I have the data in the following format in varchar form. There are 48 million rows in this format
'2015-09-18 00:00:00.000'
and want to convert it to the following format
'2015-09-18'
Can anyone help me with the code in Oracle
If your column has a timestamp type, you simply need to use to_char to format it properly:
with yourTable(yourDateColumn) as
(
select to_timestamp('2015-09-18 00:00:00.000', 'YYYY-MM-DD HH24:MI:SS.FF') from dual
)
select to_char(yourDateColumn, 'yyyy-mm-dd')
from yourTable
If your column is a string ( and storing dates in string fields is generally a very bad idea) with a fixed format, you simply need a substr:
with yourTable(yourStringColumn) as
(
select '2015-09-18 00:00:00.000' from dual
)
select substr(yourStringColumn, 1, 10)
from yourTable
Related
How can I convert 2019-07-01T00:00:00+05:30 to DateTime in SQL?
2019-07-01T00:00:00+05:30 is a varchar field. I need to convert this into DateTime to compare this to a date field.
suggest me a query to Convert (2019-07-01T00:00:00+05:30) into DateTime
Convert To date :
select cast('2019-07-01T00:00:00+05:30' as Date)
Convert To time:
select cast('2019-07-01T00:00:00+05:30' as Time)
Convert To datetime :
select convert(datetime2, '2019-07-01T10:00:30+05:30',0)
Try any of these..
select cast(convert(datetime2, '2019-07-01T10:00:30+05:30',0) as datetime)
select convert(datetime2, '2019-07-01T10:00:30+05:30',0)
One option would be to use a combination of CONVERT on the timestamp without the timezone component, then use TODATETIMEOFFSET with the timezone portion to get the final result:
WITH yourTable AS (
SELECT '2019-07-01T00:00:00+05:30' AS dt
)
SELECT
TODATETIMEOFFSET(CONVERT(datetime, LEFT(dt, 19), 126), RIGHT(dt, 6)) AS output
FROM yourTable;
This outputs:
01/07/2019 00:00:00 +05:30
Demo
Unfortunately, SQL Server truncates the time zone information when converting from datetimeoffset to dateordatetime`. But, you can calculate the offset and add it back in:
select dateadd(minute,
datediff(minute, convert(datetimeoffset, dt), convert(datetime, convert(datetimeoffset, dt))),
convert(datetime, convert(datetimeoffset, dt))
)
from (values ('2019-07-01T00:00:00+05:30')) v(dt);
For your particular timezone, the date at midnight matches the UTC date, so you are safe. I'm on the other side of the world, so this would be a more important consideration in the "western" world ("west" being west of UTC).
The following query will convert the given VARCHAR to DATETIME value:
DECLARE #DateVal AS VARCHAR (30) = '2019-07-01T00:00:00+05:30';
SELECT CAST(REPLACE(SUBSTRING(#DateVal, 0, CHARINDEX('+', #DateVal)), 'T', ' ') AS DATETIME);
I have a table containing StartDate in the format dd/mm/yyyy and yyyy-mm-dd.
I want to convert this varchar column to DATE type in the format DD/MM/YYYY.
I have tried the below.
select CONVERT(varchar(20),StartDate,103) AS [FormattedDate]
and
CONVERT(VARCHAR(20),(CAST([StartDate] AS DATE)),103)
I get the error -Conversion failed when converting date and/or time from character string.
Pls suggest.
if you only have the date string in dd/mm/yyyy or yyyy-mm-dd
select case when substring(StartDate, 3, 1) = '/'
then convert(date, StartDate, 103)
else convert(date, StartDate, 121)
end
SQL Server is actually quite good about figuring out formats for a date conversion with no formatting argument. However, it is going to assume MM/DD/YYYY for the second format and generate an error.
So, you can use try_convert() and coalesce():
select coalesce(try_convert(date, startdate, 103),
convert(date, startdate)
)
Here is a SQL Fiddle.
Then, you should go into your data and fix the column. Here is one method:
update t
set startdate = coalesce(try_convert(date, startdate, 103),
convert(date, startdate)
);
alter table t alter column startdate date;
You can add additional formatting for the result set by turning the date back into a string, using convert().
To get YYYY-MM-DD use SELECT CONVERT(varchar, getdate(), 23)
To get MM/DD/YYYY use SELECT CONVERT(varchar, getdate(), 1)
For detailed explaination try this.
Here's an example that first tries to convert the VARCHAR from a 'yyyy-mm-dd' format to the 'dd/mm/yyyy' format.
If that doesn't work out, then it just assumes it's already in the 'dd/mm/yyyy' format.
And then defaults to the first 10 characters from the string.
declare #TestTable table (StartDate varchar(10), DateFormatUsed varchar(10));
insert into #TestTable (StartDate, DateFormatUsed) values
(convert(varchar(10),GetDate() ,103), 'dd/mm/yyyy')
,(convert(varchar(10),GetDate(), 20), 'yyyy-mm-dd')
;
select t.*,
coalesce(convert(varchar(10), try_convert(date,StartDate,20),103), left(StartDate,10)) as [FormattedDate]
from #TestTable t;
But try_convert is only available since MS SQL Server 2012.
For MS SQL Server 2008 we can use a CASE WHEN with a LIKE to check the format.
declare #TestTable table (StartDate varchar(30), DateFormatUsed varchar(30));
insert into #TestTable (StartDate, DateFormatUsed) values
(convert(varchar(10),GetDate(), 103), 'dd/mm/yyyy')
,(convert(varchar(10),GetDate(), 20), 'yyyy-mm-dd')
,(convert(varchar(19),GetDate(), 20), 'yyyy-mm-dd hh:mi:ss')
;
select t.*,
(case
when StartDate like '[0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9]%'
then convert(varchar(10), convert(date, left(StartDate, 10), 20), 103)
else left(StartDate, 10)
end) as [FormattedDate]
from #TestTable t;
I am running queries in a hive environment.
I have a column which has a timestamp but is set up a string in the tables. I tried the following : all of them return Null
SELECT
,To_date(activitydate)
Cast:
,cast(activitydate as timestamp)
This is the how the data is set up in the table:
Appreciate any inputs on how I can convert this :
05/12/2017 00:00:00
SELECT
cust_id
,to_date(activitydate) activity_date
,type type_of_contact
FROM repl_task
WHERE to_date(activitydate) BETWEEN '2014-01-01' AND '2017-01-01' ;
I am running out of memory if I run this :
SELECT
cust_id
,activitydate
,SUBSTR(activitydate,4,2) AS DT
,SUBSTR(activitydate,0,2) AS MONTH
,SUBSTR(activitydate,7,4) AS YEAR
,type
FROM task
WHERE activitydate >='01/01/2016 00:00:00'
unix_timestamp function converts given format to unix timestamp and from_unixtime function converts from unix timestamp to given format:
hive> select from_unixtime(unix_timestamp('01/01/2016 00:00:00','MM/dd/yyyy HH:m:ss'),'yyyy-MM-dd');
OK
2016-01-01
Time taken: 0.118 seconds, Fetched: 1 row(s)
Can you try using to_date() with the date portion of your timestamp in ISO format:
SELECT
cust_id,
TO_DATE(CONCAT(SUBSTR(activitydate, 7, 4), '-',
SUBSTR(activitydate, 0, 2), '-',
SUBSTR(activitydate, 4, 2))) activity_date
type type_of_contact
FROM repl_task
WHERE
TO_DATE(CONCAT(SUBSTR(activitydate, 7, 4), '-',
SUBSTR(activitydate, 0, 2), '-',
SUBSTR(activitydate, 4, 2)))
BETWEEN '2014-01-01' AND '2017-01-01';
If this runs, but is not very performant, then you should consider storing your timestamps in ISO format. Storing dates as text, or as text in a non standard format, carries a penalty with most databases.
How can I convert these kind of date values from varchar to datetime2?
WITH dates AS (
SELECT '6.7.2012' AS dtm
UNION
SELECT '13.2.2012' AS dtm
UNION
SELECT '3.12.2012' AS dtm
UNION
SELECT '20.11.2012' AS dtm
)
SELECT CAST(dtm as datetime2) FROM dates
;
This results in an error:
Msg 241, Level 16, State 1, Line 6
Conversion failed when converting date and/or time from character string.
Use try_convert instead of cast:
WITH dates AS (
SELECT '6.7.2012' AS dtm
UNION
SELECT '13.2.2012' AS dtm
UNION
SELECT '3.12.2012' AS dtm
UNION
SELECT '20.11.2012' AS dtm
)
SELECT TRY_CONVERT(datetime2, dtm, 104) FROM dates
;
Results:
13.02.2012 00:00:00
20.11.2012 00:00:00
03.12.2012 00:00:00
06.07.2012 00:00:00
Note: try_convert was introduced in 2012 version, for earlier versions you need to use convert, risking an exception if the varchar value can't be converted using the specified style.
I have a table where the varchar column CREATED_BY has the data in the format
USER - dd/MM/yyyy hh:mm.
I'm trying to do data migration and need to get records where the created date is greater than a certain date, but the format of the column makes this difficult, so
SELECT * FROM TABLE_NAME WHERE -- last part of CREATED_BY > SOMEDATE
Well, since the dd/MM/yyyy hh:mm format has a fixed length, you can use the RIGHT function to extract the data part from your string:
SELECT *
FROM TABLE_NAME
WHERE CONVERT(datetime, RIGHT(CREATED_BY, 16), 103) > somedate
You need to extract the date from the string:
WHERE cast(reverse ( substring ( reverse ( #string ) , 1 , 16 ) ) as datetime) > somedate