I need to extract a comma separated list from the following:
Return should gives something like
1 : Route#1, Route#2
2 : Route#3, Route#4
3 : Route#5
4 : Route#6
I'm struggling with the STUFF function. So far I have:SELECT STUFF( (SELECT DISTINCT ';' + T4.[Outbound Trucks] FROM #TEMP4 T4 FOR XML PATH('') ),1,1,'') AS MasterRoutes
Result gives me
any help would be really appreciated.
thanks a lof for your time
If your sql server is 2017 or more :
SELECT dorno, STRING_AGG ([Outbound Trucks], ',') as CSV
FROM #TEMP4
GROUP BY dorno
Explanation Here
In you case you can eliminate doublon to like this:
with tmp as (
select distinct dorno, [Outbound Trucks] Truck from #TEMP4
)
SELECT dorno, STRING_AGG (Truck, ',') as CSV
FROM tmp
GROUP BY dorno
I was testing a query in SQL in which I need to concatenate values in the form of a comma-separated list, and it works, I just have the problem of duplicate values.
This is the query:
SELECT t0.id_marcas AS CodMarca,
t0.nombremarcas AS NombreMarca,
t0.imagenmarcas,
(SELECT String_agg((t2.name), ', ')
FROM exlcartu_devcit.store_to_cuisine t1
INNER JOIN exlcartu_devcit.cuisine t2
ON t1.cuisine_id = t2.cuisine_id
WHERE store_id = (SELECT TOP 1 store_id
FROM exlcartu_devcit.store
WHERE id_marcas = t0.id_marcas
AND status = 1)) AS Descripcion,
t0.logo,
t0.imagen,
(SELECT TOP 1 preparing_time
FROM exlcartu_devcit.store
WHERE id_marcas = t0.id_marcas
AND status = 1) AS Tiempo,
t0.orden,
(SELECT TOP 1 Avg(minimum_amount)
FROM exlcartu_devcit.store_delivery_zone
WHERE id_marcas = t0.id_marcas) AS MontoMinimo
FROM exlcartu_devcit.[marcas] t0
I thought the solution could be just adding a DISTINCT to the query to avoid repeated values in this way ...
(SELECT STRING_AGG(DISTINCT (t2.name), ', ') AS Descripcion
But apparently the STRING_AGG() function does not support it, any idea how to avoid repeated values?
Simplest way is just select from select, like this:
with dups as (select 1 as one union all select 1 as one)
select string_agg(one, ', ') from (select distinct one from dups) q;
vs original
with dups as (select 1 as one union all select 1 as one)
select string_agg(one, ', ') from dups;
I got a MSSQL database and there's this column with IDs.
Some are {}-wrapped around the ID and some are not.
I need to find out if there are duplicate entries like:
'{abcd}' and 'abcd' in one column.
Obviously I dont know 'abcd'...
Is there a simple way of joining the same column and searching for "LIKE" duplicates? Inner Join is not working for me...
You could do something like this:
SELECT Id
FROM TableName AS T0
WHERE EXISTS
(
SELECT 1
FROM TableName AS T1
WHERE T0.Id = '{' + T1.Id + '}'
-- Uncomment the next row if you want all duplicates (with or without brackets):
-- OR '{' + T0.Id + '}' = T1.Id
)
This will return all the records where the id is wrapped by curly brackets and has duplicate id just without the brackets.
You can also do like
CREATE TABLE T(
ID VARCHAR(25)
);
INSERT INTO T VALUES
('abc'),
('{abc}'),
('def'),
('ghi'),
('{ghi}');
SELECT *
FROM
(
SELECT TRIM(TRANSLATE(ID, '{}', ' ')) ID
FROM T
) TT
GROUP BY ID
HAVING COUNT(ID) > 1;
-- Or you can also do
SELECT *
FROM
(
SELECT REPLACE(REPLACE(ID, '{', ''), '}', '') ID
FROM T
) TT
GROUP BY ID
HAVING COUNT(ID) > 1;
Note that TRANSLATE() and TRIM() functions is available only in SQL Server 2017
I have a table that contains comma-separated values in a column In Postgres.
ID PRODS
--------------------------------------
1 ,142,10,75,
2 ,142,87,63,
3 ,75,73,2,58,
4 ,142,2,
Now I want a query where I can give a comma-separated string and it will tell me the number of matches between the input string and the string present in the row.
For instance, for input value ',142,87,', I want the output like
ID PRODS No. of Match
------------------------------------------------------------------------
1 ,142,10,75, 1
2 ,142,87,63, 2
3 ,75,73,2,58, 0
4 ,142,2, 1
Try this:
SELECT
*,
ARRAY(
SELECT
*
FROM
unnest(string_to_array(trim(both ',' from prods), ','))
WHERE
unnest = ANY(string_to_array(',142,87,', ','))
)
FROM
prods_table;
Output is:
1 ,142,10,75, {142}
2 ,142,87,63, {142,87}
3 ,75,73,2,58, {}
4 ,142,2, {142}
Add the cardinality(anyarray) function to the last column to get just a number of matches.
And consider changing your database design.
Check This.
select T.*,
COALESCE(No_of_Match,'0')
from TT T Left join
(
select ID,count(ID) No_of_Match
from (
select ID,unnest(string_to_array(trim(t.prods, ','), ',')) A
from TT t)a
Where A in ('142','87')
group by ID
)B
On T.Id=b.id
Demo Here
OutPut
If you install the intarray extension, this gets quite easy:
select id, prods, cardinality(string_to_array(trim(prods, ','), ',')::int[] & array[142,87])
from bad_design;
Otherwise it's a bit more complicated:
select bd.id, bd.prods, m.matches
from bad_design bd
join lateral (
select bd.id, count(v.p) as matches
from unnest(string_to_array(trim(bd.prods, ','), ',')) as l(p)
left join (
values ('142'),('87') --<< these are your input values
) v(p) on l.p = v.p
group by bd.id
) m on m.id = bd.id
order by bd.id;
Online example: http://rextester.com/ZIYS97736
But you should really fix your data model.
with data as
(
select *,
unnest(string_to_array(trim(both ',' from prods), ',') ) as v
from myTable
),
counts as
(
select id, count(t) as c from data
left join
( select unnest(string_to_array(',142,87,', ',') ) as t) tmp on tmp.t = data.v
group by id
order by id
)
select t1.id, t1.prods, t2.c as "No. of Match"
from myTable t1
inner join counts t2 on t1.id = t2.id;
I created this CTE that returns first and last names from 2 different tables. I would like to use the CTE to identify all of the records that have the same last names and the first name of one column starts with the same first letter of another column.
This is an example of the results of the CTE. I want the SELECT using the CTE to return only the highlighted results:
;WITH CTE AS
(
SELECT AD.FirstName AS AD_FirstName, AD.LastName AS AD_LastName, NotInAD.FirstName As NotInAD_FirstName, NotInAD.LastName As NotInAD_LastName
FROM PagingToolActiveDirectoryUsers AD JOIN
(
SELECT FirstName, LastName
FROM #PagingUsersParseName
EXCEPT
SELECT D.FirstName, D.LastName
FROM PagingToolActiveDirectoryUsers D
WHERE D.FirstName <> D.LastName AND D.LastName <> D.LoginName
AND D.LoginName LIKE '%[0-9]%[0-9]%'
) AS NotInAD ON NotInAD.LastName = AD.LastName
)
SELECT *
FROM CTE
WHERE (AD_LastName = NotInAD_LastName) AND (AD_FirstName LIKE ('''' + SUBSTRING(NotInAD_FirstName, 1, 1) + '%'''))
ORDER BY AD_LastName, AD_FirstName;
The result of this query returns no rows.
What am I doing wrong?
Thanks.
You're enclosing the string to be searched for with single-quotes, but it doesn't appear that the data in AD_FirstName has those single-quotes embedded in it. I suggest you replace the first line of the WHERE clause with
WHERE (AD_LastName = NotInAD_LastName) AND (AD_FirstName LIKE (SUBSTRING(NotInAD_FirstName, 1, 1) + '%'))
Best of luck.