i have a problem when counting and grouping data from 2 column on single table.
My table structure:
id, price, user_1, user_2
Data sample:
001 500 bergkamp cech<br>
002 100 cech ljungberg<br>
003 200 viera henry<br>
004 300 bergkamp pires<br>
005 200 lauren bergkamp<br>
My query:
SELECT
user_1,user_2,
count(user_1) as total1,
count(user_2) as total2
FROM
sales
group by user_1 and user_2
results with not what i want,
I want the output like this:
bergkamp 3<br>
henry 1<br>
cech 2<br>
ljungberg 1<br>
lauren 1<br>
pires 1<br>
viera 1<br>
Any help will be so appreciated, thanks
Put both user columns into one with a UNION. Then group by that temp table result and count the names
select user_name, count(*)
from
(
SELECT user_1 as user_name FROM sales
union all
SELECT user_2 FROM sales
) tmp
group by user_name
You can use a UNION:
SELECT t.user, COUNT(*) AS total
FROM
(
SELECT user_1 AS user
FROM sales
UNION ALL
SELECT user_2
FROM sales
) t
GROUP BY t.user
Related
I have a table:
personId
Date
location
abc123
15-09-2022
London
abc123
15-09-2022
Nottingham
efg321
12-09-2022
Leeds
abc123
13-09-2022
Birmingham
I want to select and return the duplicate rows based on Date and location columns, for example, in the above table: personId 'abc123' is present at location both 'London' and 'Nottingham' on the same date, so I would like to return these rows.
I have tried this query:
SELECT personId, Date FROM sampleTable GROUP BY personId, Date HAVING COUNT(*) > 1
But it gives me the count. I want the rows with all three columns. Expected result:
personId
Date
location
abc123
15-09-2022
London
abc123
15-09-2022
Nottingham
Can anyone please help me with this? Thanks
Try something like this:
SELECT
sampleTable.*
FROM
sampleTable
INNER JOIN -- acts as a filter here
(
SELECT
personId,
Date
FROM
sampleTable
GROUP BY
personId,
Date
HAVING
COUNT(*) > 1
) problemTable
ON sampleTable.personId = problemTable.personId
AND sampleTable.Date = problemTable.Date
ORDER BY
sampleTable.personId,
sampleTable.Date,
sampleTable.location
;
The derived problemTable calculates personId/Date combos that have multiple sampleTable rows. INNER JOINing sampleTable with problemTable, by nature of an INNER JOIN, returns an abridged version of sampleTable: one that only contains combos found within problemTable as well—and those are the ones you care about!
Using INNER JOIN as a filter mechanism is a common theme in SQL, so keep it in the back of your mind.
Its pretty easy using window functions.
Inner SQL returns same table with extra col that marks duplicate rows. Then outer sql filters rows that has duplicate
inner sql result
personid date location check
abc123 13-09-2022 Birmingham 1
abc123 15-09-2022 London 2
abc123 15-09-2022 Nottingham 2
efg321 12-09-2022 Leeds 1
final
personid date location check
abc123 15-09-2022 London 2
abc123 15-09-2022 Nottingham 2
SQL
WITH temp AS (
SELECT
personid,
datecol,
location,
COUNT( personid ) OVER (PARTITION BY personid, datecol) AS check
FROM sampletable
)
SELECT *
FROM temp
WHERE check > 1
I have one table with rental contracts. (Postgres v10.18)
Like this:
Table Rental
Id Start Main_tenant_id Obect_id
101011 1.1.2021 1000 200
100222 1.1.2021 2050 210
If the Object has more than one Tenant the other ones a saved in a separate Table like this:
Table Rental_extra
Id rental_id xtra_tenant
20001 100222 3000
20002 100222 2700
20003 100222 2800
And i have a Person table like this:
Table Person
Id first_name last_name
1000 Peter Mcdonald
2050 Dan Hunt
3000 Steve Cole
2700 Ian Wright
2800 William Pears
Now i need to get this output:
Goal
Id tenant 1 tenant 2 tenant 3 tenant 4
101011 Peter Mcdonald null null null
100222 Dan Hunt Steve Cole Ian Wright William Pears
What's the best way? I tried with some crosstab example but couldn't make it work.
SELECT *
FROM crosstab(
$$
SELECT t.id, tenant_nr, concat_ws(' ', p.first_name, p.last_name)
FROM (
SELECT id, 0 AS tenant_nr, main_tenant_id AS tenant_id
FROM rental
UNION ALL
SELECT rental_id, row_number() OVER (PARTITION BY rental_id ORDER BY id), xtra_tenant
FROM extra_tenant
) t
JOIN person p ON p.id = t.tenant_id
ORDER BY 1 DESC, t.tenant_nr
$$
) AS goal(id int, tenant_1 text, tenant_2 text, tenant_3 text, tenant_4 text);
db<>fiddle here
Detailed explanation here:
PostgreSQL Crosstab Query
Postgres - Transpose Rows to Columns
I've tried more or less all combinations of count and distinct (except the correct one :) ) in order to get the example below.
Input: table t1
NAME | FOOD
Mary | Apple
Mary | Banana
Mary | Apple
Mary | Strawberry
John | Cherries
Expected output:
NAME | FOOD
Mary | 3
John | 1
N.B. Mary has Apple in two rows but she has 3 as we have 3 different values in the column.
I only managed to get 4 in FOOD Column for her, but I need 3 :(
select a.name as NAME, a.count(name) as Food
from
(SELECT distinct NAME,Food from table)a
Start with a query which gives you unique combinations of NAME and FOOD:
SELECT DISTINCT t1.NAME, t1.FOOD
FROM t1
Then you can use that as a subquery in another where you can GROUP BY and Count:
SELECT sub.NAME, Count(*) AS [FOOD]
FROM
(
SELECT DISTINCT t1.NAME, t1.FOOD
FROM t1
) AS sub
GROUP BY sub.NAME;
select a.name, sum(a.FoodCount) from(
select distinct name,COUNT(food) as FoodCount from #t1 group by name, food ) as a group by a.name order by 2 desc
I dont think a count will work here, can someone help me get an sql that identifies which account numbers have multiple agents, more than two agents in the where condition.
AGENT_NAME ACCOUNT_NUMBER
Clemons, Tony 123
Cipollo, Michael 123
Jepsen, Sarah 567
Joanos, James 567
McMahon, Brian 890
Novak, Jason 437
Ralph, Melissa 197
Reitwiesner, John 221
Roman, Marlo 123
Rosenzweig, Marcie 890
Results should be something like this.
ACCOUNT_NUMBER AGENT_NAME
123 Cipollo, Michael
123 Roman, Marlo
123 Clemons, Tony
890 Rosenzweig, Marcie
890 McMahon, Brian
567 Joanos, James
567 Jepsen, Sarah
You can do this using window functions:
select t.account_number, t.agent_name
from (select t.*, min(agent_name) over (partition by account_number) as minan,
max(agent_name) over (partition by account_number) as maxan
from table t
) t
where minan <> maxan;
If you know the agent names are never duplicated, you could just do:
select t.account_number, t.agent_name
from (select t.*, count(*) over (partition by account_number) as cnt
from table t
) t
where cnt > 1;
Assuming your table name is test, this should pull all the records with duplicate ACCOUNT_NUMBER:
select * from test where ACCOUNT_NUMBER in
(select ACCOUNT_NUMBER from test
group by ACCOUNT_NUMBER having
count(ACCOUNT_NUMBER)>1)
order by ACCOUNT_NUMBER
Using count function u can get the result
CREATE TABLE #TEMP
(
AGENT_NAME VARCHAR(100),
ACCOUNT_NUMBER INT
)
INSERT INTO #TEMP
VALUES ('CLEMONS, TONY',123),
('CIPOLLO, MICHAEL',123),
('JEPSEN, SARAH',567),
('JOANOS, JAMES',567),
('MCMAHON, BRIAN',890),
('NOVAK, JASON',437),
('RALPH, MELISSA',197),
('REITWIESNER, JOHN',221),
('ROMAN, MARLO',123),
('ROSENZWEIG, MARCIE',890)
SELECT a.ACCOUNT_NUMBER,a.AGENT_NAME
FROM #TEMP A
JOIN(SELECT COUNT(1) CNT,
ACCOUNT_NUMBER
FROM #TEMP
GROUP BY ACCOUNT_NUMBER) B
ON A.ACCOUNT_NUMBER = B.ACCOUNT_NUMBER
WHERE B.CNT != 1
I have the following table:
**TABLE1**
RecordID UserID UserName Balance TranDate
---------------------------------------------------------------
100 10001 John Doe 10213.00 2013-02-12 00:00:00.000
101 10001 John Doe 1932.00 2013-04-30 00:00:00.000
102 10001 John Doe 10213.00 2013-03-25 00:00:00.000
103 10001 John Doe 14514.00 2013-04-12 00:00:00.000
104 10001 John Doe 5430.00 2013-02-19 00:00:00.000
105 10001 John Doe 21242.00 2010-02-11 00:00:00.000
106 10001 John Doe 13342.00 2013-05-22 00:00:00.000
Now what i'm trying to do is to query the two most recent transactions and arrive at this data:
RecordID UserID UserName Balance TranDate
---------------------------------------------------------------
106 10001 John Doe 13342.00 2013-05-22 00:00:00.000
101 10001 John Doe 1932.00 2013-04-30 00:00:00.000
Then using the data above I would like to compare the balances to show the difference:
UserID UserName Difference
---------------------------------------------------------------
10001 John Doe -11410.00
This just shows the difference between the two previous balances (the latest and the balance before the latest)
Now I have the following query below. This works okay to show the two most recent transactions.
SELECT
TOP 2 *
FROM Table1
WHERE UserID = '1001'
ORDER
BY TranDate DESC
Now my issues are:
Is the sql above safe to use? I am just relying on the sorting of the TranDate by the ORDER BY DESC keyword and I am not so sure if this is very much reliable or not.
How do I select the difference between the two Balances (Row 2 - Row 1 )? I was looking for some answers online and I find stuff about self-joining. I tried it but it doesn't show me my desired output.
EDIT:
This is the closest I can get to my desired result. Can someone help me out on this please? Thanks!
DECLARE #SampleTable TABLE
(
UserID INT,
UserName VARCHAR(20),
Balance DECIMAL(9,2) DEFAULT 0
)
INSERT
INTO #SampleTable
(UserID, UserName, Balance)
SELECT
TOP 2 UserID,
UserName,
Balance
FROM Table1
WHERE UserID = '1001'
ORDER
BY TranDate DESC
SELECT A.UserID,
A.UserName,
B.Balance - A.Balance AS Difference
FROM #SampleTable A
JOIN #SampleTable B
ON A.UserID = B.UserID
Thanks a lot!
You should be able to use something like the following assuming SQL Server as the RDBMS:
;with cte as
(
select recordid, userid, username, balance, trandate,
row_number() over(partition by userid order by trandate desc) rn
from table1
)
select c1.userid, c1.username,
c1.balance - c2.balance diff
from cte c1
cross apply cte c2
where c1.rn = 1
and c2.rn = 2;
See SQL Fiddle with demo.
Or this could be done using an INNER JOIN on the row_number value:
;with cte as
(
select recordid, userid, username, balance, trandate,
row_number() over(partition by userid order by trandate desc) rn
from table1
)
select c1.userid, c1.username,
c1.balance - c2.balance diff
from cte c1
inner join cte c2
on c1.rn + 1 = c2.rn
where c1.rn = 1
See SQL Fiddle with Demo