I'm trying to install casperjs from git by the manual http://docs.casperjs.org/en/latest/installation.html#installing-from-git
but I get the error
ln: failed to create symbolic link ‘/usr/local/bin/casperjs’: No such file or directory
What can I do in this case? My operating system is Windows 8.
You don't need to create symbolic link on Windows. Just add CasperJS bin directory to the %PATH% environment variable
The command "ln -sf pwd/bin/casperjs /usr/local/bin/casperjs" is for linux system valid not for windows.
You have to set the enviroment variable in Windows and add casperjs/bin directory to the path. For further information, this article is the right place https://superuser.com/questions/284342/what-are-path-and-other-environment-variables-and-how-can-i-set-or-use-them
The filesystem where you're trying to create the link (not point to, but the link itself) must support these types of links.
For example, ext3, and btrfs support these links, but ntfs (like what you typically find on a USB stick) does not.
In other words you can have this trouble on Linux just as well as on windows.
Related
In my home folder in Linux I have several config files that have "rc" as a file name extension:
$ ls -a ~/|pcregrep 'rc$'
.bashrc
.octaverc
.perltidyrc
.screenrc
.vimrc
What does the "rc" in these names mean?
It looks like one of the following:
run commands
resource control
run control
runtime configuration
Also I've found a citation:
The ‘rc’ suffix goes back to Unix's grandparent, CTSS. It had a command-script feature called "runcom". Early Unixes used ‘rc’ for the name of the operating system's boot script, as a tribute to CTSS runcom.
Runtime Configuration normally if it's in the config directory. I think of them as resource files. If you see rc in file name this could be version i.e. Release Candidate.
Edit: No, I take it back officially... "run commands"
[Unix: from runcom files on the CTSS system 1962-63, via the startup script /etc/rc]
Script file containing startup instructions for an application program (or an entire operating system), usually a text file containing commands of the sort that might have been invoked manually once the system was running but are to be executed automatically each time the system starts up.
Thus, it would seem that the "rc" part stands for "runcom", which I believe can be expanded to "run commands". In fact, this is exactly what the file contains, commands that bash should run.
Quoted from What does “rc” in .bashrc stand for?
I learnt something new! :)
In the context of Unix-like systems, the term rc stands for the phrase "run commands". It is used for any file that contains startup information for a command. It is believed to have originated somewhere in 1965 from a runcom facility from the MIT Compatible Time-Sharing System (CTSS).
Reference: https://en.wikipedia.org/wiki/Run_commands
In Unix world, RC stands for "Run Control".
http://www.catb.org/~esr/writings/taoup/html/ch10s03.html
To understand rc files, it helps to know that Ubuntu boots into several different runlevels. They are 0-6, 0 being "halt", 1 being "single-user", 2 being "multi-user"(the default runlevel), etc. This system has now been outdated by the Upstart and initd programs in most Linux Distros. It is still maintained for backwards compatibility.
Within the /etc directory are several folders labeled "rc0.d, rc1.d" etc, through rc6.d. These are the directories the kernel refers to to know which init scripts it should run for that runlevel. They are symbolic links to the system service scripts residing in the /etc/init.d directory.
In the context you are using it, it would appear that you are listing any files with rc in the name. The code in these files will set the way the services/tasks startup and run when initialized.
According to Apple's Developer Docs the Library global allows one to import compiled scripts so they can be used as a library in one's current script. This works just fine if you were to do something like the below code with myLibName.scpt located at ~/Library/Script Libraries:
myLib = Library('myLibName');
myLib.myLibMethod() // Works just fine
But, the docs also claim that one can export an environment variable — OSA_LIBRARY_PATH containing a string of : delimited paths — and Library() would then defer to that list of paths before proceeding to it's default path: ~/Library/Script Libraries. Ya know, like the bash environment variable Path. Here's the relevant piece of documentation below; it describes the path hierarchy:
The basic requirement for a script to be a script
library is its location: it must be a script document in a “Script
Libraries” folder in one of the following folders. When searching for
a library, the locations are searched in the order listed, and the
first matching script is used:
If the script that references the library is a bundle, the script’s
bundle Resources directory. This means that scripts may be packaged
and distributed with the libraries they use.
If the application running the script is a bundle, the application’s bundle Resources
directory. This means that script applications (“applets” and
“droplets”) may be packaged and distributed with the libraries they
use. It also enables applications that run scripts to provide
libraries for use by those scripts.
Any folders specified in the environment variable OSA_LIBRARY_PATH. This allows using a library
without installing it in one of the usual locations. The value of this
variable is a colon-separated list of paths, such as /opt/local/Script
Libraries:/usr/local/Script Libraries. Unlike the other library
locations, paths specified in OSA_LIBRARY_PATH are used exactly as-is,
without appending “Script Libraries”. Supported in OS X v10.11 and
later.
The Library folder in the user’s home directory, ~/Library.
This is the location to install libraries for use by a single user,
and is the recommended location during library development.
The
computer Library folder, /Library. Libraries located here are
available to all users of the computer.
The network Library folder,
/Network/Library. Libraries located here are available to multiple
computers on a network.
The system Library folder, /System/Library.
These are libraries provided by OS X.
Any installed application
bundle, in the application’s bundle Library directory. This allows
distributing libraries that are associated with an application, or
creating applications that exist solely to distribute libraries.
Supported in OS X v10.11 and later.
The problem is that it doesn't work. I've tried exporting the OSA_LIBRARY_PATH variable — globally via my .zshrc file — and then running a sample script just like the one above via both the Script Editor and the osascript executable. Nothing works; I get a "file not found" error. I found this thread-where-the-participants-give-up-hope online; it doesn't explain much. Any thoughts?
On a somewhat related note, the Scripting Additions suite provides two other methods — loadScript and storeScript — that seem like they might be useful here. Unfortunately, when you try to use them, osascript gives you the finger. Though, I did manage to return what looked like a hexadecimal buffer from a compiled script using loadScript. Anyway, any insight you guys can shed on this would be much appreciated. Thanks.
The OSA_LIBRARY_PATH environment variable is ignored by restricted executables when running with System Integrity Protection enabled.
To workaround this limitation you can either turn off SIP, or you can use an unrestricted executable.
For instance, to make osascript unrestricted, you should first make a copy, and then re-sign it with an ad-hoc signature:
cp /usr/bin/osascript ./osascript
codesign -f -s - ./osascript
Once you have the unrestricted osascript, you can run it with the OSA_LIBRARY_PATH environment variable set like this:
OSA_LIBRARY_PATH="/path/to/libs" ./osascript path/to/script.scpt
As a lousy alternative, you can put a symlink at one of the "Script Libraries" folders that osascript would look at and point it to the folder you want. Note that the symlink must be a replacement for the entire folder, it can't just exist inside of it.
rm -rf ~/Library/Script\ Libraries
ln -s "/Your/Custom/Path/Goes/Here/" ~/Library/Script\ Libraries
Tested on 10.13.2
I am trying to install Yii framework via archive file in Windows 7...after downloading the file I tried extracting it into a folder in my C:\wamp\www\bid location, however, I encounter an error saying this:
! C:\wamp\www\bid\yii-basic-app-2.0.2.tgz: Cannot create symbolic link C:\wamp\www\bid\basic\vendor\bin\markdown
A required privilege is not held by the client.
! C:\wamp\www\bid\yii-basic-app-2.0.2.tgz: Cannot create symbolic link C:\wamp\www\bid\basic\vendor\bin\yii
A required privilege is not held by the client.
I thought that perhaps Winrar can't extract tgz files so I downloaded 7-zip...Using 7-zip it extracted into a tar file and the tar file was extracted with no errors...For some reason though I do not seem to have the framework folder that seem to be in other people's directory structure...Moreover after trying create my own framework folder and performing this command:
yiic webapp C:\wamp\www\bid
It states that yiic is not recognized as an internal or external command
Can someone tell me what I'm doing wrong...I've tried setting this up numerous times and failed
You need to run 7-Zip File Manager in administrator mode.
Right-click the icon of 7-Zip File Manager, and then click "Run as administrator".
you need to call the command with php since it is actually a external command, i do it like this
php ./yiic webapp NameOfApp
This way your terminal understand that yii is a program that runs with php.
Another solution is to add the yii path to your environmental variable, regards
I have installed SenchaSDKTools-2.0.0-beta3-windows on my windows Xp 32-bit.
following is the command I am running on command prompt.
C:\Program Files\SenchaSDKTools-2.0.0-beta3>sencha app create MyApp c:\xampp\htdocs\sencha\myapp\
Giving following error
[ERROR] the current workind directory (C:\Program
Files\SenchaSDKTools-2.0.0-beta3>) is not valid SDK directory. Please
'cd' in to a SDK directory before executing this command.
environment variable has been set following way.
Variable name : Path
Value : C:\Program Files\SenchaSDKTools-2.0.0-beta3
can anyone figure out what exactly wrong in this process ?
*****Sencha Touch setup Guide steps(in Window)******
Download Sencha Touch SDK Tool. (http://www.sencha.com/products/touch/download/ -->SDK Tools Beta for Developers). Run .exe file. It will install tool to default path. (i.e. C:\Program Files\SenchaSDKTools-2.0.0-beta3)
Download Sencha Touch SDK. (Download openSource version file licensed under GPL.).
Extract SDK you just download in step 2.
Open Command line terminal (start->Run->type cmd). Change directory path to SDK path as you just extracted in step3.
Verify that Sencha Command is working properly on your machine. So Type Sencha.
E.g. sdkPath>sencha
you will see "Sencha Command v2.0.2" message with other sencha command detail.
Create app in your web directory by typing following.
E.g. sdkpath> sencha app create firstSenchaApp "path/ to/ www"
(If you have tomcat 7 installed in your computer, give path to \apache-tomcat-7.0.30-windows-x86\apache-tomcat-7.0.30\webapps)
Note: There must not be space in directory path name. _(underscore),- (desk) are allowed.
If app is not generated in step 6. There might be an error. There are as follow:
If error message appear is "sencha' is not recognized as an internal or external command, operable program or batch file.”, follow these steps to troubleshoot:
The path to SDK Tools directory is prepended to your system's PATH environment variable.
From the terminal, run
echo $PATH or echo %PATH% .
The SDK Tools directory should be displayed in part of the output. If this is not the case, add it to your PATH manually.
The environment variable SENCHA_SDK_TOOLS_{version} is set, with the value being the absolute path to the installation directory mentioned above.
For example: If the installed version is '2.0.0-beta2', a SENCHA_SDK_TOOLS_2_0_0_BETA2 must be set.
From the terminal, run
echo $SENCHA_SDK_TOOLS_2_0_0_BETA2 or echo %SENCHA_SDK_TOOLS_2_0_0_BETA2% on Windows.
If the output is empty, set the environment variable manually.
Wrong Current Working Directory
A common mistake is not running Sencha Command within either a valid SDK directory or an application directory. If the current directory is not a SDK or application directory, "sencha" command will fallback to backwards-compatible mode. As of SDK Tools release "2.0.0-beta2", you should see a clear warning in such case:
"The current working directory (...) is not a recognized Sencha SDK or application folder. Running in backwards compatible mode." So in this case follow proper step as mentioned above.
Reference:
http://www.sencha.com/forum/showthread.php?192169-Important-SDK-Tools-Sencha-Command-Update
There is an invisible file that you need to copy, called .senchasdk. Make sure it is in the folder.
I think you're having the same problem I had; I had attempted to run 'sencha app create...' from the folder containing sencha.bat. Instead, you need to run 'sencha app create...' from the sencha-touch-2.0.1.1 folder (which contains the .senchasdk file).
See this previous SO question!
Save my days.
By the way, if you can't extract the sencha-cmd to sdk tools, try to extract on other location and copy the folder [3.0.0.250] to your sdk tools > [bin] folder.
hope this helps.
We're developing an app that needs to run on a removable device (e.g. USB stick). On Linux, we're using Gnome launchers to place a shortcut to the app on the root of the device. However, we need to use relative paths for the executable and icon since we don't know in advance where the device will mount. In the .desktop file I have something like:
Exec=../myapp/myexecutable
Icon=../myapp/myicon.png
Neither the executable or icon is found. I read the spec on icon lookup in .desktop files (http://standards.freedesktop.org/icon-theme-spec/icon-theme-spec-latest.html#icon_lookup) but it didn't enlighten me.
Is there a way to get launchers to use a relative path? If not, is there another approach to achieve what I want (i.e. a shortcut with an icon and an executable, specified using relative paths)?
Relative paths are not supported*.
One solution is to have an installer. This script updates the desktop file according to the location the script is run from. Make the script executable, and the user can click it to install. The script requires the desktop file to be writable.
This was done with Linux in mind. The file is named autorun.sh; but that is just a convention, it usually won't run automatically. If you deploy this on something other than Linux, then name the file something else(autorun.linux), or adapt it to do different things according to the platform.
#! /bin/sh
#### Fixup $APPNAME.desktop.
APPNAME=xvscatter
ICONNAME=xv_logo.png
cd $(dirname "$0")
APPDIR="$PWD/$APPNAME"
EXEC="$APPDIR/$APPNAME"
ICON="$APPDIR/$ICONNAME"
sed -i -e "s#^Icon=.*#Icon=$ICON#" \
-e "s#^Exec.*#Exec=$EXEC#" "$APPNAME.desktop"
*The convention for the freedesktop is to have the icons in $HOME/.icons, /usr/share/icons or /usr/share/pixmaps. Under those directories are subdirectories for different icon sizes and types. When using one of those directories to store the icon, only the icon name(without the directory) is listed in the desktop file; otherwise record the full path to the file.
The executable, if in the path, can be listed with no pathname(unsafe). It's best to list the full path. Imagine the wrong program getting launched because the full path isn't specified.
Another possibility is to copy the desktop file to the user's desktop or to /usr/share/applications, and edit it there. Do this when the program is on read-only media.
Because none of the above results in a true install, if possible, use the platform's native installer and packaging tools(rpm,dep,portage, etc.). Those tools provide a framework for complete installation including the proper file permissions(think selinux), and desktop menus. They also provide for easy uninstall.
If the program has to run from the removable media, consider using the system install for just installing symlinks, maybe to /opt/vendor/progname.
What I did and worked perfectly was:
Exec=sh -e -c "exec \\"\\$(dirname \\"\\$0\\")/.sh/server.sh\\";$SHELL" %k
Explaining the command:
The snippet below will get the dir name of who is executing that, therefore the launcher dir name
$(dirname \\"\\$0\\")
So appending the desired path, will make this execute relative path.
Ref: https://askubuntu.com/questions/1144341/execute-shell-on-a-relative-path-on-ubuntu-launcher