I have a folder with the structure: /home/test/test123
Inside this I have another BlobFi named directory with jpg images and in test123 I have a txt file. I want to zip the contents of test123 that is BlobFi and the txt file into one folder.
Is there any PL/SQL method which can compress this test123 to test123.zip ?
I Tried referring to THIS but dont know how will I use it for my condition.
Related
I have a folder structure like this as a source
Source/2021/01/01/*.xlsx files
Source/2021/03/02/*.xlsx files
Source/2021/04/03/.*xlsx files
Source/2021/05/04/.*xlsx files
I want to drop all these excel files into a different folder called Output.
Method 1:
When I am trying this, I used copy activity and I am able to get Files with folder structure( not a requirement) in Output folder. I used Binary file format.
Method 2:
Also, I am able to get files as some random id .xlsx in my output folder. I used Flatten Hierrachy.
My requirement is to get files with the same name as source.
This is what i suggest and I have implemented something in the past and i am pretty confident this should work .
Steps
Use getmetada activity and try to loop through all the folder inside Source/2021/
Use a FE loop and pass the ItemType as folder ( so that you get folder only and NO files , I know at this time you dont; have file )
Inside the IF , add a Execute pipeline activity , they should point to a new pipeline which will take a parameter like
Source/2021/01/01/
Source/2021/03/02/
The new pipeline should have a getmetadata activity and FE loop and this time we will look for files only .
Inside the FE loop add a copy activity and now will have to use the full file name as source name .
I need to delete many folders with an exempt list which has a list of folders and files that I should not delete. So I tried delete activity and tried to use if function of Add dynamic content to check whether the file or folder name is the same of the specified ones. But I do not have what should be the parameters #if(). In other words, to use these functions, how do we get the file name or folder name?
It is difficult to get all files and folders by using GetMetadata activity.
As workarounds, you can try these ways:
1.create a Delete activity and select List of files option. Then create a file filled with those path of files and folders need to be deleted.(relative path to the path configured in the dataset).
2.using blob SDK to do this thing.
I'm relatively new to Netlogo and already struggling ;)
I have the following problem: I want my program to open a folder, check a file in that folder and afterwards remove that file from that folder. I figured the best way to do this is via a while loop, but I'm struggling to find the right syntax. Hope you all can help!
The command 'file-open' will open a file using the path provided (the string after file-open: e.g. file-open "C:\Documents\model-out.txt" will open a file titled model-out.txt in the Documents folder on the C drive.)
You can then use 'file-read' or 'file-write' to read or write to the file respectively.
The command 'file-close' will close the file, which then can be deleted with 'file-delete'.
You can also check if a file exists in a folder using the command if file-exists? "C:\Documents\model-out.txt", and if true, the file can be deleted using file-delete.
Also check the command 'set-current-directory'.
Best,
I have a folder in the server
/home/test/pictures
There are multiple .jpg files inside this pictures folder.
I want to delete these files from this pictures using plsql.
Is there a utility for this ?
you can use UTL_FILE.FREMOVE function this function will remove files from a directory, here is the parameters for the function UTL_FILE.FREMOVE (location IN VARCHAR2,filename IN VARCHAR2)
location should be in ALL_DIRECTORIES view
so calling a function would be like this:
begin
UTL_FILE.FREMOVE('C:\','TEXT.TXT');--this will remove text.txt from C drive
end;
you can read this article https://docs.oracle.com/cd/B28359_01/appdev.111/b28419/u_file.htm#BABEGHIG
I have to load file with csv extension from one particular folder to data base in ssis. file name is not known but folder and extension is fixed.
To load the content of a file, the file name with folder path is required else the connection manager can not be validated and configured.
The easiest way is to get file name is using a For Each Loop container:
Select the option [Foreach File Enumerator]
Provide the Folder path and extension (like *.csv) you already have.
Get the File Name in a variable and use it within the Source of the data flow task within the For each Loop container.
Refer