Split sql string value based on 7th delimiter - sql

Question

Present column value
(Below is column value from temp table, value here is dynamically changing)
45 | 00055 | 9/30/2016 | Vodafone | Randy Singh | Newyork | Test Msg | TBL101 | PC | 1.00 | COMP101 | CS | 1.00.............. etc
Need to divide based on 7th PIPE i.e after Test Msg
Output should be
String1
45 | 00055 | 9/30/2016 | Vodafone | Randy Singh | Newyork | Test Msg
and (as a second string)
String 2
TBL101 | PC | 1.00 | COMP101 | CS | 1.00......... etc
Function
CREATE FUNCTION dbo.SUBSTRING_INDEX
(
#str NVARCHAR(4000),
#delim NVARCHAR(1),
#count INT
)
RETURNS NVARCHAR(4000)
WITH SCHEMABINDING
BEGIN
DECLARE #XmlSourceString XML;
SET #XmlSourceString = (SELECT N'<root><row>' + REPLACE( (SELECT #str AS '*' FOR XML PATH('')) , #delim, N'</row><row>' ) + N'</row></root>');
RETURN STUFF
(
((
SELECT #delim + x.XmlCol.value(N'(text())[1]', N'NVARCHAR(4000)') AS '*'
FROM #XmlSourceString.nodes(N'(root/row)[position() <= sql:variable("#count")]') x(XmlCol)
FOR XML PATH(N''), TYPE
).value(N'.', N'NVARCHAR(4000)')),
1, 1, N''
);
END
GO
DECLARE #EmpId NVARCHAR(1000)
select #EmpId = temp from OMSOrderTemp
SELECT dbo.SUBSTRING_INDEX(#EmpId, N'|', 7) AS Result;e
Here in Result only string1 is showing and only first row.

Answer 1

Spend time for you and happy that come with solution , I have modify the your function with own logic you can try this, This is table value function i.e this function will return Table
CREATE FUNCTION dbo.SUBSTRING_INDEX
(
#str NVARCHAR(4000),
#delim NVARCHAR(1),
#count INT
)RETURNS #rtnTable TABLE
(
FirstString NVARCHAR(2000),
SecondString NVARCHAR(2000)
)
AS
BEGIN
DECLARE #cnt INT=1;
DECLARE #subStringPoint INT = 0
WHILE #cnt <=#count
BEGIN
SET #subStringPoint=CHARINDEX(#delim,#str,#subStringPoint)+1
SET #cnt=#cnt+1
END
INSERT INTO #rtnTable
SELECT SUBSTRING(#str,0,#subStringPoint-1) ,SUBSTRING(#str,#subStringPoint+1,LEN(#str))
RETURN
END
To call this function
DECLARE #s varchar(MAX)='45 | 00055 | 9/30/2016 | Vodafone | Randy Singh | Newyork | Test Msg | TBL101 | PC | 1.00 | COMP101 | CS | 1.00'
SELECT * FROM dbo.SUBSTRING_INDEX (#s,'|',7)
This will gives two column output
45 | 00055 | 9/30/2016 | Vodafone | Randy Singh | Newyork | Test Msg TBL101 | PC | 1.00 | COMP101 | CS | 1.00

Answer 2

Finally got a solution almost identical to #JaydipJ. I thought to implement in a different way but the following should do using While loop:
DECLARE #str VARCHAR(1000),
#str1 VARCHAR(1000),
#str2 VARCHAR(1000),
#pos INT,
#counter INT
SET #str = '45 | 00055 | 9/30/2016 | Vodafone | Randy Singh | Newyork | Test Msg | TBL101 | PC | 1.00 | COMP101 | CS | 1.00.............. etc'
SET #counter = 0
SET #pos = 0
WHILE #counter < 7
BEGIN
SET #pos = CHARINDEX('|', #str, #pos + 1) ---- Gets the position of delimiter '|'
SET #counter = #counter + 1 ---- Increments the counter on the given counter value
END
SET #str1 = SUBSTRING(#str, 1, #pos) ---- Splits the string on the 7th position of delimiter '|'
SET #str2 = SUBSTRING(#str, #pos + 1, LEN(#str) - #pos) ---- Splits the rest of the string
Print 'str1='+ #str1
Print 'str2='+ #str2
SELECT #str1 AS String1, #str2 AS String2
The While loop is used to iterate through the string and getting the Delimiter position, it splits the string.