I have a question that is asking:
-List the max sales for each year?
I think I have the starter query but I can't figure out how to get all the years in my answer:
SELECT TO_CHAR(stockdate,'YYYY') AS year, sales
FROM sample_newbooks
WHERE sales = (SELECT MAX(sales) FROM sample_newbooks);
This query gives me the year with the max sales. I need max sales for EACH year. Thanks for your help!
Use group by and max if all you need is year and max sales of the year.
select
to_char(stockdate, 'yyyy') year,
max(sales) sales
from sample_newbooks
group by to_char(stockdate, 'yyyy')
If you need rows with all the columns with max sales for the year, you can use window function row_number:
select
*
from (
select
t.*,
row_number() over (partition by to_char(stockdate, 'yyyy') order by sales desc) rn
from sample_newbooks t
) t where rn = 1;
If you want to get the rows with ties on sales, use rank:
select
*
from (
select
t.*,
rank() over (partition by to_char(stockdate, 'yyyy') order by sales desc) rn
from sample_newbooks t
) t where rn = 1;
Related
I have a question about ranking . (My using Pgadmin for my SQL codes)
Mange to get my sum of sales in DESC order and rank 1 to 3 for the month of APR
But how can I achieve my result by showing only rank 1 to 3 for the month of Apr , May and June.
I need to reflect only 9 rows in my table .
SELECT restaurant_id,
EXTRACT(year FROM submitted_on) AS year,
EXTRACT(month FROM submitted_on) AS month,
SUM(total_amount),
RANK() OVER (PARTITION BY(extract(month from submitted_on))
ORDER BY SUM(total_amount) DESC) rank
FROM orders
WHERE submitted_on::date BETWEEN '2021-04-01' AND '2021-06-30'
GROUP BY restaurant_id, year, month
If you just want 3 records you should use row_number instead of rank. for your requirement you can do it in this way:
select t.* from (
SELECT restaurant_id,
EXTRACT(year FROM submitted_on) AS year,
EXTRACT(month FROM submitted_on) AS month,
SUM(total_amount),
RANK() OVER (PARTITION BY(extract(month from submitted_on))
ORDER BY SUM(total_amount) DESC) rank
FROM orders
WHERE submitted_on::date BETWEEN '2021-04-01' AND '2021-06-30'
GROUP BY restaurant_id, year, month
) t
where rank <=3;
I need to write SQL query to pull the single, highest-earning day for a certain brand of each quarter of 2018. I have the following but it does not pull a singular day - it pulls the highest earnings for each day.
select distinct quarter, order_event_date, max(gc) as highest_day_gc
from (
select sum(commission) as cm, order_date,
extract(quarter from order__date) as quarter
from order_table
where advertiser_id ='123'
and event_year='2018'
group by 3,2
)
group by 1,2
order by 2 DESC
You can use window functions to find the highest earning day per quarter by using rank().
select rank() over (partition by quarter order by gc desc) as rank, quarter, order_event_date, gc
from (select sum(gross_commission) gc,
order_event_date,
extract(quarter from order_event_date) quarter
from order_aggregation
where advertiser_id = '123'
and event_year = '2018'
group by order_event_date, quarter) a
You could create the query above as view and filter it by using where rank = 1.
You could add the LIMIT clause at the end of the sentence. Also, change the las ORDER BY clause to ORDER BY highest_day_gc. Something like:
SELECT DISTINCT quarter
,order_event_date
,max(gc) as highest_day_gc
FROM (SELECT sum(gross_commission) as gc
,order_event_date
,extract(quarter from order_event_date) as quarter
FROM order_aggregation
WHERE advertiser_id ='123'
AND event_year='2018'
GROUP BY 3,2) as subquery
GROUP BY 1,2
ORDER BY 3 DESC
LIMIT 1
I have a table with snapshot data. It has productid and date and quantity columns. I need to find min value in the max date. Let's say, we have product X: X had the last snapshot at Y date but it has two snapshots at Y with 9 and 8 quantity values. I need to get
product_id | date | quantity
X Y 8
So far I came up with this.
select
productid
, max(snapshot_date) max_date
, min(quantity) min_quantity
from snapshot_table
group by 1
It works but I don't know why. Why this does not bring min value for each date?
I would use RANK here along with a scalar subquery:
WITH cte AS (
SELECT *, RANK() OVER (ORDER BY quantity) rnk
FROM snapshot_table
WHERE snapshot_date = (SELECT MAX(snapshot_date) FROM snapshot_table)
)
SELECT productid, snapshot_date, quantity
FROM cte
WHERE rnk = 1;
Note that this solution caters to the possibility that two or more records happened to be tied for having the lower quantity among those most recent records.
Edit: We could simplify by doing away with the CTE and instead using the QUALIFY clause for the restriction on the RANK:
SELECT productid, snapshot_date, quantity
FROM snapshot_table
WHERE snapshot_date = (SELECT MAX(snapshot_date) FROM snapshot_table)
QUALIFY RANK() OVER (ORDER BY quantity) = 1;
Consider also below approach
select distinct product_id,
max(snapshot_date) over product as max_date,
first_value(quantity) over(product order by snapshot_date desc, quantity) as min_quantity
from your_table
window product as (partition by product_id)
use row_number()
with cte as (select *,
row_number() over(partition by product_id order by date desc) rn
from table_name) select * from cte where rn=1
I have a table with columns month, name and transaction_id. I would like to count the number of transactions per month and name. However, for each month I want to have the top N names with the highest transaction counts.
The following query groups by month and name. However the LIMIT is applied to the complete result and not per month:
SELECT
month,
name,
COUNT(*) AS transaction_count
FROM my_table
GROUP BY month, name
ORDER BY month, transaction_count DESC
LIMIT N
Does anyone have an idea how I can get the top N results per month?
Use row_number():
SELECT month, name, transaction_count
FROM (SELECT month, name, COUNT(*) AS transaction_count,
ROW_NUMBER() OVER (PARTITION BY month ORDER BY COUNT(*) DESC) as seqnum
FROM my_table
GROUP BY month, name
) mn
WHERE seqnum <= N
ORDER BY month, transaction_count DESC
I'm trying to output a top 3 products per quarter, that should be a total of 12 rows, since 3 top products per quarter.
Closest output is the one provided below i have no idea how to like partition it every quarter
SELECT * FROM (SELECT QUARTER, PRODUCT_NAME, SUM(QUANTITY) "QTY_SOLD", SALES, SUM(PROFIT) "PROFIT_GENERATED" FROM DELIVERIES_FACT
WHERE EXTRACT(YEAR from SHIP_DATE) = 2015 GROUP BY QUARTER, PRODUCT_NAME, SALES ORDER BY "PROFIT_GENERATED" DESC)
WHERE rownum <= 3
getting an output of
I've written this SQL extracting the calendar quarter from SHIP_DATE; you can adjust as needed.
Similarly, RANK(), ROW_NUMBER(), and DENSE_RANK() all are different; you may wish to experiment with each analytical function to see which best fits your data and handles ties the way you want them to.
SELECT *
FROM (SELECT RANK() OVER (PARTITION BY SHIP_QUARTER
ORDER BY PROFIT_GENERATED desc) AS PROFIT_RANK_BY_Q,
ORIG.*
FROM
(SELECT EXTRACT(QUARTER from SHIP_DATE) AS SHIP_QUARTER,
PRODUCT_NAME,
SUM(QUANTITY) "QTY_SOLD", SALES, SUM(PROFIT) "PROFIT_GENERATED"
FROM DELIVERIES_FACT
WHERE EXTRACT(YEAR from SHIP_DATE) = 2015
GROUP BY EXTRACT(QUARTER from SHIP_DATE), PRODUCT_NAME, SALES
)
)
WHERE PROFIT_RANK_BY_Q <= 3
order by SHIP_QUARTER, PROFIT_RANK_BY_Q