Rearrange Dataset - sql

Question

I am working on some survey data and was wondering if i could rearrange the data to make it a lot more usable. The results are classified as 1-5 and I would like the preferred table to count the results by value and group by question.
original table:
year | month | customer_id | survey | q1 | q2 | q3 | q4 | q5 | q6 ----> q29
-----|-------|-------------|--------|----|----|----|----|----|---
2016 | Oct | ABC12345678 | 1 | 1 | 2 | 3 | 1 | 2 | 3
2016 | Oct | DEF12345678 | 1 | 2 | 1 | 4 | 2 | 1 | 1
2016 | Oct | GHI12345678 | 1 | 4 | 2 | 1 | 1 | 3 | 2
2016 | Oct | JKL12345678 | 1 | 2 | 3 | 2 | 4 | 1 | 3
2016 | Oct | MNO12345678 | 1 | 5 | 2 | 3 | 1 | 2 | 3
2016 | Oct | PQR12345678 | 1 | 3 | 4 | 4 | 2 | 4 | 4
2016 | Oct | STU12345678 | 1 | 1 | 5 | 3 | 1 | 2 | 5
2016 | Oct | VWX12345678 | 1 | 2 | 2 | 4 | 2 | 1 | 1
Preferred Table:
Year | Month | Survey | Question | 1 | 2 | 3 | 4 | 5 |
-----|-------|--------|----------|----|----|----|----|----|
2016 | Oct | 1 | q1 | 80 | 45 | 25 | 63 | 89 |
2016 | Oct | 1 | q2 | 65 | 75 | 35 | 53 | 69 |
I can do this with a basic select query but to do it for every question will end up with 29 unions and there must be a quicker way.
Regards,
Neil

Answer 1

This is what I would use until someone posts a better solution:
<!-- language: lang-sql -->
use tempdb;
create table #tempsurvey (year int, month varchar(32), customer_id varchar(32), survey int, [q1] int, [q2] int, [q3] int, [q4] int, [q5] int, [q6] int, [q7] int, [q8] int, [q9] int, [q10] int, [q11] int, [q12] int, [q13] int, [q14] int, [q15] int, [q16] int, [q17] int, [q18] int, [q19] int, [q20] int, [q21] int, [q22] int, [q23] int, [q24] int, [q25] int, [q26] int, [q27] int, [q28] int, [q29] int);
insert into #tempsurvey values (2016,'Oct', 'ABC12345678', 1, 1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2);
insert into #tempsurvey values (2016,'Oct', 'DEF12345678', 1, 4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5,1,4,5);
with cte as (
select t.[year], t.[month], t.customer_id, t.survey, x.question, x.answer
from #tempsurvey t
cross apply (values ('q1',q1) ,('q2',q2) ,('q3',q3) ,('q4',q4) ,('q5',q5) ,('q6',q6) ,('q7',q7) ,('q8',q8) ,('q9',q9) ,('q10',q10) ,('q11',q11) ,('q12',q12) ,('q13',q13) ,('q14',q14) ,('q15',q15) ,('q16',q16) ,('q17',q17) ,('q18',q18) ,('q19',q19) ,('q20',q20) ,('q21',q21) ,('q22',q22) ,('q23',q23) ,('q24',q24) ,('q25',q25) ,('q26',q26) ,('q27',q27) ,('q28',q28) ,('q29',q29))
as x (Question,Answer)
)
select [year], [month], [survey], question, [1]=sum(case when answer=1 then 1 else 0 end), [2]=sum(case when answer=2 then 1 else 0 end), [3]=sum(case when answer=3 then 1 else 0 end), [4]=sum(case when answer=4 then 1 else 0 end), [5]=sum(case when answer=5 then 1 else 0 end)
from cte
group by [year], [month], [survey], question;
drop table #tempsurvey;
Brad Schulz on cross apply: http://bradsruminations.blogspot.com/search/label/CROSS%20APPLY

Answer 2

Sean is correct.
It will go like this:
with subquery as (
select year, month, survey, question, tempVal from #table
unpivot
(tempVal for question in (q1, q2, q3, q4, q5, q6, q7, ..., q29)) as up
)
select year, month, survey, question,
sum(case when tempVal = 1 then 1 else 0 end) as a1,
sum(case when tempVal = 2 then 1 else 0 end) as a2,
sum(case when tempVal = 3 then 1 else 0 end) as a3,
sum(case when tempVal = 4 then 1 else 0 end) as a4,
sum(case when tempVal = 5 then 1 else 0 end) as a5
from subquery
group by year, month, survey, question