I am struggling with a query to return a list of managers with their respective employees
I have three tables as follows:
Managers
ManagerID ManagerName
1 Bob
2 Sally
3 Peter
4 George
EmployeeManager
EmployeeID ManagerID
1 1
1 1
2 2
2 2
3 3
3 3
4 4
4 4
Employees
EmployeeID EmployeeName
1 David
1 Joseph
2 Adam
2 Pete
3 Mark
3 Mavis
4 Susan
4 Jennifer
Desired Result Set
ManagerName CountEmployee Employees
Bob 2 David, Joseph
Sally 2 Anish, Pete
Peter 2 Mark, Mavis
George 2 Susan, Jennifer
The query I am currently using is as follows:
Select m.ManagerName
,Count(e.EmployeeName) Over(Partition By m.ManagerID) as CountEmployee
,Rank() Over(Partition By m.ManagerID Order By em.EmployeeID) [RankEmployee]
,e.EmployeeName
From dbo.Employees e
Left Join dbo.EmployeeManager em on em.ManagerID=e.ManagerID
Left Join dbo.Managers m on m.ManagerID=em.ManagerID;
This returns a list of managers and employees on individual rows but I'm struggling to concatenate the employee names as per the above table.
Any ideas or solutions?
Manpaal Singh
You can stuff the result to comma seperated result.
Select m.ManagerName
,Count(e.EmployeeName) Over(Partition By m.ManagerID) as CountEmployee
,Rank() Over(Partition By m.ManagerID Order By em.EmployeeID) [RankEmployee]
,STUFF((SELECT ',' + e.EmployeeName
FOR XML PATH('')), 1, 1, '') AS EmployeeName
From dbo.Employees e
Left Join dbo.EmployeeManager em on em.ManagerID=e.ManagerID
Left Join dbo.Managers m on m.ManagerID=em.ManagerID
SELECT M.ManagerName, E.EmployeeName
FROM Managers AS M
INNER JOIN EmployeeManager AS EM ON M.ManagerID = EM.ManagerID
INNER JOIN Employees AS E ON EM.EmployeeID = E.EmployeeID
ORDER BY M.ManagerName
This will give a list of managers and their employees.
when you fix the ID's of the employees table.
1 David
1 Joseph
2 Adam
2 Pete
3 Mark
3 Mavis
4 Susan
4 Jennifer
should be:
1 David
2 Joseph
3 Adam
4 Pete
5 Mark
6 Mavis
7 Susan
8 Jennifer
you can use recursive sql to convert rows in a string :
with t1 (mngId, empName) as (
select a.mngId,
b.empname
from manager as a, employee as b
where b.mngId = a.mngId),
t2 (mngID, nbr, empName, all_name) as (
select mngId,
cast(1 as Int),
min(empName),
cast(min(empName) as varchar(1000)
from t1
group by mngId
union all
select b.mngId,
b.nbr+1,
a.empName,
trim(b.all_name) concat ', ' concat a.empName
from t0 as a, t1 as b
where b.mngId = a.mngId
and a.empName > b.empName
and a.empName = (
select min( c.empName)
from t0 as c
where c.mngId = b.mngId
and c.empName > b.empName )
)
select *
from t1 as e
where nbr = (
select max(nbr)
from t1 as d
where d.mngId = e.mngId )
Related
I have the below tables:
Corporate table:
CorporateId DirectorId ManagerId SalesId
1 1 1 1
2 2 2 3
3 3 4 5
Employee table:
EmployeeId FirstName LastName
1 Tim Sarah
2 Tom Paulsen
3 Tam Margo
4 Eli Lot
5 Ziva Lit
I want to display, for one corporate,the names of the Director, Manager and Sales in rows. Example with corporate 3:
EmployeeId FirstName LastName
3 Tam Margo
4 Eli Lot
5 Ziva Lit
How can I do that? I know how to display rows as columns using pivot, but unsure if pivot can be used here also.
Any help please?
You may join the two tables as the following:
SELECT E.EmployeeId, E.FirstName, E.LastName
FROM Employee E JOIN Corporate C
ON E.EmployeeID IN (C.DirectorId ,C.ManagerId ,C.SalesId)
WHERE C.CorporateId=3
See a demo.
You can first un-pivot your rows into columns by using cross apply, after which you simply join the pivoted rows to your employee table:
select e.*
from corporate c
cross apply (
select EmployeeId from (
values (Directorid), (ManagerId), (SalesId)
)r(EmployeeId)
)r
join employee e on e.EmployeeId = r.EmployeeId
where c.CorporateId = 3;
I need help on a very basic SQL join concept, that I just can't seem to get right.
I have an employee table and a position table. The employee table is like so:
EmpID Name
1 Jane Jones
2 Bob Smith
3 Jim Adams
The position table is like this:
PosID EmpID Position DateFilled
1 1 Sales 1/2/2012
2 2 HR 4/5/2013
3 2 Mgmnt 6/1/2014
4 2 Sr. Mgmnt 7/5/2015
5 3 IT Support 4/6/2014
6 3 IT Devel. 5/11/2015
How can I get the following output:
EmpID Name Position DateFilled
1 Jane Jones Sales 1/2/2012
2 Bob Smith Sr. Mgmnt 7/5/2015
3 Jim Adams IT Devel. 5/11/2015
So, in other words, how do I join to get only the record with the max DateFilled column from the position table to join with the corresponding record in the employee table?
Any assistance would be greatly appreciated.
You can use ROW_NUMBER:
SELECT e.EmpID, e.Name, p.Position, p.DateFilled
FROM employee e
LEFT JOIN (
SELECT EmpID, Position, DateFilled,
ROW_NUMBER() OVER (PARTITION BY EmpID
ORDER BY DateFilled DESC) AS rn
FROM position
) p ON e.EmpID = p.EmpID AND p.rn = 1
You can do it using MAX() KEEP ( DENSE_RANK [FIRST|LAST] ... ) like this:
SELECT e.EmpId,
e.Name,
p.position,
p.datefilled
FROM employee e
INNER JOIN (
SELECT EmpID,
MAX( Position ) KEEP ( DENSE_RANK LAST ORDER BY DateFilled ) AS Position,
MAX( DateFilled ) AS DateFilled
FROM position
GROUP BY EmpID
) p
ON ( e.EmpId = p.EmpID );
try this
select temp.EmpID,(select position from Position where PosID =temp.PosID) position,DateFilled,Name from
(select EmpID,max(PosID) PosID,max(DateFilled) DateFilled
from position group by EmpID ) temp
inner join employee emp on emp.EmpID =temp.EmpID
This is the code I have:
use TSQL2012
select
emp.empid, emp.firstname, emp.mgrid,
manager.firstname as manager_name,
sum(unique(emp.mgrid)) as Total
from
HR.Employees AS emp, HR.Employees as manager
where
emp.mgrid = manager.empid
go
And the result I am supposed to get is:
empid firstame mgrid manager_name Total
1 2 Don 1 Sara 1
2 3 Judy 2 Don 2
3 4 Yael 3 Judy 2
4 5 Sven 2 Don 2
5 6 Paul 5 Sven
6 7 Russell 5 Sven
7 8 Maria 3 Judy
8 9 Zoya 5 Sven
I can't get the last column (Total). Any help would be appreciated
One way of doing it is by the use of CROSS APPLY:
select emp.empid, emp.firstname, emp.mgrid, manager.firstname as manager_name,
x.cnt as Total
from Employees AS emp
inner join Employees as manager on emp.mgrid = manager.empid
cross apply (
select count(*)
from Employees AS e
where e.mgrid = emp.mgrid) AS x(cnt)
Demo here
Edit:
You can also use a CTE in this way:
;With C as (
select b.mgrid, count(*) as Total
from Employees as b
group by mgrid
)
select emp.empid, emp.firstname, emp.mgrid, manager.firstname as manager_name,
Total
from Employees AS emp
inner join Employees as manager on emp.mgrid = manager.empid
inner join C on emp.mgrid = C.mgrid
Demo here
I have two tables
Employee:
Empid Ename Eage Eadd Ephone
1 x 23 b 677
2 y 24 h 809
3 z 34 u 799
Department:
Did fkEmpid dname ddescription
123 1 test test
234 1 test1 test1
667 2 hello hello
Finally I want something like this
Ename Eage Eadd Ephone dname
x 23 b 677 test,test1
y 24 h 809 hello
z 34 u 799 null
Please help me with the SQL
It certainly would be nice to know the target RDBMS. But this question is asked so often so let's try and list'em all (at least popular ones) side by side.
For SQL Server:
SELECT e.Ename, e.Eage, e.Eadd, e.Ephone, d.dname
FROM Employee e LEFT JOIN
(
SELECT fkEmpid,
STUFF((SELECT ',' + dname
FROM Department
WHERE fkEmpid = t.fkEmpid
FOR XML PATH('')) , 1 , 1 , '' ) dname
FROM Department t
GROUP BY fkEmpid
) d
ON e.Empid = d.fkEmpid
Here is SQLFiddle demo
For Mysql, SQLite, HSQLDB 2.X:
SELECT e.Ename, e.Eage, e.Eadd, e.Ephone, d.dname
FROM Employee e LEFT JOIN
(
SELECT fkEmpid,
GROUP_CONCAT(dname) dname
FROM Department t
GROUP BY fkEmpid
) d
ON e.Empid = d.fkEmpid
Here is SQLFiddle demo (MySql)
Here is SQLFiddle demo (SQLite)
For Oracle 11g:
SELECT e.Ename, e.Eage, e.Eadd, e.Ephone, d.dname
FROM Employee e LEFT JOIN
(
SELECT fkEmpid,
LISTAGG (dname, ',') WITHIN GROUP (ORDER BY dname) dname
FROM Department t
GROUP BY fkEmpid
) d
ON e.Empid = d.fkEmpid
Here is SQLFiddle demo
For PostgreSQL 9.X:
SELECT e.Ename, e.Eage, e.Eadd, e.Ephone, d.dname
FROM Employee e LEFT JOIN
(
SELECT fkEmpid,
string_agg(dname, ',') dname
FROM Department t
GROUP BY fkEmpid
) d
ON e.Empid = d.fkEmpid
Here is SQLFiddle demo
Output in all cases:
| ENAME | EAGE | EADD | EPHONE | DNAME |
---------------------------------------------
| x | 23 | b | 677 | test,test1 |
| y | 24 | h | 809 | hello |
| z | 34 | u | 799 | (null) |
Considering RDBMS as SQL SERVER 2008
select E.Ename,E.Eage,E.Eadd,E.Ephone,D.dname
into Table1
from Employee E
left join Deparment D on E.Empid=D.fkEmpid
select t1.[Ename], t1.[Eage], t1.[Eadd], t1.[Ephone],
STUFF((
SELECT ', ' + t2.dname
FROM Table1 t2
WHERE t2.Ename = t1.Ename
AND t2.Eage=t1.Eage
AND t2.Eadd=t1.Eadd
AND t2.Ephone=t1.Ephone
FOR XML PATH (''))
,1,2,'') AS Names
FROM Table1 t1
GROUP BY t1.Ename,t1.[Eage], t1.[Eadd], t1.[Ephone];
SQL FIDDLE
How can I find out duplicate rows based on a single column. I have a table in oracle which has data as given below and it has duplicates. I'm trying to select and view all rows with duplicate employee ids as explained below
EMP table:
EmpId Fname Lname Mname Jobcode Status exp_date
1 Mike Jordan A IT W 12/2014
1 Mike Jordan A IT A 12/2014
2 Angela ruth C sales P 12/2015
2 Angela ruth C IT W 12/2015
3 Kelly Mike B sales W 12/2015
From the above table i want to select all rows which duplicate empids such as below
EmpId Fname Lname Mname Jobcode Status exp_date
1 Mike Jordan A IT W 12/2014
1 Mike Jordan A IT A 12/2014
2 Angela ruth C sales P 12/2015
2 Angela ruth C IT W 12/2015
How can I do this? thank you!
SELECT a.*
FROM TableName a
INNER JOIN
(
SELECT EmpID
FROM TableName
GROUP BY EmpID
HAVING COUNT(*) > 1
) b ON a.EmpID = b.EmpID
SQLFiddle Demo
Another way, although I prefer above, is to use IN
SELECT a.*
FROM TableName a
WHERE EmpId IN
(
SELECT EmpId
FROM TableName
GROUP BY EmpId
HAVING COUNT(*) > 1
)
SQLFiddle Demo
Here's another option using a subquery and COUNT OVER PARTITION BY since you're using Oracle 11:
SELECT *
FROM (
SELECT EmpId, Fname, Lname, Mname, Jobcode, Status, exp_date,
COUNT(EmpId) OVER (PARTITION BY EmpId) EmpCount
FROM TableName
) T
WHERE EmpCount > 1
SQL Fiddle Demo (Borrowed from JW)