PHPmyadmin won't accept CREATE TABLE statement - sql

I'm trying to use a simple CREATE TABLE statement to create a new table in my very first SQL-database. PHPmyadmin won't accept the code and gives me an error statement.
There doesn't appear to be anything wrong with the syntax of my SQL command. In fact, I receive the same error statement when I copy and past an example code from any internet tutorial to create a table.
this is my SQL command:
CREATE TABLE Guestbook(
ID int AUTO_INCREMENT PRIMARY KEY NOT NULL,
Name varchar(50) NOT NULL,
Message TEXT NOT NULL,
Date datetime,
Sport varchar(30),
Practicioner BOOLEAN default 0,
)
This is the error statement:
Static analysis:
3 errors were found during analysis.
A symbol name was expected! (near "Name" at position 74)
Unexpected beginning of statement. (near "50" at position 87)
Unrecognized statement type. (near "NOT NULL" at position 91)
SQL query:
CREATE TABLE Guestbook( ID int AUTO_INCREMENT PRIMARY KEY NOT NULL, Name varchar(50) NOT NULL, Message TEXT NOT NULL, Date datetime, Sport varchar(30), Practicioner BOOLEAN default 0, )
MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 8
I can't imagine why this won't work. I'd like to be able to use to command line in phpMyadmin. and this seems pretty straigtht forward. Yet I've been fiddling around with it for ages and I can't figure out how to create even the simplest possible table.
Can anyone help me out?

You should remove the last comma in your CREATE statement:
CREATE TABLE Guestbook(
ID int AUTO_INCREMENT PRIMARY KEY NOT NULL,
Name varchar(50) NOT NULL,
Message TEXT NOT NULL,
Date datetime,
Sport varchar(30),
Practicioner BOOLEAN default 0
)

Related

Error in simple SQL when executing in python

I'm getting an error with this SQL code when I execute it in my Flask app. I swear I've done this exact thing before and it worked, so I'm not sure what's happening.
Here is the SQL:
DROP TABLE IF EXISTS user;
CREATE TABLE order (
id TEXT PRIMARY KEY,
plan_id INTEGER NOT NULL,
placed TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
ssh_key TEXT NOT NULL,
region INTEGER NOT NULL,
operating_system INTEGER NOT NULL,
enable_ipv6 INTEGER NOT NULL
expires INTEGER NOT NULL
);
Here is the relevant part of my python error:
sqlite3.OperationalError: near "order": syntax error
Thank you for the help
Order is a reserved keyword for sqlite. If you want to use a keyword as a name, you need to quote it.
https://www.sqlite.org/lang_keywords.html

Sql error while creating tables - Firebird

I have simple sql code for create table and then add constraint to it. It looks like this:
CREATE TABLE bills (
id INTEGER NOT NULL,
code VARCHAR2(25) NOT NULL,
dateOfGeneration DATE NOT NULL,
job_id INTEGER NOT NULL
);
ALTER TABLE bills ADD CONSTRAINT bills_pk PRIMARY KEY ( id,job_id );
I am using IBExpert - client for Firebird. When I execute this code I get 2 errors:
First error: - in code VARCHAR2(25) NOT NULL
Invalid token.
Dynamic SQL Error.
SQL error code = -104.
Token unknown - line 3, column 29.
(.
Second error: - in code ALTER TABLE ...
Invalid token.
Dynamic SQL Error.
SQL error code = -104.
Token unknown - line 8, column 1.
ALTER.
The first one I think is because i am using varchar2 instead of varchar. What about second error? How to fix this?
There is no VARCHAR2 type in Firebird - https://firebirdsql.org/file/documentation/reference_manuals/fblangref25-en/html/fblangref25-datatypes-chartypes.html
If you want to run two commands - you have to run TWO commands. You try to run two commands in one, but that is not a way to do it. You have to split them and run one after another. Or you have to wrap them into one EXECUTE BLOCK command.
Also IBExpert has a separate window of Script Executive for multiple commands running. It is not SQL Editor which is designed to execute ONE command, it is a separate window in another menu - https://www.ibexpert.net/ibe/pmwiki.php?n=Doc.ScriptExecutive
Table creation command is described here: https://firebirdsql.org/file/documentation/reference_manuals/fblangref25-en/html/fblangref25-ddl-tbl.html
Basically what you trying to do looks like this, if to do it in one command:
CREATE TABLE bills (
id INTEGER NOT NULL,
code VARCHAR(25) NOT NULL,
dateOfGeneration DATE NOT NULL,
job_id INTEGER NOT NULL,
PRIMARY KEY ( id,job_id )
)
or if you insist on naming then perhaps
CREATE TABLE bills (
id INTEGER NOT NULL,
code VARCHAR(25) NOT NULL,
dateOfGeneration DATE NOT NULL,
job_id INTEGER NOT NULL,
CONSTRAINT bills_pk PRIMARY KEY ( id,job_id )
)

PostgreSQL syntax error at or near INT

I made a script to create a database with PostgreSQL.
So I copy in my script, click "Analyze & Explain" in pgAdmin4 and I have no clue why it says I have a syntax error at or near 'INT' on idSituationFamiliale.
I really can't see what's wrong...
--Personnes
--
CREATE TABLE SITUATION_FAMILIALE (
idSituationFamiliale INT NOT NULL,
intituleSituationFamiliale VARCHAR(50) NOT NULL,
PRIMARY KEY(idSituationFamiliale)
);
The query is fine if you RUN it. It is wrong if you EXPLAIN / ANALYZE it.
The doc says that you can explain a CREATE TABLE AS, not a pure CREATE TABLE statement. While the former contains a SELECT statement that can be explained/analyzed, the later has nothing to be explained/analyzed and fails on the 1st field, regardless of its name or type.
You should be using integer as opposed to int.
e.g
--Personnes
--
CREATE TABLE SITUATION_FAMILIALE (
idSituationFamiliale INTEGER NOT NULL,
intituleSituationFamiliale VARCHAR(50) NOT NULL,
PRIMARY KEY(idSituationFamiliale)
);

Can't create new table

I'm new to SQL Server 2000 and face a problem. I want to make a new table but I encounter an error message with the following code:
create table Buku
(
Kode_Buku char(5) constraint PK_Kode_Buku Primary Key,
Judul_Buku varchar(10)not null,
Nama_Pengarang varchar(30) not null,
Penerbit varchar(30),
Kota_Terbit varchar(30) default,
Tahun_Terbit varchar(4) default,
Bahasa varchar(4) check,
Harga_Jual money,
)
and here's the error code:
Server: Msg 170, Level 15, State 1, Line 1
Line 1: Incorrect syntax near 'Buku'.
You have three problems:
You have multiple cases where you say default but don't specify anything
You have a check but don't specify anything
Your last column definition says money, with a trailing comma
Now, none of these lead to the exact error message you're getting, so maybe there is more you're not telling us (is there more code before the create table bit?), but these little syntax problems are far too localized to be useful in this Q & A format.
EDIT
I just ran this on a SQL Server 2000 instance and it worked just fine:
create table Buku
(
Kode_Buku char(5) constraint PK_Kode_Buku Primary Key,
Judul_Buku varchar(10) not null, -- added space here
Nama_Pengarang varchar(30) not null,
Penerbit varchar(30),
Kota_Terbit varchar(30), -- removed default here
Tahun_Terbit varchar(4), -- removed default here
Bahasa varchar(4), -- removed check here
Harga_Jual money -- removed comma here
)
So I'm not sure what you're doing differently, but I can't get the error message you are seeing with the information you've provided in the question. If you're still getting an error message with this code (and only this code), you'll need to provide more information, such as ##VERSION, what interface you're using to submit the create table statement to SQL Server, etc.

phpMyAdmin creating an attribute with '#" character in its name

I am trying to create the following table.
CREATE TABLE customer
(
cust# CHAR(3)NOT NULL ,
cname VARCHAR(30) NOT NULL ,
city VARCHAR(20) NOT NULL,
PRIMARY KEY (cust#)
)engine=InnoDB;
I am getting the following error
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'cname VARCHAR(30) NOT NULL , city VARCHAR(20) NOT NULL, PRIMARY KEY (cust#' at line 4
I have confirmed that the problem is with the '#' by replacing it with 'custNum'.
However, I must use the '#' sign. I know I can rename the field in the myPhpAdmin interface to cust# but I need to know how to escape it in the SQL statement.
*Edit to say I have already tried '\#'
Thanks
I was able to answer my own question and I'm posting here in case someone else has the same problem.
You have to use '`' around the name. So `cust#` did the trick.