Group the column value based on selective rows for an id - sql

Question

I have a table which have 4 dimensions for a foreignid.
I want to find unique combination based on 2 dimensions.
TABLE1
-----------------------------
ID NAME VALUE TABLE2ID
-----------------------------
1 TYPE 10 1
2 DIR IN 1
3 STATE MA 1
4 COUNT 100 1
5 TYPE 10 2
6 DIR IN 2
7 STATE SA 2
8 COUNT 200 2
9 TYPE 20 3
10 DIR OUT 3
11 STATE MA 3
12 COUNT 300 3
-----------------------------
Here, I want the TABLE2IDs based on the combination of TYPE and DIR rows which is unique.
So, here if you aggregate the row values based on TYPE and DIR you will get
-----------------------------
TYPE DIR TABLE2ID
-----------------------------
10 IN 1
10 IN 2
20 OUT 3
-----------------------------
Note:
The above question is answered
Additional Question related to this.
I have another table which have the count for table2 id based on hour.
I want to group all the count for all hours in a day for unique combination in table1(Don't worry about table 2 structure).
TABLE3
-----------------------------
ID TIME COUNT TABLE2ID
-----------------------------
1 2016101601 10 1
2 2016101602 20 1
3 2016101603 30 1
4 2016101604 40 1
5 2016101601 10 2
6 2016101602 20 2
7 2016101603 30 2
8 2016101604 40 2
9 2016101601 10 3
10 2016101602 20 3
11 2016101603 30 3
12 2016101604 40 3
-----------------------------
Here, I want the output be grouped based on unique value of table 1 according to type and name(regardless of table2id)
----------------------------------
TYPE DIR DATE COUNT
----------------------------------
10 IN 20161016 200
20 OUT 20161016 100
---------------------------------

Answer 1

Use a PIVOT:
Oracle Setup:
CREATE TABLE table1 ( id, name, value, table2id ) AS
SELECT 1, 'TYPE', '10', 1 FROM DUAL UNION ALL
SELECT 2, 'DIR', 'IN', 1 FROM DUAL UNION ALL
SELECT 3, 'STATE', 'MA', 1 FROM DUAL UNION ALL
SELECT 4, 'COUNT', '100', 1 FROM DUAL UNION ALL
SELECT 5, 'TYPE', '10', 2 FROM DUAL UNION ALL
SELECT 6, 'DIR', 'IN', 2 FROM DUAL UNION ALL
SELECT 7, 'STATE', 'SA', 2 FROM DUAL UNION ALL
SELECT 8, 'COUNT', '200', 2 FROM DUAL UNION ALL
SELECT 9, 'TYPE', '20', 3 FROM DUAL UNION ALL
SELECT 10, 'DIR', 'OUT', 3 FROM DUAL UNION ALL
SELECT 11, 'STATE', 'MA', 3 FROM DUAL UNION ALL
SELECT 12, 'COUNT', '300', 3 FROM DUAL;
Query:
SELECT *
FROM ( SELECT name, value, table2id FROM table1 )
PIVOT ( MAX(value) FOR name IN ( 'TYPE' AS type, 'DIR' AS DIR ) );
Output:
TABLE2ID TYPE DIR
-------- ---- ---
1 10 IN
2 10 IN
3 20 OUT
Or as an alternative:
SELECT table2id,
MAX( CASE WHEN name = 'TYPE' THEN value END ) AS type,
MAX( CASE WHEN name = 'DIR' THEN value END ) AS dir
FROM table1
GROUP BY table2id;

Answer 2

You could join two subqueries, one that selects the types and one that selects the dirs for the same id:
SELECT type, dir, a.table2id
FROM (SELECT value AS type, table2id
FROM table1
WHERE name = 'TYPE') a
JOIN (SELECT value AS dir, table2id
FROM table1
WHERE name = 'DIR') b ON a.table2id = b.table2id