Export sql query results to xml data file in oracle - sql

Question

I have an SQL query which returns two columns with data like this:.
State Name
------- ---------
Online Terminal1
Offline Terminal2
Online Terminal3
Online Terminal4
Now I want to create an XML file with a SQL query runs. XML file structure must be like this:
<?xml version="1.0" encoding="utf-8" ?>
<Terminallist name="xml data">
<Value id="0">
<Terminal>Terminal1</Terminal>
<State>Online</State>
</Value>
<Value id="1">
<Terminal>Terminal2</Terminal>
<State>Offline</State>
</Value>
<Value id="2">
<Terminal>Terminal3</Terminal>
<State>Online</State>
</Value>
<Value id="3">
<Terminal>Terminal4</Terminal>
<State>Online</State>
</Value>
</Terminallist>
I want to save XML file to a directory like this c:/file.xml.

Answer 1

Answer:-
Table name: temptable
Data in table :
Query :-
SELECT XMLElement("Terminallist ", XMLAttributes('xml data' AS "name"),XMLAgg(XMLElement("value ", XMLAttributes(rownum AS "id"),XMLForest(Terminal,state))))
FROM temptable ;
output :-
<Terminallist name = "xml data">
<value id = "1">
<TERMINAL>Terminal2</TERMINAL>
<STATE>Offline</STATE>
</value>
<value id = "2">
<TERMINAL>Terminal3</TERMINAL>
<STATE>Online</STATE>
</value>
<value id = "3">
<TERMINAL>Terminal4</TERMINAL>
<STATE>Online</STATE>
</value>
</Terminallist>
Thanks
Narendar

Answer 2

This solution uses a WITH clause to generate the ID as you want, starting from 0. Using the analytic row_number() function provides a guaranteed sort order in the result set.
NB: XMLRoot() is deprecated as part of the XML/SQL standard but generates the version header you asked for. Find out more.
with cte as (
select row_number() over (order by name) - 1 as id
, name
, state
from terminals
)
SELECT xmlroot (
XMLElement(
"Terminallist",
XMLAttributes( 'xml data' as "name"),
XMLAgg(XMLElement("Value",
XMLAttributes(cte.id as "id"),
XMLElement("Terminal",cte.name),
XMLElement("State",cte.state)
)
)
)
, version '1.0' )
FROM cte
order by cte.id
/
Here is the output:
<?xml version="1.0"?>
<Terminallist name="xml data">
<Value id="0">
<Terminal>Terminal1</Terminal>
<State>Online</State>
</Value>
<Value id="1">
<Terminal>Terminal2</Terminal>
<State>Offline</State>
</Value>
<Value id="2">
<Terminal>Terminal3</Terminal>
<State>Online</State>
</Value>
<Value id="3">
<Terminal>Terminal4</Terminal>
<State>Online</State>
</Value>
</Terminallist>
As for writing the output to a file, that depends on how you want to call the SQL. Use SPOOL if you're running it from SQL*Plus and want to save it to a local file. If running from PL/SQL you'll need to use UTL_FILE and write to a directory on the database server.

Answer 3

Using the Oracle XE database as source data I'm able to export the employees table as XML as follows...
SELECT SYS_XMLAGG(
SYS_XMLGEN(
XMLFOREST(employee_id, first_name, last_name, email, phone, hire_date, manager_id, job_title)
)
) FROM employees;
The XML will look like...
<?xml version="1.0"?>
<ROWSET>
<ROW>
<EMPLOYEE_ID>107</EMPLOYEE_ID>
<FIRST_NAME>Summer</FIRST_NAME>
<LAST_NAME>Payne</LAST_NAME>
<EMAIL>summer.payne#example.com</EMAIL>
<PHONE>515.123.8181</PHONE>
<HIRE_DATE>2016-06-07</HIRE_DATE>
<MANAGER_ID>106</MANAGER_ID>
<JOB_TITLE>Public Accountant</JOB_TITLE>
</ROW>
<ROW>
<EMPLOYEE_ID>...
The CSV list of column names for XMLForest can be obtained thus...
SELECT LISTAGG(column_name, ',') FROM user_tab_columns WHERE table_name = 'EMPLOYEES';
Luck.