InterruptAttach fails on am3352x irq number 97 for bank 0B - interrupt

Question

I am trying to attach an IRQ handler to a gpio bank 0 i.e 0B irq no 97.
At the present moment, my implementation returns with -1. What am I doing wrong? It would be a very simple issue to implement.
#include <stdio.h>
#include <unistd.h>
#include "gpio.h"
#include <sys/neutrino.h>
#include "interrupt.h"
volatile unsigned int gpio0_irq_count;
static const struct sigevent * gpio0_irq_handler (void *gpio, int id){
gpio0_irq_count++;
return NULL;
}
int main(){
int ret;
unsigned long count=0;
ret = InterruptAttach(97, gpio0_irq_handler, NULL,0,_NTO_INTR_FLAGS_TRK_MSK);
printf("%s: Registering handler for irq %d result = %d\n",__func__ , 97, ret);
if (ret)
return -1;
while(1){
printf("%s:[%lu] : gpio0_irq_count = %d\n", __func__, count++, gpio0_irq_count);
sleep(2);
}
}
The erroneous output is:
main: Registering handler for irq 97 result = -1

Answer 1

After much back and forth with QNX, it turns out that a process requesting InterruptAttach() or InterruptAttach_r() needs elevated permissions acquired through
ThreadCtl( _NTO_TCTL_IO, 0 );
Once that is executed the API's work. However, one must still configure the gpio registers to actually fire the interrupt.
GPIO_OE
GPIO_STATUS
GPIO_STATUS_SET
GPIO_CTRL
GPIO_RISINGDETECT