sum count day each year (SQL) - sql

Question

my example:
Code FromDate ToDate
-- -------- -------
101 15/12/2012 15/01/2013
101 30/11/2013 20/01/2014
I want to count diff between two date,, how many days in this year
, How can i do this with SQL?
to be result like this :
Code No.day 2012 2013 2014
-- ------ ---- ---- ----
101 82 17 46 19

Answer 1

Try something like:
select Code,sum([2012])+sum([2013])+sum([2014]) as 'No.days',sum([2012]),sum([2013]),sum([2014]) from(
select Code,
case when datepart(yy,fromdate)=datepart(yy,todate) and datepart(yy,fromdate)=2012 then datediff(dd,fromdate, todate)
when datepart(yy,fromdate)=2012 and datepart(yy,todate)>2012 then datediff(dd,fromdate,dateadd(yy,1,dateadd(dd,-datepart(dy,DATEADD(yy,1, fromdate)),fromdate)))
when datepart(yy,fromdate)<2012 and datepart(yy,todate)=2012 then DATEPART(dy,todate)
end as '2012',
case when datepart(yy,fromdate)=datepart(yy,todate) and datepart(yy,fromdate)=2013 then datediff(dd,fromdate, todate)
when datepart(yy,fromdate)=2013 and datepart(yy,todate)>2013 then datediff(dd,fromdate,dateadd(yy,1,dateadd(dd,-datepart(dy,DATEADD(yy,1, fromdate)),fromdate)))
when datepart(yy,fromdate)<2013 and datepart(yy,todate)=2013 then DATEPART(dy,todate)
end as '2013',
case when datepart(yy,fromdate)=datepart(yy,todate) and datepart(yy,fromdate)=2014 then datediff(dd,fromdate, todate)
when datepart(yy,fromdate)=2014 and datepart(yy,todate)>2014 then datediff(dd,fromdate,dateadd(yy,1,dateadd(dd,-datepart(dy,DATEADD(yy,1, fromdate)),fromdate)))
when datepart(yy,fromdate)<2014 and datepart(yy,todate)=2014 then DATEPART(dy,todate)
end as '2014'
from myTable
) as daystable
group by Code
If you need more years you will need to add some more fields in the subquery.

Answer 2

You will need to combine a few different techniques, to get the result you are after.
It helps if you have a calendar table. These are incredibly useful things, well worth researching if you are not familar. My query assumes you don't. Here I've used a recursive CTE to create one on the fly.
Sample Data
TIP: Providing sample data in format we can share, improves the odds of your question receiving an answer.
-- Table variables are a good way to share sample data.
DECLARE #Sample TABLE
(
Code INT,
FromDate DATE,
ToDate DATE
)
;
INSERT INTO #Sample
(
Code,
FromDate,
ToDate
)
VALUES
(101, '2012-12-15', '2013-01-15'),
(101, '2013-11-30', '2014-01-20')
;
The Query
This query joins your source data to the calendar table. One record is returned for each day between the from and to dates. Using the year column in the calendar table, we group the results. Counting the records returns the total days passed. To calculate the year subtotals, we use conditional aggregation. This technique uses a case expression to create new columns that are conditionally populated with a 1 or a 0, based on the year.
/* Returns date counts, split by
* year.
*/
WITH CalendarTable AS
(
/* This CTE returns 1 record for each day
* between Jan 1st 2012 and Dec 31st 2014.
*/
SELECT
CAST('2012-01-01' AS DATE) AS [Date],
2012 AS [Year]
UNION ALL
SELECT
DATEADD(DAY, 1, [Date]) AS [Date],
YEAR(DATEADD(DAY, 1, [Date])) AS [Year]
FROM
CalendarTable
WHERE
[Date] < '2014-12-31'
)
SELECT
s.Code,
COUNT(*) AS [No.Day],
SUM(CASE WHEN ct.[Year] = 2012 THEN 1 ELSE 0 END) AS [2012],
SUM(CASE WHEN ct.[Year] = 2013 THEN 1 ELSE 0 END) AS [2013],
SUM(CASE WHEN ct.[Year] = 2014 THEN 1 ELSE 0 END) AS [2014]
FROM
#Sample AS s
INNER JOIN CalendarTable AS ct ON ct.[Date] >= s.FromDate
AND ct.[Date] < s.ToDate
GROUP BY
s.Code
OPTION
(MAXRECURSION 1096)
;
Returns
Code No.day 2012 2013 2014
-- ------ ---- ---- ----
101 82 17 46 19
If you already have a calendar table you can simplify this query, by removing the CTE and updating the join.

Answer 3

Use this:
SELECT Code,SUM(No.day) AS No.day, SUM(2012) AS 2012, SUM(2013) AS 2013, SUM(2014) AS 2014
FROM TABLENAME GROUP BY Code
According to your current(Edited) question, you should use
SELECT DATEDIFF(day,'2012-06-05','2012-08-05') AS Year2012 From TABLENAME .
For example:
SELECT DATEDIFF(day, '2014/01/01', '2014/04/28');
Result: 117
SELECT DATEDIFF(hour, '2014/04/28 08:00', '2014/04/28 10:45');
Result: 2
SELECT DATEDIFF(minute, '2014/04/28 08:00', '2014/04/28 10:45');
Result: 165
You can manipulate it based on your requirement.

Answer 4

SELECT code,fromdate,todate,datediff(dd,fromdate,todate),
datediff(dd,case when year(fromdate) < 2012 then '1/1/2012' when year(fromdate) = 2012 then fromdate else '12/31/2012' end,case when year(todate) = 2012 then todate else '12/31/2012'end)'2012',
datediff(dd,case when year(fromdate) < 2013 then '1/1/2013' when year(fromdate) = 2013 then fromdate else '12/31/2013' end,case when year(todate) = 2013 then todate else '12/31/2013'end) '2013',
datediff(dd,case when year(fromdate) < 2014 then '1/1/2014' when year(fromdate) = 2014 then fromdate else '12/31/2014' end,case when year(todate) < 2014 then '1/1/2014' when year(todate) = 2014 then todate else '12/31/2014'end) '2014' FROM (SELECT '101' AS code, datefromparts(2012,12,15) AS fromdate, datefromparts(2013,1,15) AS todate
UNION
SELECT '101' AS code, datefromparts(2013,11,30) AS fromdate, datefromparts(2014,1,20) AS todate
Union
SELECT '101' AS code, datefromparts(2014,11,30) AS fromdate, datefromparts(2016,1,20) AS todate) AS s
Hope This helps