Haven't noticed much sample code/guides on how to use the CameraRoll library from React Native, I found the example in the docs a bit "vague" and confusing.
First time I'm using any of the API's so I do not fully understand how I'm suppose to use the library either. So far I've imported it like:
import {
AppRegistry,
Image,
StyleSheet,
TextInput,
Navigator,
CameraRoll,
Alert,
TouchableHighlight,
Button,
Text,
View
} from 'react-native';
quite confused with "Linking" etc, but as far as I know, this should be all I need to do in order to use the lib.
And how do I use it for something as simple as to open the gallery on the click of a button and let the user choose an image that should then be displayed in the app.
Thanks in advance, hope someone has some code to clarify this.
Here is some sample code that will grab the first 25 photos from your camera roll and display them in a ScrollView. I modified this from an example I found online here
import React, { Component, PropTypes } from 'react'
import {
CameraRoll,
Image,
ScrollView,
StyleSheet,
TouchableHighlight,
View,
} from 'react-native';
class CameraRollView extends Component {
constructor(props) {
super(props)
var controls = props.controls
this.state = {
images: [],
selected: '',
fetchParams: { first: 25 },
groupTypes: 'SavedPhotos',
}
this._storeImages = this._storeImages.bind(this)
this._logImageError = this._logImageError.bind(this)
this._selectImage = this._selectImage.bind(this)
}
componentDidMount() {
// get photos from camera roll
CameraRoll.getPhotos(this.state.fetchParams, this._storeImages, this._logImageError);
}
// callback which processes received images from camera roll and stores them in an array
_storeImages(data) {
const assets = data.edges;
const images = assets.map( asset => asset.node.image );
this.setState({
images: images,
});
}
_logImageError(err) {
console.log(err);
}
_selectImage(uri) {
// define whatever you want to happen when an image is selected here
this.setState({
selected: uri,
});
console.log('Selected image: ', uri);
}
render() {
return (
<View style={{flex: 1, backgroundColor: 'white'}}>
<ScrollView style={styles.container}>
<View style={styles.imageGrid}>
{ this.state.images.map(image => {
return (
<TouchableHighlight onPress={() => this._selectImage(image.uri)}>
<Image style={styles.image} source={{ uri: image.uri }} />
</TouchableHighlight>
);
})}
</View>
</ScrollView>
</View>
);
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
backgroundColor: '#F5FCFF',
},
imageGrid: {
flexDirection: 'row',
flexWrap: 'wrap',
justifyContent: 'center'
},
image: {
width: 100,
height: 100,
margin: 10,
},
});
export default CameraRollView
Hmm, the package you are seeking is probably react-native-image-picker. It allows you to take a photo or select one from your native device gallery.
LINK: https://github.com/react-community/react-native-image-picker
In response to the linking issue. When you save a package using:
npm install --save react-native-image-picker
What is happening here is the --save part prepares the packages dependencies to be connected to native iOS and Android. This linking is done using the command react-native link.
In some cases packages require some manual linking aswell (for example, this package requires a small amount of native iOS and Android configuration)
Related
I'm trying to add a tooltip component to my react native project, I installed React Native Elements to do this. I know it's installed correctly because the Divider component worked perfectly fine. For some reason though, the tooltip doesn't seem to work right, there are no errors but it simply doesn't do anything when I tap on the tooltip.
My entire component is here:
import React from 'react';
import {
StyleSheet,
View,
TouchableOpacity,
} from 'react-native';
import { MaterialCommunityIcons } from '#expo/vector-icons';
import { Tooltip, Text } from "#rneui/themed";
import {Colors} from './Colors';
const InfoTooltip = ({ label, info='' }) => {
return (
<View style={styles.inputLine}>
{ info != '' &&
<Tooltip popover={<Text>Tooltip Info</Text>}>
<Text>Press</Text>
</Tooltip>
}
{ info === '' &&
<Text style={styles.inputLabel}>{label}:</Text>
}
</View>
);
};
const styles = StyleSheet.create({
inputLine: {
flex: 1,
flexDirection: 'row',
},
inputLabel: {
color: Colors.Dove_Gray,
marginTop: 2,
fontSize: 14,
},
infoText: {
color: Colors.Silver,
fontSize: 12,
},
});
export default InfoTooltip;
I'm testing it on iOS and I see the text that says "Press", but when tapped, nothing happens, no popover, no error.
When setting visible to true, the tooltip is shown when I first render the app, but it locks the app up and I can no longer tap anything or scroll.
I'm not sure what I'm doing wrong, Thanks!
Starting with React Native Elements version 4.0, Tooltip is stateless. This means you need to use useState. You should declare a variable, like:
const [open, setOpen] = useState(false);
And include visible, onOpen & onClose Props for it to work:
<Tooltip
visible={open}
onOpen={() => {
setOpen(true);
}}
onClose={() => {
setOpen(false);
}}
popover="This is the popover text"
/>
More info in the Migration Guide.
I am trying to use react-native-snap-carousel but however, the swiping effect is not working as expected - it is often difficult to swipe left and right, it requires user to swipe harder to move to another picture (as illustrated in the link below).
Swiping issue with React Native Snap Carousel
I am not able to find any documented soluton but I found one possible prop - swipeThreshold. I try various value, but still the issue persist.
Does anyone know the solution to this?
I suggest you to use react-native-image-slider.
it's flexible and easy to use.
https://www.npmjs.com/package/react-native-image-slider
I made a component named slider.js:
import React, { Component } from 'react';
import {
View,
StyleSheet,
Image,
} from 'react-native';
import ImageSlider from 'react-native-image-slider';
export default class Slider extends Component {
render() {
return (
<ImageSlider
loop
autoPlayWithInterval={3000}
images={this.props.dataSource}
customSlide={({ index, item, style, width }) => (
<View key={index} style={[style, styles.customSlide]}>
<Image source={{ uri: item }} style={styles.customImage} />
</View>
)}
/>
);
}
}
const styles = StyleSheet.create({
customImage: {
height: 180,
marginRight: 20,
marginLeft: 20,
borderWidth: 1,
borderRadius: 10,
marginTop: 8,
},
customSlide: {
backgroundColor: '#eee',
},
});
you can add this to your project and use it wherever you need it like this:
import Slider from '../component/slider';
export default class App extends Component {
constructor(props) {
super(props);
this.state = {
images: [
'https://placeimg.com/640/480/nature',
'https://placeimg.com/640/480/tech',
'https://placeimg.com/640/480/animals',
'https://placeimg.com/640/480/tech',
],
}
render() {
return (
<View style={{flex: 1, backgroundColor: '#eee'}}>
<Slider dataSource={this.state.images} />
</View>
);
}
}
How do I share an image directly to an Instagram story using Expo / React Native?
This issue has already been solved for iOS for normal Instagram posts, but not stories.
Facebook's docs explain how to do this for iOS and Android, but not React Native.
Expected behavior:
Open Instagram story with the selected image.
Current behavior:
Opens Instagram story with blank screen.
The problem I'm facing:
I'm not quite sure how to generate a URI that fits Instagram's schema, as referenced in their docs.
Reproducible Snack
https://snack.expo.io/#nandorojo/share-to-instagram-story
Thank you so much!
Here is my code from the snack above:
import * as React from 'react';
import { Text, View, StyleSheet, Linking, Image } from 'react-native';
import * as FileSystem from 'expo-file-system';
const url = 'https://source.unsplash.com/daily';
export default class App extends React.Component {
_shareToStory = async () => {
// download to device
const { uri } = await FileSystem.downloadAsync(
url,
`${FileSystem.documentDirectory}meme.jpg`
).catch(e => console.log('instagram share failed', JSON.stringify(e), url));
try {
const encodedUrl = encodeURIComponent(uri);
const instagramUrl = `instagram-stories://share?backgroundImage=${encodedUrl}`;
Linking.openURL(instagramUrl);
} catch (error) {
console.log(error);
}
};
render() {
return (
<View style={styles.container}>
<Image source={{ uri: url }} style={{ height: 100, width: 100 }} />
<Text style={styles.paragraph} onPress={this._shareToStory}>
Share to Instagram Story
</Text>
</View>
);
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
justifyContent: 'center',
alignItems: 'center',
backgroundColor: '#ecf0f1',
padding: 8,
},
paragraph: {
margin: 24,
fontSize: 18,
fontWeight: 'bold',
textAlign: 'center',
},
});
If you're using Expo Managed Workflow, your options are very limited. As of SDK v38, afaik it's only possible to accomplish this on Android, and only if you're sharing a background image (due to missing Expo APIs for content permissions and pasteboard), then something like this might work:
import * as FileSystem from 'expo-file-system'
import * as IntentLaucher from 'expo-intent-launcher'
// url of the file to share
const url = '....'
// some random temporary filename
const localFile = `${FileSystem.cacheDirectory}${uuid()}.jpg`
try {
FileSystem.downloadAsync(url, localFile)
.then(({ uri }) => {
FileSystem.getContentUriAsync(uri).then(contentUri => {
IntentLauncher.startActivityAsync(
'com.instagram.share.ADD_TO_STORY',
{
data: contentUri,
flags: 1, // FLAG_GRANT_READ_URI_PERMISSION
type: 'image/jpeg', // or other based on your file type
}
).catch(console.warn)
})
})
.catch(console.warn)
} finally {
FileSystem.deleteAsync(localFile).catch(console.warn)
}
However, if you're using React Native (or have ejected to Expo Bare Workflow), then you have more options. I'd recommend using the RN community supported react-native-share library that works on both Android and iOS and supports all of the sharing options (plus many other services):
import Share from 'react-native-share'
Share.shareSingle({
method: Share.InstagramStories.SHARE_BACKGROUND_IMAGE,
backgroundImage: '....' // url of the file to share
social: Share.Social.INSTAGRAM_STORIES,
})
I am using "react-native camera" library to access the camera. So here is my code
.
import React, { Component } from "react";
import {
AppRegistry,
Dimensions,
StyleSheet,
Text,
TouchableHighlight,
View
} from "react-native";
import Camera from "react-native-camera";
import { RNCamera, FaceDetector } from "react-native-camera";
export default class App extends Component<Props> {
render() {
return (
<View style={styles.container}>
<Camera
ref={cam => {
this.camera = cam;
}}
style={styles.preview}
aspect={Camera.constants.Aspect.fill}
>
<Text style={styles.capture} onPress=
{this.takePicture.bind(this)}>
take photo
</Text>
</Camera>
</View>
);
}
takePicture() {
const options = {};
//options.location = ...
this.camera
.capture({ metadata: options })
.then(data => console.log(data))
.catch(err => console.error(err));
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
flexDirection: "row"
},
preview: {
flex: 1,
justifyContent: "flex-end",
alignItems: "center"
},
capture: {
flex: 0,
backgroundColor: "#fff",
borderRadius: 5,
color: "#000",
padding: 10,
margin: 40
}
});
Here i am able to access the back camera and whenever i am clicking on take photo, it capture image and show that instantly. But i need two changes here.
Using this code, the back camera is getting accessed but i want to access the front camera.
Also, the image i captured, should not be shown instantly. I want a button , and whenever i click on that button, it navigates to different page and show all the images there.
Is it possible in react native ?? If yes, then please suggest me the changes that i require to make in this code
To answer your second question specifically, you have two options.
A) After taken the photo, store it as base64 uri into your state or redux, then whenever you need it, display the base64 uri as a image.
B) Utilize the package react-native-fs to access file system, storing the taken photo in iOS as cache, and retrieving it whenever needed.
Based on personal experience dealing with it, I would recommend option A
To switch your camera to back camera to front camera there exists a prop in Camera component called mirrorMode, if it is true it will show the front camera, otherwise, it will be the default mode that is back camera:
<Camera
...
mirrorImage={this.state.mirrorMode}
>
You can create a state and a button that change the state to switch between that 2 cameras.
I am trying to learn the basics of react native and have started with the basic tab template. I am trying to create a social media sharing screen, where you get the list of apps and airdrop on iOS to display but unfortunately this is not working. The code I have displays an empty view and I was expecting the share dialog to appear over the top. I get the view but no sharing options.
Here is the code
`
import React from 'react';
import { View, StyleSheet } from 'react-native';
import { Share } from 'react-native';
var ActionSheetIOS = React;
export default class ShareScreen extends React.Component {
static navigationOptions = {
title: 'Share',
};
showShareActionSheet() {
ActionSheetIOS.showShareActionSheetWithOptions({
url: 'https://www.someurl.org',
});
}
render() {
return (
<View style={styles.container}>
this.showShareActionSheet();
</View>
);
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
paddingTop: 15,
backgroundColor: '#000000',
},
});
`
any ideas why this isn't working?
You need to wrap your this.showShareActionSheet(); with brackets to get it working.
<View style={styles.container}>
{this.showShareActionSheet()}
</View>
Otherwise it's gonna be considered as plain text and not as an instruction
You can use this package https://www.npmjs.com/package/react-native-share for sharing, This package will help you share the content to WhatsApp, FB, and other social apps.