How to delete the last cell in a column that contains data - vba

Question

This sounds like a very basic question (and it is), but I cannot figure it out and I cannot find a suitable solution on the web.
How do you select the last cell in a column that contains a numeric value and delete it?
I have formulas that go past this cell and return blank values in the column. This is what is tripping me up at the moment. My current code will go all the way down to where I have carried the formulas to and start deleting those cells instead of deleting the last cell with a numeric value.
My current code looks like this
Range("AA1500").End(xlUp).Select
With Selection.Delete
End With
Any help would be greatly appreciated.
Please let me know if I can clarify anything.
Thanks

Answer 1

If you want to go down past cells with arbitrary strings in them and
delete the last numeric value (but not the last cell with a alphanumeric string in it), this should work:
Sub deleteLastNum()
Dim row As Integer
row = Range("A1000").End(xlUp).row
For i = row To 1 Step -1:
If IsNumeric(Cells(i, "A")) Then
Cells(i, "A").Clear
Range("A" & CStr(i + 1), "A" & CStr(row)).Cut Destination:=Range("A" & CStr(i))
Exit For
End If
Next
End Sub
It will also delete the last cell with a formula that evaluates to a number. It moves down the range of cells in the column above it with characters in it to fill in the cleared cell.

Answer 2

What you can do is get the total number of rows of a column (A) then check is last cell value is numeric or not, if numeric then clear that cell.
Sub del()
Dim sh As Worksheet
Dim rn As Range
Set sh = ThisWorkbook.Sheets("Sheet1")
Dim k As Long
Set rn = sh.UsedRange
k = rn.Rows.Count + rn.Row - 1
If IsNumeric(Sheets("Sheet1").Range("A" & k).Value) = True Then
Sheets("Sheet1").Range("A" & k).ClearContents
End If
End Sub
This will check last cell for numeric value in column A.
Hope this is what you are asking.
EDIT
Implementing above for all the sheets in a workbook using a loop is like :
Sub del()
Dim sh As Worksheet
Dim rn As Range
For Each sh In ActiveWorkbook.Worksheets
Set sh = ThisWorkbook.Sheets(sh.Name)
Dim k As Long
Set rn = sh.UsedRange
k = rn.Rows.Count + rn.Row - 1
If IsNumeric(sh.Range("A" & k).Value) = True Then
sh.Range("A" & k).ClearContents
End If
Next sh
End Sub
This will loop through each sheet like Sheet1, Sheet2 or whatever the name of the sheet may be and check for numeric value in last cell of col A, if found numeric then it will delete the value.

Answer 3

You already got an answer to your post, just to be clear, the safest way to find the last row (let's say in Column "AA", according to your post), and ignoring blank cells in the middle, is by using the syntax below:
Sub FindlastRow()
Dim LastRow As Long
With Worksheets("Sheet1") ' <-- change "Sheet1" to your sheet's name
LastRow = .Cells(.Rows.Count, "AA").End(xlUp).Row
' rest of your coding here
End With
End Sub
Screen-shot of the result:

Answer 4

Use 'SpecialCells()'
Sub ClearLastNumber(sh As WorkSheet, columnIndex As String)
On Error GoTo ExitSub 'should 'columnIndex' column of 'sh' worksheet contain no numbers then the subsequent statement would throw an error
With sh.Columns(columnIndex).SpecialCells(xlCellTypeConstants, xlNumbers)
With .Areas(.Areas.Count)
.Cells(.Count).ClearContents
End With
End With
ExitSub:
End Sub
To be used in your "main" sub as follows
Sub Main()
Dim sh As Worksheet
For Each sh In ActiveWorkbook.Worksheets
ClearLastNumber Sh "A"
Next
End Sub