Get current week in postgreSQL - sql

I have been searching the web for the proper postgreSQL syntax for current_week. I searched through the link attached but could not get anything fruition out of it Date/Time. My task is to get Sunday as the start of the week.
I tried same as current_date but it failed:
select current_week
There has to be a current week syntax for postgreSQL.

knowing that for extract('dow' from
The day of the week as Sunday (0) to Saturday (6)
and
By definition, ISO weeks start on Mondays
You can workaround by substracting one day:
select date_trunc('week', current_date) - interval '1 day' as current_week
current_week
------------------------
2016-12-18 00:00:00+00
(1 row)
Here is sample:
t=# with d as (select generate_series('2016-12-11','2016-12-28','1 day'::interval) t)
select date_trunc('week', d.t)::date - interval '1 day' as current_week, extract('dow' from d.t), d.t from d
;
current_week | date_part | t
---------------------+-----------+------------------------
2016-12-04 00:00:00 | 0 | 2016-12-11 00:00:00+00
2016-12-11 00:00:00 | 1 | 2016-12-12 00:00:00+00
2016-12-11 00:00:00 | 2 | 2016-12-13 00:00:00+00
2016-12-11 00:00:00 | 3 | 2016-12-14 00:00:00+00
2016-12-11 00:00:00 | 4 | 2016-12-15 00:00:00+00
2016-12-11 00:00:00 | 5 | 2016-12-16 00:00:00+00
2016-12-11 00:00:00 | 6 | 2016-12-17 00:00:00+00
2016-12-11 00:00:00 | 0 | 2016-12-18 00:00:00+00
2016-12-18 00:00:00 | 1 | 2016-12-19 00:00:00+00
2016-12-18 00:00:00 | 2 | 2016-12-20 00:00:00+00
2016-12-18 00:00:00 | 3 | 2016-12-21 00:00:00+00
2016-12-18 00:00:00 | 4 | 2016-12-22 00:00:00+00
2016-12-18 00:00:00 | 5 | 2016-12-23 00:00:00+00
2016-12-18 00:00:00 | 6 | 2016-12-24 00:00:00+00
2016-12-18 00:00:00 | 0 | 2016-12-25 00:00:00+00
2016-12-25 00:00:00 | 1 | 2016-12-26 00:00:00+00
2016-12-25 00:00:00 | 2 | 2016-12-27 00:00:00+00
2016-12-25 00:00:00 | 3 | 2016-12-28 00:00:00+00
(18 rows)
Time: 0.483 ms

One method would be date_trunc():
select date_trunc('week', current_date) as current_week

Related

How can I generate a weekly series which should have start date as month start date and end date should be start date + 6 in postgresql

Below is the query I have tried:
with weeks as (
select d::date start_date, case when to_char(d::date+6,'Month') =
to_char(d::date,'Month') then d::date+ 6 else (date_trunc('month',
to_timestamp(to_char(d::date,'YYYY-MM-DD') ,'YYYY-MM-DD HH:MI:SS')) + interval '1
month - 1 day')::date end as end_date
from generate_series('2022-01-01', '2022-07-30', '7d'::interval) d
)
I want results as:
Start Date
End Date
'2022-01-01'
'2022-01-07
'2022-01-08'
'2022-01-14
And it should go from 2022-01-29 to 2022-01-31 then for next month it should start from '2022-02-01' to '2022-02-07' and should continue.
I would combine to generate_series() here. One for the start of the months, and one for the week starts.
Evaluating the week end can be achieved using the least() function by calculating the last day of the month:
select gw.week_start::date start_date,
least(gw.week_start::date + 6, date_trunc('month', gw.week_start) + interval '1 month - 1 day')::date as end_date
from generate_series('2022-01-01', '2022-07-30', interval '1 month') as gm(month_start)
cross join generate_series(gm.month_start, gm.month_start + interval '1 month - 1 day', interval '1 week') as gw(week_start);
This returns:
start_date | end_date
-----------+-----------
2022-01-01 | 2022-01-07
2022-01-08 | 2022-01-14
2022-01-15 | 2022-01-21
2022-01-22 | 2022-01-28
2022-01-29 | 2022-01-31
2022-02-01 | 2022-02-07
2022-02-08 | 2022-02-14
2022-02-15 | 2022-02-21
2022-02-22 | 2022-02-28
2022-03-01 | 2022-03-07
2022-03-08 | 2022-03-14
2022-03-15 | 2022-03-21
2022-03-22 | 2022-03-28
2022-03-29 | 2022-03-31
2022-04-01 | 2022-04-07
2022-04-08 | 2022-04-14
2022-04-15 | 2022-04-21
2022-04-22 | 2022-04-28
2022-04-29 | 2022-04-30
2022-05-01 | 2022-05-07
2022-05-08 | 2022-05-14
2022-05-15 | 2022-05-21
2022-05-22 | 2022-05-28
2022-05-29 | 2022-05-31
2022-06-01 | 2022-06-07
2022-06-08 | 2022-06-14
2022-06-15 | 2022-06-21
2022-06-22 | 2022-06-28
2022-06-29 | 2022-06-30
2022-07-01 | 2022-07-07
2022-07-08 | 2022-07-14
2022-07-15 | 2022-07-21
2022-07-22 | 2022-07-28
2022-07-29 | 2022-07-31

SQL - Split open & Close time Into intervals of 30 minutes

Purpose: I work in Hospitality Industry. I want to understand at what time the Restaurant is full and what time it is less busy. I have the opening and closing times, I want to split it 30 minute interval period.
I would really appreciate if you could ease help me.
Thanking you in advance
Table
Check# Open CloseTime
25484 17:34 18:06
25488 18:04 21:22
Output
Check# Open Close Duration
25484 17:34 18:00 0:25
25484 18:00 18:30 0:30
25488 18:08 18:30 0:21
25488 18:30 19:00 0:30
25488 19:00 19:30 0:30
25488 19:30 20:00 0:30
25488 20:00 20:30 0:30
25488 20:30 21:00 0:30
25488 21:00 21:30 0:30
I am new to SQL. I am good at Excel, but due to its limitations i want to use SQL. I just know the basics in SQL.
I have tried on the google, but could not find solution to it. All i can see use of Date Keywords, but not the Field name in the code, hence i am unable to use them.
Could you try this, it works in MySQL 8.0:
WITH RECURSIVE times AS (
SELECT time '0:00' AS `Open`, time '0:30' as `Close`
UNION ALL
SELECT addtime(`Open`, '0:30'), addtime(`Close`, '0:30')
FROM times
WHERE `Open` < time '23:30'
)
SELECT c.`Check`,
greatest(t.`Open`, c.`Open`) `Open`,
least(t.`Close`, c.`CloseTime`) `Close`,
timediff(least(t.`Close`, c.`CloseTime`), greatest(t.`Open`, c.`Open`)) `Duration`
FROM times t
JOIN checks c ON (c.`Open` < t.`Close` AND c.`CloseTime` > t.`Open`);
| Check | Open | Close | Duration |
| ----- | -------- | -------- | -------- |
| 25484 | 17:34:00 | 18:00:00 | 00:26:00 |
| 25484 | 18:00:00 | 18:06:00 | 00:06:00 |
| 25488 | 18:04:00 | 18:30:00 | 00:26:00 |
| 25488 | 18:30:00 | 19:00:00 | 00:30:00 |
| 25488 | 19:00:00 | 19:30:00 | 00:30:00 |
| 25488 | 19:30:00 | 20:00:00 | 00:30:00 |
| 25488 | 20:00:00 | 20:30:00 | 00:30:00 |
| 25488 | 20:30:00 | 21:00:00 | 00:30:00 |
| 25488 | 21:00:00 | 21:22:00 | 00:22:00 |
->Fiddle
This works for SQL Server 2019:
WITH times([Open], [Close]) AS (
SELECT cast({t'00:00:00'} as time) as "Open",
cast({t'00:30:00'} as time) as "Close"
UNION ALL
SELECT dateadd(minute, 30, [Open]), dateadd(minute, 30, [Close])
FROM times
WHERE [Open] < cast({t'23:30:00'} as time)
)
SELECT c.[Check],
iif(t.[Open] > c.[Open], t.[Open], c.[Open]) as [Open],
iif(t.[Close] < c.[CloseTime], t.[Close], c.[CloseTime]) as [Close],
datediff(minute,
iif(t.[Open] > c.[Open], t.[Open], c.[Open]),
iif(t.[Close] < c.[CloseTime], t.[Close], c.[CloseTime])) Duration
FROM times t
JOIN checks c ON (c.[Open] < t.[Close] AND c.[CloseTime] > t.[Open]);
Check | Open | Close | Duration
25484 | 17:34:00.0000000 | 18:00:00.0000000 | 26
25484 | 18:00:00.0000000 | 18:06:00.0000000 | 6
25488 | 18:04:00.0000000 | 18:30:00.0000000 | 26
25488 | 18:30:00.0000000 | 19:00:00.0000000 | 30
25488 | 19:00:00.0000000 | 19:30:00.0000000 | 30
25488 | 19:30:00.0000000 | 20:00:00.0000000 | 30
25488 | 20:00:00.0000000 | 20:30:00.0000000 | 30
25488 | 20:30:00.0000000 | 21:00:00.0000000 | 30
25488 | 21:00:00.0000000 | 21:22:00.0000000 | 22
->Fiddle

How to compare current row with previous column next row in sql

Date from Date to
2018-12-11 2019-01-08
2019-01-08 2019-02-09
2019-02-10 2019-03-14
2019-03-17 2019-04-11
2019-04-15 2019-05-16
2019-05-16 2019-06-13
output will be like this
Date from Date to Days
2018-12-11 2019-01-08 0
2019-01-08 2019-02-09 1
2019-02-10 2019-03-14 3
2019-03-17 2019-04-11 4
2019-04-15 2019-05-16 0
2019-05-16 2019-06-13 -
To return the difference between two date values in days you could use the DATEDIFF() Function, something like:
SELECT DATEDIFF(DAY, DayFrom, DayTo) AS 'DaysBetween'
FROM DateTable
You want lead() and a date diff function:
select
date_from,
date_to,
datediff(day, date_to, lead(date_from) over(order by date_from)) days
from mytable
datediff() is a SQLServer function. There are equivalents in other RDBMS.
Side note: I would recommend againts using a string value (-) for records that do not have a next record, since other values are numeric (the datatypes in a column must be consistant). null is good enough for this (which the above query will produce).
Demo on DB Fiddle:
date_from | date_to | days
:------------------ | :------------------ | ---:
11/12/2018 00:00:00 | 08/01/2019 00:00:00 | 0
08/01/2019 00:00:00 | 09/02/2019 00:00:00 | 1
10/02/2019 00:00:00 | 14/03/2019 00:00:00 | 3
17/03/2019 00:00:00 | 11/04/2019 00:00:00 | 4
15/04/2019 00:00:00 | 16/05/2019 00:00:00 | 0
16/05/2019 00:00:00 | 13/06/2019 00:00:00 | null

How to generate series for date range with minutes interval in oracle?

In Postgres below query is working using generate_series function
SELECT dates
FROM generate_series(CAST('2019-03-01' as TIMESTAMP), CAST('2019-04-01' as TIMESTAMP), interval '30 mins') AS dates
Below query is also working in Oracle but only for date interval
select to_date('2019-03-01','YYYY-MM-DD') + rownum -1 as dates
from all_objects
where rownum <= to_date('2019-03-06','YYYY-MM-DD')-to_date('2019-03-01','YYYY-MM-DD')+1
SELECT dates
FROM generate_series(CAST('2019-03-01' as TIMESTAMP), CAST('2019-04-01' as TIMESTAMP), interval '30 mins') AS dates
I want same result in Oracle for below query
SELECT dates
FROM generate_series(CAST('2019-03-01' as TIMESTAMP), CAST('2019-04-01' as TIMESTAMP), interval '30 mins') AS dates
Use a hierarchical query:
SELECT DATE '2019-03-01' + ( LEVEL - 1 ) * INTERVAL '30' MINUTE AS dates
FROM DUAL
CONNECT BY DATE '2019-03-01' + ( LEVEL - 1 ) * INTERVAL '30' MINUTE <= DATE '2019-04-01';
Output:
| DATES |
| :------------------ |
| 2019-03-01 00:00:00 |
| 2019-03-01 00:30:00 |
| 2019-03-01 01:00:00 |
| 2019-03-01 01:30:00 |
| 2019-03-01 02:00:00 |
| 2019-03-01 02:30:00 |
| 2019-03-01 03:00:00 |
| 2019-03-01 03:30:00 |
| 2019-03-01 04:00:00 |
| 2019-03-01 04:30:00 |
| 2019-03-01 05:00:00 |
| 2019-03-01 05:30:00 |
...
| 2019-03-31 19:30:00 |
| 2019-03-31 20:00:00 |
| 2019-03-31 20:30:00 |
| 2019-03-31 21:00:00 |
| 2019-03-31 21:30:00 |
| 2019-03-31 22:00:00 |
| 2019-03-31 22:30:00 |
| 2019-03-31 23:00:00 |
| 2019-03-31 23:30:00 |
| 2019-04-01 00:00:00 |
db<>fiddle here

Postgres, Update TIMESTAMP to current date but preserve time of day

In my Postgres database, I have the following table:
SELECT start_at, end_at FROM schedules;
+---------------------+---------------------+
| start_at | end_at |
|---------------------+---------------------|
| 2016-09-05 16:30:00 | 2016-09-05 17:30:00 |
| 2016-09-05 17:30:00 | 2016-09-05 18:30:00 |
| 2017-08-13 03:00:00 | 2017-08-13 07:00:00 |
| 2017-08-13 03:00:00 | 2017-08-13 07:00:00 |
| 2017-08-13 18:42:26 | 2017-08-13 21:30:46 |
| 2017-08-10 00:00:00 | 2017-08-10 03:30:00 |
| 2017-08-09 18:00:00 | 2017-08-10 03:00:00 |
| 2017-08-06 23:00:00 | 2017-08-07 03:00:00 |
| 2017-08-07 01:00:00 | 2017-08-07 03:48:20 |
| 2017-08-07 01:00:00 | 2017-08-07 03:48:20 |
| 2017-08-07 18:05:00 | 2017-08-07 20:53:20 |
| 2017-08-07 14:00:00 | 2017-08-08 01:00:00 |
| 2017-08-07 18:00:00 | 2017-08-07 20:48:20 |
| 2017-08-08 08:00:00 | 2017-08-09 00:00:00 |
| 2017-08-09 21:30:00 | 2017-08-10 00:18:20 |
| 2017-08-13 03:53:26 | 2017-08-13 06:41:46 |
+---------------------+---------------------+
Assume I also have an ID column, what I want to do is update all the start and end times to be for today (now), what is the most efficient SQL to accomplish this? My table could have millions of rows.
the best I can think of is this:
update schedules
set start_at = current_date + start_at::time
, end_at = current_date + end_at::time
WHERE start_at::date <> current_date
or end_at::date <> current_date;
The arithmetic is fast compared to accessing the rows.
if not all rows need updating, the where clause will help efficiency. Updates are expensive.