There are 2 tables - Products and Sales
Products
prod_id
prod_nm
Sales
prod_id
cust_id
sls_dt
sls_amt
Write a query selecting ALL the products. For each product show total of sales amounts in the past 30 days or 0 if not sold in 30 day withoug using subqueries.
Since different RDBMS have different date functions, you can filter by date using the following pseudo code - sls_dt > now() - 30.
Im new to sql and im trying it like this as i found this online.
Select prod_id, prod_nm from(
Select sls_amt
From Sales) as t
Where t.rank = 1
However, this isnt' working. Any help is appreciated
Try below:
select p.prod_id,
p.prod_nm,
sum(s.sls_amt)
from products p
left outer join Sales s on p.prod_id = s.prod_id
and s.sls_dt > now() - 30
group by p.prod_id,
p.prod_nm;
Related
I have a DB with that tables.
Users (userId, age)
Purchases (purchaseId, userId, itemId, date)
Items (itemId, price).
I need to display the top 3 items by revenue (1 column), share in total revenue (2 column).
Example:
itemid share
1 20
2 10
3 8
Revenue = count purchased items * price.
My code
SELECT Items.itemid, SUM(Items.price) FROM Purchases
LEFT JOIN Items ON Items.itemid = Purchases.itemId
WHERE strftime('%Y', Purchases.date) = '2020'
GROUP BY Items.itemid
ORDER BY Items.itemid DESC LIMIT 3
I do not understand how to calculate the percentage of revenue in SQL and how to display it.
You can use window functions:
SELECT i.itemid, SUM(i.price),
SUM(i.price) * 1.0 / SUM(SUM(i.price)) OVER () as ratio
FROM Purchases p JOIN
Items i
ON i.itemid = p.itemId
WHERE p.date >= '2020-01-01' AND
p.date < '2021-01-01'
GROUP BY i.itemid
ORDER BY i.itemid DESC
LIMIT 3;
Note the changes to the query:
The use of table aliases, so the query is easier to write and to read.
The date filtering uses date constants, so the optimizer can use indexes/partitions if available.
Window functions provide the total that you want.
A LEFT JOIN is unnecessary. You need a match for items to have a total price.
I have the following query which provides me with the item and item details, values, rate and quantity across each location.
I am trying to get the yearly revenue based on the Start and End Date. Example, if the chosen date was 2013-2015. The final result will create 3 columns one for 2013 revenue, one for 2014 revenue and one for 2015 revenue.
I am a newbie and still not an expert in writing queries, but here is what I have currently:
SELECT
department,
item,
itemdesc,
qty1,
qty2,
rate_1,
rate_2,
SUM(mm.days*mm.rate*mm.qty)
FROM
items it
LEFT JOIN
(SELECT
i.days, i.rate, i.days, ii.todate, ii.itemid
FROM
invoiceofitems ii
JOIN
invoices i on i.id = ii.id
WHERE
ii.todate BETWEEN #StartDate and #EndDate) mm ON mm.itemid = it.itemid
GROUP BY
department,
item,
itemdesc,
qty1, qty2,
rate_1, rate_2
ORDER BY
item
However, this does not provide me with a year to year aggregation of invoice revenue that I require.
I know this is possible to achieve via iterating through this. But how would I accomplish this and where would I start on this?
Would I need to know the start and end date of each year and iterate through that and then add a counter to the year until year= EndDate?
I'm extremely confused. Help would be appreciated.
I hope that PIVOT and YEAR help you to solve this problem (some columns are omitted):
;WITH SRC(department,item, ... , rate_2, yr, calculation) AS
(SELECT it.department, it.item, ..., it.rate_2, YEAR(ii.todate) as yr,
(i.days * i.rate *i.qty) as calculation
FROM items it
LEFT JOIN invoiceofitems ii ON ii.itemid = it.itemid
JOIN invoices i ON i.id = ii.id)
SELECT department,item, ..., [2013],[2014],[2015]
FROM SRC
PIVOT
(SUM(calculation) FOR yr IN ([2013],[2014],[2015])) PVT
The YEAR function returns only 'year' part of your date and makes grouping easier. PIVOT just rotates grouped data from rows to columns.
Consider the following query where aggregation happens across two tables: Sales and Promo and the aggregate values are again used in a calculation.
SELECT
sales.article_id,
avg((sales.euro_value - ZEROIFNULL(promo.euro_value)) / NULLIFZERO(sales.qty - ZEROIFNULL(promo.qty)))
FROM
( SELECT
sales.article_id,
sum(sales.euro_value),
sum(sales.qty)
from SALES_TABLE sales
where year >= 2011
group by article_id
) sales
LEFT OUTER JOIN
( SELECT
promo.article_id,
sum(promo.euro_value),
sum(promo.qty)
from PROMOTION_TABLE promo
where year >= 2011
group by article_id
) promo
ON sales.article_id = promo.article_id
GROUP BY sales.article_id;
Some notes on the query:
Both the inner queries return huge number of rows due to large number of articles. Running explain on teradata, the inner queries themselves take very less time, but the join takes a long time.
Assume primary key on article_id is present and both the tables are partitioned by year.
Left Outer Join because second table contains optional data.
So, can you suggest a better way of writing this query. Thanks for reading this far :)
Not really sure how the avg function got into the mix, so I'm removing it.
SELECT article_id,
(SUM(sales_value) - SUM(promo_value)) /
(SUM(sales_qty) - SUM(promo_qty))
FROM (
SELECT
article_id,
sum(euro_value) AS sales_value,
sum(qty) AS sales_qty,
0 AS promo_value,
0 AS promo_qty
from SALES_TABLE sales
where year >= 2011
group by article_id
UNION ALL
SELECT
article_id,
0 AS sales_value,
0 AS sales_qty,
sum(euro_value) AS promo_value,
sum(qty) AS promo_qty
from SALES_TABLE sales
where year >= 2011
group by article_id
) AS comb
GROUP BY article_id;
I need to build a query with 4 columns (sql 2005).
Column1: Product
Column2: Units sold
Column3: Growth from previous month (in %)
Column4: Growth from same month last year (in %)
In my table the year and months have custom integer values. For example, the most current month is 146 - but also the table has a year (eg 2011) column and month (eg 7) column.
Is it possible to get this done in one query or do i need to start employing temp tables etc??
Appreciate any help.
thanks,
KS
KS,
To do this on the fly, you could use subqueries.
SELECT product, this_month.units_sold,
(this_month.sales-last_month.sales)*100/last_month.sales,
(this_month.sales-last_year.sales)*100/last_year.sales
FROM (SELECT product, SUM(units_sold) AS units_sold, SUM(sales) AS sales
FROM product WHERE month = 146 GROUP BY product) AS this_month,
(SELECT product, SUM(units_sold) AS units_sold, SUM(sales) AS sales
FROM product WHERE month = 145 GROUP BY product) AS last_month,
(SELECT product, SUM(units_sold) AS units_sold, SUM(sales) AS sales
FROM product WHERE month = 134 GROUP BY product) AS this_year
WHERE this_month.product = last_month.product
AND this_month.product = last_year.product
If there's a case where a product was sold in one month but not another month, you will have to do a left join and check for null values, especially if last_month.sales or last_year.sales is 0.
I hope I got them all:
SELECT
Current_Month.product_name, units_sold_current_month,
units_sold_last_month * 100 / units_sold_current_month prc_last_month,
units_sold_last_year * 100 / units_sold_current_month prc_last_year
FROM
(SELECT product_id, product_name, sum(units_sold) units_sold_current_month FROM MyTable WHERE YEAR = 2011 AND MONTH = 7) Current_Month
JOIN
(SELECT product_id, product_name, sum(units_sold) units_sold_last_month FROM MyTable WHERE YEAR = 2011 AND MONTH = 6) Last_Month
ON Current_Month.product_id = Last_Month.product_id
JOIN
(SELECT product_id, product_name, sum(units_sold) units_sold_last_year FROM MyTable WHERE YEAR = 2010 AND MONTH = 7) Last_Year
ON Current_Month.product_id = Last_Year.product_id
I am slightly guessing as the structure of the table provided is the result table, right? You will need to do self-join on month-to-previous-month basis:
SELECT <growth computation here>
FROM SALES s1 LEFT JOIN SALES s2 ON (s1.month = s2.month-1) -- last month join
LEFT JOIN SALES s3 ON (s1.month = s3.month - 12) -- lat year join
where <growth computation here> looks like
((s1.sales - s2.sales)/s2.sales * 100),
((s1.sales - s3.sales)/s3.sales * 100)
I use LEFT JOIN for months that have no previous months. Change your join conditions based on actual relations in month/year columns.
I need a SQL query that will identify seasonal sales items.
My table has the following structure -
ProdId WeekEnd Sales
234 23/04/09 543.23
234 30/04/09 12.43
432 23/04/09 0.00
etc
I need a SQL query that will return all ProdId's that have 26 weeks consecutive 0 sales. I am running SQL server 2005. Many thanks!
Update: A colleague has suggested a solution using rank() - I'm looking at it now...
Here's my version:
DECLARE #NumWeeks int
SET #NumWeeks = 26
SELECT s1.ProdID, s1.WeekEnd, COUNT(*) AS ZeroCount
FROM Sales s1
INNER JOIN Sales s2
ON s2.ProdID = s1.ProdID
AND s2.WeekEnd >= s1.WeekEnd
AND s2.WeekEnd <= DATEADD(WEEK, #NumWeeks + 1, s1.WeekEnd)
WHERE s1.Sales > 0
GROUP BY s1.ProdID, s1.WeekEnd
HAVING COUNT(*) >= #NumWeeks
Now, this is making a critical assumption, namely that there are no duplicate entries (only 1 per product per week) and that new data is actually entered every week. With these assumptions taken into account, if we look at the 27 weeks after a non-zero sales week and find that there were 26 total weeks with zero sales, then we can deduce logically that they had to be 26 consecutive weeks.
Note that this will ignore products that had zero sales from the start; there has to be a non-zero week to anchor it. If you want to include products that had no sales since the beginning, then add the following line after `WHERE s1.Sales > 0':
OR s1.WeekEnd = (SELECT MIN(WeekEnd) FROM Sales WHERE ProdID = s1.ProdID)
This will slow the query down a lot but guarantees that the first week of "recorded" sales will always be taken into account.
SELECT DISTINCT
s1.ProdId
FROM (
SELECT
ProdId,
ROW_NUMBER() OVER (PARTITION BY ProdId ORDER BY WeekEnd) AS rownum,
WeekEnd
FROM Sales
WHERE Sales <> 0
) s1
INNER JOIN (
SELECT
ProdId,
ROW_NUMBER() OVER (PARTITION BY ProdId ORDER BY WeekEnd) AS rownum,
WeekEnd
FROM Sales
WHERE Sales <> 0
) s2
ON s1.ProdId = s2.ProdId
AND s1.rownum + 1 = s2.rownum
AND DateAdd(WEEK, 26, s1.WeekEnd) = s2.WeekEnd;