With the following function and stored procedure i get a resultset with 2 columns.
What i need additional is a third column total for all open invoices inner score range
It would great for any idea.
ALTER FUNCTION dbo.OpenOrders
(
#MandantId int
)
RETURNS TABLE
AS
RETURN
SELECT SUM(Invoices.Amount - ISNULL(Payment.Amount, 0)) AS Op
FROM Invoices INNER JOIN
Orders ON Invoices.OrderId = Orders.OrderId LEFT OUTER JOIN
Payment ON Invoices.InvoiceId = Payment.InvoiceId
WHERE (Orders.MandantId = #MandantId)
GROUP BY Invoice.InvoiceId, Invoices.Amount
HAVING (SUM(Invoices.Amount - ISNULL(Payment.Amount, 0)) <> 0)
ALTER PROCEDURE dbo.GetOpRanges
#MandantId int
AS
BEGIN
SELECT * INTO #tmp_ranges
FROM
//wrong in first post -> OPDebitorByMandant(#MandantId)
OpenOrders(#MandantId)
SELECT op AS [score range], COUNT(*) AS [number of occurences]
FROM
(SELECT CASE
WHEN op BETWEEN 0 AND 50 THEN ' 0- 50'
WHEN op BETWEEN 50 AND 100 THEN ' 50-100'
WHEN op BETWEEN 100 AND 500 THEN '100-500'
ELSE '500 and >' END AS op
FROM [#tmp_ranges]) AS t
GROUP BY op
RETURN
Result:
score range number of occurences range
------------------+-------------
0- 50 23
50-100 4
100-500 4
500 and > 21
What i need additional is a third column total for all open invoices inner score range.
Target result:
score range number of occurences Total
-----------+--------------------+------
0- 50 23 1.150
50-100 4 400
100-500 4 2.000
500 and > 21 22.000
Tables:
Invoices
InvoiceId CustomerId OrderId DateOfInvoice Amount
----------+----------+-------+-------------+------
1 1 20 20160301 1000.00
2 2 22 20160501 2000.00
3 1 102 20160601 3000.00
...
Orders
OrderId MandantId CustomerId DateOfOrder Amount
-------+---------+----------+-----------+-----------
20 1 1 20160101 1000.00
22 1 2 20160101 2000.00
102 1 1 20160101 3000.00
...
Payment
PaymentId MandantId CustomerId InvoiceId OrderId DateOfPayment Amount
---------+---------+----------+---------+-------+-------------+-------------
1 1 1 1 20 20160310 1000.00
2 1 2 2 22 20160505 2000.00
3 1 1 3 102 20160610 3000.00
...
hope it's helpfull and thanks again in advance for any solution
Related
My table looks like the following:
income
date
productid
invoiceid
customerid
300
2015-01-01
A
1234551
1
300
2016-01-02
A
1234552
1
300
2016-01-03
B
1234553
2
300
2016-01-03
A
1234553
2
300
2016-01-04
C
1234554
3
300
2016-01-04
C
1234554
3
300
2016-01-08
A
1234556
3
300
2016-01-08
B
1234556
3
300
2016-01-11
C
1234557
3
I need to know : Number of invoices per customer, how many customers in total (for example one invoice = several customers, two invoices = two customers, three invoices = three customers, and so..).
What is the syntax for this query?
In my sample data above, customer 1 has two invoices, customer 2 one invoice and customer 3 three invoices. So there is one customer each with a count of 1, 2, and 3 invoices in my example.
Expected result:
invoice_count
customers_with_this_invoice_count
1
1
2
1
3
1
I tried this syntax and I'm still stuck:
select * from
(
select CustomerID,count(distinct InvoiceID) as 'Total Invoices'
from exam
GROUP BY CustomerID
) a
Select Count(customerID),CustomerID From a
Group By customerID
Having Count(customerID) > 1
Please consider the following table transaction: a company regularly sends invoices to their customers that are part of the same order. The companies' clients will often pay only once per so many weeks.
(trans_date in format yyyy-mm-dd)
id order_id trans_type trans_date trans_amount
----------------------------------------------------------
1 1 invoice 2017-01-10 100
2 1 invoice 2017-05-23 150
3 1 invoice 2017-05-28 200
4 2 invoice 2017-03-01 700
5 2 payment 2017-06-16 700
6 1 payment 2017-10-12 450
7 3 invoice 2017-06-24 199
The company would like to see on what date each invoice was paid for. For example: invoice (id) 1 (part of order_id=1 group) was sent on 2017-01-10 and paid on 2017-10-12 (id=6). Invoice with id=7 has not been paid at all.
The desired output would be the payment date for each invoice (payment_date):
id order_id trans_type trans_date trans_amount payment_date
--------------------------------------------------------------------------
1 1 invoice 2017-01-10 100 2017-10-12
2 1 invoice 2017-05-23 150 2017-10-12
3 1 invoice 2017-05-28 200 2017-10-12
4 2 invoice 2017-03-01 700 2017-06-16
5 2 payment 2017-06-16 700
6 1 payment 2017-10-12 450
7 3 invoice 2017-06-24 199
For transactions 5, 6 and 7, the payment_date is empty because it is either a payment (id=5 and 6) or an unpaid invoice (id=7).
I don't understand how I should solve this issue. In combination with regular scripting, I would get the whole set and loop through it to find each payment. But how can this be solved in SQL only?
Any help would be greatly appreciated!
Did you try a simple left join?
Below code is standard SQL.
Select a.id , a.order_id, a.trans_type, a.trans_date, a.trans_amount, isnull(b.trans_date, '') As payment_date
From transaction a
Left join transaction b
On a.order_id = b.order_id
And a.trans_type = 'invoice'
And b.trans_type = 'payment'
You can do a cumulative sum of payments and invoices and get the first date when the payment total meets or exceeds the invoice total:
with ip as (
select ip.*,
sum(case when ip.trans_type = 'invoice' then ip.trans_amount else 0 end) over (order by ip.trans_date) as running_invoice,
sum(case when ip.trans_type = 'payment' then ip.trans_amount else 0 end) over (order by ip.trans_date) as running_payment,
from invoicepayments i
)
select ip.*,
(select min(ip2.trans_date)
from ip ip2
where ip2.running_payment >= ip.running_invoice and
ip.trans_type = 'invoice'
) as payment_date
from ip;
I have two table with primary key and foreign key (MaterialId)
Material Table (Multiple Material)
MaterialId MaterialName OpeningStock
1 Pen 100
2 Pencil 50
Material Stock (Multiple Material Entry)
MaterialId PurchaseQty SalesQty Date
1 500 0 2016-12-15
1 0 0 2016-12-16
1 300 0 2016-12-17
1 0 400 2016-12-18
1 0 0 2016-12-19
1 0 0 2016-12-20
1 0 400 2016-12-21
1 200 100 2016-12-22
Now When I Pass #FromDate and #Todate
I want to output like below:
Date MaterialName OpeningStock PurchaseQty SalesQty ClosingStock
2016-12-15 Pen 100 500 0 600
2016-12-16 Pen 600 0 0 600
2016-12-17 Pen 600 300 0 900
2016-12-18 Pen 900 0 400 500
2016-12-19 Pen 500 0 0 500
2016-12-20 Pen 500 0 0 500
2016-12-21 Pen 500 0 400 100
2016-12-22 Pen 100 200 100 200
Note :
1. If Something is wrong on database tables so, please guide me how to handle this situation.
2. And Also find Current Date Stock From Two Tables
You are looking for a rolling sum of the various quantity values. One way to do this is using correlated subqueries:
SELECT
t1.Date,
mt.MaterialName,
(SELECT OpeningStock FROM [Material Table] WHERE MaterialId = t1.MaterialId) +
COALESCE((SELECT SUM(t2.PurchaseQty - t2.SalesQty) FROM [Material Stock] t2
WHERE t2.Date < t1.Date AND t1.MaterialId = t2.MaterialId), 0) AS OpeningStock,
t1.PurchaseQty,
t1.SalesQty,
(SELECT OpeningStock FROM [Material Table] WHERE MaterialId = t1.MaterialId) +
COALESCE((SELECT SUM(t2.PurchaseQty - t2.SalesQty) FROM [Material Stock] t2
WHERE t2.Date <= t1.Date AND t1.MaterialId = t2.MaterialId), 0) AS ClosingStock
FROM [Material Stock] t1
INNER JOIN [Material Table] mt
ON t1.MaterialId = mt.MaterialId
ORDER BY
mt.MaterialName,
t1.Date;
Note that it is bad table design to be storing the opening stock values in a separate table from the material stock table. This means the above query would return no pencil records. A better approach would be to insert a seed record into material stock, for each material, with the amount being the initial stock.
Output:
Demo here:
Rextester
Simply do as below :
SELECT S.DATE, M.MaterialName, M.OpeningStock, S.PurchaseQty, S.SalesQty, SUM((M.OpeningStock+S.PurchaseQty)-S.SalesQty)ClosingStock FROM #TABLE
(
SELECT * FROM MaterialTABLE
) M
INNER JOIN Material S ON S.MaterialId = M.MaterialId where s.date between #FromDate and #Todate
I have an invoice_detail table that stores all invoice information. Obviously the detail table stores each line item, to break out the invoice like this:
Ticket_Detail_ID Ticket_Number Customer_ID Service_Code Total
1 1 15 Book1 4.00
2 1 15 Book2 5.00
3 1 15 Book3 6.00
4 2 16 Book1 4.00
5 2 16 Book2 5.00
6 3 17 Book1 4.00
7 3 17 Book2 5.00
8 3 17 Book3 6.00
I want to Select a count of distinct tickets based on Ticket_number That does not have a "Book3" service code. So in this example I would count:
Ticket 16, since it did not have a "Book3"
It would return:
1
My query right now is:
Select Count (Distinct Ticket_Number) as Total
From Invoice_Details
Where Service_Code <> 'Book3'
This returns:
6
Use NOT EXISTS:
SELECT COUNT(DISTINCT Ticket_Number)
FROM dbo.YourTable T
WHERE NOT EXISTS(SELECT 1 FROM dbo.YourTable
WHERE Service_Code = 'Book3'
AND Ticket_Number = T.Ticket_Number)
Here is an sqlfiddle with a demo of this.
I have an excel sheet that contains invoices of orders
Each invoice has the following data
ID = a unique id for each ID
CUSTOMER = The name of the ID
AMT = The total value of the invoices
DATE = The date of the purchase
For the following data
CID CUSTOMER AMT DATE
1 James 100 1/1/2012
2 Mark 110 1/1/2012
3 John 110 2/1/2012
1 James 200 2/1/2012
3 John 140 2/1/2012
2 Mark 120 3/1/2012
I need to select records from excel sheet so that i have this output
CID Customer INVCOUNT TotalValue
1 James 2 300
1 John 2 250
1 Mark 2 230
This is the sql i tried
Select
i.[CID],
i.[CUSTOMER],
Count(i.[CID]) as INVCOUNT,
sum(i.AMT) as TotalValue
From
[Invoices] i
Where
i.[DATE] >= #2/1/2012# And
i.[DATE] <= #3/1/2012#
Group By
i.[CID], i.[CUSTOMER]
Having
Count(i.[CID]) > 1
pls this is an excel query, not mysql. The tag i used earlier was a mistake.
WHat am i doing wrong?
To get the output you specified:
Select
1 as CID,
i.[CUSTOMER],
Count(i.[CID]) as INVCOUNT,
sum(i.AMT) as TotalValue
From
[Invoices] i
Where
i.[DATE] >= #1/1/2012# And
i.[DATE] <= #3/1/2012#
Group By
i.[CID], i.[CUSTOMER]
Having
Count(i.[CID]) > 1
To get the output I think you actually want:
Select
i.[CID],
i.[CUSTOMER],
Count(i.[CID]) as INVCOUNT,
sum(i.AMT) as TotalValue
From
[Invoices] i
Where
i.[DATE] >= #1/1/2012# And
i.[DATE] <= #3/1/2012#
Group By
i.[CID], i.[CUSTOMER]
Having
Count(i.[CID]) > 1
This should generate
CID Customer INVCOUNT TotalValue
1 James 2 300
2 John 2 250
3 Mark 2 230