I am trying to get from my table all invoices raised for those customers who spent more than 1000 over period of last 12 months. Below is my table just for two customers as example:
And my query:
SELECT
t.Customer, t.Invoice
FROM
(SELECT
CI.Customer, CI.Invoice, CI.Date,
SUM(CASE
WHEN CI.Date > DATEADD(month, -12, getdate())
THEN CI.Valuee
ELSE 0
END) as Net
FROM
CustomerInvoice CI
GROUP BY
CI.Customer, CISRV.Invoice, CISRV.Date) AS t
GROUP BY
t.Customer, t.Invoice
HAVING
SUM (t.Net) > 1000
As result I will get only invoice INV-341453 but I would like to show also invoices INV-346218 and INV-349065.
What I am doing wrong?
Use ANSI standard window functions:
select ci.*
from (select ci.*,
sum(ci.value) over (partition by ci.customer) as total_value
from CustomerInvoice CI
where CI.Date > DATEADD(month, -12, getdate())
) ci
where total_value > 1000;
By "all invoices", I assume you mean the ones in the past twelve months.
You could do this by using a grouped query to identify the customers who have gone over the 1000 threshold, and then display all invoices for those customers:
SELECT Customer, Invoice
FROM CustomerInvoice
WHERE Customer IN
(SELECT Customer
FROM CustomerInvoice
GROUP BY Customer
HAVING SUM(CASE WHEN CI.Date>DATEADD(month,-12,getdate()) THEN CI.Valuee ELSE 0 END) > 1000)
Related
I'm trying to group companies and their revenues by percentiles (>90% as Top, 50-90% as middle, < 50% as bottom, in googlesql.
Table format for revenue_table:
|company | product | revenue |
------------------------------
I'm trying out doing a cross join to split these companies up:
SELECT
company,
SUM(revenue) as revenue,
CASE
WHEN SUM(revenue) > Percentile90_Max THEN "Top"
WHEN SUM(revenue) >= Percentile50_Max THEN "Middle"
ELSE "Bottom"
END as percentile_section,
Percentile50_Max,
Percentile90_Max,
FROM revenue_table
CROSS JOIN
(SELECT
APPROX_QUANTILES(revenue,100)[offset(50)] As Percentile50_Max,
APPROX_QUANTILES(revenue,100)[offset(90)] As Percentile90_Max
FROM
(SELECT
company,
SUM(revenue) as revenue
FROM revenue_table
GROUP BY 1
)
)
GROUP BY 1,4,5
Order by 2 desc
The code above currently works, but gets broken once I change my main select statement to:
SELECT
company,
--SUM(revenue) as revenue,
CASE
WHEN SUM(revenue) > Percentile90_Max THEN "Top"
WHEN SUM(revenue) >= Percentile50_Max THEN "Middle"
ELSE "Bottom"
END as percentile_section,
--Percentile50_Max,
--Percentile90_Max,
... same code here
GROUP BY 1
Ideally my end result should just be Company + percentile_section.
How should I do this without doing another subquery? Or is subquery really the only way to go in terms of querying efficiency?
Thank you!
You should be able to calculate the quantiles as part of the aggregation, so no subquery should be necessary:
SELECT company, SUM(revenue) as revenue,
(CASE WHEN SUM(revenue) > (APPROX_QUANTILES(SUM(revenue), 100) OVER ())[offset(90)] THEN 'Top'
WHEN SUM(revenue) >= (APPROX_QUANTILES(SUM(revenue), 100) OVER ())[offset(50)] THEN 'Middle'
ELSE 'Bottom'
END) as percentile_section
FROM revenue_table
GROUP BY 1
Order by 2 desc
I have this table called table a
I need to get the CustomerID, sum(Income) of 2015, sum(Income) of 2016, did he ever bought productId A (boolean), is the total sum(income)> 1000 (boolean), number of total InvoiceID
all that in one query and the results should be with 1 row per customer.
please help I don't even know how to start!
This is basically conditional aggregation:
select customerid,
sum(case when extract(year from date) = 2015 then sales end) as sales_2015,
sum(case when extract(year from date) = 2016 then sales end) as sales_2016,
max( product = 'A' ) as ever_bought_a,
sum(income) > 1000 as sum_exceeds_1000,
count(*) as num_invoices
from t
group by customerid;
You haven't specified a database, so this is really psuedocode. You'll need to adapt it for your particular database.
I am writing two seperate SQL queries to get data for two different dates like so:
SELECT number, sum(sales) as sales, sum(discount) sa discount, sum(margin) as margin
FROM table_a
WHERE day = '2019-08-09'
GROUP BY number
SELECT number, sum(sales) as sales, sum(discount) sa discount, sum(margin) as margin
FROM table_a
WHERE day = '2018-08-10'
GROUP BY number
I tried fusing them like so to get the results for the same number in one row from two different dates:
SELECT number, sum(sales) as sales, sum(discount) sa discount, sum(margin) as margin, 0 as sales_n1, 0 as discount_n1, 0 as margin_n1
FROM table_a
WHERE day = '2019-08-09'
GROUP BY number
UNION
SELECT number, 0 as sales, 0 as discount, 0 as margin, sum(sales_n1) as sales_n1, sum(discount_n1) as discount_n1, sum(margin_n1) as margin_n1
FROM table_a
WHERE day = '2018-08-10'
GROUP BY number
But it didn't work as I get the rows for the first query with zeroes for the columns defined as zero followed by the columns of the second query in the same fashion.
How can I correct this to have the desired output ?
Use conditional aggregation:
SELECT number,
sum(case when day = '2019-08-09' then sales end) as sales_20190809,
sum(case when day = '2019-08-09' then discount end) sa discount, sum(margin) as margin_20190810,
sum(case when day = '2019-08-10' then sales end) as sales_20190809,
sum(case when day = '2019-08-10' then discount end) sa discount, sum(margin) as margin_20190810
FROM table_a
WHERE day IN ('2019-08-09', '2019-08-10')
GROUP BY number;
If you want the numbers in different rows (which you don't seem to), then use aggregation:
SELECT day, number, sum(sales) as sales, sum(discount) as discount, sum(margin) as margin
FROM table_a
WHERE day IN ('2019-08-09', '2019-08-10')
GROUP BY day, number
Looking to see if there is a way to compare the number of orders entered a day and by either a specific user (EDI) or anyone else.
I can return results for per day (but only the days where a value exists) but can't figure out a way to combine all three together (Total - by EDI - by everyone else).
Any assistance greatly appreciated.
select Date, count(Order_ID)
from orders
WHERE Date >=dateadd(day,datediff(day,0,GetDate())- 7,0) and [user] = 'EDI'
and customer = '9686'
GROUP BY Date, [user];
select Date, count(Order_ID)
from orders
WHERE Date >=dateadd(day,datediff(day,0,GetDate())- 7,0) and [user] <> 'EDI'
and customer = '9686'
GROUP BY Date, [user];
select Date, count(Order_ID)
from orders
WHERE Date >=dateadd(day,datediff(day,0,GetDate())- 7,0)
and customer = '9686'
GROUP BY Date, [user];
Use conditional aggregation:
select Date, sum(case when [user] = 'EDI' then 1 else 0 end) as cnt_edi,
sum(case when [user] <> 'EDI' then 1 else 0 end) as cnt_non_edi,
count(*) as total
from orders
where Date >= dateadd(day, datediff(day, 0, GetDate()) - 7, 0) and customer = '9686'
group by Date;
I have two tables in SQL Server.
I want to select DeptCode, DeptName, YearToDate, PeriodToDate (2 months for example) and group it by DeptCode.
There is a result which I want to get:
In YTD column I want to get sum of totalCost since 01/01/actualYear.
In PTD column I want to get the sum from last two months.
I created a piece of code which shows me correct YTD cost but I don't know how I can add next one for getting total cost for other date range. Is it possible to do this?
SELECT
d.DeptCode,
d.DeptName,
SUM(s.TotalCost) as YTD
FROM [Departments] AS d
INNER JOIN Shipments AS s
ON d.DeptCode= s.DeptCode
WHERE s.ShipmentDate BETWEEN DateAdd(yyyy, DateDiff(yyyy, 0, GetDate()), 0)
AND GETDATE()
GROUP BY d.DeptCode, d.DeptName
Your expected output doesn't match 2 months, but here's the code to accomplish what you want. You just have to add a SUM(CASE...) on the 2nd condition.
SELECT
d.DeptCode,
d.DeptName,
SUM(s.TotalCost) as YTD,
SUM(CASE WHEN s.ShipmentDate >= DATEADD(month, -2, GETDATE()) then s.TotalCost else 0 END) as PTD
FROM [Departments] AS d
INNER JOIN Shipments AS s
ON d.DeptCode= s.DeptCode
WHERE Year(s.ShipmentDate) = Year(GETDATE())
GROUP BY d.DeptCode, d.DeptName
Just add one more column that returns 0 when not in the two-month range, e.g. SUM(CASE WHEN (date check) THEN (amount) ELSE 0 END). Check out the fifth line:
SELECT
d.DeptCode,
d.DeptName,
SUM(s.TotalCost) as YTD,
SUM(CASE WHEN DateDiff(MONTH, s.ShipmentDate, GetDate()) < 2 THEN s.TotalCost ELSE 0 END) PTD,
FROM [Departments] AS d
INNER JOIN Shipments AS s
ON d.DeptCode= s.DeptCode
WHERE s.ShipmentDate BETWEEN DateAdd(yyyy, DateDiff(yyyy, 0, GetDate()), 0)
AND GETDATE()
GROUP BY d.DeptCode, d.DeptName
Try this one :
nbr_last2month_ AS
(
SELECT DISTINCT
Sum(s.[TotalCost]) AS 'PTD',
s.DeptCode,
s.DeptName
FROM [Shipements] s
LEFT JOIN [Departements] d ON d.[DeptCode] = s.[DeptCode]
WHERE Year(date_) LIKE Year(GETDATE())
AND MONTH(ShipementDate) LIKE Month(Getdate()) - 2
Group by DeptCode
),
nbr_YTD_ AS
(
SELECT DISTINCT
Sum(s.[TotalCost]) AS 'YTD',
s.DeptCode,
s.DeptName
FROM [Shipements] s
LEFT JOIN [Departements] d ON d.[DeptCode] = s.[DeptCode]
WHERE Year(ShipementDate) LIKE Year(GETDATE())
Group by DeptCode
),
SELECT
A.DeptCode,
A.DeptName,
YTD,
PTD
FROM nbr_YTD_ A
LEFT JOIN nbr_last2month_ B on B.DeptCode = A.DeptCode
ORDER BY DeptCode