here is my code
select i.RefNo,i.Premium,i.Description from (select d.Description,c.IsActiveRecord,c.RefNo,c.MovementID, c.Premium,ROW_NUMBER()
over(partition by c.premium order by c.refno) n from lif_mgm_t_contract c
inner join SDT_LJG_T_MovementDescription d with (nolock) on c.MovementID = d.MovementID ) i
where i.n = 1 and i.MovementID <> 0
so for instance
table
a
a
b
I want the query to return
a
b and not just a hope this makes sense --only a beginner
try using a group by clause
SELECT OrderNumber
FROM AccountOrder
group by OrderNumber
so if my table has the following order numbers
1
2
2
3
the query would return
1
2
3
Related
Going to use this query as a subquery, the problem is it returns many rows of duplicates. Tried to use COUNT() instead of exists, but it still returns a multiple answer.
Every table can only contain one record of superRef.
The below query I`ll use in SELECT col_a, [the CASE] From MyTable
SELECT CASE
WHEN
EXISTS (SELECT 1 FROM A WHERE
A_superRef = myTable.sysno AND A_specAttr = 'value')
THEN 3
WHEN EXISTS (SELECT 1 FROM B
INNER JOIN С ON С_ReferenceForB = B_sysNo WHERE C_superRef = myTable.sysno AND b_type = 2)
THEN 2
ELSE (SELECT C_intType FROM C
WHERE C_superRef = myTable.sysno)
END
FROM A, B, C
result:
3
3
3
3
3
3...
What if you did this? Because Im guessing you are getting an implicit full outer join A X B X C then running the case statement for each row in that result set.
SELECT CASE
WHEN
EXISTS (SELECT 1 FROM A WHERE
A_superRef = 1000001838012)
THEN 3
WHEN EXISTS (SELECT 1 FROM B
INNER JOIN С ON С_ReferenceForB = B_sysNo AND C_superRef = 1000001838012 )
THEN 2
ELSE (SELECT C_type FROM C
WHERE C_superRef = 1000001838012)
END
FROM ( SELECT COUNT(*) FROM A ) --This is a hack but should work in ANSI sql.
--Your milage my vary with different RDBMS flavors.
DUAL is what I needed, thanks to Thorsten Kettner
SELECT CASE
WHEN
EXISTS (SELECT 1 FROM A WHERE
A_superRef = 1000001838012)
THEN 3
WHEN EXISTS (SELECT 1 FROM B
INNER JOIN С ON С_ReferenceForB = B_sysNo AND C_superRef = 1000001838012 )
THEN 2
ELSE (SELECT C_type FROM C
WHERE C_superRef = 1000001838012)
END
FROM DUAL
I want to get the incremental index when note exists for the row. I am trying to achieve the same with ROW_Number() but it seems there is a problem with the method being used to generate it.
SELECT * RowNo,
(SELECT CASE
WHEN LEN(Value) > 0 THEN ROW_NUMBER()
OVER (
ORDER BY ID)
ELSE ''
END
FROM Dictionary
WHERE ID = ABC.ID) Note
FROM ABCD AS ABC WITH(NOLOCK)
INNER JOIN XYZ AS XYZ WITH(NOLOCK)
ON ABC.Id = XYZ.ID
WHERE ABC.Id = 10
output expected:
ID Name Note
1 A 1
2 B
3 C 2
4 D
5 E
6 F 3
The subquery isn't needed here, and you want to use the partition by argument to separate values having len(value)>0 from those having no value:
SELECT
ID,
Name,
CASE WHEN LEN(Value)>0 THEN ROW_NUMBER() OVER (
PARTITION BY CASE WHEN LEN(Value)>0 THEN 1 ELSE 0 END
ORDER BY ID) ELSE '' END as Note
FROM ABCD AS ABC WITH(NOLOCK)
INNER JOIN XYZ AS XYZ WITH(NOLOCK)
ON ABC.Id = XYZ.ID
Where ABC.Id = 10
I think maybe you need to change the approach to make the Dictionary query the "main" query. It's hard to say without knowing exactly what your tables look like. Which Table does the "Id" in your expected output come from?
Try like this:
WITH cte AS (
SELECT ID, ROW_NUMBER() OVER (ORDER BY ID) AS Note
FROM Dictionary WHERE ID=10
AND LEN(Value)>0
)
SELECT ABC.ID, [Name], cte.Note
FROM ABCD AS ABC WITH(NOLOCK)
INNER JOIN XYZ AS XYZ WITH(NOLOCK) ON ABC.Id = XYZ.ID
LEFT OUTER JOIN cte ON ABC.Id=cte.ID
I have the following table structure also I have mention my expected output please help me with query as I don't know much about SQL query
Table 1 : Category
Name CatId
A 1
B 2
C 3
Table 2 : Emp Details
FName Id Dob CatId
Pratik 1 1958-04-06 2
Praveen 3 1972-05-12 1
Nilesh 2 1990-12-12 2
So far I have tried to get all result with:
SELECT A.Code,A.EmpName,A.DOB,B.cname
FROM EMPMASTER A
JOIN CATMASTER B ON A.cCode = B.ccode AND A.Compcode = B.CompCode
WHERE A.compcode = 'C0001' AND month(A.DOB) >= 1
AND MONTH(A.DOB) <= 12 AND A.termflag='L'
ORDER BY A.DOB
But my problem is, I also want summary results to be displayed
Expected Summary Output :
Grouping No Of Employees
A 1
B 2
C 0
I think you can use LEFT JOIN, GROUP BY and COUNT as follows:
SELECT [Grouping] = c.Name,
[No Of Employees] = COUNT(e.ID)
FROM Category AS c
LEFT JOIN EmpDetails AS e
ON e.CatId = c.CatId
GROUP BY c.Name;
TRY THIS:
SELECT A.NAME,
(SELECT COUNT(*) FROM #EMP B WHERE A.CATID = B.CATID) AS COUNT
FROM #TEMP A
I have the following table:
ID Number Revision
x y 0
x y 1
z w 0
a w 0
a w 1
b m 0
b m 0
I need to return rows that for the same Number thare are more then one ID with the same Revision.Number can be "Null" and I don't need those values.
The output should be:
z w 0
a w 0
I have tried the following query:
SELECT a.id,a.number,a.revision,
FROM table a INNER JOIN
(SELECT id, number, revision FROM table where number > '0'
GROUP BY number HAVING COUNT(*) > 1
) b ON a.revision = b.revision AND a.id != b.id
A little addition- I have rows in my table with the same Number, ID and Revision- I don't need those rows in my query to be displayed!
It is not working! Please help me to figure out how to fix it.
Thanks.
Select t.Id,s.number,t.revision
from (Select number,count(*) 'c'
from table t1
where revision=0
group by number
having count(*) > 1
) s join table t on t.number= s.number
where revision = 0
Another simple approach:
SELECT DISTINCT b.id, b.Number, b.Revision
FROM tbl a
INNER JOIN tbl b
ON a.ID != b.ID AND a.Number = b.Number AND a.Revision = b.Revision;
This is tested in MySql 5, syntax might differ slightly.
You are not that far away with your query:
SELECT a.id,a.number,a.revision
FROM table a
JOIN (
-- multiple id for the same number and revision
SELECT number, revision
FROM table
GROUP BY number, revision
HAVING COUNT(*) > 1
) b
ON a.revision = b.revision
AND a.number = b.number
Untested, but you should get the idea. If your sql-server is a resent version you can solve this with OLAP functions as well.
To filter out rows where the whole row is duplicated we can select only unique rows via group by and having:
SELECT a.id,a.number,a.revision
FROM table a
JOIN (
-- multiple id for the same number and revision
SELECT number, revision
FROM table
GROUP BY number, revision
HAVING COUNT(*) > 1
) b
ON a.revision = b.revision
AND a.number = b.number
GROUP BY a.id,a.number,a.revision
HAVING COUNT(1) = 1
I have 2 tables as below-
Table I
ID DATE
1 05/11/12
2 23/11/12
3 29/11/12
4 04/10/12
5 20/11/12
And another table (IH) with the following info-
ID RECNO NOTE
1 1 Open
1 2 Update
1 3 Close
2 1 Open
2 2 Update
2 3 Hold
2 4 Close
3 1 Open
4 1 Open
4 2 Update
5 1 Open
I would like to output a result as shown below, displaying the Note field using the highest value of RecNo for each ID. So using the data above the output should be-
ID DATE NOTE
2 23/11/12 Close
3 29/11/12 Open
The code I have is-
SELECT I.ID, I.DATE, IH.NOTE FROM
I I, IH IH
JOIN (SELECT MAX([RECNO]) [RECNO] FROM
IH
GROUP BY RECNO) IH2 ON IH2.ID = IH.ID AND
IH2.[RECNO] = IH.[RECNO]
JOIN I I2 ON I2.ID = IH.ID WHERE
(I2.DATE>={TS ‘2012-11-22 00:00:002}) GROUP BY I2.ID
However when I execute the code I get-
Invalid Column Name 'RECNO'. Statement(s) could not be prepared.
How about this? Note, haven't tried it, I'm on my Mac at the moment.
SELECT I.ID, I.DATE, IH.NOTE
FROM I I
OUTER APPLY
(SELECT TOP 1 *
FROM IH
WHERE IH.ID = I.ID
ORDER BY RECNO DESC) IH
WHERE I.DATE >= '2012-11-22'
Your SQL is rather, uh, messy.
Assuming you are using SQL Server 2005 or greater, you can use the row_number() function, as follows:
SELECT I.ID, I.DATE, IH.NOTE
FROM I join
(select ih.*, ROW_NUMBER() over (PARTITION by id order by recno desc) as seqnum
from IH
) ih
on IH2.[RECNO] = IH.[RECNO] and seqnum = 1
WHERE I2.DATE>='2012-11-22 00:00:002'
This is assigning a sequence number in the IH table, for each id with the highest record number getting the value "1". The rest is just SQL.
Your original query is simply not correct syntactically, but I think this is what you want based on the description.
and another one
SELECT I.ID, I.DATE
,(Select TOP 1 IH.NOTE FROM IH where IH.ID=i.ID Order by Recno DESC) as Note
from I
WHERE
I.DATE>'20121122'
maybe this will help
SELECT a.ID, a.DATE, b.NOTE FROM a
inner join b on a.ID = b.ID
where b.recno in (select max(bb.recno)
from b as bb where bb.id = b.id)
http://sqlfiddle.com/#!3/fd141/2
If you don't mind the different identifiers, look at this solution:
select t1.MyID, t1.MyDate, y.Note
from t1
join
(
select MyID, max(RecNo) as RecNo
from t2
group by MyID
) x
on t1.MyID = x.MyID
left join
(
select *
from t2
) y
on t1.MyID = y.MyID
and x.RecNo = y.RecNo
where t1.MyDate >= '2012.11.22'
The complete solution is here: http://sqlfiddle.com/#!3/4ca09/3
Update: Oops, forgot to bring in the date in where clause. Updated SQL Fiddle and the query above.