Data column into db MVC4 - asp.net-mvc-4

Question

<table>
#foreach (DataRow row in Model.Rows)
{
<tr>
#foreach (DataColumn col in Model.Columns)
{
<td>#row[col.ColumnName]</td>
}
</tr>
}
</table>
#Html.ActionLink("Pass", "Insert", "Home")
When clicking the pass link i would like the columns to be inserted into db. Is there any tutorial on how to do this?

Answer 1

Please try this sample.
Create a view model class as follows
public class DataRows
{
public int Column1{ get; set; }
public string Column2 { get; set; }
public double Column3 { get; set; }
}
public class MyModel
{
public virtual DataRows[] DataSet { get; set; }
}
Retrieve all the data using your business logic into MyModel in your controller. I am demonstrating this using a sample code
public TestModel GenerateModel()
{
var model = new TestModel();
model.DataSet = this.GenerateDataGridData().ToArray();
return model;
}
private ICollection<SampleDataSet> GenerateDataGridData()
{
var list = new List<SampleDataSet>()
{
new SampleDataSet() { Column1= 1, Column2= "XXX", Column3= 23 },
new SampleDataSet() { Column1= 2, Column2= "YYY", Column3= 27 },
new SampleDataSet() { Column1= 3, Column2= "ZZ", Column3= 25 }
};
return list;
}
In the Action of your view you will be calling GenerateModel method as follows
public ActionResult MyView()
{
var model = this.GenerateModel();
return this.View(model);
}
Now you restructure your MyView page as follows
#model MyModel
#{
int i = 0;
}
#using (Html.BeginForm("Insert", "Home", FormMethod.Post))
{
<table>
<thead>
<tr>
<th>Column1</th>
<th>Column2</th>
<th>Column3</th>
</tr>
</thead>
<tbody>
#foreach (var row in Model.DataSet)
{
<tr>
<th>#row.Column1<span>#Html.HiddenFor(x => Model.DataSet[i].Column1)</span></th>
<th>#row.Column2<span>#Html.HiddenFor(x => Model.DataSet[i].Column2)</span></th>
<th>#row.Column3<span>#Html.HiddenFor(x => Model.DataSet[i].Column3)</span></th>
</tr>
i++;
}
</tbody>
</table>
<input type="submit" value="Pass" />
}
Now on submiting the data in the view will be posted to your Insert Action of Home controller and you can insert into your DB using your logic
I hope this will be a solution for your query.