I have a table that looks like this:
StgID---|---ItemNumber
1 0034
2 0035
3 0036
4 0036
5 0036
6 0058
And I need a way to assign some sort of unique item number for each row where it would look like this:
StgID---|---ItemNumber--|--SerialID
1 0034 1
2 0035 2
3 0036 3
4 0036 3
5 0036 3
6 0058 4
You can use DENSE_RANK:
SELECT *,
DENSE_RANK() OVER(ORDER BY ItemNumber) SerialId
FROM dbo.YourTable;
Related
I wish to use some sort of SQL array to subtract values from a certain row (QTYOnHand) that decreases that row value every time and throws it into a rolling calculation for the other rows. I've been thinking of some sort of Self Join/Temp Table solution, but not sure how to formulate. Also, All the results will be partitioned by the ItemID below. Help would be appreciated.
Here's some data, If I do a simple row by row subtraction I will get this: 17-3 = 14, 17-5 = 12 and so on.
(Item_ID) (ItemQty) (QTYOnHand) (QtyOnHand - ItemQty)
123 3 17 14
123 5 17 12
123 4 17 13
456 7 12 5
456 8 12 4
456 2 12 10
456 3 12 9
789 2 6 4
789 2 6 4
789 2 6 4
These are the results that I want, where I subtract every next value from the new QTYOnHand-ItemQty column value. Looks like 17-3 then 14 -5 then 9 -4 for Item_ID (123):
(Item_ID) (ItemQty) (QTYOnHand) (QtyOnHand - ItemQty)
123 3 17 14
123 5 17 9
123 4 17 5
456 7 12 5
456 8 12 -3
456 2 12 -5
456 3 12 -8
789 2 6 4
789 2 6 2
789 2 6 0
try the following:
;with cte as
(
select *, ROW_NUMBER() over (partition by Item_ID order by Item_ID) rn
from YourTable
)
, cte2 as
(
select Item_ID, ItemQty, QTYOnHand, Case when rn = 1 then QTYOnHand else 0 end - ItemQty as calc, rn
from cte
)
select Item_ID, ItemQty, QTYOnHand, sum(calc) over (partition by Item_ID order by rn) as [QtyOnHand - ItemQty]
from cte2 t1
Please find the db<>fiddle here.
I want to create a select query in SQL Server where I group the rows by a column (BaseId) and also order them by Status, RTime and Version. I want to add a column "isFirst" that has the value 1 if the BaseId value is the first in the group, and 0 if it's not.
My sample table:
Table name: Head
Id BaseId Name RTime Status Version
2 2 abc 04-12 12:34 1 1
3 3 xyz 04-12 13:10 9 1
4 2 abc 04-13 14:25 0 2
5 3 xyz 04-14 12:34 0 2
6 3 xyz 04-14 13:10 9 3
7 3 xyz 04-16 14:25 1 4
8 2 abc 04-16 17:40 1 3
9 9 sql 04-17 02:23 9 1
10 9 sql 04-17 07:31 0 2
Expected result:
isFirst Id BaseId Name RTime Status Version
1 10 9 sql 04-17 07:31 0 2
0 9 9 sql 04-17 02:23 9 1
1 5 3 xyz 04-14 12:34 0 2
0 7 3 xyz 04-16 14:25 1 4
0 6 3 xyz 04-14 13:10 9 3
0 3 3 xyz 04-12 13:10 9 1
1 4 2 abc 04-13 14:25 0 2
0 8 2 abc 04-16 17:40 1 3
0 2 2 abc 04-12 12:34 1 1
My query now looks like this:
SELECT *
FROM Head
ORDER BY BaseId desc, Status, RTime desc, Version desc
I think I should use CASE to create the isFirst column, but I've had no luck so far. Anyone could help me?
You can use row_number() and a case expression:
select
case when row_number() over(
partition by BaseId
order by Status, RTime desc, Version desc
) = 1
then 1
else 0
end isFirst,
h.*
from head h
order by BaseId desc, Status, RTime desc, Version desc
I have a query following which have a DENSE_RANK and ROW_NUMBER columns:
WITH CTE AS(
SELECT
A.SL_NO,
A.ACC_NO,
A.ACC_NAME
DENSE_RANK() OVER(ORDER BY A.ACC_NO, A.ACC_NAME) DRN,
ROW_NUMBER() OVER(PARTITION BY A.ACC_NO, A.ACC_NAME ORDER BY A.SL_NO) RN
FROM TEST_TBL A
)
SELECT *
FROM CTE A
ORDER BY A.SL_NO;
The query results in:
SL_NO ACC_NO ACC_NAME DRN RN
1 234 UNIP 3 1
2 234 UNIP 3 2
3 234 UNIP 3 3
4 256 PURP 4 1
5 256 PURP 4 2
6 289 KFAR 5 1
7 210 FHAS 2 1
8 210 FHAS 2 2
9 210 FHAS 2 3
10 110 PURP 1 1
11 110 PURP 1 2
12 110 PURP 1 3
13 110 PURP 1 4
But do wanna order the DRN column like this (The rank must be according to the acc_no and acc_name columns):
SL_NO ACC_NO ACC_NAME DRN RN
1 234 UNIP 1 1
2 234 UNIP 1 2
3 234 UNIP 1 3
4 256 PURP 2 1
5 256 PURP 2 2
6 289 KFAR 3 1
7 210 FHAS 4 1
8 210 FHAS 4 2
9 210 FHAS 4 3
10 110 PURP 5 1
11 110 PURP 5 2
12 110 PURP 5 3
13 110 PURP 5 4
Need suggestions to achieve it with or without using DENSE_RANK. Thanks in advance.
It looks like you just want the DRN column to be a dense rank as ordered by the SL_NO column. We can subquery once, and arbitrary take the minimum SL_NO value per each account, and then use dense rank afterwards:
WITH cte AS (
SELECT
SL_NO,
ACC_NO,
ACC_NAME,
ROW_NUMBER() OVER(PARTITION BY ACC_NO, ACC_NAME ORDER BY SL_NO) RN,
MIN(SL_NO) OVER (PARTITION BY ACC_NO, ACC_NAME) AS SL_NO_MIN
FROM TEST_TBL A
)
SELECT
SL_NO,
ACC_NO,
ACC_NAME,
DENSE_RANK() OVER (ORDER BY SL_NO_MIN) AS DRN,
RN
FROM cte
ORDER BY
SL_NO;
Demo
I have a list of IDs, transactions, and the date of those transactions. I want to create a count of each transaction within each ID.
The starting table I have is looks something like this:
id trxn_dt trxn_amt
1 10/31/2014 58
1 11/9/2014 34
1 12/10/2014 12
2 7/8/2014 78
2 11/20/2014 99
3 1/5/2014 120
4 2/17/2014 588
4 2/18/2014 8
4 3/9/2014 65
4 4/25/2014 74
and I want the end result to look something like this:
id trxn_dt trxn_amt trxn_count
1 10/31/2014 58 1
1 11/9/2014 34 2
1 12/10/2014 12 3
2 7/8/2014 78 1
2 11/20/2014 99 2
3 1/5/2014 120 1
4 2/17/2014 588 1
4 2/18/2014 8 2
4 3/9/2014 65 3
4 4/25/2014 74 4
Count(distinct(id)) would only give me the overall number of distinct IDs and not a running total by each ID that restarts at each new ID.
Thank you!
In SQL-Server you can use ROW_NUMBER in following:
SELECT id,
trxn_dt,
trxn_amt,
ROW_NUMBER() OVER(PARTITION BY Id ORDER BY Id, trxn_dt) AS trxn_count
FROM StarningTable
In MySQL you can do in following:
SELECT
t.id,
t.trxn_dt,
t.trxn_amt,
#cur:= IF(id=#id, #cur+1, 1) AS RowNumber,
#id := id
FROM
StarningTable t
CROSS JOIN
(SELECT #id:=(SELECT MIN(id) FROM StarningTable t), #cur:=0) AS init
ORDER BY
t.id
using Row_number we can achieve this
Select *,
ROW_NUMBER()OVER(PARTITION BY id ORDER BY (SELECT NULL))trxn_count
from Transactions
How can I create a new column (inCount) with numbering of occurrences in a specific column?
Here is an example:
id name inCount
1 Orly 1
2 Ernest 1
3 Rachel 1
4 Don 1
5 Don 2
6 Ernest 2
7 Angela 1
8 Ernest 3
9 David 1
10 Rachel 2
11 Sully 1
12 Sully 2
13 Rachel 3
14 David 2
15 David 3
16 Kevin 1
17 Kevin 2
18 Orly 2
19 Angela 2
20 Sully 3
21 Kevin 3
22 Don 3
23 Orly 3
24 Angela 3
Don from id 5 is numbered 2 because Don appears in id 4 too.
Don from id 22 is numbered 3 due to the above preceding occurrences.
I use MS SQL SERVER 2008 R2 Express edition.
Thanks.
You could use partition by, like:
select row_number() over (partition by name order by id) as inCount
, *
from YourTable
order by
id
This should work
SELECT id, Name, ROW_NUMBER() OVER(PARTITION BY Name ORDER BY id)
FROM table
ORDER BY id
EDIT: Added order by clause on the select in order to show results in same order indicated by OP. The ORDER BY in the ROW_NUMBER did not change the outcome, but I changed to id as it will keep the row_number correct for the sample data.