I am attempting to add together the values_occurrence for the id's that match. For example ID number 1 has 3 and another record shows ID number 1 having 4. I want to ADD 3 + 4 based on the ID matching.
I am trying to see which ID has the most entries in each table and then add them together.
ID value_occurrence
--------------------
1 3
1 4
so far this is what I have.
SELECT ID, COUNT(ID) AS value_occurrence
FROM TABLE1
GROUP BY ID
UNION
SELECT ID, COUNT(ID) AS value_occurrence
FROM TABLE2
GROUP BY ID
ORDER BY ID ASC;
Any help would be appreciated.
Do a union all and then aggregate:
select id, count(*) as total_cnt, sum(t1) as t1_cnt, sum(t2) as t2_cnt
from ((select id, 1 as t1, 0 as t2 from table1) union all
(select id, 0, 1 from table2)
) t
group by id
order by id;
Related
I have 3 table and I need to get the details from 2 tables where the count of UNION is greater than 1.But need to apply certain conditions as well
Table A
id entity_id name category
1 45 abcd win_1
2 46 efgh win_2
3 47 efgh1 win_2
4 48 dfgh win_5
5 49 adfgh win_4
Table B
id product_id name parent_id
1 P123 asdf win_1
2 P234 adfgh win_4
Table 3 category_list
id cat_id name
1 win_1 Households
2 win_2 Outdoors
3 win_3 Mixed
4 win_4 Omni
Now I need to have the count of UNION from Table A and Table B where they have count of cat_id greater than 1 and Table A.name != Table B.name
The result which I require is
p_id name cat_id
45 abcd win_1
P123 asdf win_1
46 efgh win_2
47 efgh1 win_2
win_5 is excluded as the count is one and win_4 should be excluded as name in Table A nd B is same.
I have run out of Ideas as i am relatively new to Oracle and DB.Any help is appreciated.
I think you can use exists to ensure that the cat_id is present in both tables
select entity_id as p_id, name, category as cat_id
from table_a a
where exists (select null from table_b where a.category = table_b.parent_id)
union
select entity_id, name, parent_id
from table_b b
where exists (select null from table_a where b.parent_id = table_a.category)
I believe you are looking for something like this -
Select T2.*
from
(Select category
from
(Select name, category from TableA
Union all
Select name, parent_id as category from TableB) t
group by category
having count(distinct name) > 1) T1
Join
(Select entity_id as Pid, name, category from TableA
Union
Select product_id as Pid, name, parent_id as category from TableB) T2
ON T1.category = T2.category;
Would you try this code.
First CTE (Common Table Expression) "list_union" gets the records for each table those have different names then makes the union. with the second CTE "list_cnt" counts the categories and finally gets the result cnt>1 with the last select statement as you pictured.
With
list_union AS (
SELECT
id,
----------
TO_CHAR(entity_id) entity_id,
----------
name,
category
FROM table_A a
WHERE NOT EXISTS(SELECT 1 FROM table_B b WHERE a.name=b.name)
----------
UNION ALL
----------
SELECT
id,
product_id,
name,
parent_id
FROM table_B b
WHERE NOT EXISTS(SELECT 1 FROM table_A a WHERE a.name=b.name)
)
,list_cnt AS (
SELECT
l.*,
----------
COUNT(*) over (PARTITION BY category) cnt
----------
FROM list_union l
)
SELECT
entity_id AS p_id,
name,
category AS cat_id
FROM list_cnt
WHERE cnt>1
ORDER BY cat_id ASC, p_id ASC
;
Just use a union all and window functions:
select ab.*
from (select ab.*,
count(distinct name) over (partition by category) as cnt
from ((select a.* from a
) union all
(select b.* from b
)
) ab
) ab
where cnt > 1;
Although you describe the problem as:
Now I need to have the count of UNION from Table A and Table B where they have count of cat_id greater than 1 and Table A.name != Table B.name
You seem to just want cat_ids that have different names across the two tables. Your sample data includes cat_id = 'win_2', which is not even in the second table.
Let's say I have a data
ID
AAA
ABB
ABC
BDS
BRD
CXD
DCU
ETS
I would like to count distinct to a first letter rows and get the number of their appearance to the right. Sorry I know I am not a very good user of a technical language, but I am new to SQL and English is not my first language.
So by script I would like to return
ID Total
A 3
B 2
C 1
D 1
E 1
I have tried
select left(id,1), count(left(id,1) as Total
from Places
group by Id
order by Total desc;
, but it didn't work. Your help will be greatly appreciated.
select left(id,1), count(*) as Total
from Places
group by left(id,1)
order by Total desc;
Is this you need?
declare #t table(val varchar(10))
insert into #t
select 'AAA' union all
select 'ABB' union all
select 'ABC' union all
select 'BDS' union all
select 'BRD' union all
select 'CXD' union all
select 'DCU' union all
select 'ETS'
select left(t1.val,1) as id ,count(t1.val) as total from #t as t1 left join
(
select distinct right(val,1) as val from #t
) as t2 on t1.val =t2.val
group by left(t1.val,1)
Result is
id total
---- -----------
A 3
B 2
C 1
D 1
E 1
Current SQL:
select t1.*
from table t1
where t1.id in ('2', '3', '4')
Current results:
id | seq
---+----
3 | 5
2 | 7
2 | 5
3 | 7
4 | 3
Attempt to select maxes:
select t1.*
from table t1
where t1.id in ('2', '3', '4')
and t1.seq = (select max(t2.seq)
from table2 t2
where t2.id = t1.id)
This obviously does not work since I'm using an in list. How can I adjust my SQL to get these expected results:
id | seq
---+----
2 | 7
3 | 7
4 | 3
Group By is your friend:
SELECT
id,
MAX(seq) seq
FROM TABLE
GROUP BY id
EDIT: Response to comment. To get the rest of the data from the table matching the max seq and id just join back to the table:
SELECT t1.*
FROM TABLE t1
INNER JOIN (
SELECT
id
MAX(seq) as seq
FROM TABLE
GROUP BY id
) as t2
on t1.id = t2.id
and t1.seq = t2.seq
EDIT: Gordon and Jean-Francois are correct you can also use the ROW_NUMBER() analytic function to get the same result. You need to check the performance difference for your application (I did not check). Here is an example of that:
SELECT *
FROM (
SELECT ROW_NUMBER() OVER (
PARTITION BY id
ORDER BY seq DESC) as row_num
,*
FROM TABLE
) as TMP
WHERE row_num = 1
This SQL Query will give you max seq from individaul ID.
SELECT t1.*
FROM t1
WHERE t1.id in ('2', '3', '4')
AND NOT EXISTS (
SELECT *
FROM t1 t2
WHERE t2.id = t1.id
AND t2.seq > t1.seq
select *
from table
where (id,seq) in
(
select id,max(seq)
from table
group by id
having id in ('2','3','4')
);
That is if id and/or seq are completely part of the PK of that table.
Here's another example, using the first/last method I mentioned earlier in the comments:
with sd as (select 3 id, 5 seq, 1 dummy from dual union all
select 2 id, 7 seq, 2 dummy from dual union all
select 2 id, 5 seq, 3 dummy from dual union all
select 3 id, 7 seq, 4 dummy from dual union all
select 3 id, 7 seq, 5 dummy from dual union all
select 4 id, 3 seq, 6 dummy from dual)
select id,
max(seq) max_seq,
max(dummy) keep (dense_rank first order by seq desc) max_rows_dummy
from sd
group by id;
ID MAX_SEQ MAX_ROWS_DUMMY
---------- ---------- --------------
2 7 2
3 7 5
4 3 6
The keep (dense_rank first order by ...) bit is requesting to keep the values associated with the rank of 1 in the order list of rows. The max(...) bit is there in case more then one row has a rank of 1; it's just a way of breaking ties.
I have 2 columns in a one-to-many relationship. I want to sort on the "many" and return the first occurrence of the "one". I need to page through the data so, for example, I need to be able to get the 3rd group of 10 unique "one" values.
I have a query like this:
SELECT id, name
FROM table1
INNER JOIN table2 ON table2.fkid = table1.id
ORDER BY name, id;
There can be multiple rows in table2 for each row in table1.
The results of my query look like this:
id | name
----------------
2 | apple
23 | banana
77 | cranberry
23 | dark chocolate
8 | egg
2 | yak
19 | zebra
I need to page through the result set with each page containing n unique ids. For example, if start=1 and n=4 I want to get back
2
23
77
8
in the order they were sorted on (i.e., name), where id is returned in the position of its first occurrence. Likewise if start=3 and n=4 and order = desc I want
8
23
77
2
I tried this:
SELECT * FROM (
SELECT id, ROWNUM rnum FROM (
SELECT DISTINCT id FROM (
SELECT id, name
FROM table1
INNER JOIN table2 ON table2.fkid = table1.id
ORDER BY name, id)
WHERE ROWNUM <= 4)
WHERE rnum >=1)
which gave me the ids in numerical order, instead of being ordered as the names would be.
I also tried:
SELECT * FROM (
SELECT DISTINCT id, ROWNUM rnum FROM (
SELECT id FROM (
SELECT id, name
FROM table1
INNER JOIN table2 ON table2.fkid = table1.id
ORDER BY name, id)
WHERE ROWNUM <= 4)
WHERE rnum >=1)
but that gave me duplicate values.
How can I page through the results of this data? I just need the ids, nothing from the "many" table.
update
I suppose I'm getting closer with changing my inner query to
SELECT id, name, rank() over (order by name, id)
FROM table1
INNER JOIN table2 ON table2.fkid = table1.id
...but I'm still getting duplicate ids.
You may need to debug it a little, but but it will be something like this:
SELECT * FROM (
SELECT * FROM (
SELECT id FROM (
SELECT id, name, row_number() over (partition by id order by name) rn
FROM table1
INNER JOIN table2 ON table2.fkid = table1.id
)
) WHERE rn=1 ORDER BY name, id
) WHERE rownum>=1 and rownum<=4;
It's a bit convoluted (and I would tend to suspect that it could be simplified) but it should work. You'd can put whatever start and end position you want in the WHERE clause-- I'm showing here with start=2 and n=4 are pulled from a separate table but you could simplify things by using a couple of parameters instead.
SQL> ed
Wrote file afiedt.buf
1 with t as (
2 select 2 id, 'apple' name from dual union all
3 select 23, 'banana' from dual union all
4 select 77, 'cranberry' from dual union all
5 select 23, 'dark chocolate' from dual union all
6 select 8, 'egg' from dual union all
7 select 2, 'yak' from dual union all
8 select 19, 'zebra' from dual
9 ),
10 x as (
11 select 2 start_pos, 4 n from dual
12 )
13 select *
14 from (
15 select distinct
16 id,
17 dense_rank() over (order by min_id_rnk) outer_rnk
18 from (
19 select id,
20 min(rnk) over (partition by id) min_id_rnk
21 from (
22 select id,
23 name,
24 rank() over (order by name) rnk
25 from t
26 )
27 )
28 )
29 where outer_rnk between (select start_pos from x) and (select start_pos+n-1 from x)
30* order by outer_rnk
SQL> /
ID OUTER_RNK
---------- ----------
23 2
77 3
8 4
19 5
Using Sql Server
I want to get max value from two table
Table1
ID Total
101 100
102 600
.....
Table2
ID Total
101 300
102 400
....
I want to get a max value from 2 table according to the id
Expected Output
ID Total
101 300 (max value in table2)
102 600 (max value in table1)
....
...
How to make a Query
Need Query Help
SELECT
ID, MAX(Total)
FROM
(
SELECT ID, Total FROM Table1
UNION ALL
SELECT ID, Total FROM Table2
) foo
GROUP BY
ID
; with
q_00 as (
select id, Total from Tbl_1
union all
select id, Total from Tbl_2
)
select id, max(Total)
from q_00
group by id
order by id ;
One other option worth considering might be
WITH T(ID, Total)
AS (SELECT ID,
MAX(Total)
FROM Table1
GROUP BY ID
UNION ALL
SELECT ID,
MAX(Total)
FROM Table2
GROUP BY ID)
SELECT ID,
MAX(Total) AS Total
FROM T
GROUP BY ID
If ID,Total is indexed in the two tables possibly this might give a better plan (untested)