Rename tag and remove attribute - xslt-1.0

Question

I have an XML document (generated by WiX heat) where I want to remove the root element name while removing the attribute. The source tree looks like this
<Wix xmlns="http://schemas.microsoft.com/wix/2006/wi">
<Fragment>
<DirectoryRef Id="HELP" />
</Fragment>
</Wix>
I figured out how to rename the node, but this doesn't remove the unnecessary attribute xmlns.
<xsl:template match='/wix:Wix'>
<Include>
<xsl:copy-of select="#*|node()"/>
</Include>
</xsl:template>
<!-- Even this template doesn't suppress the attribute xmlns -->
<xsl:template match='#xmlns'/>
I event removed the #*| from the select clause. But this doesn't have any effect.
How can I produce with XSLT 1.0 the following desired output?
<Include>
<Fragment>
<DirectoryRef Id="HELP" />
</Fragment>
</Include>

Answer 1

this doesn't remove the unnecessary attribute xmlns.
xmlnsis not an attribute - it's a namespace, a part of the node's name. If you don't want it in the output, you cannot copy the input nodes that are in a namespace - you must create new nodes instead, for example:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:wix="http://schemas.microsoft.com/wix/2006/wi"
exclude-result-prefixes="wix">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/wix:Wix">
<Include>
<xsl:apply-templates/>
</Include>
</xsl:template>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>