In Firebug I have a link with this content:
<a id="fwMainContentForm:j_idt156:2:selectRole" class="cb_or_somename cb_area_0219" onclick="jsf.util.chain(this,event,'$(this).attr(\'disabled\', \'disabled\');return true;','mojarra.jsfcljs(document.getElementById(\'fwMainContentForm\'),{\'fwMainContentForm:j_idt156:2:selectRole\':\'fwMainContentForm:j_idt156:2:selectRole\'},\'\')');return false" href="#">Somename</a>
How can I use a "classname" to access the link (clicking on it)?
I have tried the following:
WebElement rolle = driver.findElement(By.className("cb_or_somename cb_area_0219"));
But I get the error:
Exception in thread "main"
org.openqa.selenium.InvalidSelectorException: The given selector cb_or_somename cb_area_0219 is either invalid or does not result in a WebElement.
The following error occurred:
InvalidSelectorError: Compound class names not permitted
cb_or_somename cb_area_0219 is actually two classes. By.className can receive one of them
WebElement rolle = driver.findElement(By.className("cb_or_somename"));
// or
WebElement rolle = driver.findElement(By.className("cb_area_0219"));
If you want to locate the element with both of them use cssSelector
WebElement rolle = driver.findElement(By.cssSelector(".cb_or_somename.cb_area_0219"));
To find element using both classes you can use the xpath instead of className.
WebElement rolle = driver.findElement(By.xpath("//*[contains(#class,'cb_or_somename cb_area_0219')]"));
Related
WebElement SearchField =
driver.findElement(By.xpath("/html/body/div[2]/div[3]/form/div[1]/div[1]/div[1]/div/div[2]/input"));
SearchField.sendKeys("my name");
Thread.sleep(5000);
WebElement SearchButton =
driver.findElement(By.xpath("/html/body/div[2]/div[3]/form/div[1]/div[1]/div[3]/center/input[1]"));
SearchButton.submit();
Thread.sleep(3000);
driver.quit();
In above code I have tried to select the search box in google.com and enter "my name" as the value.
but it says xpath element not found.
So I took the "name" instead of xpath element and it worked.
WebElement SearchField = driver.findElement(By.name("q"));
How can I run this using xpath?
Why you want to switch to xpath if name works fine ?
There are lot of advantage if you use ID, NAME, LINKTEXT, PARTIALLINKTEXT, CSSSELECTOR, CLASSNAME and lastly XPATH :
Anyway you can try this xpath :
//input[#name='q']
this is a relative xpath. The one you are using is absolute xpath. try to avoid that.
The unique XPath for the search input element you are looking is:
//input[#name='q' and #type='text']
<a href="/lightning/n/******__Country" title="Country" tabindex="0" draggable="false" aria-describedby="operationId-17" class="slds-context-bar__label-action dndItem">
<span class="slds-truncate">Country</span></a>
I got the xpath as
WebElement tabName = driver.findElement(By.xpath("//a[contains(#href,'Country')]"));
I need to click the Country link
I have tried the following options but none work
1) driver.findElement(By.xpath("//a[contains(#href,'Country') and #title='Country']")).click();
2) Actions actions = new Actions((WebDriver) driver.getWebDriver());
actions.moveToElement(tabName).click().perform();
3) ((JavascriptExecutor) driver).executeScript("arguments[0].click();", tabName);
waitForSeconds(5);
I am getting invocation of target exception
org.openqa.selenium.WebDriverException: javascript error: Cannot read
property 'defaultView' of undefined
Can any one please tell me how to click the href link?
Try click on its parent/ancestor instead. For example, if you had
//a[text()='link of your text']
and you get the javascript error, try:
//a[text()='link of your text']/parent::*
Try the following code - it works against Salesforce Lightning UI screens:
WebElement element = driver.findElement(By.xpath("your xpath"));
JavascriptExecutor executor = (JavascriptExecutor)driver;
executor.executeScript("arguments[0].click();", element);
Sharing it after testing it and found to be working.
To click on the following link use WebDriverWait and elementToBeClickable and then click on the link using the following xpath.
WebDriverWait wait = new WebDriverWait(driver, 15);
wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//a[#title='Country']/span[#class='slds-truncate'][contains(.,'Country')]"))).click();
For those trying out in python, here is how you do it:
>>> button_link = driver.find_element_by_xpath('''//*[#id="tab-23"]/slot''')
>>> driver.execute_script("arguments[0].click();", button_link )
Try JavaScript. It worked for me
WebElement element = driver.findElement(By.xpath("strPath"));
((JavascriptExecutor) driver).executeScript("arguments[0].click();", element);
Using firefox and marking a link in my web-app I get among other things, this code which I think I can use to caprture an object:
cb_or_somename_someothername cb_area_0219
This string is "classname" in Firebug.
Going to the script I type in:
WebElement rolle = driver.findElement(By.className("cb_or_somename_someothername cb_area_0219"));
But the script does not find the element when executing.
Other onfo in the Firebug panel is:
class="cb_or_somename_someothername cb_area_0219"
onclick="jsf.util.chain(this,event,'$(this).attr(\'disabled\', \'disabled\');return true;','mojarra.jsfcljs(document.getElementById(\'fwMainContentForm\'),{\'fwMainContentForm:j_idt156:2:selectRole \':\'fwMainContentForm:j_idt156:2:selectRole\'},\'\')');return false"
href="#"
id="fwMainContentForm:j_idt156:2:selectRole"
Is my script referring the element in a wrong way?
You cannot use search by compound class name (name with spaces). Try to use search by CSS selector instead:
WebElement rolle = driver.findElement(By.cssSelector(".cb_or_somename_someothername.cb_area_0219"));
or by XPath:
WebElement rolle = driver.findElement(By.xpath("//*[#class='cb_or_somename_someothername cb_area_0219']"));
Also you still can use search by one of two class names:
WebElement rolle = driver.findElement(By.className("cb_or_somename_someothername"));
or
WebElement rolle = driver.findElement(By.className("cb_area_0219")); // Note that this class name could be generated dynamically, so each time it could has different decimal part
Update
If you get Element is not clickable... exception it seem that your element is covered by another element at the moment you try to click on it. So try to wait until this "cover" is no more visible:
new WebDriverWait(driver, 10).until(ExpectedConditions.invisibilityOfElementLocated(By.xpath("//p[#class='environtment-banner']"));
WebElement rolle = driver.findElement(By.className("cb_area_0219"));
rolle.click();
I have followig HTML code and want X path for the text "Analytics & Research"
<div id="LLCompositePageContainer" class="column-wrapper">
<div id="compositePageTitleDiv">
<h1 class="page-header">Analytics & Research</h1>
</div>
I am getting following xpath using chrome, but that didnt work.
//*[#id="compositePageTitleDiv"]
this is my code
WebElement header = driver.findElement(By.xpath("//div[#id='LLCompositePageContainer']/div[#id='compositePageTitleDiv']/h1[#class='page-header']"));
String header2 = header.getText();
System.out.println(header2);
and following error I am getting
Exception in thread "main" org.openqa.selenium.NoSuchElementException:
Unable to find element with xpath ==
//div[#id='LLCompositePageContainer']/div[#id='compositePageTitleDiv']/h1[#class='page-header']
(WARNING: The server did not provide any stacktrace information)
Command duration or timeout: 10.34 seconds For documentation on this
error, please visit:
http://seleniumhq.org/exceptions/no_such_element.html
Please try to use the below xpath:
driver.findElement(By.xpath(".//div[#id='compositePageTitleDiv']/h1")).getText();
If the element is inside the iframe. Then use the below code:
// Switching to the frame
driver.switchTo().frame(<name>);
// Storing the value of the Analytics & Research
String text = driver.findElement(By.xpath(".//div[#id='compositePageTitleDiv']/h1")).getText();
// Switching back to original window
driver.switchTo().defaultContent();
Hope this helps.
This is how it can be used :
WebElement element= driver.findElement(By.xpath("//*[#id='compositePageTitleDiv']"));
Or in case it is nested, can be accessed like this as well
WebElement element = driver.findElement(By.xpath("//html/body/div[3]/div[3]/"));
this is just a rough syntax.
No need to use Xpath here if you could simply locate the element using By.id(). Asuming are using Java, you should try as below :-
WebElement el = drive.findElement(By.id("compositePageTitleDiv"));
String text = el.getText();
Edited :- If element not found, may it is timing issues you need to implement WebDriverWait to wait for element until visible on the page as below :-
WebDriverWait wait = new WebDriverWait(webDriver, implicitWait);
WebElement el = wait.until(ExpectedConditions.visibilityOfElementLocated(By.id("compositePageTitleDiv")));
String text = el.getText();
Note :- if your element is inside any frame, you need to switch that frame before finding element as :- driver.switchTo().frame("your frame name or id");
Hope it helps..:)
You can also use
//div[#id='LLCompositePageContainer']/div[#id='compositePageTitleDiv']/
h1[contains(text(),'Analytics')]
This is the best way to reach to the specific web element, using contains minimize the chances of error.
The correct xpath is
//div[#id='LLCompositePageContainer']
/div[#id='compositePageTitleDiv']
/h1[#class='page-header']
But you could have find your answer easily with some researchs on google...
I have span tag which looks like a button on html tag
<span class="middle">Next</span>
I tried using
xpath=driver.findElement(By.xpath(".//*[#id='modal-actions-panel']/div[2]/a/span/span/span")); // by considering fixed id as reference
Using absolute
xpath=driver.findElement(By.xpath("html/body/div[4]/div[2]/a/span/span/span")); // took this from firebug
and Using
driver.findElement(By.cssSelector("span[class='middle']"));
No success!! It is throwing below exception :
Exception in thread "main" org.openqa.selenium.NoSuchElementException: Unable to locate element: {"method":"xpath","selector":"//span[contains(., \"Next\")]"}
Command duration or timeout: 30.12 seconds
For documentation on this error, please visit: http://seleniumhq.org/exceptions/no_such_element.html
For all the ways I tried it is showing the same exception with change in selector details. Can someone please help me out in finding solution so that I can find Next button that is in span tag and click it.
Next button is in iFrame: Below is the part of html covering required span tag.
Next
I also tried with :
driver.switchTo().frame("iframe-applicationname_ModalDialog_0");
WebElement el = driver.findElement(By.cssSelector("span.middle"));
But throwing below error :
Caused by: org.openqa.selenium.ElementNotVisibleException: Element is not currently visible and so may not be interacted with
Kindly let me know if needed something that I'm missing..
I think this element is inside a frame or iframe, if it is then you need to switch that frame or iframe before finding element as below :-
driver.switchTo().frame("iframe-applicationname_ModalDialog_0");
WebElement el = driver.findElement(By.cssSelector("span.middle"));
el.click();
//Now after all your stuff done inside frame need to switch to default content
driver.switchTo().defaultContent();
Edited1 :- If you are getting exception as element is not currently visible need to implement WebDriverWait to wait until element visible as below :-
WebDriverWait wait = new WebDriverWait(driver, 10);
//Find frame or iframe and switch
wait.until(ExpectedConditions.frameToBeAvailableAndSwitchToIt("iframe-applicationname_ModalDialog_0"));
//Now find the element
WebElement el = wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath(".//span[#class = 'middle' and contains(text(), 'Next')]")));
el.click();
//Once all your stuff done with this frame need to switch back to default
driver.switchTo().defaultContent();
Edited2 :- If unfortunately it's not getting visible try to click on it using JavascriptExecutor as below :-
WebDriverWait wait = new WebDriverWait(driver, 10);
//Find frame or iframe and switch
wait.until(ExpectedConditions.frameToBeAvailableAndSwitchToIt("iframe-applicationname_ModalDialog_0"));
//Now find the element
WebElement el = wait.until(ExpectedConditions.presenceOfElementLocated(By.xpath(".//span[#class = 'middle' and contains(text(), 'Next')]")));
//Now click using JavascriptExecutor
((JavascriptExecutor)driver).executeScript("arguments[0].click()" el);
//Once all your stuff done with this frame need to switch back to default
driver.switchTo().defaultContent();
Try this....
driver.findElement(By.xpath("//span[contains(#class,'middle') and contains(text(), 'Next')]"))
I tried it and it worked for me:
WebElement actionBtn=driver2.findElement(
By.xpath("//span[contains(#class,'v-menubar-menuitem-caption')
and contains(text(), 'Actions')]")
);
actionBtn.click();
Try this
new WebDriverWait(driver, 30).until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//span[contains(#class,'middle') and contains(text(), 'Next')]"))).click();