Any one help me to solve this i try my best but did not solve this? - sql

Question

ItemName Price CreatedDateTime
New Card 50.00 2014-05-26 19:17:09.987
Recharge 110.00 2014-05-26 19:17:12.427
Promo 90.00 2014-05-27 16:17:12.427
Membership 70.00 2014-05-27 16:17:12.427
New Card 50.00 2014-05-26 19:20:09.987
Out Put : Need a query which Sum the sale of Current hour and
sale of item which have maximum sale in that hour in breakdownofSale
Column.
Hour SaleAmount BreakDownOfSale
19 210 Recharge
16 160 Promo

Answer 1

This should do it
create table #t
(
ItemName varchar(50),
Price decimal(18,2),
CreatedDateTime datetime
);
set dateformat ymd;
insert into #t values('New Card', 50.00, '2014-05-26 19:17:09.987');
insert into #t values('Recharge', 110.00, '2014-05-26 19:17:12.427');
insert into #t values('Promo', 90.00, '2014-05-27 16:17:12.427');
insert into #t values('Membership', 70.00, '2014-05-27 16:17:12.427');
insert into #t values('New Card', 50.00, '2014-05-26 19:20:09.987');
with cte as
(
select datepart(hh, CreatedDateTime) as [Hour],
ItemName,
Price,
sum(Price) over (partition by datepart(hh, CreatedDateTime)) SaleAmount,
ROW_NUMBER() over (partition by datepart(hh, CreatedDateTime) order by Price desc) rn
from #t
)
select Hour,
SaleAmount,
ItemName
from cte
where rn = 1

Answer 2

Though i am not clear with the question, based on your desired output, you may use the query as below.
SELECT DATEPART(HOUR,CreatedDateTime) AS Hour, sum(Price) AS Price, ItemName AS BreakDownOfSale from TableName WHERE BY ItemName,DATEPART(HOUR,CreatedDateTime)
Replace table name and column name with the actual one.
Hope this helps!

Answer 3

Here is the sample query.
You can use SQL Server Windows functions to get the result you need.
DECLARE #Table TABLE
(
ItemName NVARCHAR(40),
Price DECIMAL(10,2),
CreatedDatetime DATETIME
)
-- Fill table.
INSERT INTO #Table
( ItemName, Price, CreatedDatetime )
VALUES
( N'New Card' , 50.00 , '2014-05-26 19:17:09.987' ),
( N'Recharge' , 110.00 , '2014-05-26 19:17:12.427' ) ,
( N'Promo' , 90.00 , '2014-05-27 16:17:12.427' ) ,
( N'Membership' , 70.00 , '2014-05-27 16:17:12.427' ) ,
( N'New Card' , 50.00 , '2014-05-26 19:20:09.987' )
-- Check record(s).
SELECT * FROM #Table
-- Get record(s) in required way.
;WITH T1 AS
(
SELECT
DATEPART(HOUR, T.CreatedDatetime) AS Hour,
CONVERT(DATE, T.CreatedDatetime) AS Date,
T.ItemName AS BreakDownOfSales,
-- Date and hour both will give unique record(s)
SUM(Price) OVER (PARTITION BY CONVERT(DATE, T.CreatedDatetime), DATEPART(HOUR, CreatedDateTime)) AS SaleAmount,
ROW_NUMBER() OVER(PARTITION BY CONVERT(DATE, T.CreatedDatetime), DATEPART(HOUR, T.CreatedDatetime) ORDER BY T.Price DESC) AS RN
FROM
#Table T
)
SELECT
T1.Date ,
T1.Hour ,
T1.SaleAmount,
T1.BreakDownOfSales
FROM
T1
WHERE T1. RN = 1
ORDER BY
T1.Hour

Answer 4

Check this simple solution, Please convert it to SQL Server Query.
This will give you perfect result even if you have multiple date data.
SELECT HOUR(CreatedDateTime), SUM(Price),
(SELECT itemname FROM t it WHERE HOUR(ot.CreatedDateTime) = HOUR(it.CreatedDateTime) AND
DATE(ot.CreatedDateTime) = DATE(it.CreatedDateTime)
GROUP BY itemname
ORDER BY price DESC
LIMIT 1
) g
FROM t ot
GROUP BY HOUR(CreatedDateTime);