAX)) +' 23:59:59' AS DATETIME)
FROM Input_Table A
WHERE DATEDIFF(DD,[Start],[End]) > 0
UNION ALL
SELECT ID,CAST(CAST([End] AS DATE) AS DATETIME),[End]
FROM Input_Table A
WHERE DATEDIFF(DD,[Start],[End]) > 0
ORDER BY 1,2,3
PostgreSQL:
SELECT ID,
TO_TIMESTAMP(startDate,'YYYY-MM-DD HH24:MI:SS'),
TO_TIMESTAMP(endDate, 'YYYY-MM-DD HH24:MI:SS')
FROM mytemp A
WHERE DATE_PART('day', endDate::date) -
DATE_PART('day',startDate::date) = 0
UNION ALL
SELECT ID,
TO_TIMESTAMP(startDate,'YYYY-MM-DD HH24:MI:SS'),
TO_TIMESTAMP(CONCAT(CAST(CAST (startDate AS DATE) AS VARCHAR) ,
' 23:59:59') , 'YYYY-MM-DD HH24:MI:SS')
FROM mytemp A
WHERE DATE_PART('day', endDate::date) -
DATE_PART('day',startDate::date) > 0
UNION ALL
SELECT ID,
TO_TIMESTAMP(CAST(CAST (endDate AS DATE) AS VARCHAR) ,
'YYYY-MM-DD HH24:MI:SS') ,
TO_TIMESTAMP(endDate,'YYYY-MM-DD HH24:MI:SS')
FROM mytemp A
WHERE DATE_PART('day', endDate::date) -
DATE_PART('day',startDate::date) > 0;
PostgreSQL Demo Here
demo:db<>fiddle
This works even when range crosses more than one day
WITH cte AS (
SELECT
id,
start_time,
end_time,
gs,
lag(gs) over (PARTITION BY id ORDER BY gs) -- 2
FROM
a
LEFT JOIN LATERAL
generate_series(start_time::date + 1, end_time::date, interval '1 day') gs --1
ON TRUE
)
SELECT -- 3
id,
COALESCE(lag, start_time) AS start_time,
gs - interval '1 second'
FROM
cte
WHERE gs IS NOT NULL
UNION
SELECT DISTINCT ON (id) -- 4
id,
CASE WHEN start_time::date = end_time::date THEN start_time ELSE end_time::date END, -- 5
end_time
FROM
cte
CTE: the generate_series function generates one row per day new day. So, there is no value if there is no date change
CTE: the lag() window function allows to move the current date value into the next row (the current end is the next start)
With this data set you can calculate the new start and end values. If there is no gs value: There is no date change. This ignored at this point. For all cases with date changes: If there is no lag value, it is the beginning (so it cannot got a previous value). In this case, the normal start_time is taken, otherwise it is a new day which takes the date break time. The end_time is taken with the last second of the day (interval - '1 second')
The second part: Because of the date breaks there is always one additional record which need to be unioned. The last record is from the beginning of the end_time (so cast to date). The CASE clause combines this step with the case of no date change which has been ignored so far. So if start_time and end_time are at the same date, here the original start_time is taken.
Unfortunately, Redshift doesn't have a convenient way to generate a series of numbers. If you table is big enough, you can use it to generate numbers. "Big enough" means that the number of rows is greater than the longest span. Perhaps another table would work, if not this one.
Once you have that, you can use this logic:
with n as (
select row_number() over () - 1 as n
from t
)
select t.id,
greatest(t.s, date_trunc('day', t.s) + n.n * interval '1 day') as s,
least(t.e, date_trunc('day', t.s) + (n.n + 1) * interval '1 day' - interval '1 second') as e
from t join
n
on t.e >= date_trunc('day', t.s) + n.n * interval '1 day';
Here is a db<>fiddle. It uses an old version of Postgres, but not quite old enough for Redshift.
Simulate loop for interval generation using recursive CTE, i.e. take range from start to midnight in seed row, take another day in subsequent rows etc.
with recursive input as (
select 'A' as id, timestamp '2019-03-04 23:18:04' as s, timestamp '2019-03-04 23:21:25' as e union
select 'A' as id, timestamp '2019-03-04 23:45:05' as s, timestamp '2019-03-05 00:15:14' as e union
select 'B' as id, timestamp '2019-03-06 23:45:05' as s, timestamp '2019-03-08 00:15:14' as e union
select 'C' as id, timestamp '2019-03-10 23:45:05' as s, timestamp '2019-03-15 00:15:14' as e
), generate_id as (
select row_number() over () as unique_id, * from input
), rec (unique_id, id, s, e) as (
select unique_id, id, s, least(e, s::date::timestamp + interval '1 day')
from generate_id seed
union
select remaining.unique_id, remaining.id, previous.e, least(remaining.e, previous.e::date::timestamp + interval '1 day')
from rec as previous
join generate_id remaining on previous.unique_id = remaining.unique_id and previous.e < remaining.e
)
select id, s, e from rec
order by id,s,e
Note:
your id column appears not to be unique, so I added custom unique_id column. If id was unique, CTE generate_id was unnecessary. Uniqueness is unavoidable for recursive query to work.
close-open range is better for representation of such data, rather than close-close range. So end time in my query returns 00:00:00, not 23:59:59. If it's not suitable for you, modify query as an exercise.
UPDATE: query works on Postgres. OP originally tagged question postgres, then changed tag to redshift.

How to use round and trunc to get dd:mm:yy:hh

I am using oracle 11g and I have normal timestamps (starttime) which produce an output as follows:
23.09.14 05:15:00,000000000
Now I want an output like
23.09.14 05
Also ok would be:
23.09.14 05:00:00,000000000
but when I use something like
round(starttime, 'HH') or trunc(starttime ,'HH24') I always get
23.09.14
with no hours at all.
Looking around here at stackoverflow I found
substr(TO_CHAR(starttime),0,LENGTH(TO_CHAR(starttime))-13)
which produces the correct output as char but when I want to sort dates it wont work because it sorts alphabetically. (so for example, 1.3., 1.4, 1.5.... instead of 1.3., 2.3., 3.3,...),
Any idea how I can get a timestamp which is rounded to the full hour?
I will have to use the statement in a group by clause. The complete statement would look like:
select round(starttime, 'HH24'), sum(counter) from wmsconsolidationorderdwct group by round(starttime, 'HH24') order by round(starttime, 'HH24') desc;
So I cannot display the rounded time and sort by the full timestamp since this would violate the group by clause.
This will truncate to the hour:
trunc(SYSTIMESTAMP) + extract(hour from SYSTIMESTAMP)/24
Edit:
I just tried it and
SELECT TRUNC(SYSTIMESTAMP ,'HH24') FROM DUAL;
returns the correct result.
Fiddle
If your purpose is to display, then use TO_CHAR with desired format model.
For example,
SQL> SELECT TO_CHAR(SYSTIMESTAMP, 'DD.MM.YY HH24') FROM dual;
TO_CHAR(SYS
-----------
28.05.15 15
SQL>
If your purpose is to do date arithmetic then you need to leave the data type as date.
For example,
SQL> alter session set nls_date_format='DD-MM-YYYY HH24:MI:SS'
2 /
Session altered.
SQL> SELECT TRUNC(SYSTIMESTAMP ,'HH24') FROM DUAL
2 /
TRUNC(SYSTIMESTAMP,
-------------------
28-05-2015 15:00:00
SQL>
If you have a timestamp object:
select my_number from(
SELECT TO_NUMBER(TO_CHAR(TO_DATE (TO_CHAR (SYSTIMESTAMP, 'DD.MM.YY HH24:MI'),
'DD.MM.YY HH24:MI'
),'HH24')) AS my_number
FROM DUAL)
order by 1
This could be simplified to:
select my_number from(
SELECT TO_NUMBER(TO_CHAR(SYSTIMESTAMP, 'HH24')) AS my_number
FROM DUAL)
order by 1

Select Dates where time is less or equal to '12:00' Oracle

I require a query that selects rows where the time is less or equal to 12:00
I had something like this in mind:
SELECT daterow FROM datecolumn WHERE daterow <= TO_DATE('12:00, HH24:MI')
However i get an error:
ORA-01843: not a valid month
How would i go about to get all rows that have a time less than 12:00 mid-day?
Try this,
SELECT daterow FROM datecolumn WHERE daterow <= TO_DATE('12:00', 'HH24:MI');
Try This:
SELECT daterow FROM datecolumn
WHERE TO_DATE(daterow,'HH24:MI') <= TO_DATE('12:00', 'HH24:MI');
In order to select all rows where time portion of the daterow column value is less than or equal to mid-day 12:00 you can use to_char() function to extract hour and minutes and to_number() to convert it to a number for further comparison:
-- sample of data. Just for the sake of demonstration
SQL> with t1(col) as(
2 select sysdate - to_dsinterval('P0DT3H') from dual union all
3 select sysdate - to_dsinterval('P0DT2H') from dual union all
4 select sysdate - to_dsinterval('P0DT1H') from dual union all
5 select sysdate + to_dsinterval('P0DT3H') from dual union all
6 select sysdate + to_dsinterval('-P2DT0H') from dual
7 )
8 select to_char(col, 'dd.mm.yyyy hh24:mi:ss') as res
9 from t1 t
10 where to_number(to_char(col, 'hh24mi')) <= 1200
11 ;
Result:
RES
-------------------
26.08.2013 08:10:59
26.08.2013 09:10:59
26.08.2013 10:10:59
24.08.2013 11:10:59
Sorry, but <= TO_DATE('12:00', 'HH24:MI') does not work. It does not extract the hour and minute from each date and compares it to 12:00. Instead it constructs the date representing high noon on the fisrt of the current month and compares each date to this date.
If you want to extract something from a date, use the extract function.
Attention: When using extract on a date, and want to extract hours, minutes or seconds, you have first to convert the date to a timestamp.
Example:
SELECT
extract(hour FROM cast(A AS TIMESTAMP)) AS h,
extract(MINUTE FROM cast(A AS TIMESTAMP)) AS m
FROM
DEMO
;
You can find a complete example on sqlfiddle. The example also shows that the to_date method doesn't work.

ADD_MONTHS function does not return the correct date in Oracle

See the results of below queries:
>> SELECT ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR'),-4) FROM DUAL;
30-NOV-10
>> SELECT ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4) FROM DUAL;
31-MAR-11
How can I get '30-MAR-11' when adding 4 months to some date?
Please help.
There is another question here about Oracle and Java
It states that
From the Oracle reference on add_months http://download-west.oracle.com/docs/cd/B19306_01/server.102/b14200/functions004.htm
If date is the last day of the month or if the resulting month has fewer days than the day component of date, then the result is the last day of the resulting month. Otherwise, the result has the same day component as date.
So I guess you have to manually check stating day and ending day to change the behaviour of the function. Or maybe by adding days instead of months. (But I didn't find a add_day function in the ref)
As a workaround, I might possibly use this algorithm:
Calculate the target date TargetDate1 using ADD_MONTHS.
Alternatively calculate the target date TargetDate2 like this:
1) apply ADD_MONTHS to the first of the source date's month;
2) add the difference of days between the source date and the beginning of the same month.
Select the LEAST between the TargetDate1 and TargetDate2.
So in the end, the target date will contain a different day component if the source date's day component is greater than the number of day in the target month. In this case the target date will be the last day of the corresponding month.
I'm not really sure about my knowledge of Oracle's SQL syntax, but basically the implementation might look like this:
SELECT
LEAST(
ADD_MONTHS(SourceDate, Months),
ADD_MONTHS(TRUNC(SourceDate, 'MONTH'), Months)
+ (SourceDate - TRUNC(SourceDate, 'MONTH'))
) AS TargetDate
FROM (
SELECT
TO_DATE('30-NOV-10', 'DD-MON-RR') AS SourceDate,
4 AS Months
FROM DUAL
)
Here is a detailed illustration of how the method works:
SourceDate = '30-NOV-10'
Months = 4
TargetDate1 = ADD_MONTHS('30-NOV-10', 4) = '31-MAR-11' /* unacceptable */
TargetDate2 = ADD_MONTHS('01-NOV-10', 4) + (30 - 1)
= '01-MAR-11' + 29 = '30-MAR-11' /* acceptable */
TargetDate = LEAST('31-MAR-11', '30-MAR-11') = '30-MAR-11'
And here are some more examples to show different cases:
SourceDate | Months | TargetDate1 | TargetDate2 | TargetDate
-----------+--------+-------------+-------------+-----------
29-NOV-10 | 4 | 29-MAR-11 | 29-MAR-11 | 29-MAR-11
30-MAR-11 | -4 | 30-NOV-10 | 30-NOV-10 | 30-NOV-10
31-MAR-11 | -4 | 30-NOV-10 | 01-DEC-10 | 30-NOV-10
30-NOV-10 | 3 | 28-FEB-11 | 02-MAR-11 | 28-FEB-11
You can use interval arithmetic to get the result you want
SQL> select date '2011-03-30' - interval '4' month
2 from dual;
DATE'2011
---------
30-NOV-10
SQL> ed
Wrote file afiedt.buf
1 select date '2010-11-30' + interval '4' month
2* from dual
SQL> /
DATE'2010
---------
30-MAR-11
Be aware, however, that there are pitfalls to interval arithmetic if you're working with days that don't exist in every month
SQL> ed
Wrote file afiedt.buf
1 select date '2011-03-31' + interval '1' month
2* from dual
SQL> /
select date '2011-03-31' + interval '1' month
*
ERROR at line 1:
ORA-01839: date not valid for month specified
How about something like this:
SELECT
LEAST(
ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR'),-4),
ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR')-1,-4)+1
)
FROM
DUAL
;
Result: 30-NOV-10
SELECT
LEAST(
ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4),
ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR')-1,4)+1
)
FROM
DUAL
;
Result: 30-MAR-11
the add_months function returns a date plus n months.
Since 30th November is the last date of the month, adding 4 months will result in a date that's the end of 4 months. This is expected behavior. If the dates are not bound to change, a workaround is to subtract a day after the new date has been returned
SQL> SELECT ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4) -1 from dual;
ADD_MONTH
---------
30-MAR-11
SELECT TO_DATE('30-NOV-10','DD-MON-RR') +
(
ADD_MONTHS(TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM'),4) -
TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM')
) RESULT
FROM DUAL;
This section in paranthesis:
ADD_MONTHS(TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM'),4) - TRUNC(TO_DATE('30-NOV-10','DD-MON-RR'),'MM')
gives you number of days between the date you entered and 4 months later. So, adding this number of days to the date you given gives the exact date after 4 months.
Ref: http://www.dba-oracle.com/t_test_data_date_generation_sql.htm
Simple solution:
ADD_MONTHS(date - 1, x) + 1
Here is the trick:
select add_months(to_date('20160228', 'YYYYMMDD')-1, 1)+1 from dual;
Enjoy!
We have come to simpler (in our understanding) solution to this problem - take the least day number from original and add_month result dates, as this:
TRUNC(ADD_MONTHS(input_date,1),'MM') + LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) - 1
Some other examples here do not work on every date, below our test results:
WITH DATES as (
SELECT TO_DATE('2020-01-31', 'YYYY-MM-DD HH24:MI:SS') as input_date,
'2020-02-29' as expected_date
FROM dual
UNION ALL
SELECT TO_DATE('2020-02-28', 'YYYY-MM-DD HH24:MI:SS'),
'2020-03-28'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-30', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-30'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-01', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-01'
FROM dual
UNION ALL
SELECT TO_DATE('2019-01-30', 'YYYY-MM-DD HH24:MI:SS'),
'2019-02-28'
FROM dual
UNION ALL
SELECT TO_DATE('2020-02-29', 'YYYY-MM-DD HH24:MI:SS'),
'2020-03-29'
FROM dual
UNION ALL
SELECT TO_DATE('2020-09-29', 'YYYY-MM-DD HH24:MI:SS'),
'2020-10-29'
FROM dual
UNION ALL
SELECT TO_DATE('2020-03-01', 'YYYY-MM-DD HH24:MI:SS'),
'2020-04-01'
FROM dual
),
methods as (
SELECT
input_date,
expected_date,
ADD_MONTHS(input_date,1) as standard_way,
add_months(input_date-1, 1)+1 as wrong_way,
TO_DATE(LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) || '-' || TO_CHAR(ADD_MONTHS(input_date,1), 'MM-YYYY'), 'DD-MM-YYYY') as good_way,
TRUNC(ADD_MONTHS(input_date,1),'MM') + LEAST(TO_CHAR(input_date, 'DD'), TO_CHAR(ADD_MONTHS(input_date,1), 'DD')) - 1 as better_way
FROM
DATES
)
SELECT
input_date,
expected_date,
standard_way,
CASE WHEN TO_CHAR(standard_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as standard_way_ok,
wrong_way,
CASE WHEN TO_CHAR(wrong_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as wrong_way_ok,
good_way,
CASE WHEN TO_CHAR(good_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as good_way_ok,
better_way,
CASE WHEN TO_CHAR(better_way,'YYYY-MM-DD') = expected_date THEN 'OK' ELSE 'NOK' END as better_way_ok
FROM
methods
;
CREATE OR REPLACE FUNCTION My_Add_Month(
STARTDATE DATE,
MONTHS_TO_ADD NUMBER
)
RETURN DATE
IS
MY_ADD_MONTH_RESULT DATE;
BEGIN
SELECT ORACLES_ADD_MONTH_RESULT + NET_DAYS_TO_ADJUST INTO MY_ADD_MONTH_RESULT FROM
(
SELECT T.*,CASE WHEN SUBSTRACT_DAYS > ADD_DAYS THEN ADD_DAYS - SUBSTRACT_DAYS ELSE 0 END AS NET_DAYS_TO_ADJUST FROM
(
SELECT T.*,EXTRACT(DAY FROM ORACLES_ADD_MONTH_RESULT) AS SUBSTRACT_DAYS FROM
(
SELECT ADD_MONTHS(STARTDATE,MONTHS_TO_ADD) AS ORACLES_ADD_MONTH_RESULT,EXTRACT(DAY FROM STARTDATE) AS ADD_DAYS FROM DUAL
)T
)T
)T;
RETURN TRUNC(MY_ADD_MONTH_RESULT);
END My_Add_Month;
/
--test & verification of logic & function both
SELECT T.*,ORACLES_ADD_MONTH_RESULT + NET_DAYS_TO_ADJUST AS MY_ADD_MONTH_RESULT,
My_Add_Month(STARTDATE,MONTHS_TO_ADD) MY_ADD_MONTH_FUNCTION_RESULT
FROM
(
SELECT T.*,CASE WHEN SUBSTRACT_DAYS > ADD_DAYS THEN ADD_DAYS - SUBSTRACT_DAYS ELSE 0 END AS NET_DAYS_TO_ADJUST FROM
(
SELECT T.*,EXTRACT(DAY FROM ORACLES_ADD_MONTH_RESULT) AS SUBSTRACT_DAYS FROM
(
SELECT T.*,ADD_MONTHS(STARTDATE,MONTHS_TO_ADD) AS ORACLES_ADD_MONTH_RESULT,EXTRACT(DAY FROM STARTDATE) AS ADD_DAYS FROM
(
SELECT TO_DATE('28/02/2014','DD/MM/YYYY') AS STARTDATE, 1 AS MONTHS_TO_ADD FROM DUAL
)T
)T
)T
)T;
Query-result
STARTDATE 2/28/2014
MONTHS_TO_ADD 1
ORACLES_ADD_MONTH_RESULT 3/31/2014
ADD_DAYS 28
SUBSTRACT_DAYS 31
NET_DAYS_TO_ADJUST -3
MY_ADD_MONTH_RESULT 3/28/2014
MY_ADD_MONTH_FUNCTION_RESULT 3/28/2014