How to parse json data in SQL Server 2012? - sql

Question

I am using SQL Server 2012.I have been assigned a task where one of my column (JsonText) of table Sample contains json data. I want to pass parse that data and insert into columns of another table (Test). I searched on net 'openjson' is supported in SQL Server 2016. How to do in SQL Server 2012?
Table1 : Sample
Id JsonText Active
JsonText
webaddress?{'data':'{"PId": "XXXX","Status": "YES","Name":"XXX","Address":"XXXX","MobileNumber":"xxx"}'}
I am intrested only 'PID,Address,MobileNumber' columns not all.
Table Test structure like this
Id, PID, Address, MobileNumber

Answer 1

Isaac your code is not working with not quoted values e.g. {"isAuthorized":"false","customerID":null}. I fixed this and your function should look like this.
ALTER FUNCTION [dbo].[JSON_VALUE]
(
#JSON NVARCHAR(3000),
#column NVARCHAR(3000)
)
RETURNS NVARCHAR(3000)
AS
BEGIN
DECLARE #value NVARCHAR(3000);
DECLARE #trimmedJSON NVARCHAR(3000);
DECLARE #start INT;
DECLARE #end INT;
set #start = PATINDEX('%' + #column + '":%',#JSON) + LEN(#column) + 2;
SET #trimmedJSON = SUBSTRING(#JSON, #start, LEN(#JSON));
Set #end = CHARINDEX(',',#trimmedJSON);
SET #value = REPLACE(SUBSTRING(#trimmedJSON, 0, #end),'"','');
RETURN #value
END

Answer 2

I created a function compatible with SQL 2012 to take care of this
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
-- =============================================
-- Author: Isaac Adams
-- Create date: 7/12/2018
-- Description: Give the JSON string and the name of the column from which you want the value
-- =============================================
CREATE FUNCTION JSON_VALUE
(
#JSON NVARCHAR(3000),
#column NVARCHAR(3000)
)
RETURNS NVARCHAR(3000)
AS
BEGIN
DECLARE #value NVARCHAR(3000);
DECLARE #trimmedJSON NVARCHAR(3000);
DECLARE #start INT;
DECLARE #length INT;
SET #start = PATINDEX('%' + #column + '":"%',#JSON) + LEN(#column) + 3;
SET #trimmedJSON = SUBSTRING(#JSON, #start, LEN(#JSON));
SET #length = PATINDEX('%", "%', #trimmedJSON);
SET #value = SUBSTRING(#trimmedJSON, 0, #length);
RETURN #value
END
GO

Answer 3

>>> at JSON_VALUE function, at PATINDEX('%", "%', #trimmedJSON);
remove space from '%", "%'
if your JSON value is like
'{"street":"street1","street2":"street232423"}'

Answer 4

You can use JSON_VALUE(ColumnName,'$.Path') for pairs Json in TSQL, for example:
select JSON_VALUE(webaddress,'$.data.PID') as 'PID',
JSON_VALUE(webaddress,'$.data.Status') as 'Status',
JSON_VALUE(webaddress,'$.data.Name') as 'Name'
from test