SQL Query With Max Value from Child Table - sql

Question

Three pertinent tables: tracks (music tracks), users, and follows.
The follows table is a many to many relationship relating users (followers) to users (followees).
I'm looking for this as a final result:
<track_id>, <user_id>, <most popular followee>
The first two columns are simple and result from a relationship between tracks and users. The third is my problem. I can join with the follows table and get all of the followees that each user follows, but how to get only the most followee that has the highest number of follows.
Here are the tables with their pertinent columns:
tracks: id, user_id (fk to users.id), song_title
users: id
follows: followee_id (fk to users.id), follower_id (fk to users.id)
Here's some sample data:
TRACKS
1, 1, Some song title
USERS
1
2
3
4
FOLLOWS
2, 1
3, 1
4, 1
3, 4
4, 2
4, 3
DESIRED RESULT
1, 1, 4
For the desired result, the 3rd field is 4 because as you can see in the FOLLOWS table, user 4 has the most number of followers.
I and a few great minds around me are still scratching our heads.

Answer 1

So I threw this into Linqpad because I'm better with Linq.
Tracks
.Where(t => t.TrackId == 1)
.Select(t => new {
TrackId = t.TrackId,
UserId = t.UserId,
MostPopularFolloweeId = Followers
.GroupBy(f => f.FolloweeId)
.OrderByDescending(g => g.Count())
.FirstOrDefault()
.Key
});
The resulting SQL query was the following (#p0 being the track id):
-- Region Parameters
DECLARE #p0 Int = 1
-- EndRegion
SELECT [t0].[TrackId], [t0].[UserId], (
SELECT [t3].[FolloweeId]
FROM (
SELECT TOP (1) [t2].[FolloweeId]
FROM (
SELECT COUNT(*) AS [value], [t1].[FolloweeId]
FROM [Followers] AS [t1]
GROUP BY [t1].[FolloweeId]
) AS [t2]
ORDER BY [t2].[value] DESC
) AS [t3]
) AS [MostPopularFolloweeId]
FROM [Tracks] AS [t0]
WHERE [t0].[TrackId] = #p0
That outputs the expected response, and should be a start to a cleaner query.

Answer 2

This sounds like an aggregation query with row_number(). I'm a little confused on how all the joins come together:
select t.*
from (select t.id, f.followee_id, count(*) as cnt,
row_number() over (partition by t.id order by count(*) desc) as seqnum
from followers f join
tracks t
on f.follow_id = t.user_id
group by t.id, f.followee_id
) t
where seqnum = 1;