I have 2 table 'sanpham' and 'danhmuc'. I use phalcon query builder to get data from 2 tables.
$laytin = $this->modelsManager->createBuilder()
->from("sanpham")
->innerJoin('danhmuc','sanpham.danhmuc=danhmuc.sodanhmuc')
->where('sanpham.sosanpham = '.$id.'')
->getQuery()
->getSingleResult();
$breadcrumbs = array('/' => Tool::getTranslation()->_('trangchu'),"/Loai-san-pham/".$laytin->tendep."/".$laytin->sodanhmuc => $laytin->tendanhmuc,'' => $laytin->tieudesanpham );
The query runs, but $laytin->tendep, $laytin->sodanhmuc, $laytin->tendanhmuc in 'danhmuc' table doesn't display. Every column in 'sanpham' table (such as: $laytin->tieudesanpham) displays properly.
You can add specific columns with:
$this->modelsManager->createBuilder()->columns('danhmuc.tendep, danhmuc.sodanhmuc')
With this method you will have to add each column you want in your output. QueryBuilder docs.
Another method is to query the Sanpham model.
For example:
class Sanpham extends \Phalcon\Mvc\Model
{
public static function findSomething($something)
{
// this is your actual query, it replaces the queryBuilder
return self::query()
->where('sanpham.sosanpham = :id:', ['id' => $something])
->innerJoin('danhmuc', 'sanpham.danhmuc = danhmuc.sodanhmuc')
->execute()->getFirst();
}
public function initialize()
{
// define the relation to danhmuc
$this->belongsTo('danhmuc', 'danhmuc', 'sodanhmuc');
}
}
class Danhmuc extends \Phalcon\Mvc\Model
{
public function initialize()
{
// there are other options besides "hasMany", like "hasOne".
// this is your relation to sanpham
$this->hasMany('sodanhmuc', 'sanpham', 'danhmuc');
}
}
class YourController extends \Phalcon\Mvc\Controller
{
public function testAction()
{
// get your first record in Sanpham matching "12345"
$sanpham = Sanpham::findSomething(12345);
// from your Sanpham object, get the related danhmuc object.
// this works because we defined the relations (belongsTo and hasMany)
$danhmuc = $sanpham->getRelated('danhmuc');
// now you have access to the values of danhmuc via the $danhmuc variable
$breadcrumbs = [
'/' => Tool::getTranslation()->_('trangchu'),
"/Loai-san-pham/" . $danhmuc->tendep => $danhmuc->tendanhmuc,
'' => $danhmuc->tieudesanpham,
];
}
}
Check the Phalcon model docs for more info on this.
Related
I have a project on laravel 5.
I wrote an SQL to select games from database, and after executing it, I got models collection, where every model has id = 1.
This is my query:
select * from `games` left join `game_vendors` on `games`.`vendor_id` =
`game_vendors`.`id` where `game_vendors`.`name` != 'some_vendor' and
`games`.`id` not in (1,2,3,4,5,6,7,8,9,10,11,12);
checked this query in mysql terminal - all is fine, id's are correct, but on postman or in the browser, I got this
array(2021) {
[0]=>
array(32) {
["id"] => int(1)
[1]=>
array(32) {
["id"] => int(1)
...
...
...
[24]=>
array(32) {
["id"] => int(1)
Model class contains this:
class Game extends Model {
protected $table = 'games';
public function vendor()
{
return $this->hasOne('App\GameVendor', 'vendor_id', 'id');
}
Use Laravel Eloquent Relationship and "WHERE NOT IN"
Update Model as
class Game extends Model {
protected $table = 'games';
public function vendor()
{
return $this->hasOne('App\GameVendor', 'vendor_id', 'id')->where('name', '!=' ,'some_vendor');
}
And use Eloquent as
$games = Game::whereNotIn('id',[1,2,3,4,5,6,7,8,9,10,11,12])->get();
foreach($games as $game){
$game->vendor->name
}
I want to get a collection of all artists with their latest image only.
The following code returns a collection of all artists but with only one image associated with the first artist.
$data = Artist::with(['images' => function($q){
$q->first();
}])
->get();
return $data;
My models:
class Artist extends Model {
public function images()
{
return $this->belongsToMany('App\Image');
}
}
class Image extends Model {
public function artists()
{
return $this->belongsToMany('App\Artist');
}
}
You can set in you modal:
public function FirstImage()
{
return $this->hasOne('image');
}
then:
$data = Artist::with('FirstImage')->get();
All of my entities (that are mapped to a database table) inherit from an entity class with a dynamic component on it called Attributes e.g.:
public abstract class Entity<T> {
public virtual T Id { get; set; }
private IDictionary _attributes;
public virtual IDictionary Attributes {
get { return _attributes ?? (_attributes = new Hashtable()); }
set { _attributes = value; }
}
}
The Attributes collection allows me to add extra fields to each entity without directly changing the entity itself. This allows me to make my application more modular.
For example say I have the following entity:
public class User : Entity<int> {
public virtual string Name { get; set; }
}
Now say I have a Forum module which needs a NumPosts property against the User. I would add the field against the Users table in the database. This field is non nullable and has a default value of 0. I then map the field using the dynamic component against the User entity.
However when I try inserting the user by saying:
session.Save(new User() { Name = "Test" });
It throws an error as it's expecting me to set a value for NumPosts and the generated SQL would be something like:
INSERT INTO Users (Name, NumPosts) VALUES ('Test', NULL)
However NumPosts does not allow nulls and hence the error. Ideally I'd like it to say the following if the Attributes collection does not contain an entry for NumPosts:
INSERT INTO Users (Name) VALUES ('Test')
An alternative is to say the following which would work fine:
session.Save(new User() { Name = "Test", Attributes = new Hashtable() { { "NumPosts", 0 } } });
The problem I have is that I don't want the modules to have a dependency on each other and I can't really say this.
For reference here's a bare bones version of session factory method which maps the NumPosts field:
return Fluently.Configure()
...
.ExposeConfiguration(c => {
// Get the persistent class
var persistentClass = c.GetClassMapping("User");
// Create the attributes component
var component = new Component(persistentClass);
// Create a simple value
var simpleValue = new SimpleValue(persistentClass.Table);
// Set the type name
simpleValue.TypeName = "Int32";
// Create a new db column specification
var column = new Column("NumPosts");
column.Value = simpleValue;
column.Length = 10;
column.IsNullable = false;
column.DefaultValue = "0";
// Add the column to the value
simpleValue.AddColumn(column);
// Ad the value to the component
component.AddProperty(new Property() { Name = column.Name, Value = simpleValue });
// Add the component property
persistentClass.AddProperty(new Property() { Name = "Attributes", Value = component });
})
.BuildConfiguration();
I'd appreciate if someone could let me know if this is possible. Thanks
You know how to make it working as described above:
... An alternative is to say the following which would work fine:
session.Save(new User()
{
Name = "Test", Attributes = new Hashtable() { { "NumPosts", 0 } }
});
... The problem I have is that I don't want the modules to have a dependency on each other and I can't really say this...
In case, that the biggest issue is the explicit Attributes initialization ("...I don't want the modules to have a dependency...") we can use:
12.2. Event system
So, with Listener like this:
[Serializable]
public class MyPersistListener : NHibernate.Event.ISaveOrUpdateEventListener
{
public void OnSaveOrUpdate(SaveOrUpdateEvent #event)
{
var entity = #event.Entity as Entity<int>; // some interface IHaveAttributes
if (entity == null) // would be more appropriate
{
return;
}
var numPosts = entity.Attributes["NumPosts"] as int?;
if (numPosts.HasValue)
{
return;
}
entity.Attributes["NumPosts"] = 0;
}
}
Based on this doc snippet:
Configuration cfg = new Configuration();
ILoadEventListener[] stack = new ILoadEventListener[] { new MyLoadListener(), new DefaultLoadEventListener() };
cfg.EventListeners.LoadEventListeners = stack;
This should be the init in our case:
.ExposeConfiguration(c => {
var stack = new ISaveOrUpdateEventListener [] { new MyPersistListener() };
c.EventListeners.SaveEventListeners= stack;
I'm new to Yii and I have a table 'Student' with fields like 'stdStudentId', 'stdName', etc.
I'm making API, so this data should be returned in JSON. Now, because I want field names in JSON to just be like 'id', 'name', and I don't want all fields returned, i made a method in the model:
public function APIfindByPk($id){
$student = $this->findByPk($id);
return array(
'id'=>$student->stdStudentId,
'name'=>$student->stdName,
'school'=>$student->stdSchool
);
}
The problem is, stdSchool is a relation and in this situation, $student->stdSchool returns array with fields like schSchoolId, schName, etc. I don't want fields to be named like that in JSON, and also I don't want all the fields from School returned and I would like to add some fields of my own. Is there a way to do this in Yii, or I'll have to do it manually by writing methods like this?
I have been looking for the same thing. There is a great php lib named Fractal letting you achieve it: http://fractal.thephpleague.com/
To explain briefly the lib, for each of your models you create a Transformer that will be doing the mapping between your model attributes and the ones that need to be exposed using the api.
class BookTransformer extends Fractal\TransformerAbstract
{
public function transform(Book $book)
{
return [
'id' => (int) $book->id,
'title' => $book->title,
'year' => $book->yr,
];
}
}
In the transformer you can also set the relation that this model have :
class BookTransformer extends TransformerAbstract
{
/**
* List of resources relations that can be used
*
* #var array
*/
protected $availableEmbeds = [
'author'
];
/**
* Turn this item object into a generic array
*
* #return array
*/
public function transform(Book $book)
{
return [
'id' => (int) $book->id,
'title' => $book->title,
'year' => $book->yr,
];
}
/**
* Here we are embeding the author of the book
* using it's own transformer
*/
public function embedAuthor(Book $book)
{
$author = $book->author;
return $this->item($author, new AuthorTransformer);
}
}
So at the end you will call
$fractal = new Fractal\Manager();
$resource = new Fractal\Resource\Collection($books, new BookTransformer);
$json = $fractal->createData($resource)->toJson();
It's not easy to describe all the potential of fractal in one answer but you really should give it a try.
I'm using it along with Yii so if you have some question don't hesitate!
Since you are getting the values from the database using Yii active record, ask the database to use column aliases.
Normal SQL would be something like the following :
SELECT id AS Student_Number, name AS Student_Name, school AS School_Attending FROM student;
In Yii, you can apply Criteria to the findByPK() function. See here for reference : http://www.yiiframework.com/doc/api/1.1/CActiveRecord#findByPk-detail
$criteria = new CDbCriteria();
$criteria->select = 'id AS Student_Number';
$student = Student::model()->findByPk($id, $criteria);
Note that in order to use a column alias like that, you will have to define a virtual attribute Student_Number in your Student{} model.
Override the populateRecord() function of ActiveRecord can achieve this!
My DishType has 5 properties and override the populateRecord function Yii would invoke this when records fetched from db.
My code is here!
class DishType extends ActiveRecord
{
public $id;
public $name;
public $sort;
public $createTime;
public $updateTime;
public static function populateRecord($record, $row)
{
$pattern = ['id' => 'id', 'name' => 'name', 'sort' => 'sort', 'created_at' => 'createTime', 'updated_at' => 'updateTime'];
$columns = static::getTableSchema()->columns;
foreach ($row as $name => $value) {
$propertyName = $pattern[$name];
if (isset($pattern[$name]) && isset($columns[$name])) {
$record[$propertyName] = $columns[$name]->phpTypecast($value);
}
}
parent::populateRecord($record, $row);
}
}
I am new on Yii framework, so please i need some help where to start.
What i need is, action and module to display a form to a user, which his will be able to edit is own profile (with profile picture), so i have 3 table
user_account || user_personal || user_general
how can i build a form that insert and update those 3 table at once?
i try this:
This is what i did, but its still not saving the data even into 1 table.
public function actionUpdate() {
$model = new ProfileUpdate();
if(isset($_POST['ProfileUpdate']))
{
$model->attributes = $_POST['ProfileUpdate'];
if($model->validate())
{
$account = new Profile();
$account->userid = Yii::app()->user->id;
$account->name = $model->name;
$account->website = $model->website;
$account->category = $model->category;
$account->save();
$this->redirect('profile');
}
}
model:
class Profile extends CActiveRecord
{
public $userid;
public $name;
public $website;
public $category;
public static function model()
{
return parent::model(__CLASS__);
}
public function tableName()
{
return 'userinfo';
}
public function primaryKey()
{
return 'id';
}
public static function userExists($user)
{
return self::model()->countByAttributes( array('username'=>$user) ) > 0;
}
}
You can use all three models in a single function
for example:
In create function
$model_account = new user_account;
$model_personal= new user_personal;
$model_general = new user_general;
$this->render('create',array(
'model_account'=>$model_account, 'model_personal' => $model_personal, 'model_general' => $model_general
));
here the all three models pass by render to create page.
in form page you can use the every model attributes as fields
Like this
echo $form->textField($model_account,'account_name');
echo $form->textField($model_personal,'email');
echo $form->textField($model_general,'address');
In create function / Update function
$model_account->attributes = $_POST['user_account'];
$model_personal->attributes = $_POST['user_personal'];
$model_general->attributes = $_POST['user_general'];
if($model_account->validate() && $model_personal->validate() && $model_general->validate())
{
$model_account->save();
$model_personal->save();
$model_general->save();
}