How to split a cell and create a new row in sql - sql

Question

I have a column which stores multiple comma separated values. I need to split it in a way so that it gets split into as many rows as values in that column along with remaining values in that row.
eg:
John 111 2Jan
Sam 222,333 3Jan
Jame 444,555,666 2Jan
Jen 777 4Jan
Output:
John 111 2Jan
Sam 222 3Jan
Sam 333 3Jan
Jame 444 2Jan
Jame 555 2Jan
Jame 666 2Jan
Jen 777 4Jan
P.S : I have seen multiple questions similar to this, but could not find a way to split in such a way.

Answer 1

This solution is built on Vertica, but it works for every database that offers a function corresponding to SPLIT_PART().
Part of it corresponds to the un-pivoting technique that works with every ANSI compliant database platform that I explain here (just the un-pivoting part of the script):
Pivot sql convert rows to columns
So I would do it like here below. I'm assuming that the minimalistic date representation is part of the second column of a two-column input table. So I'm first splitting that short date literal away, in a first Common Table Expression (and, in a comment, I list that CTE's output), before splitting the comma separated list into tokens.
Here goes:
WITH
-- input
input(name,the_string) AS (
SELECT 'John', '111 2Jan'
UNION ALL SELECT 'Sam' , '222,333 3Jan'
UNION ALL SELECT 'Jame', '444,555,666 2Jan'
UNION ALL SELECT 'Jen' , '777 4Jan'
)
,
-- put the strange date literal into a separate column
the_list_and_the_date(name,list,datestub) AS (
SELECT
name
, SPLIT_PART(the_string,' ',1)
, SPLIT_PART(the_string,' ',2)
FROM input
)
-- debug
-- SELECT * FROM the_list_and_the_date;
-- name|list |datestub
-- John|111 |2Jan
-- Sam |222,333 |3Jan
-- Jame|444,555,666|2Jan
-- Jen |777 |4Jan
,
-- ten integers (too many for this example) to use as pivoting value and as "index"
ten_ints(idx) AS (
SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
UNION ALL SELECT 10
)
-- the final query - pivoting prepared input using a CROSS JOIN with ten_ints
-- and filter out where the SPLIT_PART() expression evaluates to the empty string
SELECT
name
, SPLIT_PART(list,',',idx) AS token
, datestub
FROM the_list_and_the_date
CROSS JOIN ten_ints
WHERE SPLIT_PART(list,',',idx) <> ''
;
name|token|datestub
John|111 |2Jan
Jame|444 |2Jan
Jame|555 |2Jan
Jame|666 |2Jan
Sam |222 |3Jan
Sam |333 |3Jan
Jen |777 |4Jan
Happy playing ...
Marco the Sane