SQL: Display the table and its job by yes and no - sql

Question

This is my table:
User Table
Id | Username |
---------------
1 | jdoe |
Job Table
Id | Job |
----------------
1 | Waiter |
2 | Office |
3 | Freelance |
User Job Table
Id |UserId | JobId |
--------------------
1 | 1 | 2 |
2 | 1 | 3 |
How to select this table and display it to look like this below:
Id | Username | Waiter| Office | Freelance|
-------------------------------------------
1 | jdoe | No | Yes | Yes |

Answer 1

This is a pretty standard pivot query question, with an additional slight twist. In case a given user does not have a certain type of job assigned, you want to display 'No'. One way to do this is to make use of COALESCE and replace NULL job aggregates.
SELECT u.Id,
u.Username,
COALESCE(MAX(CASE WHEN j.Job = 'Waiter' THEN 'Yes' END), 'No') AS Waiter,
COALESCE(MAX(CASE WHEN j.Job = 'Office' THEN 'Yes' END), 'No') AS Office,
COALESCE(MAX(CASE WHEN j.Job = 'Freelance' THEN 'Yes' END), 'No') AS Freelance
FROM User u
LEFT JOIN User_Job uj
ON u.Id = uj.UserId
LEFT JOIN Job j
ON uj.JobId = j.Id
GROUP BY u.Id,
u.Username

Answer 2

Try this..
WITH cte AS
(
SELECT u.username,job,CASE WHEN uj.jobid IS NULL THEN 'No' ELSE 'yes' END AS jobid
FROM USER u INNER JOIN UserJob uj on u.id = uj.Userid
RIGHT JOIN Job j on j.id = uj.jobid
)
SELECT username,ISNULL(waiter,'no') waiter,
ISNULL(Office,'no') Office,
ISNULL(Freelance,'no') Freelance
FROM cte
PIVOT
(
MAX(jobid) FOR job IN (Waiter, Office,Freelance)
) piv
WHERE username IS NOT NULL

Answer 3

DECLARE #cols AS NVARCHAR(MAX),#Listcols AS NVARCHAR(MAX),
#query AS NVARCHAR(MAX)
select #cols = STUFF((SELECT ',' + 'Isnull('+QUOTENAME(t.Job) +',''No'') as ' + t.Job
from Job t
order by Job desc
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select #Listcols = STUFF((SELECT ',' + QUOTENAME(t.Job)
from Job t
order by Job desc
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set #query = N'SELECT Id, Username,' + #cols + N' from
(
select D1.Id, D1.Username,
COALESCE(CASE WHEN isnull(D2.UserId,0) > 0 THEN ''Yes''
Else ''No''
End, ''No'') as UserId,
D3.Job
from [User] D1
Inner Join User_Job D2
On D1.Id = D2.UserId
Inner Join Job D3
On D2.JobId = D3.Id
) x
pivot
(
max(UserId)
for Job in (' + #Listcols + N')
) p '
exec sp_executesql #query;

Answer 4

If the job items are come from a result.
CREATE TABLE #T1(id INT ,Username VARCHAR(100))
INSERT INTO #T1 SELECT 1,'jdoe'
CREATE TABLE #T2(id INT ,Job VARCHAR(100))
INSERT INTO #T2 VALUES(1,'Waiter'),(2,'Office'),(3,'Freelance')
CREATE TABLE #T3(id INT ,UserId INT ,JobId INT )
INSERT INTO #T3 VALUES(1,1,2),(2,1,3)
DECLARE #col NVARCHAR(max),#sql NVARCHAR(max)
SELECT #col=ISNULL(#col+',[','[')+Job+']' FROM #t2
PRINT #col
SET #sql='
SELECT * FROM (
SELECT uj.Job,uj.Username,CASE WHEN t3.UserId IS NULL THEN ''No'' ELSE ''Yes'' END AS f FROM (
SELECT t2.id AS JobId, t2.Job,t1.id AS UserId, t1.Username
FROM #T1 AS t1,#t2 AS t2
) uj LEFT JOIN #T3 AS t3 ON t3.JobId = uj.JobId AND t3.UserId = uj.UserId
) AS t PIVOT(MAX(f) FOR job IN ('+#col+')) p'
EXEC(#sql)