I Try To Setup The Cron Job To My Cpanel On My Servers But It Give me An Error:
The cron Job link is:
*/10 * * * * wget -O schedule http://ptcpt.publiadds.org.pt/backend/scheduled.php >/dev/null 2>&1
The Error
"-":4: bad command
errors in crontab file, can't install.
Related
so I have phantomJS and casperJS installed, everything is working fine, but I'm trying to add my casperJS file to cronjob (ubuntu) and I'm getting error:
/bin/sh: 1: /usr/local/bin/casperjs: not found
My crontab file:
0 */1 * * * PHANTOMJS_EXECUTABLE=/usr/local/bin/phantomjs
/usr/local/bin/casperjs /usr/local/share/casper-test/test.js 2>&1
Any Ideas whats wrong?
If you want to use several commands on one line, you have to separate them with a semicolon:
0 */1 * * * PHANTOMJS_EXECUTABLE=/usr/local/bin/phantomjs ; /usr/local/bin/casperjs /usr/local/share/casper-test/test.js 2>&1
Or, if you need to execute commands sequentially and only progress to next if the previous has been successful, use && operator.
For better readability you could just put those commands in a shell script and run that from cron.
I have a CentOs setup in test server.
I wanna to run a cron job (the cron needs to run apache server at 12AM) daily.
My cron.daily fodler is located in /etc/cron.daily
Please let me know the steps how to implement this.
Usually I use to restart the apache service using the below command:
service httpd restart
I wanna to do restart apache service automatically using cron 12AM daily.
Thanks in advance.
While #einterview's answer is almost correct, it's important to note that a * in the minute column will run the job every minute of that hour. If intending to run once every hour, steps would be:
SSH into server.
Get list of current user's jobs with $ crontab -l
Edit jobs list with $ crontab -e (default editor will open)
Add 0 4 * * * service mysql restart for mysql at 4:00am
Add 0 5 * * * service apache2 restart for apache2 at 5:00am
Add 0 0 * * * service apache2 restart for apache2 at 12:00 am
Save and close (Ctrl+O and Ctrl+X in nano)
Recheck with $ crontab -l
I got it and give you step by step adding cron jobs into your system:
Login to your server with SSH
Type crontab -l to display list of cron jobs,
Type crontab -e to edit your crontab,
Add 0 4 * * * /etc/init.d/mysqld restart to restart Mysql everyday at 4 AM,
Add 0 5 * * * /etc/init.d/httpd restart to restart Apache everyday at 5 AM and
Add 0 24 * * * /etc/init.d/httpd restart to restart Apache everyday at 12 AM
Save your file,
Recheck with crontab -l
Get the path for service by running: which service. This should return something like /usr/sbin/service
Add entry to contrab via crontab -e and enter the following:#daily /usr/sbin/service httpd restart
If you do not want an email sent to you whenever it is run, you should instead add the following: #daily /usr/sbin/service httpd restart > /dev/null 2>&1
To find what time cron daily runs, run: grep run-parts /etc/crontab
PS: It is important to get the full path to service.
It wasn't spelled out in the other answers so I'll say it here. There is a different list of cron jobs for the current user and the root user. On my Raspberry Pi 4, doing it the way above does not work because the current user doesnt have permission to restart the service.
This works however:
sudo crontab -l (List current jobs)
sudo crontab -e (Edit cron job list)
0 0 * * * systemctl restart openvpn.service (Add this line to the bottom)
Save and close (Ctrl+O, ENTER, Ctrl+X in nano)
sudo crontab -l (Validate job was added)
In other words, "crontab -l" will give a different list than "sudo crontab -l". Adding "sudo" to the above commands makes the job run as root.
You can use following command:
crontab -e
Add following line to cron:
0 12 * * * service httpd restart
or use following command.
echo "0 12 * * * service httpd restart" | crontab -
This site is a good one for cron time https://crontab.guru
I am not allowed to comment yet on the last one here, but actually you can just use 0 0 * * * then it will go through a-ok.
Tried on ubuntu 20.04.3 LTS
sudo crontab -e
0 8 * * * /home/<user>/restart_service.sh
# Runs above crontab 8AM everyday.
Inside restart_service.sh
#!/bin/bash
systemctl restart my_service.service
Later provide appropriate permissions for execute
chmod u+x /home/<user>/restart_service.sh
following this advice adding:
0 12 * * * /etc/init.d/httpd restart
0 24 * * * /etc/init.d/httpd restart
I get "/tmp/crontab.D6cOzs/crontab":3: bad hour
errors in crontab file, can't install.
i had to do 12 only then it worked, so I'm assuming 24 is unacceptable
I have a created a script to check to see if my glassfish server is running (installed on a freebsd system), if it isn't, the script attempts to kill the java process to ensure it's not hung, and then issues the asadmin start-domain command
If this script runs from the command line it is successful 100% of the time. When it is run from the cron tab, every line runs except the asadmin start-domain line - it does not seem to execute or at least does not complete, i.e. the server is not running after this script runs.
For anyone not familiar with glassfish or the asadmin utility used to start the server, it is my understanding that a forked process is used. could this be causing a problem via cron?
Again, in all my tests today, the script runs to completion when run from the command line. Once it's executed through the cron, it does not complete... what would be different running this from the crontab???
thanks in advance for any help... i'm pulling my hair out trying to make this work!
#!/bin/bash
JAVA_HOME=/usr/local/diablo-jdk1.6.0/; export JAVA_HOME
timevar=`date +%d-%m-%Y_%H.%M.%S`
process_name='java'
get_contents=`cat urls.txt`
for i in $get_contents
do
echo checking $i
statuscode=$(curl --connect-timeout 10 --write-out %{http_code} --silent --output /dev/null $i)
case $statuscode in
200)
echo "$timevar $i $statuscode okay" >> /usr/home/user1/logfile.txt
;;
*)
echo "$timevar $i $statuscode bad" >> /usr/home/user1/logfile.txt
echo "Status $statuscode found" | mail -s "Check of $i failed" some.address#gmail.com
process_id=`ps acx | grep -i $process_name | awk {'print $1'}`
if [ -z "$process_id" ]
then
echo "java wasn't found in the process list"
else
echo "Killing java, currently process $process_id"
kill -9 $process_id
fi
/usr/home/user1/glassfish3/bin/asadmin start-domain domain1
;;
esac
done
Also, just for completeness, here is the entry in the cron tab:
*/2 * * * * /usr/home/user1/server.check.sh >> /usr/home/user1/cron.log
Ok... found the answer to this on another site, but I thought I'd add the answer in here for future reference.
The problem was the PATH!! even though java_home was set, java itself wasn't in the path for the cron daemon.
A quick test to see what path is available to your cron, add this line:
*/2 * * * * env > /usr/home/user1/env.output
From what I can gather, the PATH initially available to cron is pretty minimal. Since java was in /usr/local/bin, i added that to the path right in the crontab and kaboom! it worked!
PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin
*/2 * * * * /usr/home/user1/server.check.sh >> /usr/home/user1/cron.log
I'm trying to set up a cron job with the following command:
crontab -l
Begin Whenever generated tasks for: myapp
* * * * * /bin/bash -l -c 'cd /Users/boris/projects/myapp && script/rails runner "Resque.enqueue(MyModel)"'
I get the following error; in which I see its loading Ruby 1.8. The problem is I'm using RVM with ruby 1.9.2. How do I specify the correct RVM path in CRON?
Subject: Cron <boris#jz> /bin/bash -l -c cd /Users/boris/projects/myapp && script/rails runner "Resque.enqueue(Place)"
X-Cron-Env: <SHELL=/bin/sh>
X-Cron-Env: <PATH=/usr/bin:/bin>
X-Cron-Env: <LOGNAME=boris>
X-Cron-Env: <USER=boris>
X-Cron-Env: <HOME=/Users/boris>
Message-Id: <20110523022400.A5B242C608D#jz.local>
Date: Sun, 22 May 2011 19:24:00 -0700 (PDT)
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require': no such file to load -- bundler/setup (LoadError)
from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/rubygems/custom_require.rb:31:in `require'
from /Users/boris/projects/myapp/config/boot.rb:6
from script/rails:5:in `require'
from script/rails:5
How do I specify the correct RVM path in CRON?
Thanks in advance
Ruby path with which ruby:
/Users/boris/.rvm/rubies/ruby-1.9.2-p180/bin/ruby
Please do not use the -l switch in cron jobs. The --login switch instructs bash to run as a login shell. Therefore, it will load your environment, and things might appear to work. However, cron jobs are by nature non-interactive, non-login shells. Invoking them as if they were is just bad practice. Also, when bash starts a login shell, it first loads the system environment (/etc/profile), and if in that file something needs to print to the screen (like motd), your cron job will report nasty errors like this:
stty: TIOCGETD: Inappropriate ioctl for device
You don't need to write a cron runner neither (following that logic, you might as well write a cron runner runner). Please keep things simple. All you need to do is configure your cron job to launch a bash shell, and make that bash shell load your environment.
The shebang line in your script should not refer directly to a ruby executable, but to rvm's ruby:
#!/usr/bin/env ruby
This instructs the script to load the environment and run ruby as we would on the command line with rvm loaded.
On many UNIX derived systems, crontabs can have a configuration section before the actual lines that define the jobs to be run. If this is the case, you would then specify:
SHELL=/path/to/bash
This will ensure that the cron job will be spawned from bash. Still, your environment is missing, so to instruct bash to load your environment, you will want to add to the configuration section the following:
BASH_ENV=/path/to/environment (typically .bash_profile or .bashrc)
HOME is automatically derived from the /etc/passwd line of the crontab owner, but you can override it.
HOME=/path/to/home
After this, a cron job might look like this:
15 14 1 * * $HOME/rvm_script.rb
What if your crontab doesn't support the configuration section. Well, you will have to give all the environment directives in one line, with the job itself. For example,
15 14 1 * * export BASH_ENV=/path/to/environment && /full/path/to/bash -c '/full/path/to/rvm_script.rb'
Full blog post on the subject
Your problem is that you're executing two commands but not as you expect. The two commands are:
/bin/bash -l -c cd /Users/boris/projects/myapp
script/rails runner "Resque.enqueue(MyModel)"
With the second only executing if the first succeeded. I think you just need some quotes:
* * * * * /bin/bash -l -c 'cd /Users/boris/projects/myapp && script/rails runner "Resque.enqueue(MyModel)"'
Those single quotes will feed your cd ... && script/rails ... pair to /bin/bash as a single command and that should change the current working directory to what you want when script/rails is executed.
Easiest solution is to use this command instead:
Begin Whenever generated tasks for: myapp
* * * * * /bin/bash -l -c 'cd /Users/boris/projects/myapp && ./script/rails runner "Resque.enqueue(MyModel)"'
I have a cron job script and i used >/dev/null 2>&1 to Stop sending Emails. But each time a file is created in the same name of PHP file with trailing numbers like phpfile.php.1, phpfle.php.2, phpfile.php.3….
Is there any script to stop that?
Add -O /dev/null to your wget command.