I want to use the step S3 CSV Input to load multiple files from an s3 bucket then transform and load back into S3. But I can see this step support only one file at once and I need to supply the file names, is there any way to load all files at once by supplying only the bucket name i.e. <s3-bucket-name>/*?
S3-CSV-Input is inspired by CSV-Input and doesn't support multi-file-processing like Text-File-Input does, for example. You'll have to retrieve the filenames first, so you can loop over the filename list as you would do with CSV-Input.
Two options:
AWS CLI method
Write a simple shell script that calls AWS CLI. Put it in your path. Call it s3.sh
aws s3 ls s3://bucket.name/path | cut -c32-
In PDI:
Generate Rows: Limit 1, Fields: Name: process, Type: String, Value s3.sh
Execute a Process: Process field: process, Output Line Delimiter |
Split Field to Rows: Field to split: Result output. Delimiter | New field name: filename
S3 CSV Input: The filename field: filename
S3 Local Sync
Mount the S3 directory to a local directory, using s3fs
If you have many large files in that bucket directory, it wouldn't work so fast...well it might be okay if your PDI runs on an Amazon machine
Then use the standard file reading tools
$ s3fs my-bucket.example.com/path/ ~/my-s3-files -o use_path_request_style -o url=https://s3.us-west-2.amazonaws.com
Related
I am trying to generate a file from a Dataframe that I have created in AWS-Glue, I am trying to give it a specific name, I see most answers on stack overflow actually uses Filesystem modules, but here this particular csv file is generated in S3, also I want to give the file a name while generating it, and not rename it after it is generated, is there any way to do that?
I have tried using df.save(s3:://PATH/filename.csv) which actually generates a new directory in S3 named filename.csv and then generates part-*.csv inside that directory
df.repartition(1).write.mode('append').format('csv').save('s3://PATH').option("header", "true")
I have a view in hive named prod_schoool_kolkata. I used to get the csv as:
hive -e 'set hive.cli.print.header=true; select * from prod_schoool_kolkata' | sed 's/[\t]/,/g' > /home/data/prod_schoool_kolkata.csv
that was in EC2-Instance. I want the path to be in S3.
I tried giving the path like :
hive -e 'set hive.cli.print.header=true; select * from prod_schoool_kolkata' | sed 's/[\t]/,/g' > s3://data/prod_schoool_kolkata.csv
But the csv is not getting stored.
I also had a problem that the csv file is getting generated but every column head is having pattern like: tablename.columnname for example prod_schoool_kolkata.id. Is there any way to remove the table names in the csv getting formed.
You have to first install the AWS Command Line Interface.
Refer the Link : Installing the AWS Command Line Interface and follow the relevant installation instructions or go to the Sections at the bottom to get the installation links relevant to your Operating System(Linux/Mac/Windows etc).
After verifying that it's installed properly, you may run normal commands like cp,ls etc over the aws file system. So, you could do
hive -e 'set hive.cli.print.header=true; select * from prod_schoool_kolkata'|
sed 's/[\t]/,/g' > /home/data/prod_schoool_kolkata.csv
aws s3 cp /home/data/prod_schoool_kolkata.csv s3://data/prod_schoool_kolkata.csv
Also see How to use the S3 command-line tool
I am having an issue with the command s3-dist-cp on Amazon EMR. What I want to achieve is being able to define the name of the file when merging all the little files in my S3 folder. Example:
s3://bucket/event/v1/2017/11/06/10/event-1234.json
s3://bucket/event/v1/2017/11/06/10/event-4567.json
s3://bucket/event/v1/2017/11/06/10/event-7890.json
.... so on
and the result is the following:
s3://test/test/event
I am able to merge all the files above but the result filename is wrong.
The command is:
s3-dist-cp --src s3://bucket/event/v1/2017/11/06/10/ --dest s3://test/test/ --groupBy='.*(event).*' --targetSize=2048
and the result I want to achieve is:
s3://test/test/events.hourly.json
How can I change the destination file name ?
I have a huge (~6 GB) file on Amazon S3 and want to get the first 100 lines of it without having to download the whole thing. Is this possible?
Here's what I'm doing now:
aws cp s3://foo/bar - | head -n 100
But this takes a while to execute. I'm confused -- shouldn't head close the pipe once it's read enough lines, causing aws cp to crash with a BrokenPipeError before it has time to download the entire file?
Using the Range HTTP header in a GET request, you can retrieve a specific range of bytes in an object stored in Amazon S3. (see http://docs.aws.amazon.com/AmazonS3/latest/API/RESTObjectGET.html)
if you use aws cli you can use aws s3api get-object --range bytes=0-xxx, see http://docs.aws.amazon.com/cli/latest/reference/s3api/get-object.html
It is not exactly as a number of lines but should allow you to retrieve your file in part so avoid downloading the full object
I'm trying to merge a large number of small files (200k+) and have come up with the following super-easy Pig code:
Files = LOAD 'hdfs/input/path' using PigStorage();
store Files into 'hdfs/output/path' using PigStorage();
Once Pig is done with the merging is there a way to remove the input files? I'd like to check that the file has been written and is not empty (i.e. 0 bytes). I can't simply remove everything in the input path because new files may have been inserted in the meantime, so that ideally I'd remove only the ones in the Files variable.
With Pig it is not possible i guess. Instead what you can do is use -tagsource with the LOAD statement and get the filename and stored it somewhere. Then use HDFS FileSystem API and read from the stored file to remove those files which are merged by pig.
A = LOAD '/path/' using PigStorage('delimiter','-tagsource');
You should be able to use hadoop commands in your Pig script
Move input files to a new folder
Merge input files to output folder
Remove input files from the new folder
distcp 'hdfs/input/path' 'hdfs/input/new_path'
Files = LOAD 'hdfs/input/new_path' using PigStorage();
STORE Files into 'hdfs/output/path' using PigStorage();
rmdir 'hdfs/input/new_path'