I have two tables in Access, Table A and Table B:
Table MasterLockInsNew:
+----+-------+----------+
| ID | Value | Date |
+----+-------+----------+
| 1 | 123 | 12/02/13 |
| 2 | 1231 | 11/02/13 |
| 4 | 1265 | 16/02/13 |
+----+-------+----------+
Table InitialPolData:
+----+-------+----------+---+
| ID | Value | Date |Type
+----+-------+----------+---+
| 1 | 123 | 12/02/13 | x |
| 2 | 1231 | 11/02/13 | x |
| 3 | 1238 | 10/02/13 | y |
| 4 | 1265 | 16/02/13 | a |
| 7 | 7649 | 18/02/13 | z |
+----+-------+----------+---+
All I want are the rows from table B for IDs not contained in A. My current code looks like this:
SELECT Distinct InitialPolData.*
FROM InitialPolData
WHERE InitialPolData.ID NOT IN (SELECT Distinct InitialPolData.ID
from InitialPolData INNER JOIN
MasterLockInsNew
ON InitialPolData.ID=MasterLockInsNew.ID);
But whenever I run this in Access it crashes!! The tables are fairly large but I don't think this is the reason.
Can anyone help?
Thanks
or try a left outer join:
SELECT b.*
FROM InitialPolData b left outer join
MasterLockInsNew a on
b.id = a.id
where
a.id is null
Simple subquery will do.
select * from InitialPolData
where id not in (
select id from MasterLockInsNew
);
Try using NOT EXISTS:
SELECT Distinct i.*
FROM InitialPolData AS i
WHERE NOT EXISTS (SELECT 1
FROM MasterLockInsNew AS m
WHERE m.ID = i.ID)
Related
Say I have a table like this:
+----+-------+
| id | value |
+----+-------+
| 1 | a |
| 1 | b |
| 2 | c |
| 2 | d |
| 3 | e |
| 3 | f |
+----+-------+
And I want to select all rows with id that are not a, and change their id to a; select all rows with id that are not b, and change the id to b; and select all rows with id that are not c, and change their id to c.
Here is the output I want:
+----+-------+
| id | value |
+----+-------+
| 1 | c |
| 1 | d |
| 1 | e |
| 1 | f |
| 2 | a |
| 2 | b |
| 2 | e |
| 2 | f |
| 3 | a |
| 3 | b |
| 3 | c |
| 3 | d |
+----+-------+
The only solution I can think of is through cross join and distinct:
select distinct a.id, b.value
from table a
cross join table b
where a.id != b.id
Is there any other way to avoid such expensive operation?
I think the typical way to write this is to generate all pairs of id and value and then remove the ones that exist:
select i.id, v.value
from (select distinct id from t) i cross join
(select distinct value from t) v left join
t
on t.id = i.id and t.value = i.value
where t.id is null;
First, I don't think this is what your query does. But this is what you seem to be describing.
From a performance perspective, you might have other sources for i and v that don't require subqueries. If so, use those for performance.
Finally, I don't think you can do much to improve the performance of this, apart from using explicit tables -- and perhaps having appropriate indexes on all the tables.
I'm getting this message while using this query, is there anything wrong?
SELECT t.tanggal_transaksi, o.nama_lengkap, SUM(td.harga * td.qty) total
FROM transaksi t, transaksi_detail td, operator o
WHERE td.transaksi_id = t.transaksi_id AND o.operator_id = t.operator_id
GROUP BY t.transaksi_id
Updated :
After using the answer from #Barbaros Özhan using this query :
SELECT t.tanggal_transaksi, o.nama_lengkap, SUM(td.harga * td.qty) total
FROM transaksi t
INNER JOIN transaksi_detail td ON ( td.transaksi_id = t.transaksi_id )
INNER JOIN operator o ON ( o.operator_id = t.operator_id )
GROUP BY t.tanggal_transaksi, o.nama_lengkap;
the data is successfully displayed. but, there are few problems that occur, the value of the same operator_id cannot appear more than 1 time. Here is the sample data :
+--------------+-------------+-------------------+
| TRANSAKSI_ID | OPERATOR_ID | TANGGAL_TRANSAKSI |
+--------------+-------------+-------------------+
| 1 | 5 | 09/29/2018 |
| 2 | 3 | 09/29/2018 |
| 3 | 3 | 09/29/2018 |
| 4 | 1 | 09/29/2018 |
| 5 | 1 | 09/29/2018 |
+--------------+-------------+-------------------+
After use the query command, the output is :
+-------------------+------------------+--------+
| TANGGAL_TRANSAKSI | NAMA_LENGKAP | TOTAL |
+-------------------+------------------+--------+
| 09/29/2018 | Lina Harun | 419800 |
| 09/29/2018 | Titro Kusumo | 484000 |
| 09/29/2018 | Muhammad Kusnadi | 402000 |
+-------------------+------------------+--------+
When viewed from the operator table, there are 2 data with the same operator_id that is unreadable
+-------------+------------------+
| OPERATOR_ID | NAMA_LENGKAP |
+-------------+------------------+
| 1 | Muhammad Kusnadi |
| 3 | Lina Harun |
| 5 | Tirto Kusumo |
+-------------+------------------+
You need to include the columns in the SELECT-list t.tanggal_transaksi, o.nama_lengkap, also in the GROUP BY-list but not the others like t.transaksi_id. So, you might use the following without any issue :
SELECT t.tanggal_transaksi, o.nama_lengkap, SUM(td.harga * td.qty) total
FROM transaksi t
INNER JOIN transaksi_detail td ON ( td.transaksi_id = t.transaksi_id )
INNER JOIN operator o ON ( o.operator_id = t.operator_id )
GROUP BY t.tanggal_transaksi, o.nama_lengkap;
Or this one :
SELECT t.transaksi_id, SUM(td.harga * td.qty) total
FROM transaksi t
INNER JOIN transaksi_detail td ON ( td.transaksi_id = t.transaksi_id )
GROUP BY t.transaksi_id;
P.S. Prefer using ANSI-92 JOIN standard rather than old-style comma-type JOIN.
I have a question about JOIN.
TABLE A | TABLE B |
-----------------------------------------|
PK | div | PK | div | val |
-----------------------------------------|
A | a | 1 | a | 10 |
B | b | 2 | a | 100 |
C | c | 3 | c | 9 |
------------------| 4 | c | 99 |
-----------------------
There are two tables something like above, and I have been trying to join two tables but I want to see all rows from TABLE A.
Something like
SELECT T1.PK, T1.div, T2.val
FROM A T1
LEFT OUTER JOIN B T2
ON T1.div = T2.div
and I want the result would look like this below.
PK | div | val |
-------------------------
A | a | 10 |
A | a | 100 |
B | null | null |
C | c | 9 |
C | c | 99 |
I have tried all JOINs I know but B doesn't appear because it doesn't exist. Is it possible to show all rows on TABLE A and just show null if it doesn't exists on TABLE B?
Thanks in advance!
If you change your query to
SELECT T1.PK, T2.div, T2.val
FROM A T1
LEFT OUTER JOIN B T2
ON T1.div = T2.div
(Note, that div comes from T2 here.), you'll get exactly the result posted (but maybe in a different order, add an ORDER BY clause if you want a specific order).
Your query as it stands will get you:
PK | div | val |
-------------------------
A | a | 10 |
A | a | 100 |
B | b | null |
C | c | 9 |
C | c | 99 |
(Note, that div is b for the row with the PK of B, not null.)
To get to your resultset, all you need to do is use T2.Div as that is the value that does not exist in the second table:
SELECT T1.PK, T2.div, T2.val
FROM A T1
LEFT OUTER JOIN B T2
ON T1.div = T2.div
SQL newb here.
I am having troubles to create a select statement.
I have one table REF with an id and a value v;
+-----+----+
| REF | |
+-----+----+
| ID | V |
| 1 | 10 |
| 2 | 20 |
| 3 | 30 |
| 4 | 40 |
| 5 | 50 |
| 6 | 60 |
| 7 | 70 |
+-----+----+
in a second table IND i have three columns with id-values;
+-----+-----+-----+
|IND | | |
|-----|-----|-----|
| ID1 | ID2 | ID3 |
| 1 | 2 | |
| | 3 | 4 |
| 5 | | |
| 6 | | 7 |
I want to receive the value of REF.v accordinlgly in each of the three columns (Table RES); the ids are distinct, there is no overlapping in between.
+-----+-----+-----+
| RES | | |
+-----+-----+-----+
| ID1 | ID2 | ID3 |
| 10 | 20 | |
| | 30 | 40 |
| 50 | | |
| 60 | | 70 |
+-----+-----+-----+
You can query your IND table, using three subqueries to retrieve the value linked to used id
Try this:
SELECT
(SELECT V FROM REF WHERE REF.ID = IND.ID1) AS V_ID1,
(SELECT V FROM REF WHERE REF.ID = IND.ID2) AS V_ID2,
(SELECT V FROM REF WHERE REF.ID = IND.ID3) AS V_ID3
FROM IND
UPDATE
About two proposed solutions (LEFT OUTER JOINs Vs SUBQUERIES)
I've tried on Sql Fiddle under Postgres 9.6 engine.
Times are the same but execution plan about LEFT OUTER JOIN is more complex
You can see SqlFiddle SUBQUERIES and SqlFiddle LEFT OUTER JOINs
SELECT ref1.V AS RefV1, ref2.V AS RefV2, ref3.V AS RefV3
FROM IND i
LEFT OUTER JOIN ref ref1
ON ref1.ID = i.ID1
LEFT OUTER JOIN ref ref2
ON ref2.ID = i.ID2
LEFT OUTER JOIN ref ref3
ON ref3.ID = i.ID3
You connect the reference table three times, using a left outer join, which lets the reference table not match the IND table, resulting in nulls where you had missing IDs. Then you select the v value from each of these joined tables, being sure to alias it, so you can tell them apart.
I have two tables, post_categories and posts. I'm trying to select * from post_categories;, but also return a temporary column with the count for each time a post category is used on a post.
Posts
| id | name | post_category_id |
| 1 | test | 1 |
| 2 | nest | 1 |
| 3 | vest | 2 |
| 4 | zest | 3 |
Post Categories
| id | name |
| 1 | cat_1 |
| 2 | cat_2 |
| 3 | cat_3 |
Basically, I'm trying to do this without subqueries and with joins instead. Something like this, but in real psql.
select * from post_categories some-type-of-join posts, count(*)
Resulting in this, ideally.
| id | name | count |
| 1 | cat_1 | 2 |
| 2 | cat_2 | 1 |
| 3 | cat_3 | 1 |
Your help is greatly appreciated :D
You can use a derived table that contains the counts per post_category_id and left join it to the post_categories table
select p.*, coalesce(t1.p_count,0)
from post_categories p
left join (
select post_category_id, count(*) p_count
from posts
group by post_category_id
) t1 on t1.post_category_id = p.id
select post_categories.id, post_categories.name , count(posts.id)
from post_categories
inner join posts
on post_category_id = post_categories.id
group by post_categories.id, post_categories.name