In MSSQL we can convert the date format into the format we wanted.
for example :
convert(char(10),column_name , 120)
in vertica database can we do the same?
SELECT CONVERT(CHAR(10),CURRENT_TIMESTAMP,120)
Maybe something like this?
select current_timestamp::varchar ;
Or this?
select left(current_timestamp::varchar, 10) ;
A look to the Data Type Coercion section and the Data Type Coercion Chart in the standard documentation would probably help...
As opposed to MS SQL, Vertica has the three classic ANSI data types to store the element of time:
DATE, which is exactly at day precision; default format usually YYYY-MM-DD.
TIME, which is usually formatted as HH24:MI:SS, plus optionally up to 6 digits for the fraction of the second
TIMESTAMP and TIMESTAMPZ for the whole timestamp; TIMESTAMPZ includes the time zone, the other not. And the default format for the TIMESTAMP is YYYY-MM-DD HH24:MI:SS.US, for example: 2017-01-29 07:45:44.896498.
Any of these input types can be formatted as you like using the same function that comes from Oracle: TO_CHAR.
MSSQL's not so self explanatory format code 120, corresponds to this format string: YYYY-MM-DD HH24:MI:SS.
And this is how you use it; I'm usig CURRENT_TIME, CURRENT_DATE and CURRENT_TIMESTAMP as input, to show what it makes out of it:
SELECT
TO_CHAR(CURRENT_TIME ,'YYYY-MM-DD HH24:MI:SS') AS from_tm
, TO_CHAR(CURRENT_DATE ,'YYYY-MM-DD HH24:MI:SS') AS from_dt
, TO_CHAR(CURRENT_TIMESTAMP,'YYYY-MM-DD HH24:MI:SS') AS from_ts
;
from_tm | from_dt | from_ts
---------------------+---------------------+---------------------
2017-01-29 07:54:05 | 2017-01-29 00:00:00 | 2017-01-29 07:54:05
The nice thing here is that this TO_CHAR() function is very common in many databases, and other SQL coders will easily understand what's happening in this bit of code.
Happy Playing
Marco the Sane
Also you can get this like this :
select getdate()::date;
There are many ways to convert date types , see documentation bellow for more details
Vertica Date Transformation
Related
My date column "timestamp" is currently listed as:
2020-11-16 20:27:38.033 +0000
It's formatted as timestamptz and I've tried every search on here and google to find a method to only pull the date part (in this example 2020-11-16) from the column so I can effectively start grouping data by Date.
Any help would be greatly appreciated.
Assuming (as you haven't stated) that the column is a string. This shows how to convert:
postgres=# SELECT ('2020-11-16 20:27:38.033 +0000'::timestamp)::date;
date
------------
2020-11-16
If it were already a timestamp, then just the ::date cast would work.
You can use ::DATE casting or use TO_CHAR() conversion if the aim is just to display in that format
such as
SELECT your_ts_column::DATE AS val_as_date,
TO_CHAR(your_ts_column, 'YYYY-MM-DD') AS val_as_str
FROM your_table
Demo
I have following 2015-06-17T00:00:00.000+05:00 string.
I want to convert this string to Date using oracle sql.
I tried lot of format mask but none works for me :
SELECT TO_DATE('2015-06-17T00:00:00.000+05:00','yyyy-mm-dd HH24:MI:SS TZR') FROM DUAL;
Any idea which format mask should i apply for above conversion.
Also please note that i only need date information i.e (mm-dd-yyyy). So its also ok if the conversion results in date information only (i.e skipping time information)
This should work:
SELECT TO_DATE(SUBSTR('2015-06-17T00:00:00.000+05:00',1,10),'yyyy-mm-dd') from dual
If you need to keep track of the time zone you should probably look at something like this:
SELECT CAST(TO_TIMESTAMP_TZ('2015-06-17T00:00:00.000+05:00','yyyy-mm-dd"T"HH24:MI:SS.FFTZH:TZM') AT TIME ZONE 'UTC' AS DATE) FROM DUAL;
I am getting invalid number error message while executing the below select statement.Can any one have an idea about the issue..Please let me know.
select TO_DATE(TO_CHAR('2015/01/22 00:00:00','YYYY/MM/DD'),'YYYY/MM/DD')
actually i want oracle standard date format without time stamp for this date '2015/01/22 00:00:00'
select to_date('2015/01/22 00:00:00','YYYY/MM/DD HH24:MI:SS') as dt
from dual
Fiddle - http://sqlfiddle.com/#!4/6a3a6/1/0
As an FYI, the Oracle DATE data type does include the time component (just not down to fractional seconds, as is the case with the TIMESTAMP data type).
If you are converting values and want to bring all the time values to zero you can use the trunc function like this (which changes 12:07:00 to 00:00:00):
select trunc(to_date('2015/01/22 12:07:00','YYYY/MM/DD HH24:MI:SS'),'DD') as dt_with_time_zerod
from dual
Fiddle - http://sqlfiddle.com/#!4/6a3a6/2/0
If the source is itself a date and you want to convert the date to a string in the Oracle default date format ('DD-MON-RR') you can achieve that by running:
select to_char(trunc(to_date('2015/01/22 12:07:00','YYYY/MM/DD HH24:MI:SS'),'DD'),'DD-MON-RR') as dt_with_time_zerod
from dual
Fiddle - http://sqlfiddle.com/#!4/6a3a6/3/0
If it's a date field, to_char without a mask will give you what you say you want.
actually i want oracle standard date format without time stamp for this date '2015/01/22 00:00:00'
I'm not sure what you mean by "Oracle standard date format." The format in which a date would appear would be based on your NLS settings (in particular, NLS_DATE_FORMAT). If you are just trying to format this string representing a date, then you might want something like the following:
SELECT TO_CHAR(TO_DATE('2015/01/22 00:00:00','YYYY/MM/DD HH:MI:SS'), 'YYYY/MM/DD')
FROM dual;
That is, you have the TO_CHAR() and TO_DATE() functions in the wrong order, and an incomplete date mask for the call to TO_DATE().
Try using date literals with the standard ISO 8601 format.
date '2015-01-22'
I suggest you not to give hour-minute-second if you do not want to show the time.
This is my simplest answer :
SELECT TO_DATE('2015/01/22','YYYY/MM/DD') FROM dual
I am new to Oracle, and I need to save date and time in an Oracle database.
I am using time stamp as datatype for row. But now my problem is it saves date and time in 12 hours format like this 17/11/2011 10:10:10 PM.
But I need it in 24 hours format like 17/11/2011 22:10:10. I didn't understand the results that Google search result provided. Can any one please help me by posting some code.
Oracle always stores timestamps (and dates) in a packed binary format that is not human readable. Formatting is done only when a timestamp (or a date) is converted to a string.
You can control the formatting of your output by coding an explicit to_char. For example
SELECT to_char( your_timestamp_column, 'DD/MM/YYYY HH24:MI:SS' )
FROM your_table
Oracle stores timestamps in an internal format (with a default representation).
You can customize this representation on output like with the to_char() function.
For input (into the database) you can use to_date().
I have a field which its format is date with time as: YYYY-MM-DD HH-MM-SS for example: 2000-08-12 00:00:00 I want to get just the date part and change its format to DD/MMM/YYYY for example the expected result of the previous example will be: 12/Aug/2000
The field definition is: Ddate timestamp without time zone DEFAULT now()
I read the whole page of Date/Time Functions and Operators and other sources as well but I couldn't find any information that is helpful.
You can use the to_char function to format your column:
SELECT TO_CHAR(ddatte, 'dd/Mon/yyyy') FROM mytable
try with:
to_char(your_Field, 'dd/mm/yyyy')