How to add decimal and remove text from alphanumerical string - vba

Question

I have a huge amount of data which is alphanumerical and I need to convert it to purely numerical. Which no text in the string.
Ex.
C0424.100 ---> 424.100 (or 0424.100)
There always is 3 places after the decimal. Any tips on how to go about this? I'm pretty new to VBA. So basically I need to remove all text and a decimal with three digits to the right of it.

Answer 1

This is well described in String functions and how to use them
However, this should get you started. I would handle the formatting in Excel afterwards, but this is the simple string to number conversion. If the strings are more complex, consider using the Search string function to find the numbers, then use Right, Left, Mid functions to trim the string. Lastly use the CDbl() function to convert the string to the double.
Macro code as follows:
Sub temp()
'
' temp Macro
Range("A2").Select
stringToConvert = Selection.Value
trimmedString = Right(stringToConvert, Len(stringToConvert) - 1)
numberToDisplay = CDbl(trimmedString)
Range("A3").Value = numberToDisplay
End Sub

Answer 2

Do you even need VBA? If your data always has just one leading alpha character then you can just use standard Excel functions. For an entry in A2 that you want to convert, place the following formula in a convenient cell (e.g. B2):
=VALUE(RIGHT(A2,LEN(A2)-1))

Answer 3

I got UDF options for you.
Option 1: If you want to remove all the alphas from the beginning of string:
Function RemoveFirstAlphas(txt As String) As String
Dim i As Long
For i = 1 To Len(txt)
Select Case Mid$(txt, i, 1)
Case "0" To "9": Exit For
Case Else: Mid$(txt, i, 1) = Chr(32)
End Select
Next
RemoveFirstAlphas = Trim(txt)
End Function
Option 2: If you want to remove all the alphas from entire string:
Function RemoveAllAlphas(txt As String) As String
Dim ObjRegex As Object
Set ObjRegex = CreateObject("vbscript.regexp")
With ObjRegex
.Global = True
.Pattern = "[a-zA-Z\s]+"
RemoveAllAlphas = .Replace(Replace(txt, "-", Chr(32)), vbNullString)
End With
End Function

Answer 4

No need for VBA. Something like:
=--MID(A1,MIN(FIND({0,1,2,3,4,5,6,7,8,9},A1&"0123456789")),99)
will return the string starting with the first digit, and convert it to a numeric value. You can then format it in the cell however you wish.
The above will work with any number of non-digit leading characters. If will only have a single non-digit character, then #Skippy answer is simpler
If you have to have a VBA routine, something like the following should work -- it will extract the first numeric substring in the string. It does not matter if there are non-digits before or after. And, if there are no digits, the function will return the #NUM! error
Option Explicit
Function ExtractNums(S As String) As Variant
Dim I As Long
For I = 1 To Len(S)
If IsNumeric(Mid(S, I, 1)) Then
ExtractNums = Val(Mid(S, I))
Exit Function
End If
Next I
ExtractNums = CVErr(xlErrNum)
End Function