SAS PROC SQL NOT CONTAINS multiple values in one statement - sql

Question

In PROC SQL, I need to select all rows where a column called "NAME" does not contain multiple values "abc", "cde" and "fbv" regardless of what comes before or after these values. So I did it like this:
SELECT * FROM A WHERE
NAME NOT CONTAINS "abc"
AND
NAME NOT CONTAINS "cde"
AND
NAME NOT CONTAINS "fbv";
which works just fine, but I imagine it would be a headache if we had a hundred of conditions. So my question is - can we accomplish this in a single statement in PROC SQL?
I tried using this:
SELECT * FROM A WHERE
NOT CONTAINS(NAME, '"abc" AND "cde" AND "fbv"');
but this doesn't work in PROC SQL, I am getting the following error:
ERROR: Function CONTAINS could not be located.
I don't want to use LIKE.

Answer 1

You could use regular expressions, I suppose.
data a;
input name $;
datalines;
xyabcde
xyzxyz
xycdeyz
xyzxyzxyz
fbvxyz
;;;;
run;
proc sql;
SELECT * FROM A WHERE
NAME NOT CONTAINS "abc"
AND
NAME NOT CONTAINS "cde"
AND
NAME NOT CONTAINS "fbv";
SELECT * FROM A WHERE
NOT (PRXMATCH('~ABC|CDE|FBV~i',NAME));
quit;
You can't use CONTAINS that way, though.

Answer 2

You can use NOT IN:
SELECT * FROM A WHERE
NAME NOT IN ('abc','cde','fbv');

Answer 3

If the number of items is above reasonable number to build inside code, you can create a table (work.words below) to store the words and iterate over it to check occurrences:
data work.values;
input name $;
datalines;
xyabcde
xyzxyz
xycdeyz
xyzxyzxyz
fbvxyz
;
run;
data work.words;
length word $50;
input word $;
datalines;
abc
cde
fbv
;
run;
data output;
set values;
/* build a has of words */
length word $50;
if _n_ = 1 then do;
/* this runs once only */
call missing(word);
declare hash words (dataset: 'work.words');
words.defineKey('word');
words.defineData('word');
words.defineDone();
end;
/* iterate hash of words */
declare hiter iter('words');
rc = iter.first();
found = 0;
do while (rc=0);
if index(name, trim(word)) gt 0 then do; /* check if word present using INDEX function */
found= 1;
rc = 1;
end;
else rc = iter.next();
end;
if found = 0 then output; /* output only if no word found in name */
drop word rc found;
run;