I wanna show the "ArticleName" of all "offers" that have more than 3 "bids". The number of the "Bids" should be output.
I don't know how I can write it down. But I think I know the Logic. It should count the same number of the Table "bid" and the column "OID" and in the end it should paste the number which is more than 3.
Picture:
Well that's easy enough:
Select ArticleName
, count(*) NumberOfBids
from Offer o
join Bid b
on b.oid = o.oid
group by ARticleName
having count(*) >= 3
SELECT * FROM (
SELECT o.ArticleName, count(b.BID) as numberOfBids
FROM Offer as o INNER JOIN bid as b ON o.oid = b.oid
GROUP BY o.ArticleName
) as c
WHERE c.numberOfBids > 3
Related
I have 3 tables:
companies (id, name)
union_products (id, name)
products (id, company_id, union_product_id, price_per_one_product)
I need to get all companies which have products with union_product_id in (1,2) and total price of products (per company) is less than 100.
What I am trying to do now:
select * from "companies" where exists
(
select id from "products"
where "companies"."id" = "products"."company_id"
and "union_product_id" in (1, 2)
group by id
having COUNT(distinct union_product_id) = 2 AND SUM(price_per_one_product) < 100
)
The problem I stuck with is that I'm getting 0 rows from the query above, but it works if I'll change COUNT(distinct union_product_id) = 2 to 1.
DB fiddle: https://www.db-fiddle.com/f/iRjfzJe2MTmnwEcDXuJoxn/0
Try to join the three tables as the following:
SELECT C.id, C.name FROM
products P JOIN union_products U
ON P.union_product_id=U.id
JOIN companies C
ON P.company_id=C.id
WHERE P.union_product_id IN (1, 2)
GROUP BY C.id, C.name
HAVING COUNT(DISTINCT P.union_product_id) = 2 AND
SUM(P.price_for_one_product) < 100
ORDER BY C.id
See a demo.
SELECT c.name FROM "companies" c
JOIN "products" p ON c.id = p.company_id
WHERE union_product_id IN (1, 2) AND price_for_one_product < 100
GROUP BY c.name
HAVING COUNT(DISTINCT p.name) =2
This would provide you all the company(s) name(s) which has provides both union_product_id 1 and 2 and the price_for_one_product/ price_per_one_product is less than 100.
Note: You might need to change price_for_one_product with price_per_one_product, as in question you have used price_per_one_product but db-fiddle link table defination has used price_for_one_product.
I think I have end up in a bit of a dead end.
Let's say I have a dataset, which is fairly easy -
person_id and book_id. Which is pretty much factual table that says person X bought books A, B and C.
I know how to find out how many persons have bought Book X and Book Y together.
This is
select a.book_id as B1, b.book_id as B2, count(b.person_id) as
Bought_Together
from dbo.data a
cross join dbo.data b
where a.book_id != b.book_id and a.person_id = b.person_id
group by a.book_id, b.book_id
Yet again this is where my brain decided to shut down. I know that I would probably need to do it so that
count(b.person_id) / all the people that bought book A * 100
but im not entirely sure.
I hope I was clear enough.
EDIT1: I'm using SQL Server 2017 currently, so i think the correct answer is T-SQL?.
In the end the format should be something similliar to this. Also there is no cases where person A could have bought three copies of book X.
Book1 Book2 HowManyPeopleBoughtBook2
1 2 50%
1 3 7%
2 3 15%
2 1 40%
3 1 60%
3 2 20%
EDIT2: Let it be said there is hundreds of thousands of rows in the database. Yes this is bit related to a data science course i am taking - hence huge amounts of data.
You can extend your logic to do this:
select a.book_id as B1, b.book_id as B2,
count(b.book_id) as bought_second_book,
count(b.book_id) * 1.0 / book_cnt as ratio_Bought_Together
from (select a.*, count(*) over (partition by a.book_id) as book_cnt
from dbo.data a
) a left join
dbo.data b
on a.person_id = b.person_id and a.book_id <> b.book_id
group by a.book_id, b.book_id, a.book_cnt;
This assumes that people buy a book only once. If there are duplicates, then count(distinct) would adjust for that.
If you would like to generate all possible combinations of the pairs of books bought together along with the percentage of the persons who bought that combination the following can help
create table data1(book_id int, person_id int)
insert into data1
select *
from (values(1,300)
,(2,300)
,(2,301)
,(1,301)
,(3,301)
)t(book_id,person_id)
with books
as (select distinct book_id
from data1 a
)
,tot_persons
as (select count(distinct person_id) as tot_cnt
from data1
)
,pairs
as (
select a.book_id as col1 /* This block generates all possible pair combinations of books*/
,b.book_id as col2
from books a
join books b
on a.book_id<b.book_id
)
select a.col1,a.col2
,count(b.person_id)*100/(select tot_cnt from tot_persons) as percent_of_persons_buying_both
from pairs a
join data1 b
on a.col1=b.book_id
where exists(select 1
from data1 b1
where b.person_id=b1.person_id
and a.col2=b1.book_id)
group by a.col1,a.col2
On my phone, apologies for typo's
SELECT
SUM(bought_b) * 100.0 / COUNT(*)
FROM
(
SELECT
person_id,
MAX(CASE WHEN book_id = 'A' THEN 1 END) AS bought_a,
MAX(CASE WHEN book_id = 'B' THEN 1 END) AS bought_b
FROM
data
WHERE
book_id IN ('A', 'B')
GROUP BY
person_id
)
person_stats
WHERE
bought_a = 1
On my phone, apologies for typo's
EDIT : just saw that you want all combinations, just just one set combination.
WITH
book AS
(
SELECT DISTINCT book_id FROM data
)
SELECT
book_a_id,
book_b_id,
bought_b * 100.0 / bought_b
FROM
(
SELECT
book_a.book_id AS book_a_id,
book_b.book_id AS book_b_id,
COUNT(DISTINCT data_a.person_id) AS bought_a,
COUNT(DISTINCT data_b.person_id) AS bought_b
FROM
book AS book_a
CROSS JOIN
book AS book_b
INNER JOIN
data AS data_a
ON data_a.book_id = book_a.book_id
LEFT JOIN
data AS data_b
ON data_b.book_id = book_b.book_id
GROUP BY
book_a.book_id,
book_b.book_id
)
stats
I have 2 tables in sybase
Account_table
Id account_code
1 A
2 B
3 C
Associate_table
id account_code
1 A
1 B
1 C
2 A
2 B
3 A
3 C
I have this sql query
SELECT * FROM account_table account, associate_table assoc
WHERE account.account_code = assoc.account_code
This query will return 7 rows. What I want is to return the rows from associate_table that is only common to the 3 accounts like this:
account id account_code Assoc Id
1 A 1
2 B 1
3 C 1
Can anyone help what kind of join should I do?
SELECT b.id account_id,a.code account_code,a.id assoc_id
FROM associate a,
account b
WHERE a.code = b.code
AND a.id IN (SELECT a.id
FROM associate a,
account b
WHERE a.code = b.code
GROUP BY a.id
HAVING Count(*) = (SELECT Count(*)
FROM account));
NOTE: this query works only if you have unique values in Id and account_code columns in account table. And also, your associate_table should contain unique combination of (id, account,code). i.e., associate table should not contain (1,A) or any pair twice.
Try this
SELECT AC.ID,AC.account_code,ASS.ID
FROM account_table AC INNER JOIN associate_table AS ASS ON AC.account_code = ASS.account_code
OK so far answer is accepted I'll post simpler one:
SELECT *
FROM account_table AS account,
associate_table AS assoc
WHERE account.account_code = assoc.account_code
HAVING (
SELECT
COUNT(*)
FROM associate_table assoc_2
WHERE assoc_2.id = assoc.id
) = 3
here 3 is the number of codes account table has, if it's gonna be dynamic (changing over time),
you can use (SELECT COUNT(*) FROM account_table) instead of exact number. Also I'm sure it will be cached by database engine, so requires less resources
I have a table called BB_BOATBKG which holds passengers travel details with columns Z_ID, BK_KEY and PAXSUM where:
Z_ID = BookingNumber* LegNumber
BK_KEY = BookingNumber
PAXSUM = Total number passengers travelled in each leg for a particular booking
For Example:
Z_ID BK_KEY PAXSUM
001234*01 001234 2
001234*02 001234 3
001287*01 001287 5
001287*02 001287 5
002323*01 002323 7
002323*02 002323 6
I would like to get a list of all Booking Numbers BK_KEY from BB_BOATBKG where the total number of passengers PAXSUM is different in each leg for the same booking
Example, For Booking number A, A*Leg01 might have 2 Passengers, A* Leg02 might have 3 passengers
Dependent of your RDBMs there might be several options availible. A solution that should work for most is:
SELECT A.Z_ID, A.BK_KEY, A.PAXSUM
FROM BB_BOATBKG A
JOIN (
SELECT BK_KEY
FBB_BOATBKGROM BB_BBK_KEY
GROUP BY BK_KEY
HAVING COUNT( DISTINCT PAXSUM ) > 1
) B
ON A.BK_KEY = B.BK_KEY
If your DBMS support OLAP functions, have a look at RANK() OVER (...)
It's a little counterintuitive, but you could join the table to itself on {BK_KEY, PAXSUM} and pull out only the records whose joined result is null.
I think this does it:
SELECT
a.BK_KEY
FROM
BB_BOATBKG a
LEFT OUTER JOIN BB_BOATBKG b ON a.BK_KEY = b.BK_KEY AND a.PAXSUM = b.PAXSUM
WHERE
b.Z_ID IS NULL
GROUP BY
a.BK_KEY
Edit: I think I missed anything beyond the trivial case. I think you can do it with some really nasty subselecting though, a la:
SELECT
b.BK_KEY
FROM
(
SELECT
a.BK_KEY,
Count = COUNT(*)
FROM
(
SELECT
a.BK_KEY,
a.PAXSUM
FROM
BB_BOATBKG a
GROUP BY
a.BK_KEY,
a.PAXSUM
HAVING
COUNT(*) = 1
) a
GROUP BY
a.BK_KEY
) b
INNER JOIN
(
SELECT
c.BK_KEY,
Count = COUNT(*)
FROM
BB_BOATBKG c
GROUP BY
c.BK_KEY
) c ON b.BK_KEY = c.BK_KEY AND b.Count = c.Count
Here is the schema for the database: http://i.stack.imgur.com/omX60.png
Question is: How many people have at least five еntitlements?
I've got this, please tell me how wrong it is and fix it.
select count(personId)
from serialNumber_tbl natural join entitlement_tbl
group by personId
having sum(entitlementID) > 5
Thank you.
The condition for at least 5 is >= 5, not > 5
You need to count the distinct ids in the entitlement table, not person
This gives you the persons, next you need to subquery it to find the count of persons.
select count(personId)
FROM
(
select personId
from serialNumber_tbl natural join entitlement_tbl
group by personId
having count(distinct entitlement_id) >= 5
) X
Your request isn't exactly clear. Are you asking for the count of people with more than five entitlement rows whether they exist on multiple serial numbers or not? If so, you could do something like:
Select Count(*) As CountOfPeople
From Person_tbl As P
Where Exists (
Select 1
From serialNumbers As S1
Join entitlement_tbl As E1
On E1.serialNumberId = S.serialNumberId
Where S1.personId = P.personId
Having Count(*) >= 5
)
Or is it that you are asking to find the number of people that have a serialNumber with more than five entitlements? If that is the case, then you could do something like:
Select Count(*) As CountOfPeople
From Person_tbl As P
Where Exists (
Select 1
From serialNumbers As S1
Join entitlement_tbl As E1
On E1.serialNumberId = S.serialNumberId
Where S1.personId = P.personId
Having Count( Distinct S1.serialNumberId ) >= 5
)