How to find next bigger / equal text in SQL Server - sql

Question

I have a table like this
id | name
------+-----------
1 | aaa
5 | aaa
2 | bbb
4 | bbb
10 | bbb
7 | ccc
9 | ccc
In my Windows Forms app, I need to "find next" button
first find "aaa" with id 1
then find "aaa" with id 5
and then find "bbb" with id 2
I use this query
select
min(name)
from
table
where
[name] >='#name'
but it always returns "aaa"
and
select
min(name)
from
table
where
[name] >'#name'
this does not return other id's

Answer 1

select top 1
[name],[id]
from [table]
where ( [name] = #name
and [id] > #id
)
or [name] > #name
order by [name],[id]
or
lead looks on the next row when the rows are ordered by the order by expressions within the over clause.
select [name],[next_id] as [id]
from (select [id],[name],lead([id]) over (order by [name],#id) as [next_id]
from [table]
) t
where [name] = #name
and [id] = #id

Answer 2

You can sort the records and then on each button click just read the next record:
select name,
id
from Table
order by name,
id

Answer 3

Alright, I think this is what you want:
create table TestTable(id int, name nvarchar(max))
GO
insert into TestTable
values
(1, 'aaa'),
(5, 'aaa'),
(2, 'bbb'),
(4, 'bbb'),
(10, 'bbb'),
(7, 'ccc'),
(9, 'ccc')
GO
create function dbo.FindNext(#lastResultOrdinal int) returns nvarchar(max)
as begin
return (select name from TestTable order by name, id offset #lastResultOrdinal rows fetch next 1 rows only)
end
GO
create function dbo.LastOrdinalWasLast(#lastResultOrdinal int) returns bit
as begin
if ((select count(id) from TestTable) = #lastResultOrdinal)
return 1
return 0
end
GO
--Fetching First Result:
select dbo.FindNext(0)
select dbo.LastOrdinalWasLast(1)
--Fetching Last Result:
select dbo.FindNext(6)
select dbo.LastOrdinalWasLast(7)
The dbo.FindNext function supposed to do the work giving it the ordinal (zero-based index + 1) of the current row; while dbo.LastOrdinalWasLast makes sure that there's no more rows to fetch.