How to do a COUNT with a WHERE clause? - sql

I actually have a query joining 3 tables to collect informations so I can calculate some KPIs, but my logic is flawed, here is my actual query :
SELECT t.idCustomer, t.nameCustomer
COUNT(DISTINCT t.idTrip),
SUM(
CASE
WHEN t.tripDone <> 1
THEN 1
ELSE 0
END),
SUM(CASE
WHEN t.codeIncident = 'CANCEL'
THEN 1
ELSE 0
END)
FROM
(SELECT customer.idCustomer, customer.nameCustomer, trip.tripDone, incident.codeIncident
FROM CUSTOMER customer
JOIN TRIP trip ON customer.idCustomer = trip.idCustomer
JOIN INCIDENT incident ON trip.idTrip = incident.idTrip) t
GROUP BY t.idCustomer, t.nameCustomer
So, I want to know for each Customer :
COUNT(DISTINCT t.idTrip) -> The number of trips by this customer
Sum when t.tripDone <> 1 -> The number of trips that are done by this customer ( not ingoing )
Sum when t.codeIncident = 'CANCEL' -> The number of trips by this customer where there was a cancellation.
The big mistake I made here, is that a trip can have multiple codeIncidents (example : one record for an idTrip with the codeIncident 'CANCEL' and another record with same idTrip with the codeIncident 'DELAYED'), so when I calculate the Sum when t.tripDone <> 1 I get a result of : '2' instead of '1' (because there are 2 records in my from Clause that have the t.tripDone <> 1 for the same idTrip).
Would you have any idea on how I should process this query so I can do the Sum when tripDone <> 1 only once for each tripId ?
Thanks a lot for the help !
If you need some more infos I'm available, and sorry for my lack of english skills !

It sounds like you want to do the same count(distinct ...) pattern for the columns you're currently summing, but with some logic. You can use case within a count instead in the same way:
...
COUNT(
DISTINCT CASE
WHEN t.tripDone <> 1
THEN t.idTrip
ELSE null
END),
COUNT(
DISTINCT CASE
WHEN t.codeIncident = 'CANCEL'
THEN t.idTrip
ELSE null
END)
The else null is a bit redundant as that's the default. As count() ignores nulls, if the when isn't matched then that trip ID isn't counted.

First Select idTrip field in your inner query that means table "t"

Related

Is there a way to collect the data and inspect in one pass using groupby function

Sample Data of table_1
Have this Query that returns
select
customer,
SUM(CASE WHEN activity IN ( 'a','b')
THEN 1
ELSE 0 END) AS num_activity_a_or_b
from table_1
group by customer
Results:
Want to extend this to return one more column if for a given code say X1 if the Activity is "a" and "c" then return num_of_a_and_c_activity.
A bit stuck how to collect and inpect the code and activities in one pass.
can we combine windowing function to achieve this.
Please advise and help
UPDATE:
based on the updated results, maybe the below query is what you need
So what i assume is that you need both a and c as well x1 .
So I count distinct activities which are a and c and then do integer division by 2. if only a is present then count distinct =1 but 1/2 =0 in integer division.
It is only 1 when both a and c are present.
select
customer,
SUM(CASE WHEN activity IN ( 'a','b')
THEN 1
ELSE 0
END) AS num_activity_a_or_b,
COUNT(DISTINCT CASE WHEN code IN ('x1') AND activity IN ( 'a','c')
THEN activity
ELSE NULL
END)/2 AS num_activity_a_and_c
from table_1
group by customer
Maybe your query can be
select
customer,
SUM(CASE WHEN activity IN ( 'a','b')
THEN 1
ELSE 0
END) AS num_activity_a_or_b,
SUM(CASE WHEN code IN ('x1') AND activity IN ( 'a','c')
THEN 1
ELSE 0
END) AS num_activity_a_or_c
from table_1
group by customer

check and compare the count from two tables without relation

I have below tables
Table1: "Demo"
Columns: SSN, sales, Create_DT,Update_Dt
Table2: "Agent"
Columns: SSN,sales, Agent_Name, Create_Dt, Update_DT
Scenario 1 and desired result set:
I want output as 0 if the count of SSN in Demo table is matched with the count of SSN in Agent table
if the count is not matched then I want result as 1
Scenario 2 and desired result set:
I want output as 0 if the sum of sales in Demo table is matched with the sum of sales in Agent table
if the sum is not matched then I want result as 1
Please help on this query part
Thanks
You can write two queries separately to take counts within the result query
SELECT (SELECT count(Demo.SSN) as SSN1 from Demo)!=(SELECT count(Agent.SSN) as SSN2 from Agent) AS Result;
Basically what the inner queries does is it checked whether the counts are equal or not and outputs 1 if it is true and 0 if it is false. Since you have asked to output 1 if it is false I used '!=' sign.
You can try the same procedure in scenario 2 also
For scenario 1
select (Case when (select count(ssn) from Demo)=(select count(ssn) from Agent) then 0 else 1 end) as desired_result
If you want to count unique ssn then:
select (Case when (select count(distinct ssn) from Demo)=(select count(distinct ssn) from Agent) then 0 else 1 end) as desired_result
For scenario 2:
select (Case when (select sum(sales) from Demo)=(select sum(sales) from Agent) then 0 else 1 end) as desired_result
I would suggest one query with both sets of information:
select (d.num_ssn <> a.num_ssn) as have_different_ssn_count,
(d.sales <> a.sales) as have_different_sales
from (select count(distinct ssn) as num_ssn,
coalesce(sum(sales), 0) as sales
from demo
) d cross join
(select count(distinct ssn) as num_ssn,
coalesce(sum(sales), 0) as sales
from agent
) a;
Note: This returns boolean values -- true/false rather than 1/0. If you really want 0/1, then use case:
select (case when d.num_ssn <> a.num_ssn then 1 else 0 end) as have_different_ssn_count,
(case when d.sales <> a.sales then 1 else 0 end) as have_different_sales
It would not surprise me if you were not only interested in the total counts but also that the agent/sales combinations are the same in both tables. If that is the case, please ask a new question with a clear explanation. Sample data and desired results help.

Why does this not return 0

I have a query like:
select nvl(nvl(sum(a.quantity),0)-nvl(cc.quantityCor,0),0)
from RCV_TRANSACTIONS a
LEFT JOIN (select c.shipment_line_id,c.oe_order_line_id,nvl(sum(c.quantity),0) quantityCor
from RCV_TRANSACTIONS c
where c.TRANSACTION_TYPE='CORRECT'
group by c.shipment_line_id,c.oe_order_line_id) cc on (a.shipment_line_id=cc.shipment_line_id and a.shipment_line_id=7085740)
where a.transaction_type='DELIVER'
and a.shipment_line_id=7085740
group by nvl(cc.quantityCor,0);
The query runs OK, but returns no value. I want it to return 0 if there is no quantity found. Where have I gone wrong?
An aggregation query with a GROUP BY returns no rows if all rows are filtered out.
An aggregation query with no GROUP BY always returns one row, even if all rows are filtered out.
So, just remove the GROUP BY. And change the SELECT to:
select coalesce(sum(a.quantity), 0) - coalesce(max(cc.quantityCor), 0)
I may be wrong, but it seems you merely want to subtract CORRECT quantity from DELIVER quantity for shipment 7085740. You don't need a complicated query for that. Especially your GROUP BY clauses make no sense if that is what you are after.
One way to write this query would be:
select
sum(case when transaction_type = 'DELIVER' then quantity else 0 end) -
sum(case when transaction_type = 'CORRECT' then quantity else 0 end) as diff
from rcv_transactions
where shipment_line_id = 7085740;
I had a query like this and was trying to return 'X' when the item is not valid.
SELECT case when segment1 is not null then segment1 else 'X' end
--INTO v_orgValidItem
FROM mtl_system_items_b
WHERE segment1='1676001000'--'Jul-00'--l_item
and organization_id=168;
..but it was returning NULL.
Changed to use aggregation with no group by and now it returns 'X' when the item is not valid.
SELECT case when max(segment1) is not null then max(segment1) else 'X' end valid
--INTO v_orgValidItem
FROM mtl_system_items_b
WHERE segment1='1676001000'--'Jul-00'--l_item
and organization_id=168;--l_ship_to_organization_id_pb;
Here is another example, proving the order of operations really matters.
When there is no match for this quote number, this query returns NULL:
SELECT MAX(NVL(QUOTE_VENDOR_QUOTE_NUMBER,0))
FROM PO_HEADERS_ALL
WHERE QUOTE_VENDOR_QUOTE_NUMBER='foo.bar';
..reversing the order of MAX and NVL makes all the difference. This query returns the NULL value condition:
SELECT NVL(MAX(QUOTE_VENDOR_QUOTE_NUMBER),0)
FROM PO_HEADERS_ALL
WHERE QUOTE_VENDOR_QUOTE_NUMBER='foo.bar';

SQL query syntax in CASE WHEN ELSE END to count

Writing a query to find the number of ED visits that were discharged from non-ED units.
The column dep.ADT_UNIT_TYPE_C column stores 1 if the unit was an ED unit.
Assume NULL values are non-ED units for the purpose of this query.
Which of the following produces this number?
I am thinking it is A because in my mind, that sound the correct syntax.
COUNT(CASE WHEN THEN ELSE END standard format)
A has that.
B doesn't have the THEN? so it is incorrect syntax?
Please help me understanding the nuances between these choices.
A.)
COUNT( CASE WHEN dep.ADT_UNIT_TYPE_C is NULL OR dep.ADT_UNIT_TYPE_C <> 1 THEN NULL
ELSE 1
END )
B.)
COUNT( CASE WHEN dep.ADT_UNIT_TYPE_C is NULL or dep.ADT_UNIT_TYPE_C <> 1
ELSE NULL
END)
C.)
CASE WHEN dep.ADT_UNIT_TYPE_C Is NULL or dep.ADT_UNIT_TYPE_C <> 1 THEN COUNT (NULL)
ELSE COUNT (1)
END
D.)
CASE WHEN dep.ADT_UNIT_TYPE_C is NULL or dep.ADT_UNIT_TYPE_C <> 1 THEN COUNT(1)
ELSE COUNT(NULL)
END
You can count the records that are returned COUNT(*) and put the condition in the where clause.
If you are using Oracle, you can use NVL.
The sample below is for Oracle, but if using mysql or SQL server, you can use the ISNULL Function.
SELECT COUNT(*) FROM dep WHERE NVL(ADT_UNIT_TYPE_C, 0) != 1
It looks like however, you are joining this to another table, probably a visit table. So, you want to count visits. Visits probably stores some kind of department id or way to join it to departments.
Something like this:
SELECT COUNT(*) FROM visit v, departments d WHERE v.dep_id = d.dep_id AND NVL(d.ADT_UNIT_TYPE_C, 0) !=1
If you want the entire list like shown above, you want to use a group by. This will show you the count for each visit by department type.
SELECT COUNT(*) FROM visit v, departments d GROUP BY d.ADT_UNIT_TYPE_C

SQL Nested Select statements with COUNT()

I'll try to describe as best I can, but it's hard for me to wrap my whole head around this problem let alone describe it....
I am trying to select multiple results in one query to display the current status of a database. I have the first column as one type of record, and the second column as a sub-category of the first column. The subcategory is then linked to more records underneath that, distinguished by status, forming several more columns. I need to display every main-category/subcategory combination, and then the count of how many of each sub-status there are beneath that subcategory in the subsequent columns. I've got it so that I can display the unique combinations, but I'm not sure how to nest the select statements so that I can select the count of a completely different table from the main query. My problem lies in that to display the main category and sub category, I can pull from one table, but I need to count from a different table. Any ideas on the matter would be greatly appreciated
Here's what I have. The count statements would be replaced with the count of each status:
SELECT wave_num "WAVE NUMBER",
int_tasktype "INT / TaskType",
COUNT (1) total,
COUNT (1) "LOCKED/DISABLED",
COUNT (1) released,
COUNT (1) "PARTIALLY ASSEMBLED",
COUNT (1) assembled
FROM (SELECT DISTINCT
(t.invn_need_type || ' / ' || s.code_desc) int_tasktype,
t.task_genrtn_ref_nbr wave_num
FROM sys_code s, task_hdr t
WHERE t.task_genrtn_ref_nbr IN
(SELECT ship_wave_nbr
FROM ship_wave_parm
WHERE TRUNC (create_date_time) LIKE SYSDATE - 7)
AND s.code_type = '590'
AND s.rec_type = 'S'
AND s.code_id = t.task_type),
ship_wave_parm swp
GROUP BY wave_num, int_tasktype
ORDER BY wave_num
Image here: http://i.imgur.com/JX334.png
Guessing a bit,both regarding your problem and Oracle (which I've - unfortunately - never used), hopefully it will give you some ideas. Sorry for completely messing up the way you write SQL, SELECT ... FROM (SELECT ... WHERE ... IN (SELECT ...)) simply confuses me, so I have to restructure:
with tmp(int_tasktype, wave_num) as
(select distinct (t.invn_need_type || ' / ' || s.code_desc), t.task_genrtn_ref_nbr
from sys_code s
join task_hdr t
on s.code_id = t.task_type
where s.code_type = '590'
and s.rec_type = 'S'
and exists(select 1 from ship_wave_parm p
where t.task_genrtn_ref_nbr = p.ship_wave_nbr
and trunc(p.create_date_time) = sysdate - 7))
select t.wave_num "WAVE NUMBER", t.int_tasktype "INT / TaskType",
count(*) TOTAL,
sum(case when sst.sub_status = 'LOCKED' then 1 end) "LOCKED/DISABLED",
sum(case when sst.sub_status = 'RELEASED' then 1 end) RELEASED,
sum(case when sst.sub_status = 'PARTIAL' then 1 end) "PARTIALLY ASSEMBLED",
sum(case when sst.sub_status = 'ASSEMBLED' then 1 end) ASSEMBLED
from tmp t
join sub_status_table sst
on t.wave_num = sst.wave_num
group by t.wave_num, t.int_tasktype
order by t.wave_num
As you notice, I don't know anything about the table with the substatuses.
You can use inner join, grouping and count to get your result:
suppose tables are as follow :
cat (1)--->(n) subcat (1)----->(n) subcat_detail.
so the query would be :
select cat.title cat_title ,subcat.title subcat_title ,count(*) as cnt from
cat inner join sub_cat on cat.id=subcat.cat_id
inner join subcat_detail on subcat.ID=am.subcat_detail_id
group by cat.title,subcat.title
Generally when you need different counts, you need to use the CASE statment.
select count(*) as total
, case when field1 = "test' then 1 else 0 end as testcount
, case when field2 = 'yes' then 1 else 0 endas field2count
FROM table1