I'm trying to add a sum function to my sql statement. Currently I'm using Oracle 12G;
my select statement is as follows
select Distinct o.id as ID, o.orderno as "order", a.itemno as "Item Number",
od.total_qty_ord/a.pallet_ptsper as "Total Pallets" From Orders o, ord_detail od,
arinvt a
where o.id = od.orders_id (+) and a.id (+) = od.arinvt_id and o.orderno = '1323-PASO'
order by ID
Currently when I run this I get two different records if my sales order has two different line items. I want to be able to sum the "Total Pallets" section of my script. Is this possible?
Must the selected o.id also entered in de group by clause? I think so.
select Distinct o.id as ID,
o.orderno as "order",
a.itemno as "Item Number",
sum(od.total_qty_ord/a.pallet_ptsper) as "Total Pallets"
From Orders o,
ord_detail od,
arinvt a
where o.id = od.orders_id (+)
and a.id (+) = od.arinvt_id
and o.orderno = '1323-PASO'
group by o.order, a.itemno, o.id ---> include the o.id
order by ID
Related
I searched and found similar questions online but not my particular one, they all use where or having clause.If theres one similar to mine please link it. It's a 2 part question and I have the first one done. Thank you in advance.
Okay so heres the question, part 1
"Find by customer, the total cost and the total discounted cost for each product on the order ?".
It also asks to use inner joins to find the customer and order it a specific way. Below is the answer.
SELECT
C.companyname, O.orderid, O.orderdate, P.productname,
OD.orderid, OD.unitprice, OD.qty, OD.discount,
(OD.unitprice * OD.qty - (OD.qty * OD.discount)) AS TotalCost,
(OD.qty * OD.discount) AS TotalDiscountedCost
FROM
Sales.Customers AS C
INNER JOIN
Sales.Orders AS O ON C.custid = O.custid
INNER JOIN
Sales.OrderDetails OD ON O.orderid = OD.orderid
INNER JOIN
Production.Products as P ON OD.productid = P.productid
ORDER BY
C.companyname, O.orderdate;
Now the second question is to
follow up and resume the first one by "customer and the order date year, the total cost and the total discounted cost on the order ?". It also asks for this, "Project following columns in the select clause as.
GroupByColumns.companyname
GroupByColumns.OrderdateYear
AggregationColumns.CountNumberOfIndividualOrders
AggregationColumns.CountNumberOfProductsOrders
AggregationColumns.TotalCost
AggregationColumns.TotalDiscountedCost
Finally to order by company name and orderdateYear( which are groups). Where im stuck is how to count the specific orders of qty that equal 1 as an aggregate function in the SELECT clause. I know it has to use the aggregate function COUNT because of the GROUP BY, just don't know how to. This is what I have.
SELECT
C.companyname, YEAR(O.orderdate) AS orderyear,OD.qty,
-- Where in the count function or if theres another way do I count all the
--single orders
--COUNT(OD.qty) AS indiviualorders,
(OD.unitprice * OD.qty - (OD.qty * OD.discount)) AS TotalCost,
(OD.qty * OD.discount) AS TotalDiscountedCost
FROM
Sales.Customers AS C
INNER JOIN
Sales.Orders AS O ON C.custid = O.custid
INNER JOIN
Sales.OrderDetails OD ON O.orderid = OD.orderid
INNER JOIN
Production.Products as P ON OD.productid = P.productid
GROUP BY
C.companyname, YEAR(O.orderdate)
ORDER BY
C.companyname, O.orderdate;
You case use a case statement inside a sum
SUM(CASE WHEN <xyz> THEN 1 ELSE 0 END)
But for the count of unique orders, use SELECT(DISTINCT ) on a key that is unique in the order table
SELECT COUNT(DISTINCT O.OrderID) As DistinctOrders FROM Table
Task: Select all orders having products belonging to ‘Sea Food’ category.
Result: OrderNo, OrderDate, Product Name
I write this query but it returns Cartesian products.
select o.orderid, o.orderdate as "Order Date", p.productname , ct.categoryname from orders o,
order_details od , products p , customers c ,categories ct
where
od.orderid = o.orderid and p.productid = od.productid and ct.categoryid = p.categoryid
and ct.categoryname = 'Seafood';
Question: What is wrong with my query ?
You're doing a CROSS JOIN on customers table since you forgot to specify the connection. This is why you should use explicit JOIN syntax rather than old syntax using commas in WHERE clause.
After translating your query into explicit syntax, you will see that there is no WHERE condition involving customers table:
select
o.orderid,
o.orderdate as "Order Date",
p.productname,
ct.categoryname
from
orders o,
inner join order_details od on od.orderid = o.orderid
inner join products p on p.productid = od.productid
inner join categories ct on ct.categoryid = p.categoryid
cross join customers c -- either you don't need this table, or you need to specify conditions
where
ct.categoryname = 'Seafood'
Basically the reason you got it was that your where clause omitted join condition involving customers table, so you were left with:
from (...), customers -- cross join when joining condition not applied in where clause
I'm using the northwind db: http://dev.assets.neo4j.com.s3.amazonaws.com/wp-content/uploads/Northwind_diagram.jpg
I have to output all orders placed by CustomerID ALFKI with more than one unique product. I get the correct orders out, but I can't figure out why it's only printing one product name per order.
My query:
SELECT a.OrderID, p.ProductName
FROM Products p
INNER JOIN 'Order Details' a
ON (p.ProductID = a.ProductID)
INNER JOIN Orders b
ON (a.OrderID = b.OrderID)
WHERE (b.CustomerID = 'ALFKI')
GROUP BY a.OrderID
HAVING COUNT(DISTINCT a.ProductID) > 1
You need the GROUP BY and HAVING to be part of a subquery, with your primary query selecting the detail using the list of OrderIDs returned from the subquery as filter criteria. Try the following syntax for T-SQL:
SELECT
a.OrderID,
p.ProductName
FROM
Products p
INNER JOIN [Order Details] a
ON (p.ProductID = a.ProductID)
INNER JOIN Orders b
ON (a.OrderID = b.OrderID)
WHERE
a.OrderID IN
(
SELECT a.OrderID
FROM [Order Details] a
INNER JOIN Orders b
ON (a.OrderID = b.OrderID)
WHERE (b.CustomerID = 'ALFKI')
GROUP BY a.OrderID
HAVING COUNT(DISTINCT a.ProductID) > 1
)
This is what I have;
SELECT c.customerFN, c.customerEmail, p.productName,
SUM(p.unitsonstock + p.unitsordered) AS "All Units"
FROM customer c
INNER JOIN order o
WHERE c.customerID=o.customerID
INNER JOIN orderDetails d
WHERE o.orderID=d.orderID
INNER JOIN product p
WHERE p.productCode=l.productCode
WHERE orderDate <= '2015-03-15'
ORDER BY productName;
When I enter this the database throws a "missing keyword" error at the fourth line. Could you tell me what it is that I'm missing
Instead of WHERE in line 5, 7 and 9 you need to use ON. You are also using function SUM, but there is no GROUP BY. Change your query like this:
SELECT c.customerFN, c.customerEmail, p.productName,
SUM(p.unitsonstock + p.unitsordered) AS "All Units"
FROM customer c
INNER JOIN order o
ON c.customerID=o.customerID
INNER JOIN orderDetails d
ON o.orderID=d.orderID
INNER JOIN product p
ON p.productCode=l.productCode
WHERE orderDate <= '2015-03-15'
GROUP BY c.customerFN, c.customerEmail, p.productName
ORDER BY p.productName;
JOIN is performed using the ON clause, not with a WHERE:
...
FROM customer c
INNER JOIN order o ON c.customerID=o.customerID
INNER JOIN orderDetails d ON o.orderID=d.orderID
INNER JOIN product p ON p.productCode=d.productCode
WHERE orderDate <= '2015-03-15'
...
The WHERE clause that comes after join should be used like you have it in your query.
Apart from the problem with the JOIN there is also a problem using SUM without grouping. You probably want something like:
SELECT c.customerFN, c.customerEmail, p.productName,
SUM(p.unitsinstock + p.unitsordered) AS "All Units"
FROM customer c
INNER JOIN order o ON c.customerID=o.customerID
INNER JOIN orderDetails d ON o.orderID=d.orderID
INNER JOIN product p ON p.productCode=d.productCode
WHERE orderDate <= '2015-03-15'
GROUP BY customerFN, customerEmail, productName
ORDER BY p.productName;
Use of SUM function implies a GROUP BY clause. Every column selected that is not part of an aggregate function like SUM must be present in the GROUP BY clause.
I have little problem with my SQL query.
I want to get my CUSTOMERS table id, name, surname, and all money they spent on my shop i've created.
SELECT o.CUSTOMER_ID AS "ID", c.name AS "Name", c.SURNAME AS "Surname",
(SELECT op.AMOUNT * p.PRICE
FROM PRODUCTS p
WHERE p.id = op.PRODUCT_ID) AS "Money spent"
FROM ORDERS o
LEFT JOIN CUSTOMERS c ON c.ID = o.CUSTOMER_ID
LEFT JOIN ORDERS_PRODUCTS op ON op.ORDER_ID = o.id
GROUP BY o.CUSTOMER_ID;
And i have error message like this:
ORA-00979: not a GROUP BY expression
00979. 00000 - "not a GROUP BY expression"
*Cause:
*Action:
Error at Line: 1 Column: 31
I have to say, that i have to use GroupBy clause, because i have this in my school project requirements.
And this is my base diagram, if it could help you.
http://i61.tinypic.com/2d1okut.jpg
As you can see in the ORACLE docs
SelectItems in the SelectExpression with a GROUP BY clause must contain only aggregates or grouping columns.
This means that if you only group by o.CUSTOMER_ID, all the other fields in the select list must be aggregate functions (like COUNT, MAX, etc.).
In the case of fields that repeat values in each group (as name and surname) you should include them in the GORUP BY clause.
To include the sum of money spent, you could add another LEFT JOIN with PRODUCTS and select SUM(op.amount*p.price) without a subquery.
That would be
SELECT o.CUSTOMER_ID AS "ID", c.name AS "Name", c.SURNAME AS "Surname",
SUM(op.AMOUNT*p.PRICE) AS "Money spent"
FROM ORDERS o
LEFT JOIN CUSTOMERS c ON c.ID = o.CUSTOMER_ID
LEFT JOIN ORDERS_PRODUCTS op ON op.ORDER_ID = o.id
LEFT JOIN PRODUCTS p ON p.id = op.PRODUCT_ID
GROUP BY o.CUSTOMER_ID, c.name AS "Name", c.SURNAME
ORDER BY o.CUSTOMER_ID, c.name AS "Name", c.SURNAME;
Remember always to define the sort order of your queries, otherwise it will be undefined.