I'm calculating historical amount from a table in years(ex. 2015-2016, 2014-2015, etc.) I would like to seek expertise if its more efficient to do it in one batch or repeat the query multiple times filtered by the date required.
Thanks in advance!
OPTION 1:
select
id,
sum(case when year(getdate()) - year(txndate) between 5 and 6 then amt else 0 end) as amt_6_5,
...
sum(case when year(getdate()) - year(txndate) between 0 and 1 then amt else 0 end) as amt_1_0,
from
mytable
group by
id
OPTION 2:
select
id, sum(amt) as amt_6_5
from
mytable
group by
id
where
year(getdate()) - year(txndate) between 5 and 6
...
select
id, sum(amt) as amt_1_0
from
mytable
group by
id
where
year(getdate()) - year(txndate) between 0 and 1
1.
Unless you have resources issues I would go with the CASE version.
Although it has no impact on the results, filtering on the requested period in the WHERE clause might have a significant performance advantage.
2. Your period definition creates overlapping.
select id
,sum(case when year(getdate()) - year(txndate) = 6 then amt else 0 end) as amt_6
-- ...
,sum(case when year(getdate()) - year(txndate) = 0 then amt else 0 end) as amt_0
where txndate >= dateadd(year, datediff(year,0, getDate())-6, 0)
from mytable
group by id
This may be help you,
WITH CTE
AS
(
SELECT id,
(CASE WHEN year(getdate()) - year(txndate) BETWEEN 5 AND 6 THEN 'year_5-6'
WHEN year(getdate()) - year(txndate) BETWEEN 4 AND 5 THEN 'year_4-5'
...
END) AS my_year,
amt
FROM mytable
)
SELECT id,my_year,sum(amt)
FROM CTE
GROUP BY id,my_year
Here, inside the CTE, just assigned a proper year_tag for each records (based on your conditions), after that select a summary for the CTE grouped by that year_tag.
Related
I am struggling to work out combining a query that should give me 3 columns of Month, total_sold_products and drinks_sold_products
Query 1:
Select month(date), count(id) as total_sold_products
from Products
where date between '2022-01-01' and '2022-12-31'
Query 2
Select month(date), count(id) as drinks_sold_products
from Products where type = 'drinks' and date between '2022-01-01' and '2022-12-31'
I tried the union function but it summed count(id) twice and gave me only 2 columns
Many thanks!
Union is for attaching sets of data on top of each other. You need conditional aggregation or a join. See below.
SELECT MONTH(date),
COUNT(*) AS total_sold_products,
COUNT(CASE WHEN type = 'drinks' THEN 1 ELSE 0 END) AS drinks_sold_products,
FORMAT((CASE
WHEN COUNT(*) > 0 THEN
COUNT(CASE WHEN type = 'drinks' THEN 1 ELSE 0 END)/COUNT(*)
ELSE 0 END),
'P') AS Percentage
FROM Products
WHERE date BETWEEN'2022-01-01' AND '2022-12-31'
GROUP BY MONTH(date)
I want to get the highest value in my query
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'
The Output would be TotalMonday ='1' and TotalTuesday ='2'
I need to get the highest value from the outputs which in this case is TotalTuesday=2
select max(daycnt) from
(Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS daycnt
from tbl_sched WHERE teacherID='2014279384'
union all
Select SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS daycnt
from tbl_sched WHERE teacherID='2014279384')
If you need the max between many columns:
Something interesting in SQLServer 2008 and above
SELECT (SELECT Max(v)
FROM (VALUES ([Total Monday]), ([Total Tuesday]), ...) AS value(v)) as [MaxDate]
From
(
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
..........
FROM tbl_sched
WHERE teacherID='2014279384'
)a
Another option:
SELECT Case When [Total Monday] > [Total Tuesday] then [Total Monday] else [Total Tuesday] End as maxvalue
FROM
(
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'
)a
I'd say the query below is better in terms of performance and highlights the intention better, because basically we are just GROUPing by days and COUNTing the groups, we don't need CASE's or SUM's (in which case SQL Server will have to go over all the records of the selected teacher).
SELECT TOP 1 Day, COUNT(*) AS Total
FROM tbl_sched
WHERE teacherID='2014279384'
AND Day IN ('Monday','Tuesday')
GROUP BY Day
ORDER BY Total DESC
You can just group by Day, sort by COUNT(*) DESC and get the top count:
SELECT TOP (1)
TotalCount = COUNT(*)
FROM
dbo.tbl_sched
WHERE
teacherID = '2014279384'
GROUP BY
Day
ORDER BY
TotalCount DESC
;
You can also include Day into the output to return the day that had the topmost result.
You can achieve this by using Max Function
Select MAX(SUM(CASE WHEN Day='Monday' THEN 1 END)) AS 'Total Monday',
MAX(SUM(CASE WHEN Day='Tuesday' THEN 1 END)) AS 'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'
I need help in removing the date dimension from the query below. In other words make the query independent of the date / time interval
My goal is to load the table into SSAS so that i would not have to change the date every time i run reports.
the query is huge (months, quarters, years, and aggregated date CR12,PR12 ...), i just gave a short example below
I sincerly appreciate any help
drop table #tmptmp
SELECT *, (DATEDIFF(day, enrollmentsDate, ShipmentDate))
- ((DATEDIFF(WEEK, enrollmentsenttDate, InitialShipmentDate) * 2)
+(CASE WHEN DATENAME(DW, enrollmentsentDate) = 'Sunday' THEN 1 ELSE 0 END)
+(CASE WHEN DATENAME(DW, ShipmentDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from tblFactoryHolidayDates where Date >= enrollmentsentDate
and Date < InitialShipmentDate)) as countdays into #tmptmp from
#tmpTouchpointsEnrollments
where EnrollmentSentDate is not null
----------------------------
drop table #tmp
select * into #tmp
from #tmptmp
where countdays < 20
drop table #tmpMetric
Select 'GrandTotal' as Dummy,'Avg days' as Metrics,'1' as MetricOrder,
Sum(case when Year(EnrollmentReceiveddate) ='2010' then (countdays) end) *1.0/
count(case when Year(EnrollmentReceiveddate) ='2010' then (patientID) end) *1.0 as Y2010,
into #tmpMetric
from #tmp
Thank you very much
I have the following two tables
activity(activity_id, title, description, group_id)
statistic(statistic_id, activity_id, date, user_id, result)
group_id and user_id come from active directory. Result is an integer.
Given a user_id and a date range of 6 days (Mon - Sat) which I've calculated on the business logic side, and the fact that some of the dates in the date range may not have a statistic result for the particular date (ie. day1 and day 4 may have entered statistic rows for a particular activity, but there may not be any entries for days 2, 3, 5 and 6) how can I get a SQL result with the following format? Keep in mind that if a particular activity doesn't have a record for the particular date in the statistics table, then that day should return 0 in the SQL result.
activity_id group_id day1result day2result day3result day4result day5result day6 result
----------- -------- ---------- ---------- ---------- ---------- ---------- -----------
sample1 Secured 0 5 1 0 2 1
sample2 Unsecured 1 0 0 4 3 2
Note: Currently I am planning on handling this in the business logic, but that would require multiple queries (one to create a list of distinct activities for that user for the date range, and one for each activity looping through each date for a result or lack of result, to populate the 2nd dimension of the array with date-related results). That could end up with 50+ queries for each user per date range, which seems like overkill to me.
I got this working for 4 days and I can get it working for all 6 days, but it seems like overkill. Is there a way to simplify this?:
SELECT d1d2.activity_id, ISNULL(d1d2.result1,0) AS day1, ISNULL(d1d2.result2,0) AS day2, ISNULL(d3d4.result3,0) AS day3, ISNULL(d3d4.result4,0) AS day4
FROM
(SELECT ISNULL(d1.activity_id,0) AS activity_id, ISNULL(result1,0) AS result1, ISNULL(result2,0) AS result2
FROM
(SELECT ISNULL(statistic_result,0) AS result1, ISNULL(activity_id,0) AS activity_id
FROM statistic
WHERE user_id='jeremiah' AND statistic_date='11/22/2011'
) d1
FROM JOIN
(SELECT ISNULL(statistic_result,0) AS result2, ISNULL(activity_id,0) AS activity_id
FROM statistic WHERE user_id='jeremiah' AND statistic_date='11/23/2011'
) d2
ON d1.activity_id=d2.activity_id
) d1d2
FULL JOIN
(SELECT d3.activity_id AS activity_id, ISNULL(d3.result3,0) AS result3, ISNULL(d4.result4,0) AS result4
FROM
(SELECT ISNULL(statistic_result,0) AS result3, ISNULL(activity_id,0) AS activity_id
FROM statistic WHERE user_id='jeremiah' AND statistic_date='11/24/2011'
) d3
FULL JOIN
(SELECT ISNULL(statistic_result,0) AS result4, ISNULL(activity_id,0) AS activity_id
FROM statistic WHERE user_id='jeremiah' AND statistic_date='11/25/2011'
) d4
ON d3.activity_id=d4.activity_id
) d3d4
ON d1d2.activity_id=d3d4.activity_id
ORDER BY d1d2.activity_id
Here is a typical approach for this kind of thing:
DECLARE #minDate DATETIME,
#maxdate DATETIME,
#userID VARCHAR(200)
SELECT #minDate = '2011-11-15 00:00:00',
#maxDate = '2011-11-22 23:59:59',
#userID = 'jeremiah'
SELECT A.activity_id, A.group_id,
SUM(CASE WHEN DATEDIFF(day, #minDate, S.date) = 0 THEN S.Result ELSE 0 END) AS Day1Result,
SUM(CASE WHEN DATEDIFF(day, #minDate, S.date) = 1 THEN S.Result ELSE 0 END) AS Day2Result,
SUM(CASE WHEN DATEDIFF(day, #minDate, S.date) = 2 THEN S.Result ELSE 0 END) AS Day3Result,
SUM(CASE WHEN DATEDIFF(day, #minDate, S.date) = 3 THEN S.Result ELSE 0 END) AS Day4Result,
SUM(CASE WHEN DATEDIFF(day, #minDate, S.date) = 4 THEN S.Result ELSE 0 END) AS Day5Result,
SUM(CASE WHEN DATEDIFF(day, #minDate, S.date) = 5 THEN S.Result ELSE 0 END) AS Day6Result
FROM activity A
LEFT OUTER JOIN statistic S
ON A.activity_id = S.activity_ID
AND S.user_id = #userID
WHERE S.date between #minDate AND #maxDate
GROUP BY A.activity_id, A.group_id
First, I'm using group by to reduce the resultset to one row per activity_id/group_id, then I'm using CASE to separate values for each individual column. In this case I'm looking at which day in the last seven, but you can use whatever logic there to determine what date. The case statements will return the value of S.result if the row is for that particular day, or 0 if it's not. SUM will add up the individual values (or just the one, if there is only one) and consolidate that into a single row.
You'll also note my date range is based on midnight on the first day in the range and 11:59PM on the last day of the range to ensure all times are included in the range.
Finally, I'm performing a left join so you will always have a 0 in your columns, even if there are no statistics.
I'm not entirely sure how your results are segregated by group in addition to activity (unless group is a higher level construct), but here is the approach I would take:
SELECT activity_id
day1result = SUM(CASE DATEPART(weekday, date) WHEN 1 THEN result ELSE 0 END)
FROM statistic
GROUP BY activity_id
I will leave the rest of the days and addition of group_id to you, but you should see the general approach.
how to calculate count based on rows?
SOURCE TABLE
each employee can take 2 days off
Employee-----First_Day_Off-----Second_Day_Off
1------------10/21/2009--------12/6/2009
2------------09/3/2009--------12/6/2009
3------------09/3/2009--------NULL
4
5
.
.
.
Now i need a table that shows the dates and number of people taking off on that day
Date---------First_Day_Off-------Second_Day_Off
10/21/2009---1-------------------0
12/06/2009---1--------------------1
09/3/2009----2--------------------0
Any ideas?
Oracle 9i+, using Subquery Factoring (WITH):
WITH sample AS (
SELECT a.employee,
a.first_day_off AS day_off,
1 AS day_number
FROM YOUR_TABLE a
WHERE a.first_day_off IS NOT NULL
UNION ALL
SELECT b.employee,
b.second_day_off,
2 AS day_number
FROM YOUR_TABLE b
WHERE b.second_day_off IS NOT NULL)
SELECT s.day_off AS date,
SUM(CASE WHEN s.day_number = 1 THEN 1 ELSE 0 END) AS first_day_off,
SUM(CASE WHEN s.day_number = 2 THEN 1 ELSE 0 END) AS second_day_off
FROM sample s
GROUP BY s.day_off
Non Subquery Version
SELECT s.day_off AS date,
SUM(CASE WHEN s.day_number = 1 THEN 1 ELSE 0 END) AS first_day_off,
SUM(CASE WHEN s.day_number = 2 THEN 1 ELSE 0 END) AS second_day_off
FROM (SELECT a.employee,
a.first_day_off AS day_off,
1 AS day_number
FROM YOUR_TABLE a
WHERE a.first_day_off IS NOT NULL
UNION ALL
SELECT b.employee,
b.second_day_off,
2 AS day_number
FROM YOUR_TABLE b
WHERE b.second_day_off IS NOT NULL) s
GROUP BY s.day_off
It is a bit awkward to handle these queries, since you have days off stored in different columns. A better layout would be to have something like
EMPLOYEE_ID DAY_OFF
Then you would have multiple rows if an employee took multiple days off
EMPLOYEE_ID DAY_OFF
1 10/21/2009
1 12/6/2009
2 09/3/2009
2 12/6/2009
3 09/3/2009
...
In that case, you could find out how many days off each person took by using the following query:
SELECT EMPLOYEE_ID, COUNT(*) AS NUM_DAYS_OFF FROM DAYS_OFF_TABLE GROUP BY EMPLOYEE_ID
And the number of people who took days off on each date like this:
SELECT DAY_OFF, COUNT(*) AS NUM_PEOPLE FROM DAYS_OFF_TABLE GROUP BY DAY_OFF
But I digress...
You can try to use an SQL CASE statement to help with this:
SELECT Employee, CASE
WHEN First_Day_Off is NULL AND Second_Day_Off is NULL THEN 0
WHEN First_Day_Off is NOT NULL AND Second_Day_Off is NULL THEN 1
WHEN First_Day_Off is NULL AND Second_Day_Off is NOT NULL THEN 1
ELSE 2
END AS NUM_DAYS_OFF
FROM DAYS_OFF_TABLE
(note that you may need to change around the syntax slightly depending on your database.
Getting dates and number of people who took off on that day might be more complicated.
I don't know if this would work, but you can try it:
SELECT
Date_Off,
COUNT(*) AS Num_People
FROM
(SELECT
First_Day_Off, COUNT(*) AS Num_People FROM DAYS_OFF_TABLE WHERE First_Day_Off IS NOT NULL GROUP BY First_Day_Off
UNION
SELECT Second_Day_Off, COUNT(*) AS Num_People FROM DAYS_OFF_TABLE WHERE Second_Day_Off IS NOT NULL GROUP BY Second_Day_Off)
GROUP BY
Num_People