order by a string as number sql - sql

Question

I have a table like follows, i need to pivot the table with weeks. i could able to create pivot table but the columns order getting shuffled since im ordering a string column. and getting output like 3nd table.
MRN Weeks
--------------------------------
GIRFTR1H0461081 52
GIRFTR1H0461083 5 - 6
GIRFTR1H0461084 0 - 1
GIRFTR1H0461085 1 - 2
GIRFTR1H0461086 11 - 12
GIRFTR1H0461087 1 - 2
I need to get output as a pivot table order by Weeks Like,
MRN | 0 - 1 | 1 - 2 | 5 - 6 |11 - 12| 52
---------------------------------------------------------------
GIRFTR1H0461081 | 0 | 0 | 0 | 0 | 0
GIRFTR1H0461083 | 0 | 0 | 1 | 0 | 0
GIRFTR1H0461084 | 1 | 0 | 0 | 0 | 0
GIRFTR1H0461085 | 0 | 1 | 0 | 0 | 0
GIRFTR1H0461086 | 0 | 0 | 0 | 1 | 0
GIRFTR1H0461087 0 | 1 | 0 | 0 | 0
When i tried to create this table, the columns order getting shuffled like bellow,
MRN | 0 - 1 | 1 - 2 |11 - 12| 5 - 6 | 52
---------------------------------------------------------------
GIRFTR1H0461081 | 0 | 0 | 0 | 0 | 0
GIRFTR1H0461083 | 0 | 0 | 0 | 1 | 0
GIRFTR1H0461084 | 1 | 0 | 0 | 0 | 0
GIRFTR1H0461085 | 0 | 1 | 0 | 0 | 0
GIRFTR1H0461086 | 0 | 0 | 1 | 0 | 0
GIRFTR1H0461087 | 0 | 1 | 0 | 0 | 0
My code is,
DECLARE #cols AS NVARCHAR(MAX),
#query AS NVARCHAR(MAX)
select #cols = STUFF((SELECT ',' + QUOTENAME(WeeksBand)
from [test_Tbl]
group by WeeksBand
order by WeeksBand
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set #query = 'SELECT CurrentSpecialty,' + #cols + ' from
(
select CurrentSpecialty, WeeksBand, EncounterId
from [Tbl_Current_PTL_Test]
) x
pivot
(
count(EncounterId)
for WeeksBand in (' + #cols + ')
) p '
execute(#query);
Please help me to sort out my issue,

Answer 1

It's doing a string (alpha) sort, and you actually want to be doing a numeric sort.
I'd change the order line from:
order by WeeksBand
to:
order by Cast(SubString(WeeksBand, 1, CASE WHEN CHARINDEX('-', WeeksBand) != 0 THEN CHARINDEX('-', WeeksBand) -1 ELSE LEN(WeeksBand) END) AS INT)
which will convert the first number into an integer value (not string) and then should order correctly.

Answer 2

I don't see why a standard pivot query should not work here. From your expected output it seems you want a 1 as a placeholder for an MRN entry which is present in that week, and 0 otherwise.
SELECT [MRN],
MAX(CASE WHEN [Weeks] = '0 - 1' THEN 1 ELSE 0 END) AS [0 - 1],
MAX(CASE WHEN [Weeks] = '1 - 2' THEN 1 ELSE 0 END) AS [1 - 2],
MAX(CASE WHEN [Weeks] = '5 - 6' THEN 1 ELSE 0 END) AS [5 - 6],
MAX(CASE WHEN [Weeks] = '11 - 12' THEN 1 ELSE 0 END) AS [11 - 12],
MAX(CASE WHEN [Weeks] = '52' THEN 1 ELSE 0 END) AS [52]
FROM [yourTable]
GROUP BY [MRN]

Answer 3

You should format Week field of first table using 2 digits as:
MRN Weeks
--------------------------------
GIRFTR1H0461081 52
GIRFTR1H0461083 05 - 06
GIRFTR1H0461084 00 - 01
GIRFTR1H0461085 01 - 02
GIRFTR1H0461086 11 - 12
GIRFTR1H0461087 01 - 02