For example,
I have output like this :-
ID
---
AB1
AB2
AB3
AB4
BD6
If I use MAX(ID), I will get 'BD6' But I want to check MAX Value For Pattern AB
How can I get that?
Simply filter the Data with ID field and then use Max():
EDIT: If ID contains number with more than 1 digits:
SELECT TOP 1 *
FROM
[Table] AS A
WHERE
RIGHT(ID, LEN(ID) - 2) = (SELECT
MAX(Cast(RIGHT(ID, LEN(ID) - 2) AS Int)) FROM [Table] WHERE ID LIKE 'AB%')
AND
ID LIKE 'AB%'
Try This. It will display all max ID for every String .
select CONCAT(ID,id1) as ID from
(
select left(id, patindex('%[^0-9]%', id) + 1) ID , max(cast(substring(id, PatIndex('%[0-9]%', id),len(id)) as numeric)) id1
from #Table
group by left(id, patindex('%[^0-9]%', id) + 1)
)a
For Specific ID value like 'AB' put value into where clause .
select CONCAT(ID,id1) as ID from
(
select left(id, patindex('%[^0-9]%', id) + 1) ID , max(cast(substring(id, PatIndex('%[0-9]%', id),len(id)) as numeric)) id1
from #Table
group by left(id, patindex('%[^0-9]%', id) + 1)
)a
where ID like '%ab%'
OutPut :
outpur for AB111
Check also live demo here.
Try it,
DECLARE #TABLE TABLE(ID VARCHAR(MAX))
INSERT INTO #TABLE (ID)
VALUES('AB1'),('AB2'),('AB3'),('AB4'),('AB11'),('AB111'),('XY112')
DECLARE #Prefix VARCHAR (10) = 'AB'
SELECT #Prefix + CAST(MAX(CAST(SUBSTRING(ID, (LEN(#Prefix) + 1),
(LEN(ID) - 2)) AS INT)) AS VARCHAR) AS ID FROM #TABLE WHERE ID LIKE
#Prefix +'%'
Try this :
SELECT 'AB' + CONVERT(NVARCHAR(10),MAX(CONVERT(INT, Nums.Numbers)))
FROM (SELECT Substring(ID, 3, 10) as Numbers
FROM #Tab tab
WHERE tab.ID LIKE 'AB%') as Nums
You can see this here => http://rextester.com/MAHKWE99983
Hope this helps!!!
You can get by this query.
create table temp
(
id varchar(10)
);
insert into temp values
('AB111'),
('AB1'),
('AB2'),
('AB3'),
('AB4'),
('BD6'),
('AB111')
;
declare #Pattern varchar(5)
set #Pattern='AB'
select distinct(Id) from temp where Id = #Pattern+convert(varchar(10),(
select MAX(Id) as Maximum from (
SELECT convert(integer,REPLACE( Id,#Pattern,'')) as Id FROM temp
where id like 'AB%'
)as test ))
with tmp as (
select 'AB1' id union all
select 'AB2' id union all
select 'AB3' id union all
select 'AB4' id union all
select 'AB111' id union all
select 'BD6' id
)
select top 1 * from tmp f1
where f1.ID LIKE 'AB%' and cast(SUBSTRING(f1.ID, 3, LEN(ID) -2) as integer) in
(
select max(cast(SUBSTRING(f2.ID, 3, LEN(ID) -2) as integer)) from tmp f2
WHERE f2.ID LIKE 'AB%'
)
SELECT MAX(ID) FROM #Tbl
GROUP BY LEFT(col_name,2)
Related
We have this column in the table named "pricehistory"
1634913730;48.38,1634916509;48.38,1635162352;37.96,1635177904;49.14,1635337722;1219.98,1635340811;27.17
that is an example data.
first is the timestamp than after ; is the price at this timestamp
But i want the average price from every timestamp in a select... is that possible?
I dont find any similiar examples somewhere and my tries to select doesnt work... i am not so good with sql
so i want average of all prices behind that ; and before ,
The , split the timestamp and prices
Some test data :
create table test ( id int not null, pricehistory text not null );
insert into test values ( 1, '1634913730;48.38,1634916509;48.38,1635162352;37.96,1635177904;49.14,1635337722;1219.98,1635340811;27.17' );
insert into test values ( 2, '1634913731;42.42,1634916609;21.21' );
If your RDBMS has some splitting function
Then it's quite easy, just split and use AVG. Here is an example using PostgreSQL :
SELECT id, AVG(SUBSTRING(v, 12, 42)::decimal) AS average
FROM test
INNER JOIN LATERAL regexp_split_to_table(pricehistory, E',') t(v) ON TRUE
GROUP BY id;
Then you get:
id | average
----+----------------------
2 | 31.8150000000000000
1 | 238.5016666666666667
(2 rows)
Otherwise
You can use a CTE to split the values manually. This is a bit more involved. Here is an example using PostgreSQL again :
WITH RECURSIVE T AS (
SELECT id,
-- We get the last value ...
SUBSTRING(pricehistory, LENGTH(pricehistory) - STRPOS(REVERSE(pricehistory), ',') + 2) AS oneprice,
pricehistory AS remaining
FROM test
UNION ALL
-- ... as we get the other values from the recursive CTE.
SELECT id,
LEFT(remaining, STRPOS(remaining, ',') - 1),
SUBSTRING(remaining, STRPOS(remaining, ',') + 1)
FROM T
WHERE STRPOS(remaining, ',') > 0
)
SELECT id, AVG(SUBSTRING(oneprice, 12)::decimal) AS average
FROM T
GROUP BY id;
Then you get:
id | average
----+----------------------
2 | 31.8150000000000000
1 | 238.5016666666666667
(2 rows)
MySql >= 8.0
I used Recursive Common Table Expressions (cte) to split pricehistory string by ','. Then I split price from timestamp by ';', cast price as decimal(10,2) and group by id to get average price by id.
WITH RECURSIVE
cte AS (SELECT id,
SUBSTRING_INDEX(pricehistory, ',', 1) AS price,
CASE WHEN POSITION(',' IN pricehistory) > 0
THEN SUBSTR(pricehistory, POSITION(',' IN pricehistory) + 1)
ELSE NULL END AS rest
FROM t
UNION ALL
SELECT id,
SUBSTRING_INDEX(rest, ',', 1) AS price,
CASE WHEN POSITION(',' IN rest) > 0
THEN SUBSTR(rest, POSITION(',' IN rest) + 1)
ELSE NULL END AS rest
FROM cte
WHERE rest IS NOT NULL)
SELECT id, AVG(CAST(SUBSTR(price, POSITION(';' IN price) + 1) AS decimal(10,2))) AS price_average
FROM cte
GROUP BY id;
A similar way to do the same (using regular expressions functions):
WITH RECURSIVE
cte AS (SELECT Id, concat(pricehistory, ',') AS pricehistory FROM t),
unnest AS (SELECT id,
pricehistory,
1 AS i,
REGEXP_SUBSTR(pricehistory, ';[0-9.]*,', 1, 1) AS price
FROM cte
UNION ALL
SELECT id,
pricehistory,
i + 1,
REGEXP_SUBSTR(pricehistory, ';[0-9.]*,', 1, i + 1)
FROM unnest
WHERE REGEXP_SUBSTR(pricehistory, ';[0-9.]*,', 1, i + 1) IS NOT NULL)
SELECT id, AVG(CAST(SUBSTR(price, 2, LENGTH(price) - 2) AS decimal(10,2))) AS price_average
FROM unnest
GROUP BY id;
you don't write what DBMS you are using.
In MS SQL-SERVER you can write something like this.
Create a function to convert string to multiple rows, and then use that in the query.
CREATE or ALTER FUNCTION dbo.BreakStringIntoRows (#CommadelimitedString varchar(1000), #Separator VARCHAR(1))
RETURNS #Result TABLE (Column1 VARCHAR(max))
AS
BEGIN
DECLARE #IntLocation INT
WHILE (CHARINDEX(#Separator, #CommadelimitedString, 0) > 0)
BEGIN
SET #IntLocation = CHARINDEX(#Separator, #CommadelimitedString, 0)
INSERT INTO #Result (Column1)
--LTRIM and RTRIM to ensure blank spaces are removed
SELECT RTRIM(LTRIM(SUBSTRING(#CommadelimitedString, 0, #IntLocation)))
SET #CommadelimitedString = STUFF(#CommadelimitedString, 1, #IntLocation, '')
END
INSERT INTO #Result (Column1)
SELECT RTRIM(LTRIM(#CommadelimitedString))--LTRIM and RTRIM to ensure blank spaces are removed
RETURN
END
create table test1 ( id int not null, pricehistory varchar(max) not null );
insert into test1 values ( 1, '1634913730;48.38,1634916509;48.38,1635162352;37.96,1635177904;49.14,1635337722;1219.98,1635340811;27.17' );
insert into test1 values ( 2, '1634913731;42.42,1634916609;21.21' );
Select *,
(
Select avg(CAST(RTRIM(LTRIM(SUBSTRING(column1, 0, CHARINDEX(';', column1, 0)))) as decimal)) From dbo.BreakStringIntoRows(pricehistory, ',')
) as AVG
FRom test1
sample output:
I have a table as the following
name
-----------
1#apple#1
2#apple#2
3#apple#4
4#box#4
5#box#5
and I want to get the result as:
name
--------------
apple 3
box 2
Thanks in advance for your help
This is what you need.
select
SUBSTRING(
name,
CHARINDEX('#', name) + 1,
LEN(name) - (
CHARINDEX('#', REVERSE(name)) + CHARINDEX('#', name)
)
),
count(1)
from
tbl
group by
SUBSTRING(
name,
CHARINDEX('#', name) + 1,
LEN(name) - (
CHARINDEX('#', REVERSE(name)) + CHARINDEX('#', name)
)
)
If your data does not contain any full stops (or periods depending on your vernacular), and the length of your string is less than 128 characters, then you can use PARSENAME to effectively split your string into parts, and extract the 2nd part:
DECLARE #T TABLE (Val VARCHAR(20));
INSERT #T (Val)
VALUES ('1#apple#1'), ('2#apple#2'), ('3#apple#4'),
('4#box#4'), ('5#box#5');
SELECT Val = PARSENAME(REPLACE(t.Val, '#', '.'), 2),
[Count] = COUNT(*)
FROM #T AS t
GROUP BY PARSENAME(REPLACE(t.Val, '#', '.'), 2);
Otherwise you will need to use CHARINDEX to find the first and last occurrence of # within your string (REVERSE is also needed to get the last position), then use SUBSTRING to extract the text between these positions:
DECLARE #T TABLE (Val VARCHAR(20));
INSERT #T (Val)
VALUES ('1#apple#1'), ('2#apple#2'), ('3#apple#4'),
('4#box#4'), ('5#box#5');
SELECT Val = SUBSTRING(t.Val, x.FirstPosition + 1, x.LastPosition - x.FirstPosition),
[Count] = COUNT(*)
FROM #T AS t
CROSS APPLY
( SELECT CHARINDEX('#', t.Val) ,
LEN(t.Val) - CHARINDEX('#', REVERSE(t.Val))
) AS x (FirstPosition, LastPosition)
GROUP BY SUBSTRING(t.Val, x.FirstPosition + 1, x.LastPosition - x.FirstPosition);
use case when
select case when name like '%apple%' then 'apple'
when name like '%box%' then 'box' end item_name,
count(*)
group by cas when name like '%apple%' then 'apple'
when name like '%box%' then 'box' end
No DBMS specified, so here is a postgres variant. The query does use regexps to simplify things a bit.
with t0 as (
select '1#apple#1' as value
union all select '2#apple#2'
union all select '3#apple#4'
union all select '4#box#4'
union all select '5#box#5'
),
trimmed as (
select regexp_replace(value,'[0-9]*#(.+?)#[0-9]*','\1') as name
from t0
)
select name, count(*)
from trimmed
group by name
order by name
DB Fiddle
Update
For Oracle DMBS, the query stays basically the same:
with t0 as (
select '1#apple#1' as value from dual
union all select '2#apple#2' from dual
union all select '3#apple#4' from dual
union all select '4#box#4' from dual
union all select '5#box#5' from dual
),
trimmed as (
select regexp_replace(value,'[0-9]*#(.+?)#[0-9]*','\1') as name
from t0
)
select name, count(*)
from trimmed
group by name
order by name
NAME | COUNT(*)
:---- | -------:
apple | 3
box | 2
db<>fiddle here
Update
MySQL 8.0
with t0 as (
select '1#apple#1' as value
union all select '2#apple#2'
union all select '3#apple#4'
union all select '4#box#4'
union all select '5#box#5'
),
trimmed as (
select regexp_replace(value,'[0-9]*#(.+?)#[0-9]*','$1') as name
from t0
)
select name, count(*)
from trimmed
group by name
order by name
name | count(*)
:---- | -------:
apple | 3
box | 2
db<>fiddle here
You can use case and group by to do the same.
select new_col , count(new_col)
from
(
select case when col_name like '%apple%' then 'apple'
when col_name like '%box%' then 'box'
else 'others' end new_col
from table_name
)
group by new_col
;
I need to truncate data from a column to 10 characters. However, I cannot have any duplicates, so I want any duplicates to end with ~1 for the first duplicate, ~2 for the second duplicate. Here's an example of what I have:
Column
------
The ABC Company Inc.
The ABC Cooperative
XYZ Associates LLC.
I'd like the result to be:
Column
------
The ABC ~1
The ABC ~2
XYZ Associ
The end doesn't have to be ~1 or ~2, I just need something to make it unique after truncating. There may be more than 3 or 4 duplicates after truncating.
So far, I'm just truncating and editing the table manually:
update Table set Column = Left(Column, 10) where len(Column) > 10
First, you care about the first 8 characters, not the first 10, because you need to reserve slots for the additional number.
Assuming that you have fewer than 10 repeats, you can do this:
with toupdate as (
select t.*,
row_number() over (partition by left(col, 8) order by (select null)) as seqnum,
count(*) over (partition by left(col, 8) ) as cnt
from t
update toupdate
set col = (case when cnt = 1 then left(col, 10)
else left(col, 8) + '~' + cast(seqnum as char(1));
The same idea can be used for a select.
Declare #Table Table (Column1 varchar(50))
Insert into #Table values
('The ABC Company Inc.'),
('The ABC Cooperative'),
('XYZ Associates LLC.')
Select NewColumn = Concat(substring(Column1,1,10),' ~',Row_Number() over (Partition By substring(Column1,1,10) Order by Column1))
From #Table
Returns
NewColumn
The ABC Co ~1
The ABC Co ~2
XYZ Associ ~1
The numbers are noisy, so I only add them when necessary:
select case when _r > 1
then Company + '~' + cast(_r as varchar(5))
else Company end as Company
from (
select Company
, ROW_NUMBER() over (partition by Company order by Company) as _r
from(
select left(Company, 10) as Company
from MyTable
) x
) y
order by Company
Company
--------------
The ABC Co
The ABC Co~2
XYZ Associ
Assuming your table is COMPANY and the field is CompanyName.....
You'll have to tweek but hope it helps..
SELECT SUBSTRING( Q.Comp, 1, 5) + '~' + CONVERT(nvarchar(4), Row) as NewFieldValue FROM
(
SELECT ROW_NUMBER() OVER(PARTITION BY SUBSTRING( C.CompanyName, 1, 6) ORDER BY SUBSTRING( C.CompanyName, 1, 6)) AS Row,
SUBSTRING( C.CompanyName, 1, 6) as Comp
FROM COMPANY C
)Q
DECLARE #Table TABLE (Column1 varchar(50))
INSERT INTO #Table VALUES
('The ABC Company Inc.')
, ('The ABC Cooperative')
, ('XYZ Associates LLC.')
, ('Acme')
, ('Ten Char 123')
, ('Ten Char 132')
, ('Ten Char 231')
;WITH FLen
AS (
SELECT Column1, LEFT(LEFT(Column1,13) + SPACE(13),13) + CHAR(164) AS Column2
FROM #Table
)
,TenCharPD -- Includes possible duplicates
AS (
SELECT Column1, LEFT(Column2,8) +
RIGHT('0' + CAST (
(ASCII(SUBSTRING(Column2, 9,1)) +
ASCII(SUBSTRING(Column2,10,1)) +
ASCII(SUBSTRING(Column2,11,1)) +
ASCII(SUBSTRING(Column2,12,1)) +
ASCII(SUBSTRING(Column2,13,1)))%100
AS NVARCHAR(2)),2) AS Column2
FROM Flen
)
,CullPD
AS (
SELECT Column1, Column2,
ROW_NUMBER() OVER (PARTITION BY Column2 ORDER BY Column2) AS rowx
FROM TenCharPD
)
UPDATE t1
SET Column1 = LEFT(Column2,9) +
CASE rowx
WHEN 1 THEN RIGHT(Column2,1)
ELSE CHAR(rowx + CAST (RIGHT(Column2,1) AS INT) * 5 + 63)
END
FROM #Table t1
JOIN CullPD cpd
ON t1.Column1 = cpd.Column1
SELECT * FROM #Table
select MAX (cast (id as numeric)) from table --whatever value it may return
select
(row_number () over (order by id)) as Number from table --will start at 1
How do I combine the two so whatever value the first query returns, I can use that value and auto increment from there, somehow combining the two (tried nesting them, but unsuccessful) or do I need to...
Declare a variable
get my max id value
make my variable equal to that
then place that value/variable in my second statement?
Like...
select
(row_number () over (order by id) + (declared_max_value)) as Number from table
Try this:
WITH CTE as
(SELECT max(Field) FROM Table)
SELECT WhatYouWant, cte.m FROM Table2
INNER JOIN CTE ON 0=0
or this:
SELECT *, t.maxField FROM Table1 OUTER APPLY (SELECT max(Field) as maxField FROM Table2) t
Try this:
SELECT
Seed.ID + ROW_NUMBER() OVER (order by T.ID) as Number,
T.ID
FROM
T CROSS JOIN
(SELECT MAX(ID) AS ID FROM T) AS Seed
Working sample: http://www.sqlfiddle.com/#!3/a14ad/3
declare #maxValue int
select #maxValue = select max(cast (id as integer)) from table
declare #uaerystring varchar(max)
select #queryString =
'(row_number () over (order by id) + '
+ #maxValue +
')as Number from table'
Execute(#queryString)
DECLARE #T Table (ID int , Value Varchar(20))
INSERT INTO #T (ID, Value)
VALUES (50, 'Value1'), (500, 'Value1'), (100, 'Value1'), (50, 'Value2'), (100, 'Value2'),(500, 'Value2')
;with CTE (Value, ID, rn)
AS
(
SELECT Value, MAX(ID), rn = ROW_NUMBER() OVER (ORDER BY Value ASC)
FROM
#T
GROUP BY Value
)
SELECT * FROM CTE
I have data such as this:
Inventors column in my table
Hundley; Edward; Ana
Isler; Hunsberger
Hunsberger;Hundley
Names are separated by ;. I want to write a SQL query which sums up the count.
Eg. The result should be:
Hundley 2
Isler 1
Hunsberger 2
Edward 1
Ana 1
I could do a group by but this is not a simple group by as you can see. Any ideas/thoughts on how to get this output?
Edit: Changed results so it doesn't create any confusion that a row only contains 2 names.
You can take a look at this. I certainly do not recommend this way if you have lots of data, BUT you can do some modifications and use it and it works like a charm!
This is the new code for supporting unlimited splits:
Declare #Table Table (
Name Nvarchar(50)
);
Insert #Table (
Name
) Select 'Hundley; Edward; Anna'
Union Select 'Isler; Hunsberger'
Union Select 'Hunsberger; Hundley'
Union Select 'Anna'
;
With Result (
Part
, Remained
, [Index]
, Level
) As (
Select Case When CharIndex(';', Name, 1) = 0
Then Name
Else Left(Name, CharIndex(';', Name, 1) - 1)
End
, Right(Name, Len(Name) - CharIndex(';', Name, 1))
, CharIndex(';', Name, 1)
, 1
From #Table
Union All
Select LTrim(
Case When CharIndex(';', Remained, 1) = 0
Then Remained
Else Left(Remained, CharIndex(';', Remained, 1) - 1)
End
)
, Right(Remained, Len(Remained) - CharIndex(';', Remained, 1))
, CharIndex(';', Remained, 1)
, Level
+ 1
From Result
Where [Index] <> 0
) Select Part
, Count(*)
From Result
Group By Part
Cheers
;with cte as
(
select 1 as Item, 1 as Start, CHARINDEX(';',inventors, 1) as Split, Inventors from YourInventorsTable
union all
select cte.Item+1, cte.Split+1, nullif(CHARINDEX(';',inventors, cte.Split+1),0), inventors as Split
from cte
where cte.Split<>0
)
select rTRIM(lTRIM(SUBSTRING(inventors, start,isnull(split,len(inventors)+1)-start))), count(*)
from cte
group by rTRIM(lTRIM(SUBSTRING(inventors, start,isnull(split,len(inventors)+1)-start)))
You can create a split function to split the col values
select splittedValues.items,count(splittedValues) from table1
cross apply dbo.split(col1,';') splittedValues
group by splittedValues.items
DEMO in Sql fiddle
first make one function who take your comma or any other operator(;) separated string into one table and by using that temp table, apply GROUP function on that table.
So you will get count for separate value.
"select d.number,count(*) from (select number from dbo.CommaseparedListToTable('Hundley;Edward;Ana;Isler;Hunsberger;Hunsberger;Hundley',';'))d
group by d.number"
declare #text nvarchar(255) = 'Edward; Hundley; AnaIsler; Hunsberger; Hunsberger; Hundley ';
declare #table table(id int identity,name varchar(50));
while #text like '%;%'
Begin
insert into #table (name)
select SUBSTRING(#text,1,charindex(';',#text)-1)
set #text = SUBSTRING(#text, charindex(';',#text)+1,LEN(#text))
end
insert into #table (name)
select #text
select name , count(name ) counts from #table group by name
Output
name count
AnaIsler 1
Hundley 2
Hunsberger 2
Edward 1