I have a column to check if contains number from 0-9 and a decimal. Since in the version of SQL am using the below does not seem working
select *
from tablename
whwere columnname like '%[^.0-9]%'
Also tried using column name like '%[0-9]%' and columnname not like '%.%' but if there is a negative sign it is not getting captured. Please advise.
The column data type is float. So can someone provide me a query to check if the column contains values from 0-9 and also it can contain decimal values these two are permitted. If say for example if I have value 9,9.99 ,-1.24 the query should output -1.24 I need this value other than decimal and number –
The issue with your LIKE clause is bad predicate logic ...like '%[^.0-9]%'should be NOT LIKE '%[^0-9.]%'
Take this sample data.
DECLARE #table TABLE (SomeNbr VARCHAR(32));
INSERT #table VALUES ('x'),('0'),('0.12'),('999'),('-29.33'),('88.33.22'),('9-9-'),('11-');
What you were trying to do would be accomplished like this:
SELECT t.someNbr
FROM #table AS t
WHERE someNbr NOT LIKE '%[^0-9.]%';
The problem here is we'll also return "88.33.22" and miss "-29.33", both valid float values. You can handle hyphens by adding a hyphen to your LIKE pattern:
SELECT t.someNbr, LEN(t.SomeNbr)-LEN(REPLACE(t.SomeNbr,'.',''))
FROM #table AS t
WHERE someNbr NOT LIKE '%[^0-9.-]%';
But now we also pick up "9-9-" and stuff with 2+ dots. To ensure that each starts with a number OR a hyphen, to ensure hyphens only exist in the front of the string (if at all) and that we a maximum of one dot:
--==== This will do a good job but can still be broken
SELECT t.someNbr
FROM #table AS t
WHERE someNbr NOT LIKE '%[^0-9.-]%' -- Can only contain numbers, dots and hyphens
AND LEN(t.SomeNbr)-LEN(REPLACE(t.SomeNbr,'.','')) < 2 -- can have up to 1 dot
AND LEN(t.SomeNbr)-LEN(REPLACE(t.SomeNbr,'-','')) < 2 -- can have up to 1 hyphen
AND PATINDEX('%-%',t.SomeNbr) < 2 -- hyphen can only be in the front
This does the trick and returns:
someNbr
--------------------------------
0
0.12
999
-29.33
All that said - **DONT DO THIS ANY OF THIS ^^^ **. There is no need to parse numbers in this way except to show others why not to. I can still break this. They way I return valid floats in a scenario like this is with TRY_CAST or TRY_CONVERT. This returns what you need and will perform better.
--==== Best Solution
SELECT t.someNbr
FROM #table AS t
WHERE TRY_CAST(t.SomeNbr AS float) IS NOT NULL;
What I am trying to do is get a range of cube numbers within our building. The issue being the the cube number data type is nvarchar. I know its what messing me up but I have no control over the DB also all of our cube numbers are prefaced with a couple of chars such as AA-1 through AA-255 (thus the nvarchar). My question is this why does the below work:
Select
PCName,
CubeNumer
From
thisTable
where
CubeNumber like 'AA-[1-9]'
The above will give me the PCNames for AA-1 through AA-9 but when I do the following:
...
where CubeNumber like 'AA-[1-20]'
it gives me AA-1 and AA-2. I see the 1 and 2 there, I get its not seeing it as a 20. So is it possible to get that range to work, or any range beside 1-9 to work with that syntax?
Regex is a string comparison and therefore will will look for specific strings. Your pattern of 'AA-[1-20]' is looking for anything that starts with AA- and then numbers 1 through 2, or 0. The correct way would be to do 'AA-[0-9]*'
If your cubes always start with AA-, you could also do a replace and then cast to convert the cube numbers to actual numbers and then do a BETWEEN query.
CAST(REPLACE(CubeNumber,'AA-','') as INT) BETWEEN 1 AND 20;
I am querying to find things ending in "ST" followed by a number 1 - 999.
SELECT NUMBER WHERE NUMBER LIKE '%ST -- works correctly to return everything ending in "ST"
SELECT NUMBER WHERE NUMBER LIKE '%[1-999] -- works correctly to return everything ending in 1 - 999
SELECT NUMBER WHERE NUMBER LIKE '%ST[1-999] -- doesn't work - returns nothing
Also tried:
SELECT NUMBER WHERE NUMBER LIKE '%ST%[1-999] -- works, but also returns things like "GRASTNT3" that have extra things between the "ST" and the number
Can anyone help this struggling beginner?
Thanks!
The problem is that [1-999] doesn't mean what you think it does.
SQL Server interprets that as a set of values (1-9, 9, 9) which basically means that if there's more than 1 digit after the ST, the entry won't be returned.
So far as I can tell, your best bet is:
SELECT NUMBER WHERE
NUMBER LIKE '%ST[1-9][0-9][0-9]' OR
NUMBER LIKE '%ST[1-9][0-9]' OR
NUMBER LIKE '%ST[1-9]'
(assuming that your numbers don't have leading zeros - if they do, replace the ones with more zeros)
You need to do
SELECT NUMBER WHERE
NUMBER LIKE '%ST[1-9][0-9][0-9]'
OR NUMBER LIKE '%ST[1-9][0-9]'
OR NUMBER LIKE '%ST[1-9]';
The group in the the [] is a Char/NChar not an Int.
Better still normalise and type your data, so you have an ST bit and an int column for the number.
If you find you need to define different filters on variable string data, consider Full Text Searching or another Lucene related technology depending on your RDBMS.
I have a column X which is full of floats with decimals places ranging from 0 (no decimals) to 6 (maximum). I can count on the fact that there are no floats with greater than 6 decimal places. Given that, how do I make a new column such that it tells me how many digits come after the decimal?
I have seen some threads suggesting that I use CAST to convert the float to a string, then parse the string to count the length of the string that comes after the decimal. Is this the best way to go?
You can use something like this:
declare #v sql_variant
set #v=0.1242311
select SQL_VARIANT_PROPERTY(#v, 'Scale') as Scale
This will return 7.
I tried to make the above query work with a float column but couldn't get it working as expected. It only works with a sql_variant column as you can see here: http://sqlfiddle.com/#!6/5c62c/2
So, I proceeded to find another way and building upon this answer, I got this:
SELECT value,
LEN(
CAST(
CAST(
REVERSE(
CONVERT(VARCHAR(50), value, 128)
) AS float
) AS bigint
)
) as Decimals
FROM Numbers
Here's a SQL Fiddle to test this out: http://sqlfiddle.com/#!6/23d4f/29
To account for that little quirk, here's a modified version that will handle the case when the float value has no decimal part:
SELECT value,
Decimals = CASE Charindex('.', value)
WHEN 0 THEN 0
ELSE
Len (
Cast(
Cast(
Reverse(CONVERT(VARCHAR(50), value, 128)) AS FLOAT
) AS BIGINT
)
)
END
FROM numbers
Here's the accompanying SQL Fiddle: http://sqlfiddle.com/#!6/10d54/11
This thread is also using CAST, but I found the answer interesting:
http://www.sqlservercentral.com/Forums/Topic314390-8-1.aspx
DECLARE #Places INT
SELECT TOP 1000000 #Places = FLOOR(LOG10(REVERSE(ABS(SomeNumber)+1)))+1
FROM dbo.BigTest
and in ORACLE:
SELECT FLOOR(LOG(10,REVERSE(CAST(ABS(.56544)+1 as varchar(50))))) + 1 from DUAL
A float is just representing a real number. There is no meaning to the number of decimal places of a real number. In particular the real number 3 can have six decimal places, 3.000000, it's just that all the decimal places are zero.
You may have a display conversion which is not showing the right most zero values in the decimal.
Note also that the reason there is a maximum of 6 decimal places is that the seventh is imprecise, so the display conversion will not commit to a seventh decimal place value.
Also note that floats are stored in binary, and they actually have binary places to the right of a binary point. The decimal display is an approximation of the binary rational in the float storage which is in turn an approximation of a real number.
So the point is, there really is no sense of how many decimal places a float value has. If you do the conversion to a string (say using the CAST) you could count the decimal places. That really would be the best approach for what you are trying to do.
I answered this before, but I can tell from the comments that it's a little unclear. Over time I found a better way to express this.
Consider pi as
(a) 3.141592653590
This shows pi as 11 decimal places. However this was rounded to 12 decimal places, as pi, to 14 digits is
(b) 3.1415926535897932
A computer or database stores values in binary. For a single precision float, pi would be stored as
(c) 3.141592739105224609375
This is actually rounded up to the closest value that a single precision can store, just as we rounded in (a). The next lowest number a single precision can store is
(d) 3.141592502593994140625
So, when you are trying to count the number of decimal places, you are trying to find how many decimal places, after which all remaining decimals would be zero. However, since the number may need to be rounded to store it, it does not represent the correct value.
Numbers also introduce rounding error as mathematical operations are done, including converting from decimal to binary when inputting the number, and converting from binary to decimal when displaying the value.
You cannot reliably find the number of decimal places a number in a database has, because it is approximated to round it to store in a limited amount of storage. The difference between the real value, or even the exact binary value in the database will be rounded to represent it in decimal. There could always be more decimal digits which are missing from rounding, so you don't know when the zeros would have no more non-zero digits following it.
Solution for Oracle but you got the idea. trunc() removes decimal part in Oracle.
select *
from your_table
where (your_field*1000000 - trunc(your_field*1000000)) <> 0;
The idea of the query: Will there be any decimals left after you multiply by 1 000 000.
Another way I found is
SELECT 1.110000 , LEN(PARSENAME(Cast(1.110000 as float),1)) AS Count_AFTER_DECIMAL
I've noticed that Kshitij Manvelikar's answer has a bug. If there are no decimal places, instead of returning 0, it returns the total number of characters in the number.
So improving upon it:
Case When (SomeNumber = Cast(SomeNumber As Integer)) Then 0 Else LEN(PARSENAME(Cast(SomeNumber as float),1)) End
Here's another Oracle example. As I always warn non-Oracle users before they start screaming at me and downvoting etc... the SUBSTRING and INSTRING are ANSI SQL standard functions and can be used in any SQL. The Dual table can be replaced with any other table or created. Here's the link to SQL SERVER blog whre i copied dual table code from: http://blog.sqlauthority.com/2010/07/20/sql-server-select-from-dual-dual-equivalent/
CREATE TABLE DUAL
(
DUMMY VARCHAR(1)
)
GO
INSERT INTO DUAL (DUMMY)
VALUES ('X')
GO
The length after dot or decimal place is returned by this query.
The str can be converted to_number(str) if required. You can also get the length of the string before dot-decimal place - change code to LENGTH(SUBSTR(str, 1, dot_pos))-1 and remove +1 in INSTR part:
SELECT str, LENGTH(SUBSTR(str, dot_pos)) str_length_after_dot FROM
(
SELECT '000.000789' as str
, INSTR('000.000789', '.')+1 dot_pos
FROM dual
)
/
SQL>
STR STR_LENGTH_AFTER_DOT
----------------------------------
000.000789 6
You already have answers and examples about casting etc...
This question asks of regular SQL, but I needed a solution for SQLite. SQLite has neither a log10 function, nor a reverse string function builtin, so most of the answers here don't work. My solution is similar to Art's answer, and as a matter of fact, similar to what phan describes in the question body. It works by converting the floating point value (in SQLite, a "REAL" value) to text, and then counting the caracters after a decimal point.
For a column named "Column" from a table named "Table", the following query will produce a the count of each row's decimal places:
select
length(
substr(
cast(Column as text),
instr(cast(Column as text), '.')+1
)
) as "Column-precision" from "Table";
The code will cast the column as text, then get the index of a period (.) in the text, and fetch the substring from that point on to the end of the text. Then, it calculates the length of the result.
Remember to limit 100 if you don't want it to run for the entire table!
It's not a perfect solution; for example, it considers "10.0" as having 1 decimal place, even if it's only a 0. However, this is actually what I needed, so it wasn't a concern to me.
Hopefully this is useful to someone :)
Probably doesn't work well for floats, but I used this approach as a quick and dirty way to find number of significant decimal places in a decimal type in SQL Server. Last parameter of round function if not 0 indicates to truncate rather than round.
CASE
WHEN col = round(col, 1, 1) THEN 1
WHEN col = round(col, 2, 1) THEN 2
WHEN col = round(col, 3, 1) THEN 3
...
ELSE null END
We have legacy table where one of the columns part of composite key was manually filled with values:
code
------
'001'
'002'
'099'
etc.
Now, we have feature request in which we must know MAX(code) in order to give user next possible value, in example case form above next value is '100'.
We tried to experiment with this but we still can't find any reasonable explanation how DB2 engine calculates that
MAX('001', '099', '576') is '576'
MAX('099', '99', 'www') is '99' and so on.
Any help or suggestion would be much appreciated!
You already have the answer to getting the maximum numeric value, but to answer the other part with regard to 'www','099','99'.
The AS/400 uses EBCDIC to store values, this is different to ASCII in several ways, the most important for your purposes is that Alpha characters come before numbers, which is the opposite of Ascii.
So on your Max() your 3 strings will be sorted and the highest EBCDIC value used so
'www'
'099'
'99 '
As you can see your '99' string is really '99 ' so it is higher that the one with the leading zero.
Cast it to int before applying max()
For the numeric maximum -- filter out the non-numeric values and cast to a numeric for aggregation:
SELECT MAX(INT(FLD1))
WHERE FLD1 <> ' '
AND TRANSLATE(FLD1, '0123456789', '0123456789') = FLD1
SQL Reference: TRANSLATE
And the reasonable explanation:
SQL Reference: MAX
This max working well in your type definition, when you want do max on integer values then convert values to integer before calling MAX, but i see you mixing max with string 'www' how you imagine this works?
Filter integer only values, cast it to int and call max. This is not good designed solution but looking at your problem i think is enough.
Sharing the solution for postgresql
which worked for me.
Suppose here temporary_id is of type character in database. Then above query will directly convert char type to int type when it gives response.
SELECT MAX(CAST (temporary_id AS Integer)) FROM temporary
WHERE temporary_id IS NOT NULL
As per my requirement I've applied MAX() aggregate function. One can remove that also and it will work the same way.